f(x) = 2x + c
g(x) = cx + 7
fg(x) = 4x + d
C and d are constants.
Work out the value of d.

May someone help me pleaseeee

Answers

Answer 1

Answer:

c=2, d=16

Step-by-step explanation:

Answer 2

The value of c is 2 and value of d is 16 when f(x) = 2x + c, g(x) = cx + 7 and fg(x) = 4x + d

What is a function?

A relation is a function if it has only One y-value for each x-value.

Given,

f(x) = 2x + c...(1)

g(x) = cx + 7..(2)

fg(x) = 4x + d..(3)

We need to find the values of c and d

fg(x) = 2(cx+7) + c

Apply distributive property

fg(x) =2cx+14+c...*

Now compare * with equation 3

2cx=4x

2c=4

Divide both sides by 2

c=2

and 14+c=d

Substitute c in above equation

14+2=d

d=16

Hence, the value of c is 2 and value of d is 16 when f(x) = 2x + c, g(x) = cx + 7 and fg(x) = 4x + d

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