g Elimination reaction simulation, Kim had tried to prepare cyclohexene from cyclohexanol using HCl as a catalyst, but he got a weird side product cyclohexyl chloride. Cyclohexyl chloride is formed possibly from the side reaction called A. SN1 substitution reaction B. E2 reaction C. E1 reaction D. SN2 substitution reaction

Answer:

2.89x10⁻⁵M = [HPO₄²⁻]

Explanation:

The equilibrium of H3PO4 in water occurs H2PO4-:

H3PO4(aq) + H2O(l) ⇄ H3O⁺(aq) + H2PO4⁻(aq)

pKa = 2.16. And as pKa = -log Ka; Ka = 10^-2.16

Ka = 6.9183x10⁻³ = [H3O⁺] [H2PO4⁻] / [H3PO4]

As both [H3O⁺] and [H2PO4⁻] comes from the same equilibrium,

[H3O⁺]=[H2PO4⁻] :

[H3O⁺] = X

[H2PO4⁻] = X

[H3PO4] = 0.042 - X

Where X is reaction coordinate

Replacing:

6.9183x10⁻³ = [X] [X] / [0.042 - X]

6.9183x10⁻³ = X² / 0.042 - X

2.905686x10⁻⁴ - 6.9183x10⁻³X - X² = 0

Solving for X:

X = -0.02M. False solution. There is no negative concentration.

X = 0.014M. Right solution

[H2PO4⁻] = 0.014M

In the second equilibrium:

H2PO4⁻(aq) + H2O(l) ⇄ HPO4-(aq) + H3O+(aq)

Based on the same principles of the last equilibrium:

pKa2 = 7.21

Ka2 = 6.166x10⁻⁸ = [HPO4-] [H3O+] / [H2PO4⁻]

[HPO4-] = X

[H3O+] = X

[H2PO4⁻] = 0.014M - X

6.166x10⁻⁸ = X² / [0.014M - X]

8.3623x10⁻¹⁰ - 6.166x10⁻⁸X - X² = 0

Solving for X:

X = -0.0000289485. False solution.

X =

Answer:

108.6 g

Explanation:

First we use the PV=nRT formula to calculate the number of nitrogen moles:

Inputting the data:

Then we convert 2.5 moles of N₂ into moles of NaN₃, using the stoichiometric coefficients of the balanced reaction:

Finally we convert 1.67 moles of NaN₃ into grams, using its molar mass:

The question is incomplete, the complete question his;

Which straight chain alkane below would you predict to be the most viscous? Why? All are liquids exhibiting the general bonding pattern CH3-(CH2)n-CH3

C9H20

C10H22

C5H12

C6H14

C12H26

Answer:

C12H26

Explanation:

Generally, the viscosity of a liquid increases with increase in molecular mass of the substance.

Liquids of high molecular mass do not flow easily. This means that they posses high viscosity.

Thus, since C12H26 has the highest molecular mass among the options given in the question, C12H26 exhibits the greatest viscosity.

Answer:

The pKa of an acid can be determined through titration with a strong base.

Gradually increase the volume of the base, stopping before the equivalence point is reached.

The pKa of the acid is equal to the pH at the midway volume to the equivalence point.

Explanation:

An acid HA dissociates in water as follows:

HA ⇄ H⁺ + A⁻      Ka

So, it produces hydrogen ions (H⁺) and a conjugate base (A⁻). The concentrations of HA, H⁺ and A⁻ at equilibrium determine the constant Ka. The pKa is calculated as:

pKa = -log Ka

The relationship between the pH of the solution and the pKa of the acid is described by the Henderson-Hasselbalch equation:

pH = pKa + log ([A⁻]/[HA])

The pKa can be experimentally determined by acid-base titration, in which a strong base is added to the acid solution. As the base is added, the acid HA is neutralized and the conjugate base A⁻ is formed. Thus, the concentration of the acid ([HA]) increases and the concentration of the conjugate base ([A⁻] decreases. The equivalence point is reached when the total amount of acid is neutralized with the added base. Before reaching the equivalence point, at the halfway point, half of the acid is neutralized and converted into the conjugate base. Thus:

[A-] = [HA] ⇒ log [A-]/[HA] = log 1 = 0 ⇒ pH = pKa

We measure the pH at that point and it is equal to the pKa of the acid.

Answer:

The lipid bilayer made up of Palmitic acid will have a higher melting transition temperature

Explanation:

The one with a higher melting transition temperature is the lipid layer with a higher melting temperature

Melting temperature of palmitoleic acid = -0.5°C

Melting temperature of palmitic acid = 62.9°C

Hence the lipid bilayer made up of Palmitic acid will have a higher melting transition temperature

Answer:

Determining the Slope on a p-t Graph. It was learned earlier in Lesson 3 that the slope of the line on a position versus time graph is equal to the velocity of the object. ... If the object has a velocity of 0 m/s, then the slope of the line will be 0 m/s. The slope of the line on a position versus time graph tells it all.

Explanation:

#carryonlearning

Answer:

2 Cu + O2 → 2 CuO

This is an oxidation-reduction (redox) reaction:

2 Cu0 - 4 e- → 2 CuII

(oxidation)

2 O0 + 4 e- → 2 O-II

(reduction)

Cu is a reducing agent, O2 is an oxidizing agent.

Answer:

CH4< CH4I< NaCl

Explanation

NaCl has the boiling point of 1,413°C ( 2,575°F )

CH3I has a boiling point of 42°C ( 107°F )

CH4 has the boiling point of -161.6°C ( -258.9°F )

Answer:

a) Covalent bonds

b) Covalent and ionic bonds

c) Covalent bonds

d) Covalent bonds

Explanation:

Metals and non-metals form ionic bonds (electrons are transferred), whereas nonmetals and nonmetals form covalent bonds.

Identify whether the compound contains ionic bonds, covalent bonds, or both.

a) CBr₄. C and Br are nonmetals. Thus, they form covalent bonds.

b) copper(II) sulfate. Sulfate contains S and O (nonmetals), which are bonded through covalent bonds. Sulfate is bonded to copper (metal) through an ionic bond.

c) N₂O₃. N and O are nonmetals. Thus, they form covalent bonds.

d) phosphorous trichloride. P and Cl are nonmetals. Thus, they form covalent bonds.

i think .117018

now to get to the 20charaeactrs minimum.

Answer:

If the gas is at STP, THE 1 mole is 22.4 liters.

Explanation:

Answer:

Danger

Explanation:

Answer:

10.5 × 10^5 M

Explanation:

E°cell = E°cathode - E°anode

E°cell = 0.85 - (-0.74) = 1.59 V

From Nernst's equation;

Ecell = E°cell - 0.0592/n log Q

1.499 = 1.59 - 0.0592/6 log [Cr^3+]/6.35x10^-4

1.499 - 1.59 = - 0.0592/6 log [Cr^3+]/6.35x10^-4

-0.091 = -0.00987 log [Cr^3+]/6.35x10^-4

-0.091/ -0.00987 = log [Cr^3+]/6.35x10^-4

9.22 = log [Cr^3+]/6.35x10^-4

Antilog (9.22) = [Cr^3+]/6.35x10^-4

1.66 × 10^9 = [Cr^3+]/6.35x10^-4

[Cr^3+] = 1.66 × 10^9 × 6.35x10^-4

[Cr^3+] = 10.5 × 10^5 M

Answer:

high melting point

Explanation:

The filament of a bulb is often heated to very high temperatures as the bulb is in operation.

Many times, electric bulbs may have to be on for a whole day and they may reach temperatures that are outrageously high in the process.

The material of the filament must have a very high melting point so that it doesn't melt while the bulb is still in operation.

Answer:

Actually the answer is High Vapor pressure

Explanation:

Acids have sour taste, low pH and dissolves metals.

The list that describes the characteristics of an acid is that it has sour taste, low pH, and dissolves metals.

An acid is a chemical substance that has the ability to donate hydrogen ions when involved in a chemical reaction.

The following are the characteristics or features of an acid:

Therefore, the list that describes the characteristics of an acid is that it has sour taste, low pH, and dissolves metals.

Learn more about acids here:

https://brainly.com/question/1302816

Answer:

The guy above used photoshop here is the actual answer.

Explanation:

The true statements about molarity and percent by mass is that they are the different units of concentration

Concentration of any substance present in any solution guves idea about their relative amount in that and it can de described in terms of molarity and percent by mass.

Hence, molarity and percent by mass are the different units of concentration and directly related to each other.

To know more about molarity & percent mass, visit the below link:

https://brainly.com/question/26150306

Answer:

E°(Ag⁺/Fe°) = 0.836 volt

Explanation:

3Ag⁺ + 3e⁻ => Ag°;            E° = +0.800 volt

Fe° => Fe⁺³ + 3e⁻ ;             E° = -0.036 volt

_________________________________

Fe°(s) + 3Ag⁺(aq) => Fe⁺³(aq) + 3Ag°(s) ...    

E°(Ag⁺/Fe°) = E°(Ag⁺) - E°(Fe°) = 0.800v - ( -0.036v) = 0.836 volt

Different boiling point.

Because in distillation the substance with lower boiling point is evaporated, leaving the other material(s).

Distillation relies on different boiling points to separate out parts of a solution.

Answer: The mass in [tex]3.75 \times 10^{21}[/tex] atoms of zinc is 0.405 g.

Explanation:

Given: Atoms of zinc = [tex]3.75 \times 10^{21}[/tex]

It is known that 1 mole of every substance contains [tex]6.022 \times 10^{23}[/tex] atoms. So, the number of moles in given number of atoms is as follows.

[tex]Moles = \frac{3.75 \times 10^{21}}{6.022 \times 10^{23}}\\= 0.622 \times 10^{-2}\\= 0.0062 mol[/tex]

As moles is the mass of a substance divided by its molar mass. So, mass of zinc (molar mass = 65.39 g/mol) is calculated as follows.

[tex]Moles = \frac{mass}{molar mass}\\0.0062 mol = \frac{mass}{65.39 g}\\mass = 0.405 g[/tex]

Thus, we can conclude that the mass in [tex]3.75 \times 10^{21}[/tex] atoms of zinc is 0.405 g.

Answer: the molecular formula of  trioxide is ClOClO3 or Cl2O4

hope its helps you.

keep smiling be happy stay safe

Answer:

1.875 × 10^6 Hz

Explanation:

From the wave formula;

V= λf

λ= wavelength of the radio waves

f= frequency of the radio waves

f= v/λ

Since radio waves is an electromagnetic wave, it possesses the speed of light which is 3 × 10^8 m/s

f= 3 × 10^8 m/s/160 m

f= 1.875 × 10^6 Hz

Answer:

Kp=Kc *(RT)+-3

Explanation:

The relation between Kp and Kc is given below:

Where,

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant , R = 0.082057 L atm.mol⁻¹K⁻¹

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

Δn = (0)-(2+1) = -3

Thus, Kp is:

Kp=Kc *(RT)+-3

Explanation:

This is a decomposition reaction. Firstly, you will want to write the chemical equation out and balance it.

[tex]2Hg_2O->4Hg+O_2[/tex] (The -> is supposed to be an arrow, sorry!)

We see that there's only 1mol of Oxygen made in the products, we can do some simple math to solve for the amount of grams of Oxygen produced according to the amount of the reactant (Hg2O).

[tex]32.2gHg_2O*\frac{1molHg_2O}{417.18gHg_2O}*\frac{1molO_2}{2molHg_2O}*\frac{32gO_2}{1molO_2}[/tex]

I want to break this down, just in case:

The 417.18gHg2O is the molecular mass of the molecule (so I doubled Hg and added 16 to it to get this number).

As we can see in the chemical equation, 1mol Hg2O produces 2mol O because Oxygen is a diatomic molecule (so there will always be two of it when it's by itself).

And finally, in 1mol O2 there are 32g of O2.

** When you do math like this, always make sure that all of your units cancel out except for the units you're looking for. For example, here we're looking for the grams of Oxygen, so after everything else cancels out, we should only have grams O2.

So, 1.23gO2 should be your answer.

Answer:

Explanation:

Answer is D 2,5-dimethylheptanal

You should accern the lowest possible number close to the parent name

Answer:

Explanation:

hope it heloed

Answer:

E = 8085 kJ

Explanation:

Given that,

The mass of a truck, m = 1500 kg

Height, h = 550 m

We need to find the gravitational potential energy of the truck. It can be calculated as follows :

[tex]E=mgh[/tex]

Put all the values,

[tex]E=1500\times 9.8\times 550\\\\E=8085000\ J\\\\or\\\\E=8085\ kJ[/tex]

So, the gravitational potential energy is 8085 kJ.

Answer:

molar heat of combustion = -5156 *10³ kJ/mol

Explanation:

A quantity of 1.435 g of naphthalene , was burned in a constant-volume bomb calorimeter. Consequently, the temperature of the water rose from 20.28oC to 25.95oC If the heat capacity of the bomb plus water was 10.17 kJ/°C, calculate the heat of combustion of naphthalene on a molar basis; that is, find the molar heat of combustion.

Step 1: Data given

Mass of naphthalene = 1.435 grams

Initial temperature of water = 20.28 °C

Final temperature of water = 25.95 °C

heat capacity of the bomb plus water was 10.17 kJ/°C

Molar mass naphtalene = 128.2 g/mol

Step 2:

Qcal = Ccal * ΔT

⇒with Qcal =the heat of combustion

⇒with Ccal = heat capacity of the bomb plus water = 10.17 kJ/°C

⇒with ΔT = the difference in temperature = T2 - T1 = 25.95 - 20.28 = 5.67°C

Qcal = 10.17 kJ/°C * 5.67 °C

Qcal = 57.7 kJ

Step 3: Calculate moles

Moles naphthalene = 1.435 grams / 128.2 g/mol

Moles naphthalene = 0.01119 moles

Step 4: Calculate the molar heat of combustion

molar heat of combustion = Qcal/ moles

molar heat of combustion = -57.7 kJ/ 0.01119 moles

molar heat of combustion = -5156 *10³ kJ/mol

Refer to the attachment.

Hope this helps you...

Answer:

1.2 L

Explanation:

Step 1: Write the balanced equation

Mg + 2 HCl ⇒ MgCl₂ + H₂

Step 2: Calculate the moles corresponding to 2.3 g of Mg

The molar mass of Mg is 24.31 g/mol.

2.3 g × 1 mol/24.31 g = 0.095 mol

Step 3: Calculate the moles of H₂ produced

0.095 mol Mg × 1 mol H₂/1 mol Mg = 0.095 mol H₂

Step 4: Calculate the volume occupied by the hydrogen

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T/P

V = 0.095 mol × (0.0821 atm.L/mol.K) × 298 K/2 atm = 1.2 L