Given P(A) = 0.6 and P(B) = 0.8, do the following. If A and B are independent events, compute P(A and B)

Answer:

VW = 6

Step-by-step explanation:

To find x, set up the following equation:

(5x - 4) + (2x) = 5x

Solve out left side

7x - 4 = 5x

Subtract 5x from both sides

2x - 4 = 0

Add 4 to both sides

2x = 4

Divide both sides by 2

x = 2

Plug into 5x - 4

5(2) - 4

10 - 4

6

Answer:

6

Step-by-step explanation:

5x - 4 + 2x = 5x

7x - 4 = 5x

-4 = -2x

2 = x

5(2) - 4

10 - 4

6

indirect variation

Verification

[tex]\\ \rm\Rrightarrow s\propto \dfrac{1}{y}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{s_1}{t_2}=\dfrac{s_2}{t_1}[/tex]

[tex]\\ \rm\Rrightarrow s_1t_1=s_2t_2[/tex]

Answer:

The product of any rational number and any irrational number will always be an irrational number.

Step-by-step explanation:

Answer:

3031081 / 40678884

Step-by-step explanation:

To solve this, we can find the surface area of the moon and Earth, and then see how much the moon covers the Earth. The surface area of a sphere is equal to 4πr², so the radius of the Earth is

4πr² = 4 * π * 6378²

and the radius of the moon is

4πr² = 4 * π * 1741²

To figure out how much of the Earth's surface that the moon covers, we can implement a ratio of moons:Earth. This will give us an understanding of how many moons go inside one Earth. We thus have

(4 * π * 1741²) : ( 4 * π * 6378²) = (4 * π * 1741²) / ( 4 * π * 6378²)

cross out the 4 * π in the numerator and denominator

1741²/6378²

Next, we want to make the denominator 1, as that gives us 1 Earth. To do this, we can divide both the numerator and denominator by 6378². Because we are applying the same expression to both the numerator and denominator, this is essentially multiplying the fraction by 1, keeping it the same. We thus have

(1741²/6378²)/(6378²/6378²)

≈0.0745/1

≈ 0.0745

To put this in a fraction, we would have

(1741²/6378²)/1

= (1741²/6378²)

= 3031081 / 40678884

9514 1404 393

Answer:

  25 ft

Step-by-step explanation:

The volume is given by the formula ...

  V = LWD . . . . . the product of length, width, depth

Solving for L, we have ...

  L = V/(WD) = (1700 ft³)/((17 ft)(4 ft)) = 100/4 ft = 25 ft

The length of the pool is 25 ft.

Answer:

7-15= -8

Step-by-step explanation:

Answer:

10 meters

Step-by-step explanation:

Answer:

can you submit the coordinet plane?

Step-by-step explanation:

Answer:

6 ft

Step-by-step explanation:

Answer:3

Step-by-step explanation:

-3x+2=-7

subtract 2 from both sides

-3x+2-2-(-7-2

simplify the arithmetic

-3x=-7-2

simplify the arithmetic aging

-3x=-9

=3

Answer:

-29

Step-by-step explanation:

(-14) + (-15) =

-14 - 15 =

-29

[tex] {x}^{2} - 17x - 60 \\ (x + 3)(x - 20)[/tex]

First we put parentheses and in each bracket we put (X) and then we put the signs x² is positive and the 17X before it is a negative q is positive with negative —> negative, and negative before 17X and negative before the 60 —> positive. And then the number that does not have (x) where did it come from, for example 60 came from 20 x 3 or 30 x 2...etc. We can verify this by multiplying the parentheses together and the same number comes out .

Or it can be checked by multiplying the first bracket 3 with x from the second parenthesis comes out 3X and negative 20 from the second parenthesis with X from the first parenthesis and subtract 3X from –20xcomes out –17X .

I hope I helped you^_^

Sorry I'm not sure if I'm right just my thinking...

set the number to be x so that (5x+2)(3x-4)??

Answer:

OPTION A :16 FEET

PERIMETER =26 1/3=76/3yard=76/3×3=76 feet

LENGTH=22feet

Width=76/2-22

WIDTH=38-22=16 FEET

Answer:

[tex]\displaystyle x_1 = 2-\sqrt{3} \text{ and } y_1 = \frac{\sqrt{3}-1}{2}[/tex]

Or:

[tex]\displaystyle x _ 2 = 2 + \sqrt{3} \text{ and } y _ 2 = -\frac{1+\sqrt{3}}{2}[/tex]

Step-by-step explanation:

We are given the equation:

[tex]\displaystyle (x^2 + 2xy) + i(y-1) = (x^2 -2x + 2y) - i(x +y)[/tex]

And we want to find the values of x and y such that the equation is true.

First, distribute:

[tex]\displaystyle (x^2 + 2xy) + i(y-1) = (x^2 -2x + 2y) +i(-x -y)[/tex]

If two complex numbers are equivalent, their real and imaginary parts are equivalent. Hence:

[tex]\displaystyle x^2 + 2xy = x^2 - 2x +2y \text{ and } y - 1 = -x -y[/tex]

Simplify:

[tex]\displaystyle 2xy = -2x +2y \text{ and }x = 1 - 2y[/tex]

Substitute:

[tex]\displaystyle 2(1-2y)y = -2(1-2y) + 2y[/tex]

Solve for y:

[tex]\displaystyle \begin{aligned} 2(y - 2y^2) &= (-2 + 4y) + 2y \\ 2y - 4y^2 &= 6y -2\\ 4y^2 + 4y - 2& = 0 \\ 2y^2 + 2y - 1 &= 0 \\ \end{aligned}[/tex]

From the quadratic formula:

[tex]\displaystyle \begin{aligned} y &= \frac{-(2)\pm\sqrt{(2)^2 - 4(2)(-1)}}{2(2)} \\ \\ &= \frac{-2\pm\sqrt{12}}{4} \\ \\ &= \frac{-2\pm2\sqrt{3}}{4}\\ \\ &= \frac{-1\pm\sqrt{3}}{2} \end{aligned}[/tex]

Hence:

[tex]\displaystyle y_1 = \frac{-1+\sqrt{3}}{2} \text{ or } y_2 = \frac{-1-\sqrt{3}}{2}[/tex]

Then:

[tex]\displaystyle x _ 1 = 1 - 2\left(\frac{-1+\sqrt{3}}{2}\right) = 1 + (1 - \sqrt{3}) = 2 - \sqrt{3}[/tex]

And:

[tex]\displaystyle x _ 2 = 1 - 2\left(\frac{-1-\sqrt{3}}{2}\right) = 1 + (1 + \sqrt{3}) = 2 + \sqrt{3}[/tex]

In conclusion, the values of x and y are:

[tex]\displaystyle x_1 = 2-\sqrt{3} \text{ and } y_1 = \frac{\sqrt{3}-1}{2}[/tex]

Or:

[tex]\displaystyle x _ 2 = 2 + \sqrt{3} \text{ and } y _ 2 = -\frac{1+\sqrt{3}}{2}[/tex]

Answer:

10.8

Step-by-step explanation:

3 3/5 divided by 1/6

(3(3/5))/(1/6)

(9/5)/(1/6)

54/5

10(4/5)

10.8

My answer is in the picture

Answer:

2x + 2y - 4

Step-by-step explanation:

The opposite sides are congruent so perimeter (P) is

P = 2(x + 2) + 2(y - 4)

  = 2x + 4 + 2y - 8

  = 2x + 2y - 4

Answer:

19,86%

Step-by-step explanation:

[tex] \frac{28}{141} = 0.198582[/tex]

➡️ [tex]0.1986[/tex]

➡️ [tex]0.1986 \times \frac{100}{100} [/tex]

➡️ [tex] \frac{0.1986 \times 100}{100} [/tex]

➡️ [tex] \frac{19.86}{100} [/tex]

➡️ [tex] = 19.86\%[/tex] ✅

5 students offers all the two subjects.

Student that offers Physic only = 15 students

Student that offers chemistry only  = 13 students

Students that offers only one subject = 28 students

Total student in the class = 35

20 offer physics.

18 offer chemistry

2 offer neither physics nor chemistry.

Therefore,

x = student that offer both subject

35 = 20 + 18 - x + 2

35 - 2 - 20 - 18 = -x

-5 = -x

x = 5

Therefore, 5 students offers all the two subjects.

Student that offers Physic only = 20 - 5 = 15

Student that offers chemistry only = 18 - 5 = 13

Students that offers only one subject = 13 + 15 = 28

learn more on Venn diagram here: https://brainly.com/question/27808502

#SPJ1

[tex]6\cdot\square=9\\\\\square=9:6\\\\\square=\frac{9}{6}\rightarrow\square=\frac{3}{2} \ (\text{devide 9 and 6 by 3})[/tex]

Answer:

Step-by-step explanation:

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]

v=t^2-8t+15

[tex]\boxed{\sf {\displaystyle{\int}^b_a}x^ndx=\left[\dfrac{x^{n+1}}{n+1}\right]^b_a}[/tex]

[tex]\\ \sf\longmapsto s={\displaystyle{\int}}vdt[/tex]

[tex]\\ \sf\longmapsto s={\displaystyle{\int^4_2}}t^2-8t+15[/tex]

[tex]\\ \sf\longmapsto s=\left[\dfrac{t^3}{3}-8\dfrac{t^2}{2}+15t\right]^4_2[/tex]

[tex]\\ \sf\longmapsto s=\left[\dfrac{t^3}{3}-4t^2+15t\right]^4_2[/tex]

[tex]\\ \sf\longmapsto s=\left(\dfrac{4^3}{3}-4(4)^2+15(4)\right)-\left(\dfrac{2^3}{3}-4(2)^2+15(2)\right)[/tex]

[tex]\\ \sf\longmapsto s=\left(\dfrac{64}{3}-64+60\right)-\left(\dfrac{8}{3}-16+30\right)[/tex]

[tex]\\ \sf\longmapsto s=\left(\dfrac{64}{3}-4\right)-\left(\dfrac{8}{3}+14\right)[/tex]

[tex]\\ \sf\longmapsto s=\dfrac{64}{3}-4-\dfrac{8}{3}-14[/tex]

[tex]\\ \sf\longmapsto s=\dfrac{64}{3}-\dfrac{8}{3}-4-14[/tex]

[tex]\\ \sf\longmapsto s=\dfrac{46}{3}-18[/tex]

[tex]\\ \sf\longmapsto s=15.3-18[/tex]

[tex]\\ \sf\longmapsto s=|-2.7|[/tex]

[tex]\\ \sf\longmapsto s=2.7km[/tex]

Answer:

2/3 can be wrtten in three ways

Step-by-step explanation:

1: 6/9

2. 4/6

3.20/30

Answer:

2n+18

Step-by-step explanation:

2xn=2n

2x9=18

2n+18

Answer:

A) 3x+4

B) Twice of sum of a number and 9.

Answer:  [tex](x-9)^2 + (y-12)^2 = 225\\\\[/tex]

This is the same as writing (x-9)^2 + (x-12)^2 = 225

========================================================

Explanation:

Any circle equation fits the template of [tex](x-h)^2 + (y-k)^2 = r^2\\\\[/tex]

The center is (9,12) which tells us the values of h and k in that exact order.

h = 9

k = 12

To find the radius r, we need to find the distance from the center (9,12) to a point on the circle. The only point we know on the circle is the origin (0,0).

Apply the distance formula to find the distance from (9,12) to (0,0)

[tex]d = \sqrt{ (x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{ (9-0)^2+(12-0)^2}\\\\d = \sqrt{ (9)^2+(12)^2}\\\\d = \sqrt{ 81+144}\\\\d = \sqrt{ 225}\\\\d = 15\\\\[/tex]

The distance from (9,12) to (0,0) is 15 units. Therefore, r = 15

An alternative to finding this r value is to apply the pythagorean theorem. The distance formula is effectively a modified version of the pythagorean theorem.

---------------------

Since h = 9, k = 12 and r = 15, we can then say:

[tex](x-h)^2 + (y-k)^2 = r^2\\\\(x-9)^2 + (y-12)^2 = 15^2\\\\(x-9)^2 + (y-12)^2 = 225\\\\[/tex]

which is the equation of this circle.

Answer:

y = 68

A = 44

Step-by-step explanation:

No matter what may be true, that doesn't look like an a to me.

x = y = 68                x and y are opposite equal sides and are therefore =.

68 + 68 + A = 180  all triangles are 180 degrees.

136 + A = 180          Subtract 136 from both sides

A = 180 - 136

A = 44

Answer:

Step-by-step explanation:

d