Answer:
He is wrong.
In my answer I found the complete volume of the pool and then what the volume would be 10 cm empty. You probably only need to find the 10 cm emptied to answer, just a heads up. if you have any questions though let me know.
Step-by-step explanation:
To most easily figure out the volume of the empty pool I think it is easiest to break it up into four parts..
First break off that skinny end bit so it will have 1 m in height, 4 m in length and 5m in width. Width is never going to shange because of how we are breaking this up, and the width is the distance from you into the paper, if that makes sense. Basically not up and down or left and right.
Next another rectangular prism from the right side with 2 height, 2m length and again 5m width.
Now you have a trapezoidal prism with one base of length 1m, another of base 2m and a height of length 4m.
To fond the volume of prisms you want to find the area of their bases then multiply it by their heights. In this instance height is going to be the width again, and the bases are th parts facing us on the picture.
For a rectangular prism area of the base is easy, just multiply length by height. a trapezoid is taking the two bases (b1 and b2) ading them together and dividing that sum by 2, THEN taking this new number and multiplying it by what would be the height of the trapezoid. the trapezoid has its bases as two heights, and its height then would be the horizontal length of the pool. Sorry if that is confusing. Here are the three volumes though.
Rectangular 1: 4*1*5 = 20 m^3
Rectangular 2" 2*2*5 = 20m^3
Trapezoidal: = ([1+2]/2)*4*5 = 30 m^3
So total it is 70 m^3
The question then says each cubic meter can contain 1,000 liters of water. 70 m^3 then is 70,000 liters
The question also says there are three barrels of 20,000 liters each, so combined that's 60,000 liters.
Finally it wants to know if Sam is right saying if you dump all of the 60,000 liters into the pool the surface of the water will not reach the top of the pool by 10 cm. 60,000 is less than 70,000, but we don't know how much lower it is in cm.
The trick here is to know that we are lowering a specific dimension of each prism to a certain amount to be lower by 10cm
In the 4x1x5 rectangular prism the 1m side is lowering.
In the 2x2x5 rectangular prism the 2m side representing the vertical length is getting some amount taken away.
int he trapezoidal prism both of the "bases" are getting an amount taken.
So the trick here is to set up the math again, except this time with 10 cm less being subtracted from each part, then solving t and see if it gets us the 60,000 liters or 60 m^3. Since we are measurng in meters, 10 cm less is the same a subtracting .1, or if you prefer subtracting a decimeter.
4*1*5 becomes 4(.9)5 = 18
2*2*5 becomes 2(1.9)5 = 19
Trapezoidal: = ([1+2]/2)*4*5 becomes ([(.9)+(1.9)]/2)*4*5 = 28
Adding this all together gets us 65 or 65,000 liters. This means that if the pool is filled 10 cm from the top the volume would be 65,000 liters, still more than if the three tankers are emptied completely into it.
You could have probably just done the second part, where we sbtracted 10 cm from each of the dimensions, but I am going to leave it all since I wrote it.
9514 1404 393
Answer:
Sam is not correct.
Step-by-step explanation:
As shown in the attachment, the "base" (front face) of this prism can be divided into a rectangle and a trapezoid. The relevant area formulas are ...
A = LW . . . . area of a rectangle of length L and width W
A = 1/2(b1 +b2)h . . . . area with parallel bases b1 and b2 and height h
__
The rectangle portion of the "base" of the pool has area ...
A = (10 m)(1 m) = 10 m²
The trapezoid portion of the "base" of the pool has area ...
A = 1/2(6 m +2 m)(1 m) = 4 m²
Then the "base" area is ...
B = 10 m² +4 m² = 14 m²
__
The volume of the prism is given by ...
V = Bh . . . . where B is the base area and h is the distance between bases
V = (14 m²)(5 m) = 70 m³
We are told that 1 m³ = 1000 L and that 3 tankers of 20,000 L each are emptied into the pool. That leaves an unfilled volume of ...
70 m³ -3×(20 m³) = 10 m³ . . . . unfilled volume
__
The surface area of the pool is ...
A = LW = (10 m)(5 m) = 50 m²
So the unfilled volume has a height of ...
V = Bh
10 m³ = (50 m²)h
h = (10/50) m = 20/100 m = 20 cm . . . . . the height of the unfilled space
The water in the pool will be 20 cm below the top, not 10 cm. Sam is not correct.
Suppose that y varies inversely with x. Write a function that models the inverse function x=7 when y=3
9514 1404 393
Answer:
y = 21/x
Step-by-step explanation:
The inverse variation relation means ...
y = k/x
For the given values, we can determine the constant k:
3 = k/7
3×7 = k = 21
Then the function is ...
y = 21/x
I don't understand plz help
9514 1404 393
Answer:
x = 2
Step-by-step explanation:
Triangles QST and QSR are congruent, so angle QST is congruent to angle QSR.
(3x +24)° = 30°
3x = 6 . . . . . . . . . divide by °, subtract 24
x = 2 . . . . . . . . . . divide by 3
__
Additional comment
What matters here is the relationship between the two marked acute angles. The fact that point Q is equidistant from the sides of angle TSR tells you that QS is an angle bisector and the two angles have equal measures. (The definition of an angle bisector is that it is equidistant from the sides of the angle.)
Recognition that the two triangles are congruent is another way to see that the marked acute angles have the same measure. The triangle congruence can be claimed on the basis of the HL theorem, since both are right triangles, have the same hypotenuse (QS), and have legs (QT, QR) with the same measure.
what is the average rate of change between:
x=1 and x=2
x=2 and x=3
x=3 and x=4
Rate of change = RΔ = (y2-y1)/(x2-x1) = Δy/Δx
(X1,Y1)(X2,Y2)
(1, 2) (2, 4)
RΔ = Δy/Δx
= (4-2)/(2-1)
RΔ = 2
(2, 4) (3, 8)
RΔ = (8-4)/(3-2)
RΔ = 4
(3, 8) (4, 16)
RΔ = (16-8)/(4-3)
RΔ = 8
what is the solution for 3(x+3)=12
Answer: 3×4=12
Step-by-step explanation:
Brackets: X=1 , so 1+3=4 and 3+4=12
Which system of linear inequalities is represented by
the graph?
+
oyz_x+3 and 3x – y> 2
o ye}x+3 and 3x –y> 2
o y }x+3 and 3x + y> 2
O ya 4x+3 and 2x-y> 2
Answer:
o ye}x+3 and 3x –y> 2 system of linear inequalities is represented by the graph.
PLEASE LET ME KNOW IF ¡ AM WRONG!
The system of linear inequalities represented by the graph is
y ≥ (1/3)x + 3 and 3x - y > 2
Option A is the correct answer.
What is inequality?It shows a relationship between two numbers or two expressions.
There are commonly used four inequalities:
Less than = <
Greater than = >
Less than and equal =≤
Greater than and equal = ≥
We have,
We see that,
When we graph,
y ≥ (1/3)x + 3 and 3x - y > 2 we get the graph shown.
y ≥ (1/3)x + 3
This inequality is positive on the y-axis.
3x - y > 2
3x > 2 + y
This inequality is positive on the x-axis.
Thus,
The system of linear inequalities represented by the graph is
y ≥ (1/3)x + 3 and 3x - y > 2
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if 100% = Rs 120,then. A.120% = Rs 84 B. 20% = Rs 84 C. 70% = Rs 84 D. 30% = Rs 84
Answer:
70% is Rs 84
just use the formula
x% of 120= 84
and you will get the answer
?? I got 5 minutes left, please help.
Answer:
Here we know that:
[tex]m(v) = \frac{M_0}{\sqrt{1 - \frac{V}{C} } }[/tex]
Where V is the speed, C = 3*10^8 m/s
We want to solve:
[tex]m(v) = \frac{M_0}{\sqrt{1 - \frac{V}{C} } } = 2*M_0[/tex]
We can just isolate V from the above equation, so we will get:
[tex]\frac{M_0}{\sqrt{1 - \frac{V}{C} } } = 2*M_0[/tex]
[tex]\frac{1}{\sqrt{1 - \frac{V}{C} } } = 2[/tex]
[tex]1 = 2\sqrt{1 - \frac{V}{C} }[/tex]
[tex](1/2)^2 = 1 - \frac{V}{C}[/tex]
[tex]V = (1 - (1/4))*C = (3/4)*C = (3/4)*3*10^8 m/s = (9/4)*10^8 m/s[/tex]
That is the velocity such that the effective mass is twice the rest mass.
Prove that if a and b are positive integers,then there exists a unique integers q and r such that a=bq+r where 0≤r<b
Step-by-step explanation:
Correct option is
C
0≤r<b
If r must satisfy0≤r<b
Proof,
..,a−3b,a−2b,a−b,a,a+b,a+2b,a+3b,..
clearly it is an arithmetic progression with common difference b and it extends infinitely in both directions.
Let r be the smallest non-negative term of this arithmetic progression.Then,there exists a non-negative integer q such that,
a−bq=r
=>a=bq+r
As,r is the smallest non-negative integer satisfying the result.Therefore, 0≤r≤b
Thus, we have
a=bq1+r1, 0≤r1≤b
A ream of a certain brand of paper weighs about 4.533 pounds. A ream contains 500 sheets of paper. How much does a sheet of paper weigh?
Step-by-step explanation:
As a ream or
500
sheets of paper weigh
4.818
pounds
One sheet of paper weighs
4.818
500
=
0.009636
pounds.
It is apparent that pound is too big a unit for a sheet of paper.
As each pound has
16
ounces, one can say
one sheet of paper weighs
0.009636
×
16
=
0.154176
ounces.
If ounce is too big, as we have
1
pound equal to
28.34952
grams
one sheet of paper weighs
0.154176
×
28.34952
≈
4.371
grams
please mark as brainliest
Refer to the Lincolnville School District bus data. Information provided by manufacturers of school buses suggests the mean maintenance cost per year is $4,400 per bus with a standard deviation of $1,000. Compute the mean maintenance cost for the Lincolnville buses. Does the Lincolnville data seem to be in line with that reported by the manufacturer? Specifically, what is the probability of Lincolnville’s mean annual maintenance cost, or greater, given the manufacturer’s data?
Answer:
Step-by-step explanation:
Add all of the Maintenance costs up, divide by 80. (the number of costs).
Excel formula =SUM(F2:F81) 364151.00/80 = 4551.8875 Rounded to 4552 is your answer.
Your answer in part (b) read "one and one- fourth" is called a mixed number since it has a whole number part and a fraction part. What does the word "and" indicate in the name of this fraction?
9514 1404 393
Answer:
the end of the whole number and the beginning of the fraction
Step-by-step explanation:
The word "and" means the whole part and the fractional part should be considered together as having a value equal to their sum. It signifies the separation between the whole-number part and the fractional part.
__
It has the same meaning as when used in a decimal mixed number:
1.2 = "one and two tenths"
Find the value of x.
Plz help :/
Answer:
10
Step-by-step explanat
ion:
A calculator was used to perform a linear regression on the values in the
table. The results are shown to the right of the table.
х
y
1
9
N
6
LinReg
y = ax+b
0=-3.6
b=12.8
r2=.9969230769
r=-.9984603532
3
2
4
-2
5
-5
What is the line of best fit?
A. y = -3.6x + 12.8
O B. -0.998 = -3.6x + 12.8
O c. y = 12.8x - 3.6
D. y = -0.998x + 12.8
Answer:
Step-by-step explanation:
A y = -3.6x + 12.8
The line of best fit is,
⇒ y = - 3.6x + 12.8
What is an expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Now, Given that;
⇒ y = ax + b.
And, the best fitting line has values of a = - 3.6 and b = 12.8.
Hence, All you need do is put that into the general equation and try different values for it.
So you have y = - 3.6 x + 12.8
Now Let's run a couple of numbers.
The table shows 1 and 9 for the first entry. This means when x = 1, y should come pretty close to nine.
y = - 3.6(1) + 12.8
y = 9.2
Which is not a bad result for x = 1
You might want to check to see if anything else comes closer in your choices. If it does, then you have to try other points.
C
-0.998 = -3.6(1) + 12.8
This answer cannot work. We've already shown that x =1 will leave us close to 9 not -998
So, C is incorrect.
B
y = 12.8x - 3.6
Let x = 1
y = 12.8(1) - 3.6
y = 9.2 is right by coincidence. We must try another value. The hardest one is going to be 5 and - 5
y= 12.8*5 - 3.6
y = 64 - 3.6 which is no where's near - 5.
So B is wrong.
A
y = -0.998(1) + 12.8 Does this give 9 or anywhere near it? 11.802 You might argue that that is not a bad result. So let's try another pair.
x = 3. y should come to somewhere near 2.
y = -0.998 * 3 + 12.8 which comes to roughly nine. You can check this out.
It is not close enough to 2 to be acceptable.
Thus, The correct option is,
⇒ y = - 3.6x + 12.8
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Noel and Casey both start at the same place. Noel walks due south and Casey walks due east. After some time has passed, Noel is 6 miles south and Casey is 8 miles east. At this time, Noel is walking at a rate of 2 mph and Casey is walking at a rate of 1 mph. How fast is the distance between them increasing at this time
Answer:
2.04 miles per hour
Step-by-step explanation:
Given
Noel
[tex]n_1 =6miles[/tex]
[tex]r_1 = 2mph[/tex]
Casey
[tex]c_1 = 8miles[/tex]
[tex]r_2 =1mph[/tex]
Required
The rate at which the distance increases
Their movement forms a right triangle and the distance between them is the hypotenuse.
At [tex]n_1 =6miles[/tex] and [tex]c_1 = 8miles[/tex]
The distance between them is:
[tex]d_1 = \sqrt{n_1^2 + c_1^2}[/tex]
[tex]d_1 = \sqrt{6^2 + 8^2}[/tex]
[tex]d_1 = \sqrt{100}[/tex]
[tex]d_1 = 10miles[/tex]
After 1 hour, their new position is:
New = Old + Rate * Time
[tex]n_2 = n_1 + r_1 * 1[/tex]
[tex]n_2 = 6 + 2 * 1 = 8[/tex]
And:
[tex]c_2 = c_1 + r_2 * 1[/tex]
[tex]c_2 = 8 + 1 * 1 = 9[/tex]
So, the distance between them is now:
[tex]d_2 = \sqrt{n_2^2 + c_2^2}[/tex]
[tex]d_2 = \sqrt{8^2 + 9^2}[/tex]
[tex]d_2 = \sqrt{145}[/tex]
[tex]d_2 = 12.04[/tex]
The rate of change is:
[tex]\triangle d = d_2 -d_1[/tex]
[tex]\triangle d = 12.04 -10[/tex]
[tex]\triangle d = 2.04[/tex]
ASAP PLEASE!!The table and the relative frequency histogram show the distribution of the number of tails and three coins are tossed. Find the probability P(T=1). write your answer as a fraction.
Explanation:
P(T = 1) is the notation that means "The probability of getting exactly one tail". The table shows 3/8 in the bottom row, under the "1" in the top row. So that's why P(T = 1) = 3/8
Or it might make more sense to say P(one tail) = 3/8 so we don't have too many equal signs going on.
Solve the inequality: w - (14) < 8
[tex]w - (14) < 8 \\ = w < 8 + 14 \\ \\ w = < 22[/tex]
Step by Step Explanation:
Move the constant to the right - hand side and change its signThen add the numbers ☆彡Hanna#CarryOnLearning
in the right triangle AB, mc=90, a=4, and sinA=1/2. what is the length of the hypotenuse?
Given:
In a right angle triangle ABC, [tex]m\angle C=90^\circ , a=4[/tex] and [tex]\sin A=\dfrac{1}{2}[/tex].
To find:
The length of the hypotenuse.
Solution:
It is given that [tex]m\angle C[/tex], so opposite side of this angle is the hypotenuse, i.e., c.
In a right angle triangle,
[tex]\sin \theta=\dfrac{Perpendicular}{Hypotenuse}[/tex]
In the given triangle,
[tex]\sin A=\dfrac{a}{c}[/tex]
Substituting the given values, we get
[tex]\dfrac{1}{2}=\dfrac{4}{c}[/tex]
By cross multiplication, we get
[tex]1\times c=4\times 2[/tex]
[tex]c=8[/tex]
Therefore, the length of the hypotenuse is 8 units.
A study is conducted to see how effective aspirin is in reducing temperature in children. A sample of 6 children suffering from influenza had their temperatures taken immediately before and 1 hour after administration of aspirin. The results are given below. We would like to conduct a paired differences t-test for this situation. The data follows:
Patient Temperature Before Temperature After Difference
1 103.7 102.6 1.1
2 103.7 102.7 1
3 100.7 98.8 1.9
4 102.7 103.5 -0.8
5 102.7 101.3 1.4
6 100.7 99.4 1.3
Mean 102.4 101.4 1
Std. Dev. 1.4 1.9 0.9
Required:
Calculate the appropriate test statistic of a matched pairs t-test for this data to see if taking aspirin will reduce a child's fever.
Answer:
Then t(s) is in the rejection region for H₀ we reject H₀ and conclude that the aspirin will reduce a child´s fever
Step-by-step explanation:
Tem.Before Tem.After diff.
103.7 102.6 1.1
103.7 102.7 1
100.7 98.8 1.9
102.7 103.5 -0.8
100.7 99.4 1.3
102.4 101.41 (Mean)
1.4 1.9 0.9 Std. Dev.
n = 6
df = 6 - 1 = 5
CI we propose to be 95 %
Then α = 5 % α = 0.05
The test is a one-tail test ( we want to know if taking aspirin will reduce a child´s fever
Hypothesis test
Null Hypothesis H₀ μd = 0
Alternative Hypothesis Hₐ μd > 0
(NOTE:) μd (average) = Temp Before - Temp. after
Therefore if μd > 0 means that there is a statistical difference between values before ( bigger ) and after or that the aspirin will reduce a child´s fever
To find t(c) from t-student table df = 5 and α = 0.05
t(c) = 2.015
To compute t(s)
t(s) = μd/ sd/√n t(s) = 0.98/ 0.9/√6
t(s) = 2.66
Comparing t(s) and t(c)
t(s) > t(c)
Then t(s) is in the rejection region for H₀ we reject H₀ and conclude that the aspirin will reduce a child´s fever
PLEASEEEEEE HELPPPPPP IM BEGGGGINGGG SOMEONE PLEASEEEEE PLEASEEEEEEE
Answer:
x+120°+20°=180°[ sum of interior angle of triangle]
x+140°=180°
x=40°
then,
x+y= 180°[being straight line]
40°+y= 180°
y=140°
State whether the data described below are discrete or continuous and explain why?
The distance between cities in a certain contry.
a. The data are discrete because the data can only take on specific values.
b. The data are discrete because the data can take on any value in an interval.
c. The data are continuous because the data can take on any value in an interval.
d. The data are continuous because the data can only take on specific values.
Answer:
c. The data are continuous because the data can take on any value in an interval.
Step-by-step explanation:
Discrete data are those which can take up only specific values. Discrete data values may include the number of children in a particular school, the number of visitors received per day. All this values are specific and cannot just take up any number one f values within an interval. Continous data on the other hand can take up any number of data values between an interval. Continous data types are usually height temperature, length(distance data). There can be infinite number of possible data within interval values.
I need help I’ll give u brainlest
Answer:
216 yd³
Step-by-step explanation:
Volume of a rectangular prism
= product of the three orthogonal sides
= 6yd * 6yd * 6yd
= 216 yd³
Answer:
216
Step-by-step explanation:
:)
ANSWER ALL QUESTIONS
1. In a class of 28 pupils, 13 have pencils, 9 have erasers and 9 have neither pencils nor erasers. How
many pupils have both pencils and erasers?
2. A universal set, U consists of prime numbers with P and Q as subsets of U. If P and Q are given by
P = {n: 3(n + 1) = 2(n + 10)}, and Q = {n: 7<n<31}, list the elements of P n Q.
1. 3
29-9=19
13+9=22
22-19=3
I don't know number 2, sorry.
Carson is going to see a movie and is taking his 2 kids. Each movie ticket costs
$14 and there are an assortment of snacks available to purchase for $3.50
each. How much total money would Carson have to pay for his family if he
were to buy 2 snacks for everybody to share? How much would Carson have
to pay if he bought x Snacks for everybody to share?
Total cost with 2 snacks:
Total cost with x sn
acks:
49 dollars
Step-by-step explanation:
14 times 3 is 42 and 3.50 times 2 is 7, so 42 plus 7 is 49.
Total cost with 2 snacks = $35
Total cost with x snacks = 28+3.50x
Given :
Carson is going to see a movie and is taking his 2 kids. Movie ticket costs $14 and snacks cost $3.50.
Explanation :
Carson buys 2 snacks . we need to find the total cost that Carson have to pay where he buy 2 snacks.
Total cost = cost of ticket (2 kids) + cost of 2 snacks
[tex]Total \; cost = 14(2) + 2(3.50)=35[/tex]
Total cost with 2 snacks = $35
Total cost with x snacks = cost of ticket (2 kids) + cost of x snacks
[tex]Total \; cost = 14(2) + 3.50(x)\\Total \; cost = 28+3.50x[/tex]
Total cost with x snacks = 28+3.50x
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[tex]\huge{\boxed{ \sum_{n=1}^{\infty}\frac{3n}{3^n \: n!}=}}[/tex]
[tex]HOLA!![/tex]
Answer:
[tex]{\boxed{ \sum_{n=1}^{\infty}\frac{3n}{3^n \: n!}=e^{\frac{1}{3} } }}[/tex]
Explanation:
[tex]{\boxed{ \sum_{n=1}^{\infty}\frac{3n}{3^n \: n!}=}}[/tex]
For this we have to take into account:
[tex]{\boxed{ \sum_{n=1}^{\infty}\frac{x^{n} }{n!} =e^{x} }}[/tex]
Using the properties of factorials and exponents we have:
[tex]n!=(n-1)n![/tex] Also. [tex]\frac{n^{x} }{ n^{y} }=n^{x-y}[/tex]
We replace:
[tex]{\boxed{ \sum_{n=1}^{\infty}\ \frac{1}{3^{n-1}.(n-1)! } }}[/tex]
Shape it:
[tex]{\boxed{ \sum_{n=1}^{\infty}\frac{(\frac{1}{3} )^{n-1} }{(n-1)!} }}[/tex]
Finally:
[tex]{\boxed{ \sum_{n=1}^{\infty}\frac{(\frac{1}{3} )^{n-1} }{(n-1)!} =e^{\frac{1}{3} } }}[/tex]
a bag contains 5white and 3red identical balls.if the balls are drawn at random after the other without replacement. what is the probability that the first red ball is picked at fifth draw
Answer:
2/7
Step-by-step explanation:
Use the digits 0 - 9 to fill in the blank.
[tex]243 \frac{1}{5} = blank[/tex]
Answer:
use 0-9 to fill in blanks
Step-by-step explanation:
the angles of a triangle is 2x,3x and 5x find the value of x
Here,
2x+3x+5x = 180 (sum of all angles of triangle are equal to 180)
or, 10x = 180
or, x = 180/10
x = 18
Therefore, the value of x is 18.
Hope this solution may help you☺
Answer:
2x + 3x + 5x = 180(sum of all the interior angles of a triangle is 180° )
10x = 180°
x=180/10
x = 18°
help me please it’s timed !!!
While
AB is A. 5Welcome :)If someone can pls give the answer with steps that would be greatly appreciated :)
[tex]\sf \bf {\boxed {\mathbb {TO\:FIND:}}}[/tex]
The measures of [tex]x[/tex] and [tex]y[/tex].
[tex]\sf \bf {\boxed {\mathbb {SOLUTION:}}}[/tex]
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {x\:=\: 210°\:and\:\:y\:=\: -30°}}}}}}[/tex]
[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:EXPLANATION:}}}[/tex]
An exterior angle of a triangle is equal to sum of two opposite interior angles.
And so we have,
[tex] 40° = 70° + y[/tex]
[tex]➪ \: y= 40° - 70°[/tex]
[tex]➪ \: y = - 30°[/tex]
Also,
[tex]\sf\pink{Sum\:of\:angles\:on\:a\:straight\:line\:=\:180°}[/tex]
[tex]y[/tex] + [tex]x[/tex] = [tex]180°[/tex]
[tex]➪ \: -30° + x= 180°[/tex]
[tex]➪ \:x = 180° + 30°[/tex]
[tex]➪ \:x = 210°[/tex]
[tex]\sf\purple{Therefore,\:the\:measures \:of\:the\:unknown\:angles\:are\:"x=210°"\:and\:"y=-30°.}[/tex]
[tex]\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{ヅ}}}}}[/tex]
The Utica Boilermaker is a 15-kilometer road race. Sara is signed up
to nin this race and has done the following training runs:
I.
10 miles
II.
44,880 feet
III. 15,560 yards
Which run(s) are at least 15 kilometers?
Answer:
10 miles
Step-by-step explanation:
10 miles= 16093.44km
44880ft=13.679424km
15560yards= 14.228064