Graph the data set.
{(−1, 0.5), (0, 1), (1, 2), (3, 8), (5, 32)}

Which kind of model best describes the data?

A. Cubic
B. Exponential
C. Linear
D. None

Answer:

a^2 + b^2 = c^2

4+16 = c^2

20 = c^2

c = [tex]\sqrt{20}[/tex] = [tex]2\sqrt{5}[/tex]

Step-by-step explanation:

Answer:

y=2x-8

Step-by-step explanation:

Hi there!

We want to find an equation of the line parallel to y=2x-4 but has the same x intercept as 3x-4y=12

Parallel lines have the same slope, but different y intercepts

In y=2x-4, which is written in y=mx+b form, m is the slope and b is the y intercept

2 is in the place of where the slope would be, so the slope of that line is 2

That means the slope of the line parallel to it would also have a slope of 2

Here is the equation of the parallel line so far:

y=2x+b

We need to find b, the y intercept

Typically, we'll substitute a point into the equation to solve for b, but we don't have a point, yet

We're given that the new line has the same x intercept as 3x-4y=12

The x intercept is the point where the line passes through the x axis, and so the value of y at that point is 0

Let's substitute 0 for y in 3x-4y=12 and solve for x to find the x intercept

3x-4(0)=12

Multiply

3x=12

Divide both sides by 3

x=4

So the value of the x intercept is 4. As a point, it's (4,0)

So now substitute the values of the point (4,0) into y=2x+b to find b

0=2(4)+b

Multiply

0=8+b

Subtract 8 from both sides

-8=b

Substitute -8 as b into the equation

y=2x-8

Hope this helps!  

Answer:

1/2

Step-by-step explanation:

the dilation factor should be 1/2

Answer:

should be 1/2 as your answer

=========================================================

Explanation:

It's a bit strange why your teacher has the "26 degree" label pointing at a side length, rather than an actual angle. I'm assuming your teacher meant to aim it at angle C. In other words, I'm assuming they meant to say angle C = 26 degrees.

If that assumption is correct, then,

A+B+C = 180

38+B+26 = 180

B+64 = 180

B = 180-64

B = 116

Then we can use the law of sines like so:

a/sin(A) = b/sin(B)

a/sin(38) = 10/sin(116)

a = sin(38)*10/sin(116)

a = 6.84986152123146

a = 6.8

Side 'a' is approximately 6.8 inches long. So that's why the answer is choice A.

Answer:

The area of the circle is exactly π times the square of its radius. If you are given that the radius is within 0.1cm of 8.5cm, i.e. lies between 8.4 cm and 8.6 cm, its square will lie between p=8.4² = 70.56 and q=8.6² = 73.96 cm².

Answer:

The area of the circle is exactly π times the square of its radius. If you are given that the radius is within 0.1cm of 8.5cm, i.e. lies between 8.4 cm and 8.6 cm, its square will lie between p=8.4² = 70.56 and q=8.6² = 73.96 cm².

Step-by-step explanation:

thanks for question dear

Answer:

The answer to your question is 1, or answer choice A.

Step-by-step explanation:

x+ 2 /7 = 3 /7 x+ 6 /7

x+ 2 /7 − 3 /7 x= 3 /7 x+ 6 /7 − 3 /7 x

4 /7 x+ 2 /7 = 6 /7

4 /7 x+ 2 /7 − 2 /7 = 6 /7 − 2 /7

4 /7 x= 4 /7

( 7 /4)*( 4 /7 x)=( 7 /4 )*( 4 /7 )

x=1  

Answer:

[tex]y = 2x + 7[/tex]

Step-by-step explanation:

Use Point Slope Form since we are given the slope and coordinates. Why is the slope 2x?

In Depth: Parallel lines never touch so they are Lines that have same slope but different y intercept. An example is a square. A square has four parallel sides. The upper and lower sides will never touch because they are the same slope and they both have a finite distance vertically between them.

Back to the question, let use the Point Slope Form,

[tex]y - y_{1} = m(x - x_{1})[/tex]

Where y1 is the y coordinate of the given point, m is the slope and x is the x coordinates of the given points.

Substitute

[tex]y - ( - 1) = 2(x - ( - 4)[/tex]

[tex]y + 1 = 2(x + 4)[/tex]

Simplify

[tex]y + 1 = 2x + 8[/tex]

[tex]y = 2x + 7[/tex]

28

How?

We can see that 28 is the lowest common multiple also it is <30

Answer: 28.

Step-by-step explanation: 28 is divisible by 4: 28 / 4 = 7. 28 is divisible by 14: 28 / 14 = 2. And 28 is less than 30

Answer:

36 degrees

Step-by-step explanation:

10 corners/sides.

the sum of all exterior angles in a polygon is always 360 degrees.

so, one exterior angle here is 360/10 = 36 degrees

Answer:

A

For something to be a function every x value bust have at most 1 y value and in A 9 has 2 y values so it cant be a function

Answer:

(3+a)

Step-by-step explanation:

3a + a^2

-------------

a

Factor out an a in the numerator

a(3+a)

-------------

a

Cancel like terms

(3+a)

Step-by-step explanation:

[tex] \frac{3a + {a}^{2} }{a} \\ = \frac{3a}{a} + \frac{ {a}^{2} }{a} \\ = 3 + a \\ thank \: you[/tex]

Answer:

[tex]4\sqrt{5}[/tex]

Step-by-step explanation:

In order to solve this problem, we can use the pythagorean theorem, which is

a^2 + b^2 = c^2, where and b are the legs of a right triangle and c is the hypotenuse. Since we are given the leg lengths, we can substitute them in. So, where a is we can put in a 4 and where b is we can put in an 8:

a^2 + b^2 = c^2

(4)^2 + (8)^2 = c^2

Now, we can simplify and solve for c:

16 + 64 = c^2

80 = c^2

c = [tex]\sqrt{80}[/tex]

Our answer is not in simplified radical form because the number under is divisible by a perfect square, 16. We can divide the inside, 80,  by 16, and add a 4 on the outside, as it is the square root of 16:

c = [tex]4\sqrt{5}[/tex]

The length of the hypotenuse in the given right triangle, with legs measuring 4 and 8, is approximately 8.94.

To find the length of the hypotenuse in a right triangle, we can use the Pythagorean theorem. According to the theorem, in a right triangle, the square of the hypotenuse's length is equal to the sum of the squares of the lengths of the other two sides.

In this case, let's label the lengths of the legs as 'a' and 'b', with 'a' being 4 and 'b' being 8. The hypotenuse, which we need to find, can be represented as 'c'.

Applying the Pythagorean theorem, we have:

[tex]a^2 + b^2 = c^2[/tex]

Substituting the given values:

[tex]4^2 + 8^2 = c^2[/tex]

16 + 64 = [tex]c^2[/tex]

80 = [tex]c^2[/tex]

To find the length of the hypotenuse 'c', we need to take the square root of both sides:

√80 = √ [tex]c^2[/tex]

√80 = c

The square root of 80 is approximately 8.94.

Therefore, the length of the hypotenuse in the given right triangle, with legs measuring 4 and 8, is approximately 8.94.

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Answer:

B

Step-by-step explanation:

Pardons for Confederate leaders

Answer:

Shane=x

Abha=y

x+y>=2000

x-y=178 Which leads to x=178+y ..... #1

hence by substitution in the inequality

178+2y>=2000

2y>=2000-178

2y>=1822

y>=911 ......in #1

x>=178+911

x>=1089

Solutions x>=1089 & y>=911

Answer:

The expression is not factorable with rational numbers.

x² − 4x + 7

Answer:

C

Step-by-step explanation:

The sum of distances from any point on the ellipse to each foci equals a certain amount, no matter what point on the ellipse it starts from. The foci are on the major radius of the ellipse (the longer length of horizontal/vertical). The foci are of equal distance from the center, with one on each side.

If you wanted to find where the foci are using the major and minor radius, we can find that, representing the distance between the center and any foci as g,

g² = major radius² - minor radius². Then, the distance between the center and the foci is equal to g

Answer:

1.5

Step-by-step explanation:

y=2x - 3

0 = 2x - 3

-2x = - 3 /÷(-2)

x = 3 ÷ 2

x = 1.5 3/2

Answer:

64percents

Step-by-step explanation:

25-9=16 grams - weight of copper

(16/25)*100=64 percents

230.000 childrenㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

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Answer:

230 children

Step-by-step explanation:

Answer:

Answer is 0.002

Step-by-step explanation:

15÷7500 = 0.002

Answer:

ampota ma,pakyu

Step-by-step explanation:

what is the answer dapalon taka karun

Answer:

520 cars

Step-by-step explanation:

Let the car sold in March be x, x+5%*x=546. (105/100)*x=546. x=520

If there was an increase of 5% on the number of cars sold in March, the number of cars sold in March was approximately 520.

To calculate the number of cars sold in March, we'll use the information that the number of cars sold in April was an increase of 5% compared to March.

Let's assume the number of cars sold in March is represented by 'x'.

According to the given information, the number of cars sold in April was 546, which is equal to 100% + 5% of the number of cars sold in March.

We can set up the equation:

x + 0.05x = 546

Combining like terms, we get:

1.05x = 546

To solve for 'x', we divide both sides of the equation by 1.05:

x = 546 / 1.05

Using a calculator, we find:

x ≈ 520.00

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Answer:

total pages = 20

Step-by-step explanation:

60% of an unknown number is 12

Let the unknown number (total pages) be x.

60/100 of x = 12

60/100 * x = 12

3/5 x = 12

x = 12 * 5/3

x = 20

Answer:

x = ±i ,  x=1

Step-by-step explanation:

(x^2+1)(x-1)=0

Using the zero product property

x^2 +1 = 0   x-1= 0

x^2 = -1       x=1

Taking the square root of the equation on the left

sqrt(x^2) = sqrt(-1)

x = ±i   where  i is the imaginary number

We still have x=1 from the equation on the right

Answer:

12 hours

Step-by-step explanation:

For Ravi,

12 hours = 1 job

Given this, we can figure out how much Ravi does in 6 hours, and from that, we can figure out how much Raman can do in 6 hours. Finally, we can use that to figure out how many hours it would take for Raman to do the job.

12 hours = 1 job

First, to find how much Ravi does in 6 hours, we need to make the equation

6 hours = something

To do this, we know that 12/2 = 6, so we can divide both sides by 2 in the original equation to get

6 hours = 1/2 job.

Therefore, in 6 hours, Ravi does 1/2 of the job. As Raman and Ravi do the job in 6 hours, Raman must do the remaining work, or 1-1/2 = 1/2 of the job in 6 hours.

Therefore, for Raman,

6 hours = 1/2 job

We need to make the equation so that

1 job = something, as that something would be how many hours it would take for Raman to do the job. We know that 1/2 * 2 = 1, so we can multiply both sides by 2 to get

12 hours = 1 job for Raman.

Answer:

1/4

Step-by-step explanation:

2/5 divided by 8/5 is the same as 2/5 * 5/8. we cross out the same 5's to get 2/8. We simplify that to 1/4.

1/4 is our answer.

Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that [tex]\mu = 32, \sigma = 1.5[/tex]

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.645 = \frac{X - 32}{1.5}[/tex]

[tex]X - 32 = -1.645*1.5[/tex]

[tex]X = 29.5[/tex]

Heights of 29.5 and below could be a problem.

Answer:

Hello,

Step-by-step explanation:

[tex]\dfrac{f(x)}{3} =\dfrac{x^4+x^3+x^2+1}{(x-1)(x+2)} \\\\=\dfrac{(x^2+3)(x-1)(x+2)-3x+7}{(x-1)(x+2)} \\=x^2+3-\dfrac{3x-7}{(x-1)(x+2)} \\\\=x^2+3-\dfrac{3}{x-1} +\dfrac{1}{(x-1)(x-2)} \\\\\dfrac{f(x)}{3}-\dfrac{3x^2+9}{3} =-\dfrac{3}{x-1} +\dfrac{1}{(x-1)(x-2)} \\\\\\ \lim_{x \to +\infty} (\dfrac{f(x)}{3}-\dfrac{3x^2+9}{3} )\\\\=0+0=0\\\\\\P(x)=-x^2-3[/tex]

Answer:

[tex]g(x)=-3x^2-9[/tex]

Explanation:

[tex]3\frac{x^4+x^3+x^2+1}{x^2+x-2}[/tex]

+[tex]\frac{p(x)(x^2+x-2)}{x^2+x-2}[/tex]

We need p(x) need to be a degree 2 polynomial so the numerator of the second fraction is degree 4. Our goal is to cancel the terms of the first fraction's numerator that are of degree 2 or higher.

So let p(x)=ax^2+bx+c.

[tex]3\frac{x^4+x^3+x^2+1}{x^2+x-2}[/tex]

+[tex]\frac{p(x)(x^2+x-2)}{x^2+x-2}[/tex]

Plug in our p:

[tex]3\frac{x^4+x^3+x^2+1}{x^2+x-2}[/tex]

+[tex]\frac{(ax^2+bx+c)(x^2+x-2)}{x^2+x-2}[/tex]

Take a break to multiply the factors of our second fraction's numerator.

Multiply:

[tex](ax^2+bx+c)(x^2+x-2)[/tex]

=[tex]ax^4+ax^3-2ax^2[/tex]

+[tex]bx^3+bx^2-2bx[/tex]

+[tex]cx^2+cx-2c[/tex]

=[tex]ax^4+(a+b)x^3+(-2a+b+c)x^2+(-2b+c)-2c[/tex]

Let's go back to the problem:

[tex]3\frac{x^4+x^3+x^2+1}{x^2+x-2}[/tex]

+[tex]\frac{ax^4+(a+b)x^3+(-2a+b+c)x^2+(-2b+c)x-2c}{x^2+x-2}[/tex]

Let's distribute that 3:

[tex]\frac{3x^4+3x^3+2x^2+3}{x^2+x-2}[/tex]

+[tex]\frac{ax^4+(a+b)x^3+(-2a+b+c)x^2+(-2b+c)x-2c}{x^2+x-2}[/tex

So this forces [tex]a=-3[/tex].

Next we have [tex]a+b=-3[/tex]. Based on previous statement this forces [tex]b=0[/tex].

Next we have [tex]-2a+b+c=-3[/tex]. With [tex]b=0[/tex] and [tex]a=-3[/tex], this gives [tex]6+0+c=-3[/tex].

So [tex]c=-9[tex].

Next we have the x term which we don't care about zeroing out, but we have [tex]-2b+c[/tex] which equals [tex]-2(0)+-9=-9[/tex].

Lastly, [tex]-2c=-2(-9)=18[/tex].

This makes [tex]p(x)=-3x^2-9[/tex].

This implies [tex]g(x)\frac{(-3x^2-9)(x^2+x-2)}{x^2+x-2}[/tex] or simplified [tex]g(x)=-3x^2-9[/tex]