Answer:
A.
–2; –250; –156,250
Step-by-step explanation:
A(1) = -2 x 5(1) - 1 = -11
A(4) = -2 x 5(4) -1 = -41
A(8) = -2 x 5(8) -1 = -81
...............................................................................................................................................
an=a1(r)^(n-1)
a1=first term
r=common ratio
n=which term
so
an=-2(5)^(n-1)
first term is -2
4th term is subsitue 4 for n
a4=-2(5)^(4-1)
a4=-2(5)^3
a4=-2(125)
a4=-250
4th term is -250
--------------------------
8th term
a8=-2(5)^(8-1)
a8=-2(5)^7
a8=-2(78125)
a8=-156250
8th term is -156250
...............................................................................................................................................
A(1)=2*5^1-1=2*5^0=2*1=2
a(4)=2*5^4-1=2*5^3=2*125=250
a(8)=2*5^8-1=2*5^7=2*78,125=156,250
...............................................................................................................................................
2, 250, 156, 250
What is (0,6] n (6,8]?
Answer:
(6) the letter n : intersection which means the number you will find at the first bracket and has the same number at the other bracket
When a sprinkler is installed in the ground, the spray of water goes up and falls in the pattern of a parabola. The height, in inches, of a spray of water is given by the equation h(x)=160x−16x2 where x is the number of feet away from the sprinkler head the spray is. What is the height of the spray 2 feet away from the sprinkler head?
Answer:
(1) 256 inches
(2) 5 feet
(3) 400 inches
(4) 10 feet
Step-by-step explanation:
(1) The function that gives the height in inches of the spray of water at a distance x from the sprinkler head is given as follows;
h(x) = 160·x - 16·x²
At x = 2 feet, we have;
h(2) = 160 × 2 - 16 × 2² = 256
Therefore, the height of the spray water at a horizontal distance of 2 feet from the sprinkler head h(2) = 256 inches
(2) The x-coordinate, [tex]x_{max}[/tex], of the maximum point of a parabola given in the form, y = a·x² + b·x + c is found using the following formula;
[tex]x_{max}[/tex] = -b/(2·a)
The x-coordinate, [tex]x_{max}[/tex], of the maximum point of the given equation of the parabola, h(x) = 160·x - 16·x², (a = -16, b = 160) is therefore;
[tex]x_{max}[/tex] = -160/(2 × (-16)) = 5
Therefore, the number of feet along the way, the function will reach maximum height, [tex]x_{max}[/tex] = 5 feet
(3) The function, h(x) = 160·x - 16·x², will reach maximum height, [tex]h_{max}[/tex], at x = 5, therefore;
[tex]h_{max}[/tex] = h(5) = 160 × 5 - 16 × 5² = 400
The maximum height of the spray, [tex]h_{max}[/tex] = 400 inches
(4) The water is at ground level where h(x) = 0, therefore;
At ground level, h(x) = 0 = 160·x - 16·x²
160·x - 16·x² = 0
∴ 16·x × (10 - x) = 0
By zero product rule, we 16·x = 0, or (10 - x) = 0, from which we have;
x = 0, or x = 10
The water is at ground level at x = 0 and x = 10 feet, therefore, the water will hit the ground again (the second time after leaving the sprinkler head at x = 0) at x = 10 feet.
Help me solve this please!
Answer Should be 45
Answered by Gauthmath must click thanks and mark brainliest
Prove that angle ABD is congruent to angle CBE
with solution!
ANSWER:
the conditions are the angle a is equal to angle c and ab = bc . Hence we need to prove that the triangles is congruent to the triangle cbe. ... angle A =angle C and AB=BC.
Decide!!!!!!!!!!!!!!!!!!!!!
Answer:
15 unitsStep-by-step explanation:
Let the coordinates of point B are (x, y).
Since the rotation is clockwise the angle measure between OA and OB is -60° (IV quadrant).
x = 15 cos (-60°) = 7.5y = 15 sin (-60°) = -12.99The distance between A and B is:
AB = [tex]\sqrt{(15-7.5)^2+(0+12.99)^2} = \sqrt{225}[/tex] = 15 unitsAnother solutionSince OA = OB = 15 units and AOB is 60° angle the triangle OAB is equilateral. Hence AB is same as OA and OB, so AB = 15 units.
A game involves correctly choosing the 5 correct numbers from 1 through 18 that are randomly drawn. What is the probability that a person wins the game, if they enter a) once? b) 7 times with a different choice each time?
Answer:
[tex]=\frac{1}{8568}\ = .00011\\\ =\frac{7}{8568} = .00081[/tex]
Step-by-step explanation:
[tex]5/18\cdot \:4/17\cdot \:3/16\cdot \:2/15\cdot \:1/14=\frac{1}{8568}[/tex]
A correct description of the line defined by y-6= -1/2(x+7) is
a. it is a line through (-7,6) with a slope of 1/2
b. it is a line through (7,-6) with a slope of -1/2
c. it is a line through (-7,6) with a slope of -1/2
d. it is a line through (7,-6) with a slope of 1/2
Answer:
C
Step-by-step explanation:
The correct answer is C
Because taking the point to be (a,b)
[tex]y - b = m(x - a) \\ \: is \: the \: \: equation \: \: of \: \: a \: line[/tex]
repost , can someone help asap!
Answer:
y = -3/4x + 3
Step-by-step explanation:
The first four terms of a sequence are, 9,2,-5,-12.
State the pattern of the sequence using algebraic expressions.
Answer:
[tex]a_{n}[/tex] = 16 - 7n
Step-by-step explanation:
There is a common difference between consecutive terms , that is
2 - 9 = - 5 - 2 = - 12 - (- 5) = - 7
This indicates the sequence is arithmetic with nth term
[tex]a_{n}[/tex] = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 9 and d = - 7 , then
[tex]a_{n}[/tex] = 9 - 7(n - 1) = 9 - 7n + 7 = 16 - 7n
Help Exit This Box-and-Whisker Plot displays the distribution of scores of a recent physics test. What is the median number of this set of physics test scores? Physics Test Scores
Answer: A) 87
The median value is the second quartile (Q₂), which is 87.
Answer:
A: 87
Step-by-step explanation:
Sorry for this very late response. But if anyone is not sure if answer A is correct, it is. I can confirm this because I just took the test. I hope I could help! (:
What is the length of segment AB
A) 3
B) [tex]\sqrt{20}[/tex]
C) [tex]\sqrt{41}[/tex]
D) 9
Answer: [tex]\large \boldsymbol {C) \ AB=\sqrt{41} }[/tex]
Step-by-step explanation:
The formula for the distance between points:[tex]\bf AB= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex] Coordinates of point A (0;5 ); coordinates of point B(4;0)[tex]\bf AB= \sqrt{(0-4)^2+(5-0)^2} =\sqrt{16+25} =\sqrt{41}[/tex]
Sal washed 5 cars in 50 minutes. What is the unit rate?
Answer:
since Sal washed 5 cars in 50 minutes, we can express his time as follow:
[tex] \frac{5 \: cars}{50 \: minutes} [/tex]
simplifying it by diving by 5, we get:
[tex] \frac{1 \: car}{10 \: minutes} [/tex]
Thus the rate will be 10 minutes per car (10 min/car)
Answer:
10 mins / car
Step-by-step explanation:
50 / 5 = 10
Harish
covers
3/10
of the distance between two cities in
1 4/5
hours. If he travels at the same speed, how much of the total distance would he cover in
3 1/5
hours?
Answer:
Step-by-step explanation:
Distance traveled in [tex]1\frac{4}{5}[/tex] hours = [tex]\frac{3}{10}[/tex]
Distance traveled in 1 hour = [tex]\frac{3}{10}[/tex] ÷ [tex]1\frac{4}{5}[/tex]
[tex]=\frac{3}{10}[/tex] ÷ [tex]\frac{9}{5}[/tex]
[tex]= \frac{3}{10}*\frac{5}{9}\\\\=\frac{1}{2}*\frac{1}{3}\\\\=\frac{1}{6}[/tex]
distance traveled in 3 1/5 hours = [tex]\frac{1}{6}*3\frac{1}{5}[/tex]
=[tex]=\frac{1}{6}*\frac{8}{5}\\\\=\frac{1}{3}*\frac{4}{5}\\\\=\frac{4}{15}[/tex]
Please help me fast
Answer:
864
Step-by-step explanation:
A=6a^2=6·12^2=864
Answer:
864 in^2
Step-by-step explanation:
2(144+144+144) = 2(432) = 864 in^2.
Hope this helped!
2. Give an example of a rational number that is not a whole number.
This are a few of Rational numbers are not whole numbers: 8,−3,32,7−5.
Step-by-step explanation: Hope this helps
HELP ASAP PLEASEREEEEE
Answer:
uh
Step-by-step explanation:
my guy, I DK.
How would I find cos(180º) without a calculator?
Answer:
Step-by-step explanation:
The cos of an angle is the adjacent / hypotenuse.
In this case the adjacent and hypotenuse are the same length so the answer is 1 in some form.
You are going left when you talk about 180 degrees. So the adjacent = - 1
The answer you want is -1 / 1
Cos(180) = - 1
Will give brainliest need a quick answer
ILL MARK BRAINIEST IF U DO THIS RIGHT!!!
Answer:
D because even though the flat fee is 150 paying 5$ a hour it will cost less
if X=2
y=-1
z=3
Find the value of
a. 2y3(cube) z2(square)
Step-by-step explanation:
2y³z²
2(-1)³(3)²
=2(-1)(9)
=-18
Function g can be thought of as a scaled version of f(x)=|x|
Answer:
g(x) = 1/2 |x|
Step-by-step explanation:
Scaling f(x) means it's of the form g(x) = a|x|
From the graph, it appears to pass through the point (2, 1). By subbing in the values for this point, the equation can be found to be:
1 = a|2|
a = 1/2
Therefore, g(x) = 1/2 |x|
Whose perfect square should be added to the sum of the greatest three digit prime number and the smallest two-digit prime number, so that the resultant number is perfect square of 32? pls give me ans pls pls pls
Answer:
Step-by-step explanation:
Let y is the required number.
a/c to question,
y² + greatest three digit prime number + smallest two digit prime number = 32²
we know, greatest three digit prime number = 997
smallest two digit prime number = 11
now, y² + 997 + 11 = 32²
or, y² + 1008 = 1024
or, y² = 1024 - 1008
or, y² = 16
or, y = 4
hence, required number number is one digit even number e.g., y = 4
Hope this answer helps you :)
Have a great day
Mark brainliest
Ai giải giúp mình giải bài này với
[tex]\sqrt{36x^{2} -60x+25} =4[/tex]
Answer:
x=[tex]\frac{3}{2}[/tex] and x=[tex]\frac{1}{6}[/tex]
Step-by-step explanation:
[tex]\sqrt{36x^2-60x+25}=4[/tex]
=> [tex]\sqrt{36x^2-60x+25}^{2} =4^{2}[/tex]
=> [tex]{36x^2-60x+25}=16[/tex]
=> [tex]36x^2-60x+25-16=16-16[/tex]
=> [tex]36x^2-60x+9=0[/tex]
=> [tex]x_{1,\:2}=\frac{-\left(-60\right)\pm \sqrt{\left(-60\right)^2-4\cdot \:36\cdot \:9}}{2\cdot \:36}\\\\\sqrt{\left(-60\right)^2-4\cdot \:36\cdot \:9}=48[/tex]
=> [tex]x_{1,\:2}=\frac{-\left(-60\right)\pm \:48}{2\cdot \:36}[/tex]
=>[tex]x_{1} = \frac{-\left(-60\right)+48}{2\cdot \:36}\\\\x_{1}=\frac{60+48}{2\cdot \:36}\\\\x_{1}=\frac{108}{72} \\\\\\x_{1}=\frac{3}{2}\\[/tex]
=> [tex]x_{2}=\frac{-\left(-60\right)-48}{2\cdot \:36}\\\\x_{2} =\frac{60-48}{2\cdot \:36}\\\\x_{2}=\frac{12}{2\cdot \:36}\\\\\x_{2}=\frac{12}{72}\\\\x_{2}=\frac{1}{6}[/tex]
asap help -------------------
Answer:
C. Complex
Step-by-step explanation:
A complex number consists of a real part (-4.8) and an imaginary part (56i)
The table shows values for a quadratie function
What is the average rate of change for this function for the interval from 1
Please see
Pic
Answer:
B
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is
[tex]\frac{f(b)-f(a)}{b-a}[/tex]
Here [ a, b ] = [ 1, 3 ] , then
f(3) = 18 ← value of y when x = 3
f(1) = 2 ← value of y when x = 1
Then
average rate of change = [tex]\frac{18-2}{3-1}[/tex] = [tex]\frac{16}{2}[/tex] = 8 → B
Geometry, please answer question ASAP
BECAUSE ACCORDING TO THE PERIMETER (TRIANGLE ) FORMULA = B * H / 2.
B = BASE.
H = HEIGHT.
THE HEIGHT IS A VARIABLE VLAUE NEEDED IN ORDER TO ONTINUE TO SOLVE AND EVENTUALLY LEADING TO THE ANSWER (TRIANGLE PERIMETER.
Can someone please help me with my maths question
Answer:
a) log 2 (48 ×3 ×9 )
log 2 1296
10.3
b) log 4 24 - log 4 3/4 log 4 2
log 4 36
2.58
| 3 x - 2 | = 4x + 4
Answer: -2/7
|3x - 2| - 4x = 4
1) (3х - 2) - 4х = 4, if 3x - 2 >= 0
2) -(3x - 2) - 4x = 4, if 3x - 2 < 0
1)
3х - 4х = 4 + 2
-x = 6
x = -6
3х - 2 >= 0
3х >= 2
x >= 2/3 - wrong
2)
-3х + 2 - 4х = 4
-7х = 2
x = -2/7
3x-2<0
3x<2
3(-2/7)<2-right
Answer in Detail !!! ✨
Answer:
3300cm²
Step-by-step explanation:
30cm+30cm=60cm 60cm is the lengh of the whole joint structure.We will put it in the equation as "a".
heigh stays the same(10cm) because the pieces are not stacked one on top of the other.They are joined on their sides.We will put it as "c".
Widht also stays the same.its 15 cm and we will put it as letter "b".
So
a=60cm
b=15cm
c=10cm
We need to calculate the surface area of the entire joint structure.
1.First thing to do is to calculate the top part which is:
a*b=15*60=900cm²
2.The bootom side is the same 900cm².
3.The front side is:
a*c=60*10=600cm²
4.The back side is the same as front so it is 600cm².
5.The left side is:
c*b=10*15=150cm²
6.The right side is the same as the left and it is 150cm²
Now we just add it up.
S(surface)=900*2+600*2+150*2=3300cm²
If you want the whole exercise in one equation:
S=2*(a*b)+2*(a*c)+2*(b*c)
Draw the graphs of the pair of linear equations : x + 2y = 5 and 2x - 3y = -4 Also find the points where the lines meet the x - axis .
Answer:
(1, 2)
Step-by-step explanation:
Given the equation of the lines x + 2y = 5 and 2x - 3y = -4
First we need to make x the subject of the formulas
For x+2y = 5
x = 5 - 2y ... 1
For 2x - 3y = -4
2x = -4+3y
x = (-4+3y)/2 ... 2
Equate 1 and 2
5 - 2y = (-4+3y)/2
2(5-2y) = -4+3y
10 - 4y = -4+3y
-4 -3y = -4-10
-7y = -14
y = 14/7
y = 2
Substitute y = 2 into 1
x = 5 = 2y
x = 5 - 2(2)
x = 5 - 4
x = 1
Hence the point where the lines meet will be at (1, 2)
