given a right-angled triangle with area 30 square centimeters and one of the legs of the right-angled triangle has 5cm, of the sum of the altitudes of the triangle can be expressed as a/b where gcd(a,b)=1. find a+b.geometry

Answers

Answer 1

Answer:

See explanation

Step-by-step explanation:

If A = 30 = 1/2ab = 1/2(5)(b)

60 = 5b

b = 12

a/b = 5/12

a + b = 5 + 12 = 17

Answer 2

Answer:

See explanation

Step-by-step explanation:

If A = 30 = 1/2ab = 1/2(5)(b)

60 = 5b

b = 12

a/b = 5/12

a + b = 5 + 12 = 17


Related Questions

Water flows from a bathroom tap at a rate of 2 gallons every 6 seconds. At this rate, how many minutes will it take to fill an 80-gallon tub?

Answers

Answer:

240 minutes

Step-by-step explanation:

i divide 80 divided by 2 then multiply the answer which is 40 by 6 and get 240

what is the sum of the interior angles of a regular hexagon ​

Answers

Answer:

see below

Step-by-step explanation:

The sum of the interior angles of any polygon can be found with the formula 180(n - 2) where n = number of sides. In this case, n = 6 so the answer is 180(6 - 2) = 180 * 4 = 720°.

Answer:

The sum of the interior angles of a regular hexagon is 720°

Step-by-step explanation:

As we know that the sum of interior angle is 180(n-2). So the number of sides of hexagon is 6. Now, 180(6-2)=180*4=720°

a farmer has 40 4/5 of beans 3/4 of the beans are pinto beans how many pounds of pinto bean are there

Answers

Answer: Amount of pinto beaks [tex]=30\dfrac{3}{5}\text{ pounds}[/tex]

Step-by-step explanation:

Given: Amount of beans a farmer has = [tex]40\dfrac{4}{5}\text{ pounds}=\dfrac{40\times5+4}{5}\text{ pounds}[/tex]

[tex]=\dfrac{204}{5}\text{ pounds}[/tex]

Also, [tex]\dfrac{3}{4}[/tex] of the beans are pinto beans .

Amount of pinto beaks = [tex]\dfrac 34\times[/tex] (Amount of beans a farmer has)

= [tex]\dfrac34\times\dfrac{204}{5}=\dfrac{153}{5}\text{ pounds}[/tex]

[tex]=30\dfrac{3}{5}\text{ pounds}[/tex]

Amount of pinto beaks [tex]=30\dfrac{3}{5}\text{ pounds}[/tex]

have two one-quart jars; the first is filled with water, and the second is empty. I pour half of the water in the first jar into the second, then a third of the water in the second jar into the first, then a fourth of the water in the first jar into the second, then a fifth of the water in the second jar into the first, and so on. How much water in quarts is in the first jar after the $10^{\textrm{th}}$ pour? Express your answer as a common fraction.

Answers

Answer:

water in quarts is in the first jar after 10th pour = 12/11

Step-by-step explanation:

Let X represent first jar and Y represents second jar.

have two one-quart jars; the first is filled with water, and the second is empty

Lets give the initial value of 2 to the first jar which is filled with water. Lets say there are two liters of water in first jar.

Lets give the initial value of 0 to the second as it is empty.

So before any pour, the values are:

X: 2

Y: 0

pour half of the water in the first jar into the second

After first pour the value of jar X becomes:

Previously it was 2.

Now half of water is taken i.e. half of 2

2 - 1 = 1

So X = 1

The value of jar Y becomes:

The half from jar X is added to second jar Y which was 0:

After first pour the value of jar Y becomes:

0 + 1 = 1

Y = 1

a third of the water in the second jar into the first

After second pour the value of jar X becomes:

Previously it was 1.

Now third of the water in second jar Y is added to jar X

1 + 1/3

=  (3 + 1)/3

= 4/3

X = 4/3

After second pour the value of jar Y becomes:

Previously it was 1.

Now third of the water in Y jar is taken and added to jar X so,

1 - 1/3

=  (3 - 1)/3

= 2/3

Y = 2/3

a fourth of the water in the first jar into the second

After third pour the value of jar X becomes:

Previously it was 4/3.

Now fourth of the water in the first jar X is taken and is added to jar Y

= 3/4 * (4/3)

= 1

X = 1

After third pour the value of jar Y becomes:

Previously it was 2/3

Now fourth of the water in the second jar X is added to jar Y

= 2/3 + 1/4*(4/3)

= 2/3 + 4/12

= 1

Y = 1

a fifth of the water in the second jar into the first

After fourth pour the value of jar X becomes:

Previously it was 1

Now fifth of the water in second jar Y is added to jar X

= 1 + 1/5*(1)

= 1 + 1/5

=  (5+1) / 5

= 6/5

X = 6/5

After fourth pour the value of jar Y becomes:

Previously it was 1.

Now fifth of the water in Y jar is taken and added to jar X so,

= 1 - 1/5

= (5 - 1)  / 5

= 4/5

Y = 4/5

a sixth of the water in the first jar into the second

After fifth pour the value of jar X becomes:

Previously it was 6/5

Now sixth of the water in the first jar X is taken and is added to jar Y

5/6 * (6/5)

= 1

X = 1

After fifth pour the value of jar Y becomes:

Previously it was 4/5

Now sixth of the water in the first jar X is taken and is added to jar Y

= 4/5 + 1/6 (6/5)

= 4/5 + 1/5

= (4+1) /5

= 5/5

= 1

Y = 1

a seventh of the water in the second jar into the first

After sixth pour the value of jar X becomes:

Previously it was 1

Now seventh of the water in second jar Y is added to jar X

= 1 + 1/7*(1)

= 1 + 1/7

=  (7+1) / 7

= 8/7

X = 8/7

After sixth pour the value of jar Y becomes:

Previously it was 1.

Now seventh of the water in Y jar is taken and added to jar X so,

= 1 - 1/7

=  (7-1) / 7

= 6/7

Y = 6/7

a eighth of the water in the first jar into the second

After seventh pour the value of jar X becomes:

Previously it was 8/7

Now eighth of the water in the first jar X is taken and is added to jar Y

7/8* (8/7)

= 1

X = 1

After seventh pour the value of jar Y becomes:

Previously it was 6/7

Now eighth of the water in the first jar X is taken and is added to jar Y

= 6/7 + 1/8 (8/7)

= 6/7 + 1/7

= 7/7

= 1

Y = 1

a ninth of the water in the second jar into the first

After eighth pour the value of jar X becomes:

Previously it was 1

Now ninth of the water in second jar Y is added to jar X

= 1 + 1/9*(1)

= 1 + 1/9

=  (9+1) / 9

= 10/9

X = 10/9

After eighth pour the value of jar Y becomes:

Previously it was 1.

Now ninth of the water in Y jar is taken and added to jar X so,

= 1 - 1/9

=  (9-1) / 9

= 8/9

Y = 8/9

a tenth of the water in the first jar into the second

After ninth pour the value of jar X becomes:

Previously it was 10/9

Now tenth of the water in the first jar X is taken and is added to jar Y

9/10* (10/9)

= 1

X = 1

After ninth pour the value of jar Y becomes:

Previously it was 8/9

Now tenth of the water in the first jar X is taken and is added to jar Y

= 8/9 + 1/10 (10/9)

= 8/9 + 1/9

= 9/9

= 1

Y = 1

a eleventh of the water in the second jar into the first

After tenth pour the value of jar X becomes:

Previously it was 1

Now eleventh of the water in second jar Y is added to jar X

= 1 + 1/11*(1)

= 1 + 1/11

= (11 + 1) / 11

= 12/11

X = 12/11

After tenth pour the value of jar Y becomes:

Previously it was 1.

Now eleventh of the water in Y jar is taken and added to jar X so,

= 1 - 1/11

=  (11-1) / 11

= 10/11

Y = 10/11

Answer:

6/11

Step-by-step explanation:

1/2 + (1/2)(2/11) = 6/11

sus

Divide a 7-inch line into three parts so that each part is 1 inch longer than one before it.

Answers

Answer:

Hey there!

We can write an equation:

x+x+1+x+2=7

3x+3=7

3x+4

x=4/3

The lines are 4/3, 7/3, and 10/3.

Let me know if this helps :)

The pepper plant has 2/3 as many fruits on it as the tomato plant has. The tomato plant has 9 fruits on it. How many fruits does the pepper plant have on it?

Answers

Answer:

The pepper plant has 15 fruits on it.

Step-by-step explanation:

Let the tomato plant have x plants. Let the pepper plant have y plants. Since the pepper plant has 2/3 more fruits on it than the tomato plant, we have that y - x = 2x/3

collecting like terms,

y = 2x/3 + x

The above is the number of plants the pepper plant has.

y = 2x/3 + x

y = (2x + 3x)/3

y = 5x/3

Since x = number of fruits on tomato plant = 9, then

y = 5x/3

y = 5(9)/3

y = 5 × 3

y = 15

Since y = number of fruits on pepper plant = 15

So, the pepper plant has 15 fruits on it.

A family club keeps a small amount of money on hand for members to borrow for short periods of time. The simple interest charged is 7.5%. Stephen borrowed $5,000 for 3 months. How much, to the nearest dollar, was he required to pay back at the end of 3 months?

Answers

Answer:

$6125

Step-by-step explanation:

5000 x 3 x .075 = 1,125

5000 + 1125 = 6125

PLS HELP I WILL GIVE BRAINLIST AND A THANK YOU!!!!!!!! Pls help me :)

Answers

Answer:

67°

Step-by-step explanation:

CGE + AGC + AGG = 180 (angles on a straight line)

23°+90°+x=180°

x=67°

4.
Aliyah, Brenda and Candy share a sum of money in the ratio of 3:5:6. After
Candy gives $100 to Aliyah and $50 to Brenda, the ratio becomes 2 : 3:3.
(a) Suppose Aliyah has $3x at the start, express Candy's initial sum of money in
terms of x.
(b) Find the value of x.
(c) Hence, how much money does Brenda have in the end?

Answers

Answer:

(a) Candy's initial sum as a terms of x is $6x

(b) x = $60

(c) $350

Step-by-step explanation:

The given parameters are;

The ratio in which Aliyah, Brenda and Candy share the sum of money = 3:5:6

The amount Candy later gives Aliyah = $100

The amount Candy later gives Brenda = $50

The new ratio of the sum of the shared money between Aliyah, Brenda and Candy = 2:3:3

(a) Whereby Aliyah has $3x at the start, we have;

Total sum of mony = Y

Amount of Aliyah's initial share = Y × 3/(3 + 5 + 6) = Y×3/14

Therefore, Y×3/14 = $3x

x = Y×3/14 ÷ 3 = Y/14

Amount of Candy's initial share = Y × 6/14

Therefore Candy's initial sum as a terms of x = $6x

(b) Given that Aliyah's and Candy's initial sum as a function of x are   $3x and $6x, therefore, in the ratio 3:5:6, Brenda's  initial sum as a function of x = $5x

Which gives;

Total amount of money = $14x

With

6x - 150, 3x + 100, and 5x + 50, the ratio =is 2:3:3

Therefore, we have;

14·x × 2/(2 + 3 + 3) = (6·x - 150)

14·x × 2/(8) = (6·x - 150)

14·x × 1/4 = (6·x - 150)

7·x/2 = (6·x - 150)

12·x - 300 = 7·x

12·x - 7·x = 300

5·x = 300

x = $60

(b) The final amount of money with Brenda = 5x + 50 = 5 × 60 + 50 = $350

The final amount of money with Brenda = $350.

solve for x and y plz 12x - 5y = -20 x + 4 = y

Answers

Answer:

(0,4)

Step-by-step explanation:

System of Equations:

[tex]\left \{ {{12x-5y=-20} \atop {x+4=y}} \right.[/tex]

x= y-4 .... Change format so you can substitute to first equation

12(y-4)-5y=-20 .... Plug in x= y-4  to first equation

12y - 48 -5y = -20 ..... Distributed

7y -48 =-20 .... Added like terms

7y=28 .... Added 48 to both sides

y=4

.... Plug y into the second equation to find x

x + 4=y

x +4 = 4 .... Plugged in y

x = 4-4 .... Subtracted 4 from both sides

x=0

Your answer is (0,4)

Hope this helps:)

Show that the 9x^2-24xy+16y^2-12x+16y-12=0 represents a pair of parallel lines .Find the distance between the lines.

Answers

First of all u will 9x^2-24xy+16y^2-12×16y-12=0 u will add the 9x^ then u will subtract 2-24

PLEASE help me with this question!!! REALLY URGENT!

Answers

Answer:

B

Step-by-step explanation:

So we have a table of values of a used car over time. At year 0, the car is worth $20,000. By the end of year 8, the car is only worth $3400.

We can see that this is exponential decay since each subsequent year the car depreciates by a different value.

To find the rate of change the car depreciates, we simply need to find the value of the exponential decay. To do this (and for the most accurate results) we can use the last term (8, 3400).

First, we already determined that the original value (year 0 value) of the car is 20,000. Therefore, we can say:

[tex]f(t)=20000(r)^t[/tex]

Where t is the time in years and r is the rate (what we're trying to figure out).

Now, to solve for r, use to point (8, 3400). Plug in 8 for t and 3400 for f(t):

[tex]3400=20000(r)^8\\3400/20000=17/100=r^8\\r=\sqrt[8]{17/100}\approx0.8[/tex]

In other words, the rate of change modeled by the function is 0.8.

As expected, this is exponential decay. The 0.8 tells us that the car depreciates by 20% per year.

How many equilateral triangles in the plane have two vertices in the set {(0, 0), (0, 1), (1, 0), (1, 1)}?

Answers

Answer:

12

Step-by-step explanation:

There are 4 points, so there are C(4,2) = 4C2 = 6 pairs of  

points and since two equilateral triangles can be drawn having

that pair of points as vertices, there are 12 equilateral  

triangles that can be drawn having two vertices in the set  

{(0,0), (0,1), (1,0), (1,1)}.

The number of the equilateral triangles in the plane have two vertices in the set {(0, 0), (0, 1), (1, 0), (1, 1)} will be 12.

What is an equilateral triangle?

An equilateral triangle in geometry is a triangle with equal-length sides on all three sides. In the well-known Euclidean geometry, an equilateral triangle is also equiangular, meaning that each of its three internal angles is 60 degrees and congruent with the others.

There are 4 points, so there are C(4,2) = 4C2 = 6 pairs of points and since two equilateral triangles can be drawn having that pair of points as vertices, there are 12 equilateral triangles that can be drawn having two vertices in the set {(0,0), (0,1), (1,0), (1,1)}.

Therefore, the number of the equilateral triangles in the plane that have two vertices in the set {(0, 0), (0, 1), (1, 0), (1, 1)} will be 12.

To know more about equilateral triangles follow

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Write the slope-intercept form of the equation for the line. (-1,-3) (1,1)

Answers

Answer:

y = 2 x − 1

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

We can find the slope from the slope equation

m = (y2-y1)/(x2-x1)

   = ( 1- -3)/(1 - -1)

   = (1+3)/(1+1)

   = 4/2

  =2

find the multiplicative inverse of 3 by 4 minus 5 by 7​

Answers

Answer:

28

Step-by-step explanation:

[tex]\frac{3}{4}-\frac{5}{7}[/tex]

Least Common Denominator of 4 & 7 is 4 * 7 = 28

[tex]\frac{3}{4}-\frac{5}{7}=\frac{3*7}{4*7}-\frac{5*4}{7*4}\\\\\\=\frac{21}{28}-\frac{20}{28}\\\\\\=\frac{21-20}{28}\\\\\\=\frac{1}{28}[/tex]

Multiplicative inverse of [tex]\frac{1}{28}[/tex] is [tex]\frac{28}{1} = 28[/tex]

Yup it equals 28 fir this one

A.) Pinky bought 1. 1/2 kg of apples and 5. 1/4 kg of mangoes 1. 1/2 kg of oranges. Find the total weight of fruits B.) if her family eats 3/4 kg of apples and 2. 1/2 kg of mangoes and 1/2 kg of oranges. Find the weight of fruits left (Please say the answer with explanation who says the answer first I will mark them as the brainliest)

Answers

Answer:

A. Total weight of the fruits is 2.25 kg

B. There are no more fruits left.

Step-by-step explanation:

A.

To get the total weight of the fruits, we will first of all have to sort out the fruits and multiply the weight of the fruits by the number available.

Weight of apples:

we have one 1apple weighing 1/2 kg. The weight will be 1 |X 1/2 = 1/2 kg

Weight of mangoes:

We have five mangoes weighing 1/4 kg. Total weight will be 5 X 1/4 = 5/4 kg

Weight of oranges:

We have one orange weighing 1/2 kg. Total weight will be 1X 1/2 = 1/2 kg

Total weight of the fruits will be total weight of Mangoes + oranges + apples

= 1/2 + 5/4 + 1/2 = 2.25kg

B.

If her family begins to eat off some portions of the fruits, we will have to calculate the sum total of all the weights of fruits eaten

The portion eaten will be 3/4 + (2 X 1/2) + 1/2 = 2.25kg

If this happens the family would have eaten all of the fruits because

the original weight present is only 2.25kg of fruits to start with

PLEASE help me with this question! No nonsense answers please. This is really urgent.

Answers

Answer:

32

Step-by-step explanation:

This is because you would want the feet and the radium kinda meeting up in a way and would need to make sure you can fill it in with th e drive way as it will be on a horizontal base so you would need X2 of the driveway to make it into a standing up horizontal base

Hope this helps

If this seems incorrect please comment with the answer that it should be and I shall change my answer thanks you :)

Use a trigonometric ratio to find the value of x. Round your answer to the nearest tenth.

3.1
3.4
4.8
2.6

Answers

The answer would be C) 4.8

For the function f(x) = -12x + 7, find the
matching value for x when f(x) = 17. Write
your answer as a fraction.

Answers

Answer:

[tex]\large\boxed{x=-\frac{5}{6}}[/tex]

Step-by-step explanation:

f(x) is the same value as y. Therefore, y = 17. We can place this into slope intercept form (except with a defined value for y) and solve for x.

Start by subtracting 7 from both sides. Then, divide by -12 to solve for x. Finally, simplify the fraction.

17 = -12x + 7

10 = -12x

-10/12 = x

-5/6 = x

[tex]\large\boxed{x=-\frac{5}{6}}[/tex]

4x
5.
If 7:5 = (x + 2y): (x - y), find the value of
5y

Answers

Answer:

5/2 OR 2.5

Step-by-step explanation:

( x + 2y ) = 7 , ( x - 2y ) = 5

x = 7 - 2y , x = 5 + 2y

substitute the two eqns together:

7 - 2y = 5 + 2y

7 - 5 = 2y + 2y

2 = 4y

y = 1/2

when y = 1/2 ,

5y = 5(1/2)

= 5/2 OR 2.5

3m-2-5n+p terms and coefficients

Answers

Answer: Answers are in the steps.

Step-by-step explanation:

The coefficients are 3, -5, and 1  

The terms are, 3m, -2,-5n and p

The table below shows one doctor's patients who got the flu and whether or not they took a vitamin each day. What is P(took a vitamin | got the flu)? (Note: If your fraction will reduce, you need to reduce it.)

Answers

Answer:

1/4

Step-by-step explanation:

25 people took a vitamin and still got the flu and the total number is 100 so the fraction is 25/100 which can be reduce to 1/4

The P(took a vitamin | got the flu) will be 1/4.

What is the unitary method?

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

Here, the table below shows one doctor's patients who got the flu and whether or not they took a vitamin each day.

We need to find the P(took a vitamin | got the flu).

Now, 25 people took a vitamin and still got the flu.

The total number is 100.

So, the fraction is 25/100 which can be reduce to 1/4.

P(took a vitamin | got the flu) = 25/100

P(took a vitamin | got the flu) = 1/4

Therefore, the P(took a vitamin | got the flu) will be 1/4.

Learn more about the unitary method;

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last one hopefullly hahah

Answers

you are correct. all angles (except central) are not equal (iff TU and CB are not parallel)

the triangles are not similar

Answer:

it's A

They don't give you enough information to determine if they are similar or not

Tim has an after-school delivery service that he provides for several small retailers in town. He uses his bicycle and charges $1.25 for a delivery made within 1 1/2 mi, $1.70 for a delivery of at least 1 1/2 mi but less than 1 3/4 mi, $2.15 for a delivery of at least 1 3/4 mi but less than 2 miles, and so on. If tim raised his rates by 10% what would he be paid to deliver a package 3 1/8 miles

Answers

Answer:

$4.84

Step-by-step explanation:

Given that

For delivery within [tex]1\frac{1}2[/tex] mi, charges = $1.25

For delivery within [tex]1\frac{1}2[/tex] mi - [tex]1\frac{3}4[/tex] mi, charges = $1.70

For delivery within [tex]1\frac{3}4[/tex] mi - 2 mi, charges = $2.15

and

so on.

i.e.

For delivery within 2 mi - 2[tex]\frac{1}4[/tex] mi, charges = $2.60

For delivery within 2[tex]\frac{1}4[/tex] mi - 2[tex]\frac{1}2[/tex] mi, charges = $3.05

For delivery within 2[tex]\frac{1}2[/tex] mi - 2[tex]\frac{3}4[/tex] mi, charges = $3.50

For delivery within 2[tex]\frac{3}4[/tex] mi - 3 mi, charges = $3.95

For delivery within 3 mi - 3[tex]\frac{1}4[/tex] mi, charges = $4.40

So, every 0.25 mi or [tex]\frac{1}4[/tex] mi increase in distance, there is an increase of $0.45 in the charges.

It is given that there is increase of 10% in the rates.

i.e. for every 0.25 mi increase in distance, there is an increase of 0.45*1.10 = $0.495 in the charges.

The distance of [tex]3\frac{1}8[/tex] miles lies within the range 3 mi - 3[tex]\frac{1}4[/tex] mi.

So actual charges after increase of 10%

[tex]\Rightarrow \$4.40 \times \dfrac{110}{100}\\\Rightarrow \$4.40 \times 1.10\\\Rightarrow \bold{\$4.84}[/tex]

calculate the amount and compound interest on rupees 4000 at the rate of 8% per annum compounded annually for 2 years​

Answers

Step-by-step explanation:

To calculate the compound interest we use the formula

C = A - P

Where

A is the amount

P is the principal

C is the compound interest

To find the amount we use the formula

[tex]A = P(1 + \frac{r}{100} ) ^{n} [/tex]

where P is the principal

r is the rate

n is the period

From the question

P = 4000 rupees

rate = 8%

n = 2 years

Substitute the values into the above formula

That's

[tex]A = 4000( 1 + \frac{8}{100} )^{2} [/tex]

[tex]A = 4000 ({1 + 0.08})^{2} [/tex][tex]A = 4000 ({1.08})^{2} [/tex]

A = 4665.6

The amount is 4665.60 rupees

Since the amount is found we can now find the compound interest

C = 4665.60 - 4000

C = 665.6

The compound interest is 665.60 rupees

Hope this helps you

A line passes through point (5, –3) and is perpendicular to the equation y = x. What's the equation of the line?

Answers

Answer:

y = -x +2

Step-by-step explanation:

y =x  has a slope of 1

Perpendicular lines have slopes that multiply to -1

m* 1 = -1

The slope of the perpendicular line is -1

We have a slope and a point

y = mx+b

y= -1x+b

Substitute the point into the equation

-3 = -1(5) +b

-3 =-5 +b

Add 5 to each side

-3+5 = b

2 =b

y = -x +2

A delivery truck company just bought a new delivery truck and they need to know the maximum volume it can carry. In the front of the truck, there is an extra ledge that sticks out over the driver's cab for extra storage space. What is the maximum amount of cargo that can fit into the new truck?

Answers

Answer:

The answer is below

Step-by-step explanation:

To find the maximum amount of cargo the truck can carry, we need to find the volume of the truck.

Volume = length × width × height.

Firstly 1 feet (1') = 12 inches (12"),

For the extra ledge that sticks out, the height = 7'8" = 7.667 feet, the width = 16'9" - 14'3" = 16.75 - 14.25 = 2.5 feet, the length = 2'7" = 2.583 feet

Volume of extra ledge = length × width × height = 2.583 × 2.5 × 7.667 = 49.5 feet³

For the truck, the height = 7'8" = 7.667 feet, the length = 14'3" = 14.25 feet, the width = 6'6" = 6.5 feet

Volume of truck = length × width × height = 14.25 × 6.5 × 7.667 = 710.16 feet³

The maximum volume = volume of extra ledge + volume of truck = 49.5 + 710.16 = 759.66 feet³

Which system of linear inequalities is represented by
the graph?
Oy> x-2 and y < x + 1
O y< x-2 and y > x + 1
Oy x + 1
O y > x-2 and y < x + 1

Answers

Answer:

The correct option is;

y < x - 2, and y > x + 1

Step-by-step explanation:

The given graph of inequalities is made up of parallel lines. Therefore, the slope of the inequalities are equal

By examination of the graph, the common slope = (Increase in y-value)/(Corresponding increase in x-value) = (0 - 1)/(-1 - 0) = 1

Therefore, the slope = 1

We note that the there are three different colored regions, therefore, the different colored regions opposite to each inequalities should be the areas of interest

The y-intercept for the upper bounding linear inequality, (y >) is 1

The y-intercept for the lower bounding linear inequality, (y <) is -2

The two inequalities are y > x + 1 and y < x - 2

The correct option is y < x - 2, and y > x + 1.

The system of linear inequalities is represented by  the graph is y> x-2 and y < x + 1

Inequalities is an expression that shows the non equal comparison of two or more variables and numbers.

Given that:

y and x are variables, plotting the inequalities using geogebra online graphing tool.

The system of linear inequalities is represented by  the graph is y> x-2 and y < x + 1

Find out more on linear inequalities at: https://brainly.com/question/21103162

A certain mixture of paint contains 5 parts white paint for every 4 parts blue paint. If a can of paint contains 75 ounces of white paint, how many ounces of blue paint are in the can?

Answers

Answer:

60 ounces.

Step-by-step explanation:

Given:

A mixture contains 5 parts of white paint for every 4 parts of blue paint.

i.e. Ratio of white paint : blue paint = 5 : 4

Quantity of White paint = 75 ounces

To find:

How many ounces of blue paint = ?

Solution:

Here, we are given the ratio of white and blue paint in the mixture.

Also, we are given the quantity of white paint in the paint can.

And we have to find the quantity of other paint in the can.

Let us use all the given statements to find the unknown quantity of blue paint.

Ratio of white paint : blue paint= Ratio of quantity of white paint: blue paint

[tex]\dfrac{5}{4} = \dfrac{75}{\text{Quantity of blue paint}}\\\Rightarrow \text{Quantity of blue paint} = 15 \times 4\\\Rightarrow \text{Quantity of blue paint} = 60\ ounces[/tex]

So, the quantity of blue paint in the can is 60 ounces.

Use mathematical induction to prove the statement is true for all positive integers n. 8 + 16 + 24 + ... + 8n = 4n(n + 1)? Please show work

Answers

Answer:

The sum of the series is Sₙ = n/2 [2·a + (n - 1)·d] where a = 8 and d = 8, therefore 8 + 16 + 24 + ... + 8·n = 4·n·(n + 1)

Step-by-step explanation:

The parameters given are;

8 + 16 + 24 + ... + 8·n = 4·n·(n + 1)

The given series of numbers can be checked to find;

16 - 8 = 24 - 16 = 8

Therefore, the series of numbers is an arithmetic progression with first term = 8, and common difference = 8, we have;

The sum of n terms of an arithmetic progression, Sₙ, is given as follows;

Sₙ = n/2 [2·a + (n - 1)·d]

Where;

a = The first term of the series of numbers = 8

d = The common difference = 8

∴ Sₙ = n/2 × [2×8 + (n - 1)×8] = n [2×8/2 + (n - 1)×8/2]  =  n × [8 + (n - 1)×4]

Sₙ =  n × [8 + (n - 1)×4] =  n × [8 + 4·n - 4] = n × [8  - 4 + 4·n] = n × [4 + 4·n]

Sₙ =n × [4 + 4·n] = 4 × n×(n + 1) = 4·n·(n + 1).

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