Answer:
735 N
Explanation:
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Question 4 of 5
Which pair of objects would repel each other?
O A. A positively charged particle and a neutral particle
OB. A negatively charged particle and a neutral particle
O C. Two positively charged particles
OD. A positively charged particle and a negatively charged particle
Answer:
Two positively charged particles
Explanation:
I said two positively charged particles because if I say c or d what ever it is for you guy it can be wrong so just pick the one that says Two positively charged particles
Answer: C Two positively charged particles.
Explanation:
just trust me on it, i've done the same quiz.
what would be Vy and pllzzzzzzz help
Answer:
2400m/s , 2240,2080,1920m/s
You and your dad are pushing your car out of the mud. You apply a force of 200 N and your dad applies a force of 250 N. What is the net force? Will the car move and if so, in what direction?
A. 450 N, yes, in the direction of the pushing
B. 0 N, no
C. 50 N, yes, in the direction of the dad
Answer:
I believe it's A (450 N)
Explanation:
Since both you and your dad are pushing in the same direction, you must add the force N to get the net force, which in this case in 450 N
what is the formula of parallelogram method to work out the sum of two vectors
Answer:
The sum of vectors P and Q is given by the vector R, the resultant sum vector using the parallelogram law of vector addition. If the resultant vector R makes an angle ϕ with the vector P, then the formulas for its magnitude and direction are: |R| = √(P2 + Q2 + 2PQ cos θ) β = tan-1[(Q sin θ)/(P + Q cos θ)]
What did you observe when clear water was poured on the soil around the well? Explain whether it matched your prediction.
Answer:
When water is added to soil, it can replace the oxygen that is naturally in the soil, and make the soil darker. This means wetter soil will have less oxygen compared with drier soil. When enough water is added, soil can become saturated and the water will start to form a layer on top of it.
Explanation:
Consider the following arrangement with a frictionless/massless pulley. Determine the force F required to move block A if the coefficient of static friction between block A and the floor is 0.35 and the coefficient of static friction between block A and block B is 0.25
Answer: The free - body diagrams for blocks A and B. frictionless surface by a constant horizontal force F = 100 N. Find the tension in the cord between the 5 kg and 10 kg blocks. The string that attaches it to the block of mass M2 passes over a frictionless pulley of negligible mass. The coefficient of kinetic friction Hk between M.
Explanation: Hope this helped :)
A physical quantities?
a)cannot be measured
b)Can be expected in the form of low.
c)can be represent completely by its magnitude and unit
d)Both B and C
Answer:
B and C
Explanation:
Both B and C should be the answer
Alice and Julio’s company makes protective coverings for off-roading vehicles. Alice’s job involves harvesting a natural polymer from trees. Julio’s job is to take that material and change it chemically to create a synthetic polymer.
Which materials do Alice and Julio most likely work with?
Alice works with vulcanized rubber, and Julio works with natural rubber.
Alice works with natural rubber, and Julio works with vulcanized rubber.
Alice works with cellulose, and Julio works with nylon.
Alice works with nylon, and Julio works with cellulose.
Answer:
Alice works with natural rubber and Julio works with vulcanised rubber.
Explanation:
Natural rubber is a polymer from tree.So it satisfies the profession of Alice.vulcanised rubber is artificial or synthetic polymer.So it satisfies the profession of JulioAnswer:
B. Alice works with natural rubber, and Julio works with vulcanized rubber.
Explanation:
I just took the test and got 100 percent.
I hope this helps you!!!!
Please mark my answer the Brainiset. Thank You!!!!!
1. A truck is traveling at a speed of 12 km/s is going to school. It took 10 seconds to get to school. What was the distance?
Answer:
120km
Explanation:
To get speed you divide distance by time.
PLEASE HELP!!!!
1. Suppose a planet orbits a star at the same distance
as Earth (1 AU) but with a period of roughly 200
Earth days. The mass of the central star is:
a. less than the mass of our sun.
b. the same as the mass of our sun.
c.greater than the mass of our sun.
d. impossible to determine without
knowing the mass of the planet.
Since the period of the supposed planet is less than the period of the earth orbiting the sun, That means the mass of the central star is greater than the mass of the sun. The answer is option C
According to Kepler's third law of planetary motion for planets and satellites, he described circular orbit about the same center body stating that:
The squared of the period is directly proportional to the cube of the radius. That is,
[tex]T^{2} \alpha r^{3}[/tex]
The orbital period formula is expressed as :
[tex]T^{2}[/tex] = 4[tex]\pi ^{2}[/tex] [tex]r^{3}[/tex] ÷ GM
Suppose a planet orbits a star at the same distance as Earth (1 AU) but with a period of roughly 200 Earth days. The mass of the central star will be greater than the mass of our sun based on the formula given above.
In a geostationary orbit, whatever the mass of the satellite may be, they will travel at the same speed in a particular orbit. mass M in the above formula becomes the mass of the sun or the center mass.
Since the period of the supposed planet is less than the period of the earth orbiting the sun, That means the mass of the central star is greater than the mass of the sun.
Therefore, the correct answer is option C
Learn more here: https://brainly.com/question/19680441
why is all motion relative
Explanation:
All motions are relative to some frame of reference. Saying that a body is at rest, which means that it is not in motion, merely means that it is being described with respect to a frame of reference that is moving together with the body
Answer:
Motion is always described in relation to a reference point.
Explanation:
For example, if a car is driving at the speed of 30 miles per hour and you are standing by the road, to you, the car appears to be moving 30 miles per hour down the road. However, if you were in a car also driving at 30 miles per hour next to the truck, the same truck wouldn't appear to move.
could someone answer this
The given kinematic equations of motion are derived from Newton's Laws
of Motion.
A) The ball's speed the instant it left the soccer player's foot is approximately 11.074 m/s.B) The time it took the ball to rise to its maximum height is approximately 1.129 seconds.
Reasons:
The direction the ball is kicked = Upwards in the air
Maximum height to which the ball rises = 6.25 m
A) The speed of the ball the instant it left the soccer player's foot
Solution:
The equation to use is; v² = v₀² + 2·[tex]a_y[/tex]·(y - y₀)
[tex]a_y[/tex] = The acceleration due to gravity ≈ -9.81 m/s²
At the maximum height, y - y₀ = 6.25 m
The velocity at the maximum height, v = 0
v₀ = The speed of the ball the instant it left the soccer player's foot
Which gives;
v² = v₀² + 2·[tex]a_y[/tex]·(y - y₀)
0 = v₀² - 2 × 9.81 × (6.25) = v₀² - 122.625
v₀² = 122.625
v₀ = √(122.625) ≈ 11.074
The ball's speed the instant it left the soccer player's foot, v₀ ≈ 11.074 m/s.
B) Required:
The time it takes the soccer ball to rise to the maximum height.
Solution:
The equation of motion required is v = v₀ + [tex]a_y[/tex]·t
At the maximum height, v = 0
v₀ ≈ 11.074 m/s
v = v₀ + [tex]a_y[/tex]·t
Which gives;
0 = 11.074 - 9.81 × t
[tex]t \approx \dfrac{11.074}{9.81} \approx 1.129[/tex]
The time it took the ball to rise to its maximum height, t ≈ 1.129 seconds
Learn more here:
https://brainly.com/question/24458315
A Rocket took 5 minutes to travel the 185 km. How fast did the Rocket travel in kilometers per minute (km/min)?
Answer:
The rocket travelled 37km per minute
Explanation:
185÷5=37
what is pole of magnet
and
define the term magnetic line of force
Answer:
1. The magnetic pole is the region at each end of a magnet where the external magnetic field is the strongest.
2. magnetic line of force - a line of force in a magnetic field. field line, line of force - an imaginary line in a field of force; direction of the line at any point in the direction of the force
Explanation:
A skateboarder, starting from the top of a ramp 4,5 m above the ground, skates down the ramp. The mass of the skateboarder and his board is 65 kg
Answer:
Kinetic energy is 2886.5Joule
See image for solutionPlease help me thank you
Fr+Cl=FeCl3
How does the force block A exerts on block B compare to the force block B exerts on block A?
Draw and label a force diagram for each block, using equality marks on the vectors.
By Newton's third law, we will see that the force that block A exerts on block B is equal in magnitude but in opposite direction than the force that block B exerts on block A.
Remember that Newton's third law says that whenever two objects interact, they exert equal and opposite forces on each other.
The force that block B exerts on block A is equal to block B's weight, which is:
[tex]W_b = 0.05kg*9.8m/s^2 = 0.49 N[/tex]
Then the force that block A exerts on block B is equal in magnitude but in opposite direction, thus it will be equal to:
F' = -0.49N
Then the diagram is the one that you can see below.
If you want to learn more, you can read:
https://brainly.com/question/13952508
most of the waves in the electromagnetic spectrum are
Answer:
The entire electromagnetic spectrum, from the lowest to the highest frequency (longest to shortest wavelength), includes all radio waves (e.g., commercial radio and television, microwaves, radar), infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.
Based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical equation:
(
)Zn + (
)HCl → (
)ZnCl2 + (
)H2
Answer:
Given equation
[tex]\\ \sf\longmapsto Zn+HCl\longrightarrow ZnCl_2+H_2[/tex]
Balanced equation
[tex]\\ \sf\longmapsto Zn+2HCl=ZnCl_2+H_2[/tex]
Reactant side:-
Zn=1Cl=2H=2Product side:-
Zn=1Cl=2H=2Hence balanced
Answer:
1 2 1 1
Explanation:
Which layer is the igneous rock type?
options:
A
B
C
D
Calculate the potential difference across a 25-Ohm. resistor if a 0.3-A current is flowing through it.
Answer:
I=0.3 A
R=25 Ohm
V=?
V=IR
0.3X25=7.5
Answer:
7.5 V
Explanation:
current × resistance = voltage
the acceleration due to gravity is caused by a field force. TRUE OR FALSE?
Answer:
I think it's true,,
Explanation:
maybeee truee
Two Force 16N and 4N acts at rights angle each other calculate the resultant force
Do Small objects exert no gravitational force ? True or false
Answer:
False -
F = G M1 M2 / R^2
So F depends on M1 and M2 and as long either is not zero there will be a gravitational force between them.
Why is it important to try to use as many renewable resources as possible?
Answer:
It is important to use renewal resources because we use so many non- renewable resources that we may lose the ability to make a lot of things like gasoline or power for our cities.
Please can someone solve this for me i will really appreciate it
Answer:
• Average current = 25,000 Amperes
• Time = 0.80 seconds
a)
[tex]{ \rm{quantity \: of \: charge = current \times time}} \\ { \rm{q = 25000 \times 0.80}} \\ { \boxed{ \mathfrak{answer : \: { \rm{quantity \: of \: charge = 20000 \: coulombs}} }}}[/tex]
b)
[tex]{ \rm{number \: of \: electrons = \frac{current}{charge \: quantity} }} \\ \\ { \rm{n = \frac{25000}{20000} }} \\ \\ { \boxed{ \mathfrak{ \: answer : \: { \rm{n = 1.25 \: }}}}}[/tex]
[tex]{ \underline{ \mathfrak{ \green{Good \: grace}} \: \:⚜ \: \: { \blue{ \mathfrak{Good \: God}}}}}[/tex]
H is a chemical (blank) and H2 is a chemical (blank)
Please I need help!
Answer:
"H" is a chemical symbol and "H2" is chemical formula.
Who is most likely to be offered a higher auto loan rate based on their credit-
to-debt ratio?
A. Juan has $10,000 in credit and owes $6,000.
B. Chester has $5,000 in credit and owes $750
C. Jalissa has $5000 in credit and owes $500.
credjtar
D. Nancy has $10,000 in credit and owes $2,000.
SUBMIT
HELP ME PLEASE
Answer:
A - Juan
Explanation:
I took the test!
A 100g mass is attached to a string that is 75 cm long. The mass is swung in a horizontal circle that goes around once every 0.80 seconds.
What is the centripetal acceleration of the mass?
What is the tension in the string?
Answer:
Centripetal acceleration = 46.26m/s2
Tension = 4.6N
Explanation:
Centripetal acceleration is given by the following formula: [tex]a_c = \frac{v^2}{r}[/tex]
So, to calculate acceleration we first need velocity and radius.
The radius is given to us as 75cm = 0.75m, and we can find velocity from the following formula:[tex]v=r\omega[/tex] where w = the angular velocity given by: [tex]\omega = \frac{2\pi}{T}[/tex]
We are given a period of 0.80s, meaning that our angular velocity is:
[tex]\frac{2\pi}{0.80} = 7.85 rad s^{-1}[/tex]
Now we just need to multiply is by the radius to find the velocity:
[tex]0.75*7.85=5.89ms^{-1}[/tex]
Finally we square the velocity and divide by the radius to find the final centripetal acceleration: [tex]\frac{5.89^{2} }{0.75} =46.26ms^{-2}[/tex]
[tex]F=\frac{mv^{2} }{r}[/tex] so we just need to multiply the centripetal acceleration by mass to get the tension force of the string: [tex]46.26*0.1 = 4.6N[/tex]
Hope this helped!
A 9.0V battery is connected across a 2.2kilo ohms and 6.8kilo omhs resistors connected in series. what is the potential differences across 2.2kilo ohms resistor.
Answer:
[tex]V_{2.2} =2.2V[/tex]
Fast and loose: that's a classic voltage divider. the drop from the i-th resistor is [tex]R_i \over {\sum R}[/tex] of the drop across the whole series. In our situation, it's [tex]2.2\cdot 10^3 \over {2.2\cdot10^3 + 6.8\cdot 10^3[/tex] of 9 V. By plugging numbers in a calculator, it's 22/90 of 9V, or 2.2V
With Ohm's Law
The series is equivalent of a single resistor of Resistance [tex]2.2\cdot 10^3+6.8\cdot 10^3 \Omega = 9.0 k\Omega[/tex]. By Ohm's first Law ([tex]V=Ri[/tex]) the current flowing through the resistor is [tex]9V = 9*10^3\Omega i \rightarrow i=1mA[/tex]. At this point, the drop across the first resistor is, again by Ohm's law[tex]V = 2.2 \cdot 10^3 \Omega \cdot 1\cdot 10^{-3} A = 2.2V[/tex]