given circle o, what are the values of x and y?

Answer:

Let's call the length of the field "l", and the width of the field "w".

If the area of the field is 72 square meters, then we have:

l x w = 72

And if the length is 6 meters longer than the width, we have:

l = w+6

So looking at the first equation (l x w = 72), we can substitute the l for a w+6.

And we obtain:

(w+6) x (w) = 72

Which simplifies to w^2 + 6w = 72.

This quadratic equation is pretty easy to solve, you just need to factor it.

w^2 + 6w - 72 = 0

(w-6)(w+12)

This leaves the roots of the  quadratic equation to be 6 and -12, but in this case, a width of -12 wouldn't make sense.

So, the width of the rectangular field is 6, and the length of the field is 12.

Let me know if this helps!

Answer:

we assume one side is x and other side must be x+6 and when we multiple it together we can find x²+6x =72

Step-by-step explanation:

one side is 6 and. other is 12 so the lenght= 12 the width=6

Answer:

what can i help u with

Step-by-step explanation:

I really can't help u with that sorry i am bad at math

Answer:

[tex] 3x + y = 2 [/tex]

Step-by-step explanation:

[tex] y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1}(x - x_1) [/tex]

[tex] y - 5 = \dfrac{-7 - 5}{3 - (-1)}(x - (-1)) [/tex]

[tex] y - 5 = \dfrac{-12}{4}(x + 1) [/tex]

[tex] y - 5 = -3(x + 1) [/tex]

[tex] y - 5 = -3x - 3 [/tex]

[tex] 3x + y = 2 [/tex]

Answer:

-2/3

Step-by-step explanation:

The slope is -2/3 because the slope formula, y2-y1/x2-x1

[tex]\huge\text{Hey there!}[/tex]

[tex]\boxed{\huge\boxed{\mathsf{Formula: m = \dfrac{y_2- y_1}{x_2- x_1}}}}[/tex]

[tex]\boxed{\huge\boxed{\mathsf{m = \dfrac{14 -10}{-18 - (-12)}}}}\\\\\\\huge\textsf{14 - 10 = \bf \boxed{\bf 4}}\\\\\\\huge\textsf{-18 - (-12)}\\\huge\textsf{= -18 + 12}\\\huge\textsf{= \bf -6}\\\\\boxed{\huge\boxed{\mathsf{m = \dfrac{4}{-6}}}}[/tex]

[tex]\boxed{\huge{\boxed{\mathsf{m = \dfrac{4\div2}{-6\div2}}}}}\\\\\huge\boxed{\mathsf{4\div2 = \bf 2}}\\\huge\boxed{\mathsf{-6\div2 = \bf -3}}\\\\\\\boxed{\boxed{\huge\boxed{\mathsf{\star m = \bf \dfrac{2}{-3}\star}}}}[/tex]

[tex]\boxed{\boxed{\huge \boxed{\mathsf{Answer: }\frak{\dfrac{2}{-3}}}}}\huge\checkmark[/tex]

[tex]\huge\boxed{\frak{Good\ luck\ on\ your\ assignment\ \& \ enjoy \your \ day!}}[/tex]

~[tex]\rm{Amphitrite1040:)}[/tex]

I assume you're supposed to find the limit as n approaches infinity, not x.

You have

[tex]\displaystyle \lim_{n\to\infty}\frac{4^n-5.3^n+1}{2.4^n+2} = \lim_{n\to\infty}\frac{\left(\dfrac4{5.3}\right)^n-\left(\dfrac{5.3}{5.3}\right)^n+\dfrac1{5.3^n}}{\left(\dfrac{2.4}{5.3}\right)^n+\dfrac2{5.3^n}} \\\\ = \lim_{n\to\infty}\frac{\left(\dfrac4{5.3}\right)^n-1+\dfrac1{5.3^n}}{\left(\dfrac{2.4}{5.3}\right)^n+\dfrac2{5.3^n}}[/tex]

For |x| < 1, we have lim |x|ⁿ = 0 as n goes to infinity. Then each exponential term converges to 0, which leaves us with -1/0. This means the limit is negative infinity.

On the other hand, perhaps you meant to write

[tex]\displaystyle \lim_{n\to\infty}\frac{4^n-5\times3^n+1}{2\times4^n+2}[/tex]

The same algebraic manipulation gives us

[tex]\displaystyle\lim_{n\to\infty}\frac{\left(\dfrac44\right)^n-5\left(\dfrac34\right)^n+\dfrac1{4^n}}{2\left(\dfrac44\right)^n+\dfrac2{4^n}} = \lim_{n\to\infty}\frac{1-5\left(\dfrac34\right)^n+\dfrac1{4^n}}{2+\dfrac2{4^n}}[/tex]

Again the exponential terms converge to 0, but this time we're left with the limit 1/2.

Answer:

360cm³

Step-by-step explanation:

Volume of a triangular prism = Base area * Height of prism

Height of prism = 15cm

Base area = 1/2 * 6 * 8

Base area = 24cm²

Volume of the prism = 15 * 24

Volume of the prism = 360cm³

​

Answer: x = 2 and y = -4

x + 2y = -6

x = -6-2y

Putting this in value of x in

6x + 2y = 4

6(-6-2y) + 2y = 4

-36-12y+2y = 4

-10y = 4+36

y = 40/(-10)

y = -4

Now putting this value of y in

x + 2y = -6

x + 2(-4) = -6

x -8 = -6

x = -6+8

x = 2

Therefore x = 2 and y = -4

If we put these values we can check this

x + 2y = -6

2 + 2(-4) = -6

2 -8 = -6

-6 = -6

please click thanks and mark brainliest if you like :)

a right angle can have at least 2

Xochitl needs to pay $8.50 to buy 3 pounds of cherries.

The expression for the cost to buy p pounds of cherries would be

$(4p - 3.50)

An equation is written in the form of variables and constants separated by the operation of multiplication and division,

An equation states that terms in different forms on both sides of the equality sign are equal.

Multiplication and division do not separate the terms of an equation.

Given, The price per pound of the cherries is $4 per pound and she has a coupon for $3.50 off the final amount.

Therefore, The cost of 3 pounds of cherries before the discount would be,

= $(3×4).

= $12.

And after the discount, it would be $(12 - 3.50).

= $8.50.

An expression for the cost to buy p pounds of cherries would be,

= $(4p - 3.50)

learn more about equations here :

https://brainly.com/question/29657992

#SPJ2

Answer:

x=- 31/3

Step-by-step explanation:

distribute 5(2x+3)-4x=-4+3x(x-4)

10x+15-4x=-4+3(x-4)

combine like terms

distribute

Answer: Choice A (both are smiley faces)

This is because the reflection doesn't flip the faces upside down or anything (instead it does a left-right swap in a way). This is why both faces are smiley faces.

The derivative of a function f(x) is defined as

[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h[/tex]

For f(x) = 3x ² + 4, we have

[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{(3(x+h)^2+4) - (3x^2+4)}h[/tex]

[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{(3(x^2+2xh+h^2) - 3x^2}h[/tex]

[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{6xh+3h^2}h[/tex]

[tex]f'(x)=\displaystyle\lim_{h\to0}(6x+3h) = \boxed{6x}[/tex]

Answer:

37

Step-by-step explanation:

360 -(110+110+66) = 74

74/2 = 37

Answer:

Not enough infomation, you need to provide #12

Step-by-step explanation:

5 by 3

3rd one

there we have to find hypotenuse.

Answer:

+- 5/3

Step-by-step explanation:

When we construct a right triangle with legs with length 3 and 4. The hypoteneuse must 5. Since tan(x) = opp/adj = 4/3 and sec(x) = hyp/adj,

We get the answer to be 5/3. Now there is a +- there because if we use the unit circle, if we take the point (-3, -4), we get tan(x) = (-4/-3) = 4/3. However, the hypoteneuse for sec(x) is always positive so sec(x) = 5/-3 = -5/3.

That is why there are two solutions, one with the terminal arm in Q3 and one in Q1. But that's the explanation using the unit circle.

Answer:

Step-by-step explanation:

If the account grows steadily, this is a linear representation, where the constant, steady growth translates to the slope of a line.

Area of a square is side^2

Diagonal of a square is sqrt(2) x side

Using this rewrite the area formula as :

1/2 x diagonal^2

Area = 1/2 x 40^2 = 800

Area = 800 m^2

Answer = b) 800m^2

Answer:

A) 3

B)60

C)4

Step-by-step explanation:

y = kx

36 = 12k

A)k=3

~~~~~~~~~~

b) 60

12*5

c) 4  

12/3

Answer:

5.2561

step by step explanation:

using BODMAS, multiplication comes before addition.

Therefore,

[tex] \sqrt{1.13 + (2.84 \times 9.33)} [/tex]

[tex] \sqrt{1.13 + 26.4971} [/tex]

[tex] \sqrt{27.6272} [/tex]

Therefore the answer is

5.2561

Answer:

cos^2(θ)

Step-by-step explanation:

Answer:

V=l×w×h

so the answer is 66km

11×2×3=66

Answer:

a + b = 5.30

a + b = 7

No

Step-by-step explanation:

Expressing the information as system of linear equation :

Let apples = a, oranges = b

If $5.30 is charged for one apple and one orange, then we have ;

a + b = 5.30 - - - (1)

If $14 is charged for 2 apples and 2 oranges, then we have ;

2a + 2b = 14 - - - - (2)

a + b = 7

Since both equations gives varying combined cost for equal amount of the fruit, then a unique cost cannot be obtained for each fruit from the systems of equation using simultaneous equation process.

From (1)

a = 5.30 - b

Put a = 5.30 - b in (2)

2(5.30 - b) + 2b = 14

10.6 - 2b + 2b = 14

10.6 = 14 - - - - - (variables cancels out).

Answer:No the System has no solution

Step-by-step explanation:

Answer:

Question 3: 220 centimeters

Question 4: 31.4 millimeters

Step-by-step explanation:

Question 3:

Formula for circumference: 2πr

2πr

Exchange π for 22/7

2 · (22/7) · r

Exchange r (radius) for 35

2 · (22/7) · 35

Simplify:

2 · (22/7) · 35

44/7 · 35

220; 220 centimeters

Question 4:

Formula for circumference: 2πr

2πr

Exchange π for 3.14

2 · 3.14 · r

Exchange r (radius) for 5

2 · 3.14 · 5

Simplify:

2 · 3.14 · 5

6.28 · 5

31.4; 31.4 millimeters

Answer:

Step-by-step explanation:

Concept:

Here, we need to know the idea of circumference.

The circumference is the perimeter of a circle. The perimeter is the curve length around any closed figure.

Circumference = 2πr

Solve:

Question # 1

r = 35 cm

π = 22/7

Circumference = 2πr

Circumference = 2 (22/7) (35)

Circumference = 2 (110)

Circumference = 220 cm

Question # 2

r = 5 mm

π = 3.14

Circumference = 2πr

Circumference = 2 (3.14) (5)

Circumference = 10 (3.14)

Circumference = 31.4 mm

Hope this helps!! :)

Please let me know if you have any questions

Answer:

line of symmetry is : x=2

Step-by-step explanation:

Answer:

Thus, the required line of symmetry is x = 2.

Step-by-step explanation:

Answer:

[tex] 7 \: {ft}^{2} [/tex]

Step-by-step explanation:

Area of the trapezoidal table

[tex] =\frac{1}{\cancel 2}(4 + 3)\times \cancel 2[/tex]

[tex] = 7 \: {ft}^{2} [/tex]

Answer:

7 ft squared

Step-by-step explanation:

Area of the trapezoidal table

Answer:

x = 9

Step-by-step explanation:

When doing these types of problems, the main goal is to get the variable by itself. Its kind of hard to explain with words so I will just use numbers.

15x + 14 = 149

(Subtract 14 on both sides. Remember, when you do something (Like subtracting, adding, etc.) on one side you have to do it to the other.)

15x + 14 = 149

       -14 =  -14

---------------------------

15x = 135

(Divide 15 on both sides. Since we need to use inverse operation to cancel the 15 out, we would divide 15 on both sides.)

15x/15 = 135/15

x = 9

Hope this helps :)

Answer:

Step-by-step explanation:

[tex]\sf 15x + 14 = 149[/tex]

[tex]\sf 15x+14-14=149-14[/tex]

[tex]\sf 15x=135[/tex]

[tex]\sf \cfrac{15x}{15}=\cfrac{135}{15}[/tex]

[tex]\sf x=9[/tex]

Answer:

Step-by-step explanation:

6. Yes: these two angles are opposite 2 equal line.

7. No: We don't know that AC bisects <JAD

8. No: We don't know that JCA or DCA are right angles.

9. Yes. Both angles have AC in common. JD is a straight line which has 180 degrees. AC intersects a JD and creates 2 angles. We know their total but not their equality.

10. Yes. They are given as equal.

Not everything you see is true just because it looks that way.

Answer:

Step-by-step explanation:

Find the slope of the line

(x₁ , y₁) = (6 , 8)   & (x₂ , y₂) = (0 , 5)

[tex]Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{5-8}{0-6}\\\\=\frac{-3}{-6}\\\\=\frac{1}{2}[/tex]

m = 1/2  ;(x₁ , y₁) = (6 , 8)

y - y₁ = m(x - x₁)

[tex]y - 8 = \frac{1}{2}(x - 6)\\\\y - 8 =\frac{1}{2}x -\frac{1}{2}*6\\\\y - 8 =\frac{1}{2}x- 3\\\\y = \frac{1}{2}x - 3 + 8\\\\y = \frac{1}{2}x + 5[/tex]