Frank, Carl, and Vinny started a lawn-mowing business over the summer. This table shows how many lawns each worker mowed during the summer months.Display the data in matrix W with rows indicating workers. What is element w11?

Possible Answers:
15
17
28
24

Answer:

It took Chau 5 hours, 52 minutes, and 30 seconds to clean both rooms.

Step-by-step explanation:

Given that Chau took 5 3/8 hours to clean the bedroom, and then he took a 1/2 to clean the den, to determine how much total time did he take to clean two rooms the following calculation must be performed:

5 + 3/8 + 1/2 = X

5 + 0.375 + 0.5 = X

5.875 = X

0.875 = 7/8

60/8 x 7 = 52.5

Therefore, it took Chau 5 hours, 52 minutes, and 30 seconds to clean both rooms.

Answer:

3:8

Step-by-step explanation:

i will gadit

that only

Answer:

(-3,5),(-3,-5),(3,5),(3,-5)

Step-by-step explanation:

i changed my answer :)

Hello!

1) 6/10 × 10/6 × 5/9 = 1/10 × 10 × 5/9 = 1 × 5/9 = 5/9 or 0,5

2) 6/10 × 4/3 × 10/20 = 6 × 4/3 × 1/20 = 2 × 4 × 1/20 = 2 × 1/5 = 2/5 or 0,4

Good luck! :)

Answer:

1) 5/9

2) 2/5

Explanation:

1) 6/10 × 10/6 × 5/9=

Multiply all the denominators and all the numerators then simplify= 300/540 = 5/9

2)  6/10 × 4/3 × 10/20=

Multiply all the denominators and all the numerators then simplify= 240/600 = 2/5

Answer:

The probability would be 1/8.

Step-by-step explanation:

The probability of the spinner landing on an odd number is 1/2, and the probability of the spinner landing on a number greater than 8 is 1/4. So we multiply those two probabilites to get our answer 1/8.

Answer:

The 99% confidence interval for the difference in the two proportions is (-0.0247, 0.2833).

Step-by-step explanation:

Before building the confidence interval, we need to understand the Central Limit Theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

A BYU-Idaho professor took a survey of his classes and found that 82 out of 90 people who had served a mission had personally met a member of the quorum of the twelve apostles.

This means that:

[tex]p_S = \frac{82}{90} = 0.9111[/tex]

[tex]s_S = \sqrt{\frac{0.9111*0.0888}{90}} = 0.045[/tex]

Of the non-returned missionaries that were surveyed 86 of 110 had personally met a member of the quorum of the twelve apostles.

This means that:

[tex]p_N = \frac{86}{110} = 0.7818[/tex]

[tex]s_N = \sqrt{\frac{0.7818*0.2182}{110}} = 0.0394[/tex]

Distribution of the difference:

[tex]p = p_S - p_N = 0.9111 - 0.7818 = 0.1293[/tex]

[tex]s = \sqrt{s_S^2+s_N^2} = \sqrt{0.045^2+0.0394^2} = 0.0598[/tex]

Calculate a 99% confidence interval for the difference in the two proportions.

The confidence interval is:

[tex]p \pm zs[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

99% confidence level

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].

The lower bound of the interval is:

[tex]p - zs = 0.1293 - 2.575*0.0598 = -0.0247[/tex]

[tex]p + zs = 0.1293 + 2.575*0.0598 = 0.2833[/tex]

The 99% confidence interval for the difference in the two proportions is (-0.0247, 0.2833).

Answer: 332 cubic inches

Step-by-step explanation:

You can eliminate 69 and 99 as those answers don't make any sense. This leaves you with 703 and 332.

It says the wall of the pipe is 1.25 inches thick so you multiply that by 2 and subtract it by the diameter to get the insider diameter of 5.5

Now you just use the equation V = (3.14)(r^2)(14) where the radius is half of 5.5.

So to finalize the equation you get V = (3.14)(5.5)^2(14) which comes out to 332 cubic inches

The best choice is 332 cubic inches.

69 cubic inches and 99 cubic inches are less and 703 cubic inches is a large approximation.

Diameter = d= 8 inches

Height= Length = l= 14 inches

Thickness= 1.25 inches

Outer Radius= R= diameter/2= 8/2=4 inches

Inner radius = r= Radius - thickness

                            = 4- 1.25= 2.75 inches

Volume of the cylinder = Area × length

                                      = π r²× l

                                       = 22/7 × (2.75)² × 14

                                          = 332. 616 inches cube

So the best answer is 332 cubic inches

https://brainly.com/question/21067083

Answer:

below

Step-by-step explanation:

A AND C is the right option

congruent angles are angles with exactly the same measure

Answer:  Choice B)  [tex]\sqrt{2}[/tex]

Work Shown:

[tex]\sec^2(\theta) = \tan^2(\theta) + 1\\\\\sec^2(\theta) = (\tan(\theta))^2 + 1\\\\\sec^2(\theta) = (-1)^2 + 1\\\\\sec^2(\theta) = 2\\\\\sec(\theta) = \sqrt{2}\\\\[/tex]

Note: secant is positive in quadrant Q4, when theta is between 3pi/2 radians and 2pi radians (270 degrees and 360 degrees). So that's why we don't consider the minus form of the plus minus.

(4) y = (3 - 2x)³ + 24x

Use the power and chain rules:

dy/dx = 3 (3 - 2x)² d/dx [3 - 2x] + 24

dy/dx = 3 (3 - 2x)² (-2) + 24

dy/dx = -24x ² + 72x - 30

(5) y = 54x - (2x - 7)³

Same basic procedure:

dy/dx = 54 - 3 (2x - 7)² d/dx [2x - 7]

dy/dx = 54 - 3 (2x - 7)² (2)

dy/dx = -24x ² + 168x - 240

Answer:

10 + 8 + 10 + 10 + 10 + 10 + 8 + 8 + 6 + 6

Answer:

2 = x          -7 = x

Step-by-step explanation:

f(x) = (x - 2)(x + 7)

y  = (x - 2)(x + 7)

Set y = 0

0 = (x - 2)(x + 7)

Using the zero product property

0 = x-2    0 = x+7

2 = x          -7 = x

Answer:

Zeros happen when f(x) = 0. There are two zeros in the given function:

Therefore solve both equations above and you'll get:

Answer:

a. 2

b. The 90% confidence interval for the difference between the two population means is (1.02, 2.98).

c. The 95% confidence interval for the difference between the two population means is (0.83, 3.17).

Step-by-step explanation:

Before solving this question, we need to understand the central limit theorem and the subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Sample 1:

[tex]\mu_1 = 13.6, s_1 = \frac{2.2}{\sqrt{50}} = 0.3111[/tex]

Sample 2:

[tex]\mu_2 = 11.6, s_2 = \frac{3}{\sqrt{35}} = 0.5071[/tex]

Distribution of the difference:

[tex]\mu = \mu_1 - \mu_2 = 13.6 - 11.6 = 2[/tex]

[tex]s = \sqrt{s_1^2+s_2^2} = \sqrt{0.3111^2+0.5071^2} = 0.595[/tex]

a. What is the point estimate of the difference between the two population means?

Sample difference, so [tex]\mu = 2[/tex]

b. Provide a 90% confidence interval for the difference between the two population means.

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.9}{2} = 0.05[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.05 = 0.95[/tex], so Z = 1.645.

The margin of error is:

[tex]M = zs = 1.645(0.595) = 0.98[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 2 - 0.98 = 1.02

The upper end of the interval is the sample mean added to M. So it is 2 + 0.98 = 2.98

The 90% confidence interval for the difference between the two population means is (1.02, 2.98).

c. Provide a 95% confidence interval for the difference between the two population means.

Following the same logic as b., we have that [tex]Z = 1.96[/tex]. So

[tex]M = zs = 1.96(0.595) = 1.17[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 2 - 1.17 = 0.83

The upper end of the interval is the sample mean added to M. So it is 2 + 1.17 = 3.17

The 95% confidence interval for the difference between the two population means is (0.83, 3.17).

Answer:

The number of newborns who weighed between 1614 grams and 5182 grams was of 586.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The mean weight was 3398 grams with a standard deviation of 892 grams.

This means that [tex]\mu = 3398, \sigma = 892[/tex]

Proportion that weighed between 1614 and 5182 grams:

p-value of Z when X = 5182 subtracted by the p-value of Z when X = 1614.

X = 5182

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{5182 - 3398}{892}[/tex]

[tex]Z = 2[/tex]

[tex]Z = 2[/tex] has a p-value of 0.9772

X = 1614

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{1614 - 3398}{892}[/tex]

[tex]Z = -2[/tex]

[tex]Z = -2[/tex] has a p-value of 0.0228

0.9772 - 0.0228 = 0.9544.

Out of 614 babies:

0.9544*614 = 586

The number of newborns who weighed between 1614 grams and 5182 grams was of 586.

Answer:

A, B, and E apply

Step-by-step explanation:

One thing we can do is to make everything in the same format, under one square root, with no non-square roots.

First, we can say that 6 is equal to √36 as 6² =36, and 6 ≥ 0. Therefore, 6√3 = √36 * √3 = √108

For A, √3 * √36 = √108, so this applies

For B, √18 * √6 = √108, so this applies

For C, 108² = √something bigger than 108 = √11664, so this does not apply

For D, √54 ≠ √108, so this does not apply

For E, √108 = √108, so this applies

For F, √3 * √6 = √18, so this does not apply

Answer:

0.5679

Step-by-step explanation:

From. The table Given above :

The probability of female Given an advanced degree ;

P(F|A) = p(FnA) / p(A)

From the table, p(FnA) = 322

P(Advanced degree), P(A) = (245 + 322) = 567

Hence,

P(F|A) = p(FnA) / p(A) = 322 / 567 = 0.5679

Step-by-step explanation:

here's the answer to your question

Answer:

sorry my bad bro I have no clue

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Since point P is the center of dilation, it doesn't move. (It is "invariant.") The other points on the figure move to 1/4 of their original distance from P. On this diagram, it is convenient that the distances are all multiples of 4 units, so dividing by 4 is made easy.

Answer:

1/425

Step-by-step explanation:

The first card can be any card, so we don’t have to evaluate the probability.

Now we can suppose that the exit card is a two

- For the second card we have 3/51 of possibilities that is a 2 = 1/17

- For the third card we have 2/50 of possibilities that is a 2 = 1/25

1/17 * 1/25 = 1/425

Answer:

Assessing the association between supplemental vitamin A exposure and mortality and morbidity for measles:

Regarding the relative risk, the correct statement is:

a. Exposure to vitamin A appears to protect against morbidity and mortality for measles.

Step-by-step explanation:

Relative risk for incidence of measles = 0.75

Relative risk for measles mortality = 0.5

Relative risk for mortality and morbidity for measles = 0.375 (0.75 * 0.5)

The combined relative risk is less than 50%

The association is weak because RR is less than 1.

Therefore, there is no association between supplemental vitamin A exposure and mortality and morbidity for measles.

The three modes are 5, 12, and 150 since they occur the most times and they tie one another in being the most frequent (each occurring 3 times).

Only the 7 and 8 occur once each, and aren't modes. Everything else is a mode. It's possible to have more than one mode and often we represent this as a set. So we'd say the mode is {5, 12, 150} where the order doesn't matter.

9514 1404 393

Answer:

  a = 94.8, B = 29.3°, C = 31.7°

Step-by-step explanation:

Side 'a' can be found using the Law of Cosines:

  a² = b² +c² -2bc·cos(A)

  a = √(2809 +3249 -6042·cos(119°)) ≈ √8987.22 ≈ 94.8

Then one of the other angles can be found from the Law of Sines.

  sin(C)/c = sin(A)/a

  C = arcsin(c/a·sin(A)) ≈ arcsin(0.525874) ≈ 31.7°

Then the remaining angle can be found to be ...

  B = 180° -A -C = 180° -119° -31.7° = 29.3°

__

The solution is a ≈ 94.8, B ≈ 29.3°, C ≈ 31.7°.

Answer:

   =(s^2 - t^2)/4

Step-by-step explanation:

a + b = s and a - b = t,

Add the two equations together

a + b = s

a - b = t

----------------

2a = s+t

a = (s+t)/2

Subtract the two equations

a + b = s

- a + b = -t

-------------------

2b =(s-t)

b = (s-t)/2

We want to find ab

ab = (s+t)/2 *  (s-t)/2

FOIL

    =(s^2 - t^2)/4

Answer:

10:3

Step-by-step explanation:

Make 2 1/2 an improper fraction, you will get 5/2. You dont have to do anything to the 3/4.

For you to find the ratio of an fraction, you have to take the numerator but the denominator has to be the same.

So make 5/2 to a 10/4.

Take the numerator 10 & 3.

Your answer will be 10:3

No problem.

Solution :

Group   Before     After

Mean    693.75    743.75

Sd         155.37     143.92

SEM        54.93     50.88

n              8            8

Null hypothesis : The preparation course not effective.

[tex]$H_0: \mu_d = 0$[/tex]

Alternative hypothesis : The preparation course is effective in improving the exam scores.

[tex]$H_a : \mu_d>0$[/tex]  (after -  before)

Answer:

3.1 gallons

Step-by-step explanation:

To solve this, we need to figure out how many gallons of gas go into 72 miles. We know 23 miles is equal to one gallon of gas, and given that the ratio of miles to gas stays the same, we can say that

miles of gas / gallons = miles of gas / gallons

23 miles / 1 gallon = 72 miles / gallons needed to go to Bob's mother's house

If we write the gallons needed to go to Bob's mother's house as g, we can say

23 miles / 1 gallon = 72 miles/g

multiply both sides by 1 gallon to remove a denominator

23 miles = 72 miles * 1 gallon /g

multiply both sides by g to remove the other denominator

23 miles * g = 72 miles * 1 gallon

divide both sides by 23 miles to isolate the g

g = 72 miles * 1 gallon/23 miles

= 72 / 23 gallons

≈ 3.1 gallons

Answer:

(0 ; 3)

Step-by-step explanation:

hello :

the midpoint of the line segment is : ((-2+2)/2 ;(-2+8)/2 )

(0 ; 3)