- BRAINLIEST answerer
1. When do we use the method of Difference of two squares?
*
(Factoring polynomials)
Answer:
a
Step-by-step explanation:
Help me pls i give brain
Answer:
4 3/4
Step-by-step explanation:
8 1/2=8 2/4
8 2/4-3 3/4= 4 3/4
Please helppppppppppppp
Answer:
101
HOPE THIS HELPS
- Todo ❤️
Step-by-step explanation:
Suplemetary angles
180-79=101
50 POINTS PLS HELP ME I'LL MARK BRAINLIEST
Find a polynomial of degree n that has only the given zeros. (There are many correct answers.)
x = −3, 8; n = 3
Thank you so much!!
Answer:
Step-by-step explanation:
Here we need to find a 3rd degree polynomial that has only two distinct zeros: {-3, 8}.
Focusing on the zero x = 8 and assuming that this 8 has a multiplicity of 2, we come up with the following polynomial in which the factor x - 8 shows up twice:
f(x) = a(x - 8)(x - 8)(x + 3), or f(x) = a(x - 8)^2(x + 3)
One such polynomial is thus
f(x) = a(x - 8)^2(x + 3), where 'a' is a constant coefficient. This polynomial has a double zero at x = 8 and a third zero at x = -3.
Step-by-step explanation:
The polynomial has degree 3 and two zeros: - 3 and 8.
Since it has degree 3 it should have 3 zero's.
Two possible scenarios
1. -3 has multiplicity of two:
a(x + 3)²(x - 8) - is the factored form of the polynomial where a is the constant2. 8 has multiplicity of two:
a(x + 3)(x - 8)² - is the factored form of the polynomialState the slope and y-intercept for the line
y = 4x – 2?
Answer:
Slope: 4 y-intercept: y=-2
Step-by-step explanation:
The equation is in slope-intercept form:
y=mx+b where m is the slope and b is the y-intercept.
Write in slope-intercept form an equation of the line that passes through the given points. (0,−1),(−8,−2)
Write 2.04 × 10 ⁴ as an ordinary number
Answer:
20400
Step-by-step explanation:
its 2.03x10x10x10x10 so first ten: 20.4 and ten: 204 3rd ten: 2040 last ten :20400
solve pls brainliest
Answer:
first put 2 in the numerator for the first blank and 2/9 in the second blank
Step-by-step explanation:
1/3 equals 3/9 and 3/9-1/9=2/9
Answer:
[tex]\frac{3}{9}[/tex]
Step-by-step explanation:
1. Which of the following equations is equivalent to y = ? 048 = 7x - 21 28 = 12x - 36 O 4x - 3 = 84 O4x - 12 = 84
Answer:
4x - 12 = 84
Step-by-step explanation:
The last answer choice is correct because when you cross-multiply:
[tex]4(x-3) = 12(7)[/tex] [tex]4x - 12 = 84[/tex]you get 4x - 12 = 84.
Therefore, the last option is correct.
Answer:
D would be the answer (4x-12=84)
Step-by-step explanation:
4/7=12/x-3
=>1/7=3/x-3
=>x-3=21
Multiplying both sides by 4
4(x-3)=4x21
=>4x-12=84
Hope this helped :)
If you can walk 1/4 mile in 1/2 hour, how far could you walk in one hour?
Answer:
1/2 + 1/2 = 1
1/4 + 1/4 = 1/2
So you would walk 1/2 mile in 1 hour
Answer:
1/2
Step-by-step explanation:
1/4*2 multiply 1/4 by 2 because its you walk 1/4 in half a hour so times that by 2 for a full hour.
The blank of a line segment is the point that divides a line segment into two congruent line segments
Answer:
da i dont even know thias
Step-by-step explanation:
find the value of x. only type the “number”
Step-by-step explanation:
5x - 6 = 3x + 2
5x - 3x = 2 + 6
2x = 8
x = 8/2
x = 4
Which ratio is equivalent to 7:3?
217
49:9
12: 8
28:12
Answer:
i think it is 49:9
Step-by-step explanation:
because number going in 49:9 by which multiple it is 7x7 is 49 3x3 is 9 so the answer is 49:9
Answer:
28:12
Step-by-step explanation:
Multiply both 7 and 3 by 4 and you get the ratio 28:12.
1.) -3x-8=-14
2.) 4x-6=14
3.)-3-3x=-30
4.) -5x+5=5
Answer:
1.) x = 2
2.) x = 5
3.) x = 9
4.) x = 0
Step-by-step explanation:
1.) -3x - 8 = -14
-3x = -6
x = 2
2.) 4x - 6 = 14
4x = 20
x = 5
3.) -3 - 3x = -30
-3x = -27
x = 9
4.) -5x + 5 = 5
-5x = 0
x = 0
What is 4 times 3/4 multiples by 3/4
Answer:
9/4
hope it helps.................
Find the value of x.
Answer:
i think the answer should be 8
Step-by-step explanation:
Which linear inequality is represented by the graph?
Answer:
the first option
Step-by-step explanation:
pls helppppppp ill give brainliest
Answer:
2n-3
Step-by-step explanation:
three less so -3
Julie runs three less than 2 times what Hannah ran
Hannah ran n miles
so Julie ran three less than 2n
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Question ~}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Prove that ~
[tex] \dfrac{d}{dx}\sec(x) = \sec(x) \tan(x) [/tex]
by using first principle of differentiation ~
Answer:
METHOD I:(by using the first principle of differentiation)
We have the "Limit definition of Derivatives":
[tex]\boxed{\mathsf{f'(x)= \lim_{h \to 0} \{\frac{f(x+h)-f(x)}{h} \} ....(i)}}[/tex]
Here, f(x) = sec x, f(x+h) = sec (x+h)
Substituting these in eqn. (i)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \{\frac{sec(x+h)-sec(x)}{h} \} }[/tex]
sec x can be written as 1/ cos(x)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{1}{cos(x+h)} -\frac{1}{cos(x)} \} }[/tex]
Taking LCM[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{cos(x)-cos(x+h)}{cos(x)cos(x+h)} \} }[/tex]
By Cosines sum to product formula, i.e.,[tex]\boxed{\mathsf{cos\:A-cos\:B=-2sin(\frac{A+B}{2} )sin(\frac{A-B}{2} )}}[/tex]
=> cos(x) - cos(x+h) = -2sin{(x+x+h)/2}sin{(x-x-h)/2}
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{2sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{sin(\frac{h}{2} )}{h} }[/tex]
I shifted a 2 from the first limit to the second limit, since the limits ar ein multiplication this transmission doesn't affect the result[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{2sin(\frac{h}{2} )}{h} }[/tex]
2/ h can also be written as 1/(h/ 2)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{1\times sin(\frac{h}{2} )}{\frac{h}{2} } }[/tex]
We have limₓ→₀ (sin x) / x = 1.[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: 1 }[/tex]
h→0 means h/ 2→0Substituting 0 for h and h/ 2
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+0)}{cos(x+0)cos(x)} }[/tex]
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)cos(x)} }[/tex]
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)}\times \frac{1}{cos x} }[/tex]
sin x/ cos x is tan x whereas 1/ cos (x) is sec (x)[tex]\implies \mathsf{f'(x)= tan(x)\times sec(x) }[/tex]
Hence, we got
[tex]\underline{\mathsf{\overline{\frac{d}{dx} (sec(x))=sec(x)tan(x)}}}[/tex]
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
METHOD II:(by using other standard derivatives)
[tex] \boxed{ \mathsf{ \frac{d}{dx} ( \sec \: x) = \sec x \tan x }}[/tex]
sec x can also be written as (cos x)⁻¹We have a standard derivative for variables in x raised to an exponent:
[tex] \boxed{ \mathsf{ \frac{d}{dx}(x)^{n} = n(x)^{n - 1} }}[/tex]
Therefore,
[tex] \mathsf{ \frac{d}{dx}( \cos x)^{ - 1} = - 1( \cos \: x) ^{( - 1 - 1} } \\ \implies \mathsf{\ - 1( \cos \: x) ^{- 2 }}[/tex]
Any base with negative exponent is equal to its reciprocal with same positive exponent[tex] \implies \: \mathsf{ - \frac{1}{ (\cos x) {}^{2} } }[/tex]
The process of differentiating doesn't just end here. It follows chain mechanism, I.e.,
while calculating the derivative of a function that itself contains a function, the derivatives of all the inner functions are multiplied to that of the exterior to get to the final result.
The inner function that remains is cos x whose derivative is -sin x.[tex] \implies \mathsf{ - \frac{1}{ (\cos x )^{2} } \times ( - \sin x) }[/tex]
cos²x can also be written as (cos x).(cos x)[tex] \implies \mathsf{ \frac{ \sin x }{ \cos x } \times ( \frac{1}{cos x} ) }[/tex]
sin x/ cos x is tan x, while 1/ cos x is sec x[tex] \implies \mathsf{ \tan x \times \sec x }[/tex]
= sec x. tan x
Hence, Proved!
The graphs of two rational functions of f and g are shown. One of them is given by the expression 2-3x/x. Which graph is it? Thanks will mark brainliest
Answer:
It's the left graph, y = f(x)
Step-by-step explanation:
If you find the x-intercepts, you'd solve (2-3x)/x = 0. This means you'd really solve 2-3x=0, which gives you x=3/2.
So the graph must have an x-intercept at (1.5, 0). Only f(x) has that.
[tex]y=\frac{2-3x}{x}[/tex]
Vertical asymptote[tex]\Rightarrow x=0[/tex]
[tex]2-3x=0\\\Rightarrow 3x=2\\\Rightarrow x=\frac{2}{3}[/tex]
Zeroes [tex]x=\frac{2}{3}[/tex]
[tex]\Rightarrow[/tex]graph cuts [tex]x-axis[/tex] at [tex]x=\frac{2}{3}[/tex]
Horizontal asymptote[tex]=\frac{coefficient \ of \ higest \ degree \ term \ in \ numerator}{coefficient \ of \ higest \ degree \ term \ in \ denominator}[/tex]
[tex]y=\frac{-3}{1}[/tex]
[tex]=-3[/tex]
Horizontal asymptote[tex]y=-3[/tex]
[tex]\therefore[/tex] Given graph is [tex]y=f(x)[/tex]
Anne goes out to buy lunch every Friday. On average she spends around $18 each time. How much money can she save in one year if she stops going out for lunch each week?
Find the value if f(x) = -3x -8 and g(x) = x2 + 3. f(-3) =
Step-by-step explanation:
f(x) = -3x - 8
f(-3) = -3(-3) - 8
f(-3) = 9 - 8
f(-3) = 1
help!! !,
is it right or not
Answer:
No
Step-by-step explanation:
The answer is to find the sum of each number, because factors are pulling out from total numbers, but when multiplying you don't need to pull out anything so it would be number
Yep!!! Your correct
Please help xxxxxxxx
Answer:
a. [tex]\bold{45000\times \:10^7}[/tex]b. [tex]\bold{3500}[/tex]Step-by-step explanation:
a. [tex]\left(5\times \:10^3\right)\left(9\times \:10^7\right)[/tex]
[tex]5\times 10^3 = 5000\\\\5000\times \:9\times \:10^7[/tex]
[tex]\mathrm{Multiply\:the\:numbers:}\:5000\times \:9=45000[/tex]
[tex]=45000\times \:10^7[/tex]
b. [tex]\left(7\times 10^5\right)\div \left(2\times 10^2\right)[/tex]
[tex]\left(7\times 10^5\right)\div \left(2\times 10^2\right)=\frac{7\times \:10^5}{2\times \:10^2}[/tex]
[tex]\frac{10^5}{10^2} = 10^3[/tex]
[tex]\frac{7\times \:10^3}{2}[/tex]
[tex]\mathrm{Factor}\:\: 10^3 : 2^3\times5^3[/tex]
[tex]\frac{7\times \:2^3\times \:5^3}{2}[/tex]
[tex]\frac{2^3}{2}=2^2[/tex]
[tex]7\times \:2^2\times \:5^3=3500[/tex]
Solve for x x^2 + 6x + 1 = 0
Answer:
x = -.1715 ≈ - .172 or x = -5.83
Step-by-step explanation:
x² + 6x + 1 = 0
x² + 6x = -1
Complete the square Add to both sides (1/2 of the x-term, then square it.)
x² + 6x + 9 = -1 + 9
(x + 3)(x + 3) = 8
(x + 3)² = 8
[tex]\sqrt{(x + 3)^{2}[/tex] = [tex]\sqrt{8}[/tex]
x + 3 = ± [tex]\sqrt{8}[/tex]
x = -3 ± [tex]\sqrt{8}[/tex]
x = -3 + [tex]\sqrt{8}[/tex] or x = -3 - [tex]\sqrt{8}[/tex]
x = -.1715 ≈ - .172 or x = -5.83
Using the appropriate Algebraic identity evaluate the following:(a²b - c)²
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
Answer:
Below.
Step-by-step explanation:
(a^2b - c)^2
= (a^2b - c)(a^2b - c)
= a^4b^2 - a^2bc - a^2bc + c^2
= a^4b^2 - 2a^2bc + c^2.
find the value of 4x-6y when x=3 and y= -2
Answer:
here the answer is 24
Step-by-step explanation:
answerrrrrerrr issss hereeeeeee
Answer:
0
Step-by-step explanation:
4 multiply by x(3) = 12
6 multiply by y(2) = 12
12 -12 =0
Teresa is maintaining a camp fire. She can keep the fire burning for 4 hours with 6 logs. She wants to know how
many logs (g) she needs to keep the fire burning for 18 hours. She assumes all logs are the same.
How many logs does Teresa need to maintain the fire for 18 hours?
Answer:
27
Step-by-step explanation:
6/4 = 1.5
1.5 * 18 = 27
write a peacewise function for the graph
please help me
Answer:
[tex]\left \{ {{y=x; \ \ x\le 0} \atop {y=4+ \frac12x;\ \ x>0}} \right.[/tex]
Step-by-step explanation:
If you look at the graph you see that:
before 0, the graph has same y as it has x, or y=x.
after 0, the graph starts at 4, and increases by 1 every 2 steps horizontally, or has a slope of 1/2.
Finally, the 0 has to be included in the blue part of the graph based on where the solid dot is.
find the slope of the line
Answer:
3 i belive 100 pecent tho
Step-by-step explanation:
