Answer:
Decison region :
Reject H0 : if χ² > 6.251
12.229
Step-by-step explanation:
Given :
Manufacturer A B C D
Unacceptable 29 17 9 22
Acceptable 171 183 191 178
Total 200 200 200 200
H0: There is no relationship between quality and manufacturer.
H1: There is a relationship.
Testing using the goodness of fit :
Chisquare = (observed - Expected)² / Expected
Expected Values:
19.25 19.25 19.25 19.25
180.75 180.75 180.75 180.75
Chi-Squared Values:
4.93831 0.262987 5.45779 0.392857
0.525934 0.0280083 0.581259 0.0418396
χ² = 4.93831 + 0.262987 + 5.45779 + 0.392857
+ 0.525934 + 0.0280083 + 0.581259 + 0.0418396 = 12.229
Degree of freedom, df = (4-1)(2-1) = 3*1= 3
The critical value,
χ² at 0.10, 3 = 6.251
Decison region :
Reject H0 : if χ² > 6.251
Reject H0 : 12.229 > 6.251
If the cutoff Z score on the comparison distribution is 2.33 and the sample value has a score of 2.35 on the comparison distribution, the correct decision is to:____.
A) fail to reject the null hypothesis.
B) reject the null hypothesis.
C) accept the researc hypothesis.
D) reject the research hypothesis.
Answer:
B) reject the null hypothesis.
Step-by-step explanation:
The variance of the scores on a skill evaluation test is 143,641 with a mean of 1517 points. If 343 tests are sampled, what is the probability that the mean of the sample would differ from the population mean by less than 36 points
Answer:
The probability that the mean of the sample would differ from the population mean by less than 36 points=0.9216
Step-by-step explanation:
We are given that
The variance of the scores on a skill evaluation test=143,641
Mean=1517 points
n=343
We have to find the probability that the mean of the sample would differ from the population mean by less than 36 points.
Standard deviation,[tex]\sigma=\sqrt{143641}[/tex]
[tex]P(|x-\mu|<36)=P(|\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}|<\frac{36}{\frac{\sqrt{143641}}{\sqrt{343}}})[/tex]
[tex]=P(|Z|<\frac{36}{\sqrt{\frac{143641}{343}}})[/tex]
[tex]=P(|Z|<1.76)[/tex]
[tex]=0.9216[/tex]
Hence, the probability that the mean of the sample would differ from the population mean by less than 36 points=0.9216
Find the factors of function f, and use them to complete this statement. f(x)=2x^(4)-x^(3)-18x^(2)+9x
From left to right, function f has zeros at
Hello,
[tex]f(x)=2x^4-x^3-18x+9x\\\\=x(2x^3-x^2-18x+9)\\\\=x(x^2(2x-1)-9(2x-1))\\\\=x(2x-1)(x^2-9)\\=x(2x-1)(x-3)(x+3)\\[/tex]
Zeros are : 0; 1/2; -3; 3.
The zeros of the function are -3, 0, 1/2 and 3.
The given function is [tex]f(x)=2x^{4} -x^{3} -18x^{2} +9x[/tex].
What are the zeros of a function?Zeros of a function are the points where the graph of the function meets the X-axis i.e., at the solutions of f(x) = 0.
Now, factorise the given function, that is f(x)=x(2x³-x²-18x+9).
=x[x²(2x-1)-9x(2x-1)]
=x(2x-1)(x²-9)
=x(2x-1)(x+3)(x-3)
= -3, 0, 1/2, 3
Therefore, the zeros of the function are -3, 0, 1/2 and 3.
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For each of the following, assume that the two samples are obtained from populations with the same mean, and calculate how much difference should be expected, on average, between the two sample means. Each sample has n =4 scores with s^2 = 68 for the first sample and s^2 = 76 for the second. (Note: Because the two samples are the same size, the pooled variance is equal to the average of the two sample variances).
a) 4.24.
b) 0.24.
c) 8.48.
d) 6.00.
Next, each sample has n=16 scores with s^2 = 68 for the first sample and s^2 = 76 for the second.
a) 0.12.
b) 2.12.
c) 4.24.
d) 3.00.
Answer:
d)6.00
d)3.00
Step-by-step explanation:
We are given that
n=4 scores
[tex]S^2_1=68[/tex]
[tex]S^2_2=76[/tex]
We have to find the difference should be expected, on average, between the two sample means.
[tex]S_{M_1-M_2}=\sqrt{\frac{S^2_1}{n_1}+\frac{S^2_2}{n_2}}[/tex]
[tex]n_1=n_2=4[/tex]
Using the formula
[tex]S_{M_1-M_2}=\sqrt{\frac{68}{4}+\frac{76}{4}}[/tex]
[tex]S_{M_1-M_2}=\sqrt{\frac{68+76}{4}}[/tex]
[tex]S_{M_1-M_2}=\sqrt{36}=6[/tex]
Option d is correct.
Now, replace n by 16
[tex]n_1=n_2=16[/tex]
[tex]S_{M_1-M_2}=\sqrt{\frac{68}{16}+\frac{76}{16}}[/tex]
[tex]S_{M_1-M_2}=\sqrt{\frac{68+76}{16}}[/tex]
[tex]S_{M_1-M_2}=\sqrt{9}=3[/tex]
Option d is correct.
The population standard deviation for the temperature of beers found in Scooter's Tavern is 0.26 degrees. If we want to be 90% confident that the sample mean beer temperature is within 0.1 degrees of the true mean temperature, how many beers must we sample
Answer:
19 beers must be sampled.
Step-by-step explanation:
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1 - 0.9}{2} = 0.05[/tex]
Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].
That is z with a pvalue of [tex]1 - 0.05 = 0.95[/tex], so Z = 1.645.
Now, find the margin of error M as such
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
The population standard deviation for the temperature of beers found in Scooter's Tavern is 0.26 degrees.
This means that [tex]\sigma = 0.26[/tex]
If we want to be 90% confident that the sample mean beer temperature is within 0.1 degrees of the true mean temperature, how many beers must we sample?
This is n for which M = 0.1. So
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
[tex]0.1 = 1.645\frac{0.26}{\sqrt{n}}[/tex]
[tex]0.1\sqrt{n} = 1.645*0.26[/tex]
[tex]\sqrt{n} = \frac{1.645*0.26}{0.1}[/tex]
[tex](\sqrt{n})^2 = (\frac{1.645*0.26}{0.1})^2[/tex]
[tex]n = 18.3[/tex]
Rounding up:
19 beers must be sampled.
Find the quotient of the following
Answer:
you simply have to do ide the coefficients and subtract the power
Which answers describe the shape below? Check all that apply.
A. Square
B. Quadrilateral
C. Rhombus
D. Trapezoid
E. Rectangle
F. Parallelogram
Answer:
b and f
Step-by-step explanation:
Christian and Tanae both leave Disneyland at the same time. Christian travels north at 65 mph. Tanae travels south at 55 mph. How long will it take them to be 540 miles apart? Which of the following equations would you use to solve this word problem?
65t + 55(t − 1) = 540.
65t + 55t = 540.
65t + 55(t + 1) = 540.
None of these choices are correct.
Answer:
Step-by-step explanation:
B looks like it would work.
You add speeds * time when you are travelling in opposite directions.
I don't know why you would add or subtract 1 as in A and C
120 * t = 540
t = 540/120
t = 4.5 hours.
So after 4.5 hours they are 540 miles apart.
Answer:
b
Step-by-step explanation:
How do I solve this?
The answer for the first line segment : (-3,-7) (-4,0)
The answer for 2nd line segment is :(-3,8) (-9,-5)
Step-by-step explanation:
Let do line segment QR and ST. first.
Step 1: Find a line that contains a points that is perpendicular to the line of reflection
"A reflection of a pre image and new image is perpendicular to the line of reflection.
This means for points Q,S,T and R, there is a line that. contains one point that is perpendicular to the line of reflection.
A line that is perpendicular to the line of reflection is the negative reciprocal of the slope so this means all 4 lines must be on a different slopes but the slopes must be 1/2.
To simplify, things, here are the lines that will all 4 points be on
Point R will be on line y=1/2x-11/2Point Q will be on line y=1/2x+2Point S will be on line y=1/2x+19/2Point T will be on line y=1/2x-1/2Step 2: Find a point where both the line and line of reflection intersect at.
Now we need to find a line where both the line of reflections and the 4 lines will intersect at separately.
The line with Point R will intersect with the line of reflection at point (1,-5)The line with Point Q will intersect with line of reflection at Point (-2,1)The line with Point S will intersect at point (-5,7)The line worth Point T will intersect at Point(-1,-1).Step 3: Find the endpoints given the midpoint and the originally endpoint.
A reflection per and new image is equidistant from the point of reflection. So we. an say that the point where the line intersect is the midpoint of the pre and new image.
Using this info,
The endpoint for R prime is (-3, -7).The endpoint for Q prime is (-4,0). The endpoint of S prime is (-3,8).The endpoint of T prime is (-9,-5).Connect R prime and Q prime. And that the new line segments
Connects S prime and T prime and that the new line segments.
x(x-y) - y( x- y) simplify
Step-by-step explanation:
x²-xy-xy+y²
x²+2xy+y²
hope it helps
A shipment of 50 precision parts including 4 that are defective is sent to an assembly plant. The quality control division selects 10 at random for testing and rejects the entire shipment if 1 or more are found defective. What is the probability this shipment passes inspection?
Answer:
0.3968 = 39.68% probability this shipment passes inspection.
Step-by-step explanation:
The parts are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.
Hypergeometric distribution:
The probability of x successes is given by the following formula:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
In which:
x is the number of successes.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this question:
50 parts means that [tex]N = 50[/tex]
4 defective means that [tex]k = 4[/tex]
10 are chosen, which means that [tex]n = 10[/tex]
What is the probability this shipment passes inspection?
Probability that none is defective, so:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 0) = h(0,50,10,4) = \frac{C_{4,0}*C_{46,10}}{C_{50,10}} = 0.3968[/tex]
0.3968 = 39.68% probability this shipment passes inspection.
15. The area of a triangle is 72 in the base is 12 in. Find the height.
Answer:
[tex]hright =12[/tex]
Step-by-step explanation:
----------------------------------------
The formula to find the area of a triangle is [tex]A=\frac{1}{2}bh[/tex] where [tex]b[/tex] stands for the base and [tex]h[/tex] stands for the height.
But we already know the area and the base. So to find the height, let's substitute 72 for [tex]A[/tex] and 12 for [tex]b[/tex], and solve.
[tex]72=\frac{1}{2}(12)(h)[/tex]
[tex]72=6h[/tex]
Here, divide both sides by 6
[tex]12=h[/tex]
--------------------
Hope this is helpful.
Answer:
height = 12
Step-by-step explanation:
.............
What is the y-intercept of the line given by y=4x - 6
Answer:
y= -6
Step-by-step explanation:
the y-intercept is -6, which corresponds to point (0,-6)
remember that you're using the
y=mx+b format of an equation of a line where b is the y-intercept.
Also, if you make x=0, y will be -6.
What is the correct equation for the graph?
tan graph and its tax because tax=0
add 10ft 3in + 3ft 9in + 8ft 10in
Which of the following is not true regarding the flow of information from the adjusted trial balance on the end-of-period spreadsheet?
The correct statement about the flow of information from the adjusted trial balance on the end-of-period spreadsheet is A. The revenue and expense account balances flow into the income statement.
What is an Adjusted Trial Balance?This refers to the general ledger balance after some changes have been done an account balance such as accrued expenses, depreciation, etc.
Therefore, we can see that from the complete information, the statement that is false about the adjusted trial balance on the end-of-period spreadsheet is option A because the revenue and expense account balances does not flow into the income statement.
The other options from the complete text are:
a. The revenue and expense account balances flow into the income statement.b. The asset and liability account balances flow into the retained earnings statement.c. The revenue and expense account balances flow into the retained earnings statement.d. The retained earnings and dividends account balances flow into the balance sheet.
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Please help me >_< will give out brainliest
====================================================
Explanation:
We have an octagon because there are n = 8 sides. The diagram below shows one way to number the sides so you can count them efficiently (without missing any or double counting any).
----------------
Plug n = 8 into the formula below
S = 180(n-2)
S = 180(8-2)
S = 180(6)
S = 1080
The 8 interior angles add up to 1080 degrees.
The average height of a current NBA player is 79 inches with a standard deviation of 3.4 inches. A random sample of 35 current NBA players is taken. What is the probability that the mean height of the 35 NBA players will be more than 80 inches?
Answer:
0.0409 = 4.09% probability that the mean height of the 35 NBA players will be more than 80 inches.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
The average height of a current NBA player is 79 inches with a standard deviation of 3.4 inches.
This means that [tex]\mu = 79, \sigma = 3.4[/tex]
A random sample of 35 current NBA players is taken.
This means that [tex]n = 35, s = \frac{3.4}{\sqrt{35}}[/tex]
What is the probability that the mean height of the 35 NBA players will be more than 80 inches?
This is 1 subtracted by the p-value of Z when X = 80. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{80 - 79}{\frac{3.4}{\sqrt{35}}}[/tex]
[tex]Z = 1.74[/tex]
[tex]Z = 1.74[/tex] has a p-value of 0.9591
1 - 0.9591 = 0.0409
0.0409 = 4.09% probability that the mean height of the 35 NBA players will be more than 80 inches.
Write the range of the function using interval notation.
Given:
The graph of a function.
To find:
The range of the given function using interval notation.
Solution:
Range: The set of y-values or output values are known as range.
From the given graph, it is clear that the function is defined for [tex]0<x<4[/tex] and the values of the functions lie between -2 and 2, where -2 is excluded and 2 is included.
Range [tex]=\{y|-2<y\leq 2\}[/tex]
The interval notation is:
Range [tex]=(-2,2][/tex]
Therefore, the range of the given function is (-2,2].
A plane flying horizontally at an altitude of 2 miles and a speed of 410 mi/h passes directly over a radar station. Find the rate at which the distance from the plane to the station is increasing when it is 5 miles away from the station.
Answer:
[tex]82\sqrt{21}\text{ or approximately 375.77 miles per hour}[/tex]
Step-by-step explanation:
Please refer to the diagram below. R is the radar station and x is the distance from the station to the plane.
We are given that the plane is flying horizontally at an altitude of two miles and at a speed of 410 mph. And we want to find the rate at which the distance from the plane to the station is increasing when it is five miles away from the station.
In other words, given da/dt = 410 and x = 5, find dx/dt.
From the Pythagorean Theorem:
[tex]a^2+4=x^2[/tex]
Implicitly differentiate both sides with respect to time t. Both a and x are functions of t. Hence:
[tex]\displaystyle 2a\frac{da}{dt}=2x\frac{dx}{dt}[/tex]
Simplify:
[tex]\displaystyle a\frac{da}{dt}=x\frac{dx}{dt}[/tex]
Find a when x = 5:
[tex]a=\sqrt{5^2-2^2}=\sqrt{21}[/tex]
Therefore, dx/dt when da/dt = 410, x = 5, and a = √(21) is:
[tex]\displaystyle \frac{dx}{dt}=\frac{(\sqrt{21})(410)}{5}=82\sqrt{21}\approx 375.77\text{ mph}[/tex]
The rate at which is distance from the plane to the radar station is increasing at a rate of approximately 375.77 miles per hour.
Carin opened a money market account with a deposit of $3,000. This account earns 2% simple interest annually. How many years will it take for her $3,000 deposit to earn $430 in interest, assuming she does not withdraw any of the money?
Answer:
The correct answer is - 7.166 years
Step-by-step explanation:
Given:
principle amount: 3000
rate of interest: 2%
time?
Interent to get: 430
Formula:
I = P*t*r/100
here p = principle
I = interest
r = rate of intrest and t = time
Solution putting value and deriving Time as formula:
(3000*2*t)/100 = 430
t = 43000/3000*2
= 7.166 years.
g Use properties of logarithms to condense the logarithmic expression. Write the expression as a single logarithm whose coefficient is 1. Evaluate logarithmic expressions if possible.
Answer:
[tex]4\log_bx - \log_by = \log(\frac{x^4}{y})[/tex]
Step-by-step explanation:
Given
[tex]4\log_bx - \log_by[/tex]
Required
Express as a single expression
Using power rule of logarithm, we have:
[tex]n\log m = \log m^n[/tex]
So, we have:
[tex]4\log_bx - \log_by = \log_bx^4 - \log_by[/tex]
Apply quotient rule of logarithm
[tex]4\log_bx - \log_by = \log(\frac{x^4}{y})[/tex]
if angle ACB = angle DCD, angle BAC = 3x-10, angle ECD= 45degrees, and angle EDC = 2x+10 wgat is x
Answer:
x = 20
Step-by-step explanation:
3x -10 = 2x +10
x = 20
Find the distance between the two points in simplest radical form. (-6,1) and (−8,−4)
Answer: 5
Step-by-step explanation: I think it is 5
A professor is interested in whether or not college students have a preference (indicated by a satisfaction score) for reading a textbook that has a layout of one column or layout of two columns. In the above experiment, what is the dependent variable
Answer:
Satisfaction score
Step-by-step explanation:
The dependent variable may be described as the variable which is being measured in a research experiment. In the scenario described above, the dependent variable is the satisfaction score which is used to measure preference for a one or two column textbook. The dependent variable can also seen as the variable which we would like to predict, also called the predicted variable . The predicted variable here is the satisfaction score.
Okay, let's calculate the year end adjustment for overhead. Based on the data below, determine the amount of the year end adjustment to cost of goods sold due to over or under allocated manufacturing overhead during the year
Answer:
the adjustment made to the cost of goods sold is -$2,014
Step-by-step explanation:
The computation of the adjustment made to the cost of goods sold is given below:
Total actual overhead expenses $110,822
Less: Total overheads allocated -$112,836
Adjustment made to the cost of goods sold -$2,014
Hence, the adjustment made to the cost of goods sold is -$2,014
The same should be considered
Lauren flips a coin, spins the spinner, and rolls a standard number cube. Find the probability that the coin will
show heads, the spinner will land on green, and the cube will show an even number.
Lauren will get 2/25 because the coin only lands on heads or tail
The parametric equations for the paths of two projectiles are given. At what rate is the distance between the two objects changing at the given value of t? (Round your answer to two decimal places.) x1 = 10 cos(2t), y1 = 6 sin(2t) First object x2 = 4 cos(t), y2 = 4 sin(t) Second object t = π/2
Answer:
- [tex]\frac{4}{\sqrt{29} }[/tex]
Step-by-step explanation:
The equations for the 1st object :
x₁ = 10 cos(2t), and y₁ = 6 sin(2t)
2nd object :
x₂ = 4 cos(t), y₂ = 4 sin(t)
Determine rate at which distance between objects will continue to change
solution Attached below
Distance( D ) = [tex]\sqrt{(10cos2(t) - 4cos(t))^2 + (6sin2(t) -4sin(t))^2}[/tex]
hence; dD/dt = - [tex]\frac{4}{\sqrt{29} }[/tex]
30 students in grade 8 finished their summer packet before August 15.
This was 12% of all the students. How many students are in grade 8?
There are 1,200 people at the beach. If 88% of them went in the water,
how many people DID NOT go in the water?
A $800 T.V. is on sale for 15% off. What is the cost of the T.V.?
You go out to dinner and the bill is $45.12. You want to leave
an 18% tip. How much money should you leave?
Answer:
1)250 2) 144 3)
Step-by-step explanation:
1) 12/100 = 30/x 2) 1200*0.88
12x=3000 1200-1056
x=250 144
3)800*0.15 4) 45.12*0.18
800-120 45.12+8.12
680 about 53.24
Find the area of the geometric figure.
3 yd
3 yd
Traperoid
7 yd
Step-by-step explanation:
The question isn't clear, so I'll just give you a formula to find the area of trapezoid,
(a+b)*h/2, where a = base side, b = top side, h = height.
So, let's say two sides are 3 yd and 7 yd, and height is 3 yd, so the area becomes,
(3+7)*3/2
= 10*3/2
= 30/2
= 15 yd²
Answered by GAUTHMATH
