given a∥b and c∥d, m<4=35. find m<1, m<2, and m<3
its the rsm problem lesson 6 homework geometry

Answer:

There can be several such functions; however, the basic condition that needs to be met for a function to be positive for the interval [–3, –2] is that it should be multiplied by (-1) Hence, one such function that is positive for the entire interval is f(x) = -x

Step-by-step explanation:

9514 1404 393

Answer:

  an infinite number

Step-by-step explanation:

Between any pair of numbers, there are ...

  an infinite number of rational numbers, and

  an infinite number of irrational numbers

Step-by-step explanation:

[tex] \frac{2}{4} + 5 \times 36 + 2 \frac{6}{3} [/tex]

[tex] = \frac{1}{2} + 180 + 2 \times \frac{2}{1} [/tex]

[tex] = \frac{1}{2} + 180 + 4[/tex]

[tex] = \frac{1 + 360 + 8}{2} [/tex]

[tex] = \frac{369}{2} [/tex]

[tex] = 184 \frac{1}{2} \: or \: 184.5(ans)[/tex]

Answer:

39/250

Step-by-step explanation:

15 3/5 = 78/5 and percent means per 100, so

(78/5)/100 = (78/5)(1/100)

=78/500 = 39/250

Answer:

Step-by-step explanation:

let the line between 2 tria be y

sin 60/8√2 = sin 90/y

y=13.06

sin 45/13.06 = sin 90/x

x=18.46

Answer:

First, find the hypotenuse of the right triangle with the 60° & 30°.

[tex]sin(60) = \frac{8\sqrt{2}}{h} \\\\sin(60)h=8\sqrt{2}\\\\\frac{\sqrt{3}}{2} h=8\sqrt{2}\\\\h=\frac{8\sqrt{2}}{\frac{\sqrt{3}}{2}}=8\sqrt{2}*\frac{2}{\sqrt{3}} =\frac{16\sqrt{2} }{\sqrt{3}} =\frac{16\sqrt{2}(\sqrt{3}) }{\sqrt{3}(\sqrt{3})} =\frac{16\sqrt{6} }{3}[/tex]

Use that side length to find x.

[tex]sin(45)=\frac{\frac{16\sqrt{6}}{3}}{x}\\\\sin(45)x=\frac{16\sqrt{6}}{3} \\\\\frac{\sqrt{2}}{2}x=\frac{16\sqrt{6}}{3} \\\\x=\frac{\frac{16\sqrt{6}}{3}}{\frac{\sqrt{2}}{2}}=\frac{16\sqrt{6}}{3}*\frac{2}{\sqrt{2}}=\frac{16\sqrt{2}\sqrt{3}(2)}{3\sqrt{2} }=\frac{32\sqrt{3} }{3}[/tex]

Answer:

h²=p²+b²

(7√2)²=x²+x²

(49×2)=2x²

2x²=49ײ

x²=49×2/2

x²=49

x=√49=7

x=7

OAmalOHopeO

Step-by-step explanation:

[tex]{ \bf{( \frac{ - 10 {a}^{3} {b}^{5} \times 6 {a}^{6} {b}^{2} }{ {12a}^{9} {b}^{5} } ) {}^{3} }} \\ \\ = { \sf{( \frac{ - 60 {a}^{9} {b}^{7} }{12 {a}^{9} {b}^{5} } ) {}^{3} }} \\ \\ = { \sf{(5 {b}^{2}) {}^{3} }} \\ = { \sf{125 {b}^{5} }}[/tex]

Answer:

31) 4d + 28            33) 10 + 5

Step-by-step explanation:

31) 4 ( d + 7) = 4 x 7 = 28 = 4d + 28

33) 5 ( 2m + 1 ) = 5. 2m + 5 . 1: 10m + 5

Answer:

Step-by-step explanation:

Answer:

By the Sum Rule, the derivative of 1−sin(x) 1 - sin ( x ) with respect to x x is ddx[1]+ddx[−sin(x)] d d x [ 1 ] + d d x [ - sin ( x ) ] .

The distance between each of the students' houses are:

Aakash & Bao Ying live 9 blocks away from each other

Aakash & Chris live 3 blocks away from each other

Aakash & Donna live 66 blocks away from each other

Bao Ying & Chris live 6 blocks away from each other

Bao Ying & Donna live 57 blocks away from each other

Chris & Donna live 63 blocks away from each other

To solve this question, we represent each with the first letter of their names.

So, we have:

[tex]A= 5\ west[/tex] --- Aakash

[tex]B= 4\ east[/tex] ---- Bao Ying

[tex]C = 2\ west[/tex] --- Chris

[tex]D = 61\ east[/tex] ---- Donna

I've added the picture and the number line that represent the scenario as an attachment.

To calculate how far each lives from each other's, we start by representing west as negative and east as positive.

So, the representations become:

[tex]A = -5[/tex]

[tex]B = 4[/tex]

[tex]C = -2[/tex]

[tex]D = 61[/tex]

The absolute difference of each represents how far they live from one another.

Aakash & Bao Ying         Aakash & Chris                 Aakash & Donna

[tex]AB = |-5 -4| =9[/tex]          [tex]AC = |-5 --2| =3[/tex]         [tex]AD = |-5 -61| =66[/tex]

Bao Ying & Chris                 Bao Ying & Donna

[tex]BC = |4 --2| =6[/tex]                [tex]BD = |4 -61| =57[/tex]

Chris & Donna

[tex]CD = |-2 -61| =63[/tex]

This means that

Aakash & Bao Ying live 9 blocks away from each other

Aakash & Chris live 3 blocks away from each other

Aakash & Donna live 66 blocks away from each other

Bao Ying & Chris live 6 blocks away from each other

Bao Ying & Donna live 57 blocks away from each other

Chris & Donna live 63 blocks away from each other

To carry out the above computations from the number line, we simply count the numbers from one to the other.

For instance:

There are 3 numbers from Akash to Chris.

This means that: Aakash & Chris live 3 blocks away from each other

Learn more about number line at:

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Answer:

y =6

Step-by-step explanation:

We can write a ratio to solve

3           y

----- = ----------

4            8

Using cross products

3*8 = 4y

24 = 4y

Divide by 4

24/4 = 4y/4

6 = y

Answer:

3.2 hours

Step-by-step explanation:

12 workers * 4 hours = 48 worker hours

15 workers  * x hours = 48 worker hours

48 /15 =3.2 hours

Answer:

3 hours and 12 minutes.

Step-by-step explanation:

12 Workers complete a job in 4 hours

1 worker complete a job 12 × 4 = 48

15 workers complete a job = 48/15 = 3³/¹⁵ = 3¹/⁵

= 3 hours + 1/5 × 60  minutes = 3 hours 12 minutes.

Answer:

[tex]c - 2 = 25 + 10 \sqrt c + c[/tex]

Step-by-step explanation:

Given

[tex]\sqrt{c-2} - \sqrt c = 5[/tex]

Required

Isolate radical, then square both sides

We have:

[tex]\sqrt{c-2} - \sqrt c = 5[/tex]

Isolate radical

[tex]\sqrt{c - 2} = 5 + \sqrt c[/tex]

Square both sides

[tex](\sqrt{c - 2})^2 = (5 + \sqrt c)^2[/tex]

[tex]c - 2 = 25 + 2 * 5 * \sqrt c + c[/tex]

[tex]c - 2 = 25 + 10 \sqrt c + c[/tex]

After completing the square the quadratic equation [tex]3x^{2} -12x-15=0[/tex] is equivalent to [tex](x-2)^2=3^2[/tex].

"It is a polynomial equation with degree two."

"It is a method that is used for converting a quadratic expression of the form [tex]ax^2 + bx + c[/tex] to [tex]a(x - h)^2 + k[/tex] "

For given example,

We have been given a quadratic equation.

[tex]3x^{2} -12x-15=0[/tex]

First we divide above quadratic equation by 3,

[tex]x^{2} -4x-5=0\\\\x^2-4x=5[/tex]                             ................(i)

Now for completing the square first find [tex](\frac{-b}{2a} )[/tex]

[tex]\frac{-b}{2a}\\=\frac{-(-4)}{(2)(1)}\\\\ =\frac{4}{2}\\\\ =2[/tex]

Add [tex](\frac{-b}{2a} )^2[/tex] on both the sides of equation (i),

[tex]x^{2} -4x+4=5+4\\\\(x-2)^2=9\\\\(x-2)^2=3^2[/tex]

Therefore, after completing the square the quadratic equation [tex]3x^{2} -12x-15=0[/tex] is equivalent to [tex](x-2)^2=3^2[/tex].

Learn more about completing the square here:

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Answer:

The answer is 1,000

SInce the beginning number is 3 and there are ten possible numbers to put in the remaining three slots, there are exactly 1,000 possible combinations for a 3-digit code. The answer is 1,000. There are 3 rows of 10 digits. The number of combinations 10 to the thid power which is 1000 (10 * 10 * 10)

Answer:

x=6 square root 3 y=9

Step-by-step explanation:

x= 3 square root 3 * 2

y=3 square root 3 times square root 3

Answer:

how did not orderstan that

Answer:

z -2 = 10

Step-by-step explanation:

11z-9-10z+7 = 10

Combine like terms on the left side

11z -10z     -9+7  =10

z -2 = 10

Answer: z=12

Step-by-step explanation:

[tex]11z-9-10z+7=10\\z-9+7=10\\z-2=10\\z=12[/tex]

9514 1404 393

Answer:

  A. 281,634

Step-by-step explanation:

You can identify the number after the first two "rules".

Choices A and C have 3 in the tens place.

Choice A has 6 in the hundreds place.

9514 1404 393

Answer:

  38.1% decrease

Step-by-step explanation:

A percentage change is found from ...

  % change = (change)/(original amount) × 100%

  = (new value - original amount)/(original amount) × 100%

  = (13 -21)/21 × 100% = -8/21 × 100% ≈ -38.1%

Frazer's speed decreased by 38.1% during the second part.

_____

Additional comment

A negative % change represents a decrease; a positive % change represents an increase.

Answer:

jo pahle wale X hai na na X + x plus 1 unhen Yad Karke answer 1 aaega FIR X + 2 =_= + 3 X + 3 yah answer Aaya 1 or 2 X + ka ok

Step-by-step explanation:

FIR hai x+ x and ++ 2021 x

2021x

FIR + Kannan donon ko x

ans

x - 3 X

x - 4042

yah answer aayega ine donon ka the solve this question ok friend

Answer:

You have to follow PEMDAS or parenthesis, exponents, multiplication, division, addition, and subtraction. It's an order to solve equations. I listed the steps and the answers for you below :) I have throughly checked them so they should be correct! yw :D

Step-by-step explanation:

1. 5x + 4x - 6x = 24

9x - 6x = 24

3x = 24

24/3 = 8

x = 8

2. 8y + 5 - 4y + 1 = 46

8y - 4y = 4y

5 + 1 = 6

4y + 6 = 46

4y = 46 - 6

4y = 40

40/4 = 10

y = 10

3. 33 = 5 ( x + 8 ) + 3

33 =  5x + 40 + 3 (because we distributed)

33 = 5x + 43

5x + 43 = 33 (just rewriting it to make it easier)

5x = 33 - 43

5x = -10

-10/5 = -2

so x = - 2

4. 2m + 3 ( m - 8 ) = 1

2m + 3m - 24 = 1

we got 3m - 24 because we distributed the 3

5m - 24 = 1

5m = 25

25/5 = 5

m = 5

5. p + p - 2p + 4p = - 48

2p - 2p + 4p = - 48

4p = - 48

- 48 / 4 = - 12

p = - 12

6. 2 ( y + 5 ) + 3y = 25

2y + 10 + 3y = 25

5y + 10 = 25

5y = 25 - 10

5y = 15

15/5 = 3

y = 3

7. 1/4 h + 3/4 h + 1/2 h + 2 = 5

1/4 h + 3/4 h + 1/2 = 3/2 h

3/2 h + 2 = 5

3/2 h = 5 - 2

3/2 h = 3

h = 2

8. 60 = 4 ( k + 3 ) + 2 ( k - 3 )

60 = 4k + 12 + 2k - 6

4k + 12 + 2k - 6 = 60

6k + 6 = 60

6k = 60 - 6

6k = 54

k = 9

9. - 2 ( d + 1.4 ) - 1.8 = 20.6

-2d + - 2.8 - 1.8 = 20.6

-2d - 2.8 = 22.4

-2d = 25.2

d = - 12.6

10. 8 - 2 ( w + 4 ) = 10

8 + - 2 w + - 8 = 10

-2w + 9 + - 8 = 10

-2w = 10

10 / -2 = -5

w = -5

Answer:

Step-by-step explanation:

1 are = 100 m²

Assuming the ten squares are congruent, the area of each square is 160/10 = 16 are

16 are × 100 m²/are = 1600 m²

each side is √1600 = 40 m

The length of side of plot is 40 meters.

The total space occupied by a flat (2-D) surface or shape of an object is known as area.

Draw a square on a piece of paper with a pencil. It has two dimensions. The term "area" refers to the area that the shape occupies on the paper.

Now picture your square as being comprised of smaller unit squares. The number of unit squares required to cover a 2-D shape's total surface area is used to calculate its area.

Given the area of 10 square plot is 160 are,

here 1 are = 100 m²

area of 10 square plot = 160 x 100 = 16,000 m²

area of 1 square plot = 16000/10 = 1600 m²

area of square is "a²"

where a is side of square

area = a² = 1600 m²

a = √1600

a = 40 m

Hence the length of side of each plot is 40 meters.

Learn more about area;

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Step-by-step explanation:

sorrry .......................

Answer:

they are asking which claims are true vs false

Step-by-step explanation:

I totally get not wanting to bother our teachers again,... (that is why we're here)

m (AB = 20

m<ABD = 140

m (AD = 60

I think they want to know which ones (based on the "graph") are true,...