For an experiment, Doris brought a container filled with snow into a warm environment. After 4
minutes, 12.88 grams of the snow remained. How many grams of snow were in the container
originally if 44% of it had melted after the 4 minutes?

The answer is:

999^3 = 997002999

Answer:

∠EFG=2×∠EHG

∠EFG=2×42

∠EFG=84°

so,m∠EFG=84°

------------------------

hope it helps...

have a nice day!!

[tex]answer = 3 {x}^{2} {e}^{ {x}^{3} } [/tex]

Answer:

[tex] \displaystyle f'(x) = 3x^2 {e}^{ {x}^{3} } [/tex]

Step-by-step explanation:

we would like to figure out the first derivative of the following:

[tex] \displaystyle f(x) = {e}^{x ^{3} } [/tex]

to do so take derivative In both sides:

[tex] \displaystyle f'(x) = \frac{d}{dx} {e}^{x ^{3} } [/tex]

to differentiate the above we can consider composite function derivation given by

[tex] \rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dx} f'(g(x)) \times \frac{d}{dx} g'(x)[/tex]

let

g(x)=u

so we obtain:

[tex] \displaystyle f'(x) = \frac{d}{dx} {e}^{u} \times \frac{d}{dx} u[/tex]

substitute back:

[tex] \displaystyle f'(x) = \frac{d}{dx} {e}^{ {x}^{3} } \times \frac{d}{dx} {x}^{3} [/tex]

by using derivation rule we acquire:

[tex] \displaystyle f'(x) = 3x^2 {e}^{ {x}^{3} } [/tex]

and we are done!

Answer:

✔️2 sets of corresponding angles

<D and <S

<R and <L

✔️2 sets of corresponding sides

DR and SL

RM and LT

Step-by-step explanation:

When two polygons are congruent, it implies that they have the same shape and size. Therefore, their corresponding angles and sides are congruent to each other.

When naming congruent polygons, the arrangement of the vertices are kept in a definite order of arrangement.

Therefore, Given that polygon DRMF is congruent to SLTO, the following angles and sides correspond to each other:

<D corresponds to <S

<R corresponds to <L

<M corresponds to <T

<F corresponds to <O

For the sides, we have:

DR corresponds to SL

RM corresponds to LT

MF corresponds to TO

FD corresponds to OS.

We can select any two out of these sets of corresponding angles and sides as our answer. Thus:

✔️2 sets of corresponding angles

<D and <S

<R and <L

✔️2 sets of corresponding sides

DR and SL

RM and LT

Answer:

g = 10

Step-by-step explanation:

First, let's find the missing value of the 'C'

180 - 110 = 70 degrees

Now that we have the answer for one side, we can make an equation:

2g + 9g + 70 = 180 (area of a triangle is 180 degrees)

11g + 70 = 180

11g = 180 - 70

11g = 110

g = 110 / 11

g = 10

The value of g is 10 so we can now add them to the expression:

2g = 2(10) = 20

9g = 9(10) = 90

To make sure that you have the correct answer, add the values so that you get an answer as 180:

70 + 20 + 90 = 180

hope this helps....

From the given figure, We can notice that :

∠BCA + 110° = 180°      (Because they make a Linear Pair)

⇒  ∠BCA = 180° - 110°

⇒  ∠BCA = 70°

We know that : Sum of the Angles in a Triangle should be equal to 180°

⇒  2g° + 9g° + ∠BCA = 180°

⇒  11g° + 70° = 180°

⇒  11g° = 180° - 70°

⇒  11g° = 110°

⇒  g° = 10°

⇒  9g° = (9 × 10) = 90°

⇒  2g° = (2 × 10) = 20°

Answer:

Step-by-step explanation:

Because this is an isosceles trapezoid, the diagonals are congruent. That means that DF is the same length as EG which is 11.

Answer:

Each shirt costs $18.50

Step-by-step explanation:

Questions such as these usually involve quite simple calculations, but they are important in being able to convert a scenario described in words into math calculations.

First, read the information carefully and then summarize what you are given in short sentences. Pat bought  6  shirts.  He paid using a check and cash.

The total amount paid was  $ 25  +  $ 86  =  $ 111

The shirts all cost the same price.

The cost of each shirt was:  111  ÷  6  =  $ 18.50

Answer:

Each shirt was 18.50

Step-by-step explanation:

The total cost of the 6 shirts was 25+86 = 111

Divide the total by 6 to find the cost of each shirt

111/6 =18.5

Each shirt was 18.50

Answer:

Yes

Step-by-step explanation:

As long as no x values repeat it is considered a function

In the given set no x values repeat therefore it is a function

Answer:

Yes.

Step-by-step explanation:

Each input has exactly one output. Therefore, this is indeed a function.

Try this option:

1. the required surface area consists of: A=A₁+A₂+A₃, where

2. A₁=pi*r*l - the surface of the cone:

pi=3.14; r=4/2=2 cm; l=sqrt(6²+2²)=2√10≈6.33 (cm);

A₁=3.14*2*6.33=39.74 (cm²).

3. A₂=a²-pi*r² - the surface of the top plane:

A₂=36-3.14*4=23.43 (cm²).

4. A₃=5*a² - the surface of the five planes of the given cube:

A₃=5*6²=180 (cm²).

5. the required area:

A=39.74+23.43+180=243.17 (cm²).

Answer: 243.17

Given:

[tex]\cos \theta =\dfrac{3}{5}[/tex]

[tex]\sin \theta <0[/tex]

To find:

The quadrant of the terminal side of [tex]\theta[/tex] and find the value of [tex]\sin\theta[/tex].

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

[tex]\cos \theta =\dfrac{3}{5}[/tex]

[tex]\sin \theta <0[/tex]

Here cos is positive and sine is negative. So, [tex]\theta [/tex] must be lies in Quadrant IV.

We know that,

[tex]\sin^2\theta +\cos^2\theta =1[/tex]

[tex]\sin^2\theta=1-\cos^2\theta[/tex]

[tex]\sin \theta=\pm \sqrt{1-\cos^2\theta}[/tex]

It is only negative because [tex]\theta [/tex] lies in Quadrant IV. So,

[tex]\sin \theta=-\sqrt{1-\cos^2\theta}[/tex]

After substituting [tex]\cos \theta =\dfrac{3}{5}[/tex], we get

[tex]\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}[/tex]

[tex]\sin \theta=-\sqrt{1-\dfrac{9}{25}}[/tex]

[tex]\sin \theta=-\sqrt{\dfrac{25-9}{25}}[/tex]

[tex]\sin \theta=-\sqrt{\dfrac{16}{25}}[/tex]

[tex]\sin \theta=-\dfrac{4}{5}[/tex]

Therefore, the correct option is B.

Answer:

[tex]y=-x+1[/tex]

Step-by-step explanation:

Slope can be represented as rise over run (change y-values over change in x-values). Since the y-value is changing by -2 every time the x-value is changing by 2, the slope of the line must be [tex]\frac{-2}{2}=-1[/tex].

In slope-intercept form [tex]y=mx+b[/tex], [tex]m[/tex] represents the slope of the line, [tex]b[/tex] represents the y-intercept, and [tex](x, y)[/tex] represent the coordinates of any point the line passes through.

To find [tex]b[/tex], substitute [tex]m=-1[/tex] and any point the line passes through.

Using (1, 0) from the table:

[tex]0=-1(1)+b,\\0=-1+b,\\b=1[/tex]

Thus, the equation of this line is [tex]\boxed{y=-x+1}[/tex]

Answer:

D

Step-by-step explanation:

Step-by-step explanation:

(1, -3). (3, 0)

(0 + 3)/(3 - 1) = 3/2 is the slope

Answer:

3x - 4

Step-by-step explanation:

(6x^2 − 8x) ÷ (2x) =

(6x^2)/2x - 8x/2x =                 

3x - 4

Answer:

(C). 3x - 4

Step-by-step explanation:

It will be easily to break this down so,

6/2=3

x^2/x=x

therefore, 6x^2/2x = 3x

Minus stay minus

8/2 = 4

x/x=1

therefore, 8x/2x=4

If we put it all together,

3x - 4

if this helps you, please give brainliest!

Slope is 0.75 or 3/4 I believe!

Answer: 5 Seconds

Step-by-step explanation: Given the equation of the height expressed ad;

h(t) = - 16t^2 + initial height

Given that initial height = 400feet

h(t) = - 16t^2 + 400

The waste will hit the ground at when h(t) = 0

substitute

0 =  - 16t^2 + 400

16t^2 = 400

t² = 400/16

t² = 25

t = √25

t = 5secs

Answer:

22 feet

Step-by-step explanation:

When graphing the equation, the peak or the maximum of the equation is reached the 1st second of the throw and it reaches 22 feet.

Answer:

I would answer but I have no numbers to give the answer

Answer:

Y=6000-400x

Step-by-step explanation:

Y=6000-400x where 6000 is beginning total, x represents how many months have passed, and 400x reduces the total by 400 for x number of months.

Answer:

[tex]a = 3\sqrt{7}[/tex]

Step-by-step explanation:

Given

See attachment

Required

Determine (a)

To do this, we make use of Pythagoras theorem.

[tex]12^2 = a^2 + 9^2[/tex]

[tex]144 = a^2 + 81[/tex]

Collect like terms

[tex]a^2 = 144 -81[/tex]

[tex]a^2 = 63[/tex]

Take square roots

[tex]a = \sqrt{63}[/tex]

Expand

[tex]a = \sqrt{9*7}[/tex]

Split

[tex]a = \sqrt{9}*\sqrt{7}[/tex]

[tex]a = 3\sqrt{7}[/tex]

Answer:

Option 4

Step-by-step explanation:

3x(x+2)-4(x+2)

(3x-4)(x+2)

3x²+6x-4x-8

3x²+2x-8

Brainliest please

Answer:

(x + 2)(3x - 4)

3x^2 + 2x - 8

Step-by-step explanation:

Factor out x + 2.

You get: (x + 2)(3x - 4)

Now multiply it out:

(x + 2)(3x - 4) = 3x^2 - 4x + 6x - 8 = 3x^2 + 2x - 8

A. 0

Answer:

Solution given

(x1,y1)=G(3, -2),

(x2,y2)=H(7, -2)

now

slope=(y2-y1)/(x2-x1)=(-2+2)/(7-3)=0/4=0

Answer:

0

Step-by-step explanation:

To find the slope

m= ( y2-y1)/(x2-x1)

 = ( -2 - -2)/ ( 7-3)

   = (-2+2)/(7-3)

   = 0/4

Answer:

Step-by-step explanation:

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=

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9

=

21