In the 3-slit interference pattern, the secondary peak intensity is always half the principal maximum intensity. Therefore, the ratio of the peak intensity of the secondary peak to the primary peak is 1/2.
To understand why this is, consider the constructive interference that occurs at the main maxima. This occurs when the path difference of the waves reaching the screen through each slot is equal to an integer multiple of the wave's wavelength.
This gives us strong intensities at these points, which are the main maxima. On the other hand, at the second-order maximum, the path difference of the waves reaching the screen through each slit is equal to an odd multiple of half the wavelength of the wave.
This results in weaker intensity at these locations, which are secondary maxima. Since the sidelobe intensity is weaker than the main lobe, the ratio of the peak intensity of the sidelobe to the main lobe is 1/2.
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Two point-like particles, each of mass m, are originally separated by a distance d and moving in opposite directions each with a speed of v. What is the maximum value for v so that the particles will eventually move back together under the influence of the mutual gravitational attraction?
The angular momentum of a system does not depend on the point about which it is taken, according to equation (iv). the particles eventually move back together because of mutual gravitational attraction.
How to repair?As depicted in the following diagram, assume that two particles are present at positions P and Q at some point in time.
Think about a point R that is y miles away from a point Q, or QR=y PR=dy.
LP=mv0+mvd=mvd is the system's angular momentum around point P.
I The system's angular momentum around point Q is given by LQ=mvd+mv0=mvd.....(ii)
System's angular momentum about point R is given by LR=mv(d, y)+mv(y, d)=mvd....(iii)
The result of comparing equations I (ii), and (iii) is L P = LQ = LR....... (iv)
The angular momentum of a system does not depend on the point about which it is taken, according to equation (iv).
What causes the gravitational pull of objects?All objects with mass are attracted to one another by the gravitational attraction, which has a magnitude that is directly proportional to the masses of the two objects and inversely proportional to the square of their distance from one another.
What are the benefits of gravitational attraction?Our feet remain firmly planted on the ground thanks to gravity, which also keeps the Moon in orbit around the Earth, the Earth in orbit around the Sun, the Sun in orbit around the galactic core of our Milky Way galaxy, and the Milky Way and Andromeda galaxies orbiting each other.
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A certain 50.0-Hz AC power line radiates an electromagnetic wave having a maximum electric field strength of 13.0 kV/m. (a) What is the wavelength of this very low frequency electromagnetic wave? (b) What is its maximum magnetic field strength?
An electromagnetic wave radiating from a specific 50.0-Hz AC power line has a maximum electric field strength of 13.0 kV/m. This extremely low frequency electromagnetic pulse has a wavelength of 6.00 x [tex]10^{6}[/tex]m.
An electromagnetic wave is what?A sinusoidal graph illustrates electromagnetic waves. It is made up of time-varying electric and magnetic fields that are perpendicular to each other and to the direction that waves travel.
How do wavelength and frequency relate to one another?Inverse proportionality describes the relationship between frequency and wavelength. Longer wavelengths are correlated with lower frequency, and vice versa. The fact that a wave's speed is equal to the product of its frequency and wavelength helps to explain how these two properties are related.
Briefing:
Given that,
Frequency of the power line, f = 50.0 Hz
Value of maximum electric field strength of 13.0 kV/m
The wavelength of this very low frequency electromagnetic wave is given by using relation as:
[tex]c = f[/tex]λ
λ [tex]= \frac{c}{f}[/tex]
λ [tex]= \frac{3.8 * 10^{8} m/s }{50}[/tex]
λ = 6 x [tex]10^{6}[/tex] m
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NAME THAT DISORDER
For the following scenarios, identify the psychological disorder indicated (if there is definitely a disorder). Indicate the reason why you chose that diagnosis (i.e., what are the symptoms/behaviors presented). According to your textbook (or any other source you would like to use), what might be an appropriate course of treatment (use all that could apply) for the diagnosis you chose. Try to be as specific as possible.
Homework assignment is due prior to the start of class on WEDNESDAY, DECEMBER 14TH.
1. When Lila saw the policeman turn on his flashing blue lights and motion her to pull over, her heart rate increased, her mouth felt dry, and she quite nervous about what was going to happen.
2. Although doctors could find no evidence of brain damage, Ralph could not remember driving the car that was involved in the accident that resulted in the deaths of his wife and son.
3. When Sammi saw Andrea three months ago, Andrea was too busy to talk. She was involved in all kinds of plans for a vague new business that she was sure to make her a fortune. But just last week, Sammi heard that Andrea was feeling very low, was sleeping most of the time, and had given up all plans to do just about anything.
4. Timothy was having an increasingly difficult time completing his reading assignments. He was becoming unsure if what he was reading was really there or if his mind was making things up. This was not helped by the “kryptonite rays” being emitted by the smoke detector and the hidden camera spying on him from behind the mirror in his room.
5. Ever since her home was burglarized, Maria double checks to make sure the doors are locked before going to bed.
6. Randall is so afraid of bacteria that each day he must wash each dish and utensil three times in scalding, soapy water and then rinse each dish exactly twenty seconds. If he deviates from this ritual in the slightest way, he must wash all the dishes and utensils again.
7. Everything was hopeless. Francine felt that because she was such a horrible wife and mother she felt she didn’t deserve to live and that her husband should find a better person to be with. She cried all the time and couldn’t escape her sadness.
8. When the helicopter crash landed, Yusef was horrified. He and he pilot were injured and the gas tank could blow at any time. Although he had a broken arm, Yusef was able to pull both himself and the unconscious pilot out of the plane and to safety before it blew. But ever since that time, the unbroken arm he used to save himself and the pilot has been ‘paralyzed’ and Yusef does not appear to be too upset about it.
9. Carlos, who is turning 40, is very worried about having about having a heart attack since his brother, father, and grandfather died of heart attacks in their 40s.
10. On the way home, Celia found herself having difficulty breathing, and her heart was pounding so hard that she could barely see clearly. She pulled off the road where she continued to hyperventilate, feel dizzy, and have sweaty palms. After about 10 minutes or so, her breathing returned to normal and she continued on her drive home.
Where the exercise here is to name the disorder, note that:
It should be mentioned that medication (such as antidepressants or benzodiazepines) and/or counseling may be used to treat a panic disorder such as cognitive-behavioral therapy.
A suitable course of treatment for dissociative disorders may involve counseling (such as cognitive-behavioral therapy, trauma-focused therapy, or psychodynamic therapy) and/or medication.
The focus of psychodynamic therapy is on unconscious processes as they show in the client's current behavior. Client self-awareness and knowledge of the effect of the past on present behavior are the aims of psychodynamic therapy.
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two small spheres carry electric charges of equal magnitudes. there are equally spaced points (a , b , and c) which lie along the same line.
The right response is option number B. Electric field can be represented by a vector arrow because of vector quantity. To calculate the size of the electric field, we can apply the equation E=k |Q| r2E=k|Q| r2.
How can you determine an electric field's direction at a specific location?The electrical force acting on a positive test charge at a location in space has the same direction as the electrical field there.
What three types of electric fields are there?Electric field components can be found in electromagnetic waves , X-rays, radio waves, and microwaves. Within a conductor that is carrying current, there is an external electric field. Charges create electrical fields.
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the use of the doppler effect in the study of astronomy
current is moving through a copper ribbon in the direction shown. the ribbon is suspended between the poles of a magnet as indicated. when the voltage is measured between a and b, it is observed that a is at higher potential than b. which of the following explains this observation?
The option that explains this observation is option E:
The electric field in the ribbon is distorted by the magnetic field. This distortion creates an electric field component directed from point A to point B that deflects electrons in the ribbon toward point B.Which way will the electron be deflected by the electric field?The physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them, is known as an electric field (or E-field). It can also refer to a system of charged particles' physical field.
Negatively charged electrons will be diverted in the direction of the positive electrode, or (+) plate. Positively charged protons will be diverted in the direction of the negative electrode, or (-) plate.
Therefore, Magnetic lines of force in space are bent by ferromagnetic materials in a static magnetic field. The distortion impact on the static magnetic field is disturbed by the material flaws.
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See full question below
Current Current is moving through a copper ribbon in the direction shown. The ribbon is suspended between the poles of a magnet as indicated. When the voltage is measured between A and B, it is observed that A is at higher potential than B. Which of the following explains this observation?
A The electrons in the ribbon behave like magnetic dipoles; thus, they align with the magnetic field of the magnet that deflects electrons in the ribbon toward point A.
B The electrons in the ribbon behave like magnetic dipoles; thus, they align with the magnetic field of the magnet that deflects electrons in the ribbon toward point B.
с Electrons moving through the magnetic field experience a magnetic force to the left that deflects electrons in the ribbon toward point A.
D Electrons moving through the magnetic field experience a magnetic force to the right that deflects electrons in the ribbon toward point B.
E The electric field in the ribbon is distorted by the magnetic field. This distortion creates an electric field component directed from point A to point B that deflects electrons in the ribbon toward point B.
In an experiment, students hold a closed, rectangular loop of wire of mass mm, width LyLy, and length LxLx at rest above a very long wire that has a current II. The current-carrying wire is aligned along the origin, as shown in the diagram. The students release the loop from rest, and the loop falls in a direction perpendicular to the current-carrying wire. The students use an ammeter to measure the current in the loop as the loop passes very close to the wire but does not touch it. Which of the following statements best describes the experimental results and provides the principles that explain the results?
The induced current will be counterclockwise when the center of the loop is above the wire and clockwise when the center of the loop is below the wire. This is because the net magnetic field flux inside the loop is out of the page when the center of the loop is above the wire and is into the page when the center of the loop is below the wire.
Answer A: The induced current will be counterclockwise when the center of the loop is above the wire and clockwise when the center of the loop is below the wire. This is because the net magnetic field flux inside the loop is out of the page when the center of the loop is above the wire and is into the page when the center of the loop is below the wire.
A
The induced current will be clockwise until the top of the loop reaches the wire and will be counterclockwise when the top of the loop goes below this point. This is because the induced current is proportional to the rate of change of the magnetic field flux, which increases when the top of the loop is above the wire and decreases when the top of the loop is below the wire.
Answer B: The induced current will be clockwise until the top of the loop reaches the wire and will be counterclockwise when the top of the loop goes below this point. This is because the induced current is proportional to the rate of change of the magnetic field flux, which increases when the top of the loop is above the wire and decreases when the top of the loop is below the wire.
B
The induced current will always be clockwise as the loop falls. This is because the induced current is determined by the change of the magnetic flux inside the loop. The net magnetic flux is out of the page and increasing when the center of the loop is above the wire and into the page and decreasing when the center of the loop is below the wire.
Answer C: The induced current will always be clockwise as the loop falls. This is because the induced current is determined by the change of the magnetic flux inside the loop. The net magnetic flux is out of the page and increasing when the center of the loop is above the wire and into the page and decreasing when the center of the loop is below the wire.
C
The induced current will be clockwise until the bottom of the loop reaches the wire and will be counterclockwise when the bottom of the loop goes below this point. This is because the induced current is proportional to the rate of change of the magnetic field flux, which increases when the bottom of the loop is above the wire and decreases when the bottom of the loop is below the wire.
Answer D: The induced current will be clockwise until the bottom of the loop reaches the wire and will be counterclockwise when the bottom of the loop goes below this point. This is because the induced current is proportional to the rate of change of the magnetic field flux, which increases when the bottom of the loop is above the wire and decreases when the bottom of the loop is below the wire.
D
The induced current will always be counterclockwise as the loop falls. This is because the induced current is determined by the change of the magnetic flux inside the loop. The net magnetic flux is out of the page and decreasing when the center of the loop is above the wire and into the page and increasing when the center of the loop is below the wire.
The correct option is that C. The induced current will be clockwise until the bottom of the loop reaches the wire and will be counterclockwise when the bottom of the loop goes below this point. This is because the induced current is proportional to the rate of change of the magnetic field flux, which increases when the bottom of the loop is above the wire and decreases when the bottom of the loop is below the wire.
What is the current about?According to Faraday's law, the magnetic flux change rate in a circuit equals the magnitude of the induced EMF in the circuit. Additionally inversely correlated with the rate of change of magnetic flux in the circuit is hens induced current.
Lenz's law states that an induced current will flow in the opposite direction of the cause that is causing it. When the bottom of the loop is below this point, the induced current is counterclockwise until the bottom of the loop reaches the wire. This is because the magnetic field flux changes more quickly when the bottom of the loop is above the wire because the induced current is proportional to this
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(1) A table tennis ball is dropped
onto the floor from a height of
4m and it rebounds to a height of
3m. If the time of contact with the floor is 0.01s, what is the magnitude and direction of the acceleration during the contact.
Answer:
Here, h1=4.00m,h92)=3.00m,Delta t =0.01 s.Letv1 be the velocity of the ball (actind downwards) just before striking the floor an dv20 be the velocity of the ball (acting upwaeds) ust after striking the floor. Then, change in velocity of the ball in time Δtv2−(−v1)v2+v1
:. acceleration, a=v2+v1Δt ..(i)
When body falls from height h1,
then u=o,v1,a=gandS=h1
As, v21=u2+2aS,
:. v_(1) ^(2) =0 + g h_(10 or v12–√gh1
Taking motion of the ball after striking the floor, then u=v2,v=0,a=−g,S=h2
As, v2=u22as,∴v21=0+2gh1orv_(1) =sqrt 32 g h_(1)Tak∈gmotionoftheballa>erstrik∈gthe⌊,⌋thenu=v_(2), v=0, a=- g, S=h_(2)As,v2=u2+2aS,wehave0 = v_(2)^(2) +2 (-g) h_92) otr v2=2–√gh2
Putting values in (i) we get,
a=2–√gh2+2–√gh1Δt)
a=2–√×9.8×3+2–√×9.8×40.01
= 1652m/s2.
Explanation:
A car moving with a speed of 90km/hr was brought to rest by the application of the
Brakes in 10s How far did the car travel after the brakes were applied?
The distance travelled by the car after the brake was applied is 125 m.
What is the distance travelled by the car?
The distance travelled by the car is calculated by applying the following kinematic equation as shown below.
Mathematically, the distance travelled by the car at the given average speed is calculated as;
s = [ ( v + u ) / 2 ] t
where;
v is the final velocity of the car = 0u is the initial velocity of the car = 90 km/hr = 25 m/st is the time of motion of the car = 10 sThe distance travelled by the car is calculated as;
s = [ ( 0 + 25 m/s ) / 2 ] ( 10 s )
s = 125 m
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Two long parallel wires are placed side by side on a horizontal table. The wires carry equal currents in the same direction. Which of the following statements are true? Check all that apply. The magnetic field is a maximum at a point midway between the two wires The magnetic force between the two wires is attractive. The magnetic force between the two wires is repulsive. The magnetic field at a point midway between the two wires is zero.
When two long parallel wires are placed side by side on a horizontal table and the wires carry equal currents in the same direction, the magnetic field at a point midway between the two wires is zero.
When two parallel wires carry current in the same direction, they exert equal and opposite attractive forces on each other. Thus, the net magnetic field at midpoint is zero. While, Two parallel wires carrying current in opposite directions repel and try to move away from each other.
Similarly, if you have two parallel wires with current traveling in opposite directions, as you do in the series circuit, then the magnetic fields of the two wires will be traveling in the same direction at the point at which they intersect, and therefore repel each other.
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Field poles are electromagnets whose ____ change as the flow of current alternates in the field windings.
Field poles are electromagnets whose polarities change as the flow of current alternates in the field windings.
An electromagnet is a sort of magnet wherein the magnetic area is produced with the aid of an electric current. Electromagnets generally encompass cord wounds into a coil. A cutting edge through the wire creates a magnetic discipline that is focused inside the hole in the middle of the coil.
Electromagnets create a magnetic discipline through the application of power. When you introduce the modern, either from a battery or any other supply of strength, it flows through the wire. This creates a magnetic discipline around the coiled cord, magnetizing the metal as though it were a permanent magnet.
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a hydraulic lift (jack) has two pistons, one large and one small. the pistons are at the same elevation. if it is equilibrium, which piston exerts the greatest force
The force exerted at the large piston will be double in magnitude in comparison with the force applied at the smaller piston.
We know, according to the pascal's law,
The pressure applied at any point in the incompressible fluid is equal in magnitude at each and every point.
So,
P = Force/Area
Where P is pressure,
If pressure is same, then we can write,
F₁/A₁ = F₂/A₂
Where,
F₁ is the force applied at the small piston,
A₁ is the area of the smaller piston,
F₂ is the force at the larger piston,
A₂ is the area of the larger piston,
It is also given that, area if the larger piston is two times the area of the smaller piston so,
A₂ = 2A₁
So, putting the values we get,
F₂/F₁ = 2
So, F₂ = 2F₁
It means that the force exerted by the larger piston will be double in magnitude.
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What does the law of conservation of energy state?
energy cannot be destroyed but it can change forms
energy always gets used up in every chemical reaction
energy can be destroyed but not created
energy is always the same and it cannot be changed
I think it is "energy cannot be destroyed but it can change forms".
TRUE OR FALSE in physics, every physical quantity is measured with respect to a unit. time is measured in seconds, length is measured in meters, and mass is measured in kilograms. knowing the units of physical quantities will help you solve problems in physics.
The unit of G is found out to be m³/kg * s².
The force of gravitational attraction is represented by the equation.
F = (G m₁ m₂)/r²
where,
F is the magnitude of the gravitational attraction on either body
m₁ and m₂ are the masses of the bodies,
r is the distance between them
G is the gravitational constant
We need to find the unit of G,
G = (F * r²)/(m₁ m₂)
Let us place the units for the above formula,
G = (N * m²)/kg²
N = kg m/s²
G = (kg * m * m²)/ kg² * s²
G = m³/kg * s²
Thus, the correct option is m³/kg * s².
The question is incomplete. The complete question is 'Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes the moon to orbit the earth. The force of gravitational attraction is represented by the equation.
F= Gm1 m2 /r^2
where F is the magnitude of the gravitational attraction on either body, m1 and m2 are the masses of the bodies, r is the distance between them, and G is the gravitational constant. In Sl units, the units of force are kg m/s^2, the units of mass are kg, and the units of distance are m. For this equation to have consistent units, the units of G must be which of the following?
a. kg^3/ms^2
b. kgs^2/m^3
c. m^3/kgs^2
d. m/kgs^2
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Students will design an experiment to determine how the magnitude of the force on a segment of straight, current-carrying wire depends on the length of the wire segment and on the strength of the magnetic field. Which of the following experimental procedures will allow the students to determine both of these relationships? A Making measurements of the force on several different straight segments of wire, increasing the length of the wire and increasing the magnetic field strength with each measurement. B Making measurements of the force on several different straight segments of wire, increasing the length of the wire and decreasing the magnetic field strength with each measurement с Making measurements of the force on several different straight segments of wire, keeping the length of the wire constant while increasing the magnetic field strength with each measurement. D Making measurements of the force on several different straight segments of wire, increasing the length of the wire while keeping the magnetic-field strength the same with each measurement, then repeating the measurements while decreasing the length of the wire and increasing the magnetic field strength with each measurement E Making measurements of the force on several different straight segments of wire, increasing the length of the wire while keeping the magnetic-field strength constant with each measurement, then repeating the measurements while keeping the length of the wire constant while increasing the magnetic field strength with each measurement.
The experimental procedures that will allow the students to determine both of these relationships is option E:
Making measurements of the force on several different straight segments of wire, increasing the length of the wire while keeping the magnetic-field strength constant with each measurement, then repeating the measurements while keeping the length of the wire constant while increasing the magnetic field strength with each measurement.What happens to the magnetic field when the length of wire increases?The formula F = IL x B calculates the magnetic force acting through a magnetic field on a current-carrying wire. The magnetic field acts on a wire when a current is conducted through it in a direction that is perpendicular to both the magnetic force.
By increasing the amount of current flowing through the wire, the magnetic field's strength can be enhanced. As you get further from the wire, the strength gets weaker. If the amount of current flowing through it stays constant, its length and thickness have no bearing.
Therefore, the length of the wire in the magnetic field has an impact on the magnetic force's strength as well. The force acting on a wire increases with wire length in a magnetic field.
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Two carts on an air track have the same mass and speed and are traveling toward each other. If they collide and stick together, find the total momentum and total kinetic energy of the HINT (a) the total momentum O The final momentum is zero. O The final momentum is half the initial momentum. O The final momentum is twice the initial momentum. O There is not enough information to tell.
If they collide and remain united then the total momentum of the system is zero.
Total momentum by using the Principle of Momentum Conservation,
m* Va-m* Va=2* Vb
Final speed and total momentum of system = zero
p = 0
Due to the inelastic impact and the same masses and speeds, the system's total kinetic energy is reduced to zero. Before and after a collision, the total kinetic energy are, respectively:
Ka = mv²
Kb = 0
The combination of a particle's mass and velocity produces momentum.
A vector quantity with both magnitude and direction is momentum. Isaac Newton's second equation of motion states that the force applied to a particle is equivalent to the time rate of change of momentum.
Any grouping of particles has a momentum equal to the vector sum of their momenta. A modification in one particle's momentum is perfectly balanced by a modification in the momentum of another particle, according to Newton's third law, which states that particles exert equal and opposite forces on one another.
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when the glass gob comes out of the oven, it is dangerously hot. What happens to the thermal energy of the gob between that time and when it is a bottle than can be touched?
Answer:
decreases
Explanation:
The thermal energy of the gob decreases by heating the air around the gob and the mold in which the bottle is made
a particle moves under the influence of a conservative force. the equation for the potential energy as a function of position is given by: u(x)
A particle moves under the influence of a conservative force, The maximum x-coordinate of the particle at x = -3 m is 7 m.
Given that,
Potential energy of the particle u(x) = 5x² - 20x + 2
We know the relation between force and potential energy as,
F = -du/dx = -d/dx (5x² - 20x + 2) = -(10 x - 20 ) = 20 - 10 x at mean position x = 2.
At x = -3, amplitude is given by x = 2 - (-3) = 5
The maximum x co-ordinate is given as x = 5 + 2 = 7 m
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based on the graphic, in what part of the electromagnetic spectrum does vegetation have the strongest response?
Between 400 nm and 700 nm of the electromagnetic spectrum, vegetation has the strongest response.
The electromagnetic spectrum travels in waves and spans an extensive spectrum from very long radio waves to very brief gamma rays. The human eye can simplest come across only a small portion of this spectrum called visible light.
In order from maximum to lowest power, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible mild, infrared radiation, and radio waves.
In a tumbler, the purple mild travels the fastest, and the violet light travels the slowest of all seven hues. Velocity and wavelength are without delay proportional.
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In a diffraction experiment, a coherent light source illuminates a pair of identical slits in a barrier, and the resulting pattern is projected on a screen that is separated from the barrier by 2.05 m. A student sketches the pattern that appears on the screen. The locations of the centers of the bright and dark fringes are accurate, but the shading is only qualitative. The color chosen may not be an ideal match to the actual light source. TITUTE THI HT -50.0 -40.0 -30.0 -20.0 -10.0 0.0 10.0 20.0 30.0 40.0 50.0 y (cm) * 25% Part (a) Enter the ratio of the slit separation, d, to the slit width, D, as a whole number. d = D TT 7 8 9 HOME E 4 5 6 sino cos tan cotano asin acos atan acotan sinh cosho tanh) cotanh O Degrees Radians 1 2 3 + 0 END . VO BACKSPACE DE CLEAR Submit Hint Feedback I give up! Hints: 1% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback. A 25% Part (b) Calculate and enter the ratio of the slit width to the wavelength of the light source. A 25% Part (C) If the slit separation is 17 um, then calculate and enter the wavelength, in nanometers, of the light source. 25% Part (d) What is the slit width, in micrometers?
(a) The ratio of the slit separation d, to the slit width D;
d/D = 0.0001
(b The ratio of the slit width to the wavelength of the light source λ;
d/λ = 51.25
(c) The wavelength, in nanometers, of the light source;
λ = 331.7 nm
(d) The slit width, in micrometers;
d = 20.5 µm
(a) We know that Fringe width is given by,
[tex]\beta =\frac{D\lambda}{d}[/tex]
Where,
D = slit to screen distance
λ = wavelength
d = slit width
Given in the question,
D = 2.05 m
[tex]\beta =4 cm=0.04m[/tex]
Now,
[tex]\frac{d}{D} =\frac{\lambda}{\beta } =\frac{400*10^{-9} }{0.04}[/tex]
d/D = 0.0001
Hence,
The ratio of the slit separation d, to the slit width D;
d/D = 0.0001
(b) Ratio of d & λ,
[tex]\frac{d}{\lambda} =\frac{D}{\beta }[/tex]
[tex]\frac{d}{\lambda}=\frac{2.05}{0.04}[/tex]
[tex]\frac{d}{\lambda}=51.25[/tex]
Hence,
The ratio of the slit width to the wavelength of the light source λ;
d/λ = 51.25
(c) The wavelength of the light source,
[tex]\lambda=\frac{D\beta }{d}[/tex]
[tex]\lambda=\frac{17*10^{-6} *0.04}{2.05}[/tex]
[tex]\lambda=331.7nm[/tex]
Hence,
The wavelength, in nanometers, of the light source;
λ = 331.7 nm
(d) The slit width,
[tex]d =\frac{D\lambda}{\beta }[/tex]
[tex]d=\frac{400*10^{-9} *2.05}{0.04}[/tex]
[tex]d=20.5 \mu m[/tex]
Hence,
The slit width, in micrometers;
d = 20.5 µm
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Joan is initially driving her car at 10 m/s when she decides to go faster. She accelerates uniformly at 4 m/s2 for 100 meters. How fast is Joan going?
a
50 m/s
b
35 m/s
c
30 m/s
d
26 m/s
Joan is going with speed 30 m/s. Hence, option (C) is correct.
What is acceleration?Acceleration is the rate at which a velocity changes over time. It qualifies as a vector quantity because it possesses both direction and magnitude. Meter/second^2 (m/s^2) is the SI unit of acceleration.
Given that: initial speed of the car: u = 10 m/s.
Uniform acceleration of the car: a = 4 m/s^2.
Distance travelled: s = 100 meters.
Let, the final speed is = v
Using the formula v² = u² + 2as, we get:
v = √(10² + 2×4×100) m/s.
= 30 m/s.
Hence, final speed of the car is 30 m/s.
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a hollow metal sphere has inner radius a and outer radius b. the hollow sphere has charge 2 q. a point charge q sits at the center of the hollow sphere. you may want to review (page 658) . for help with math skills, you may want to review
The inner radius of a hollow metal sphere is a, and the outside radius is b. The hollow sphere has a point charge q in the center. There will be a distribution of q charges on the inner surface.
What is a charge of electricity?Electric charge can be interpreted as an excess or shortage of electrons and is the amount of imbalanced electricity (either positive or negative) in a body. There are two varieties: positive (+) and negative (–).
How is electricity produced?We all studied the structure of an atom with an equal amount of protons, neutrons, and electrons in physics and chemistry. Protons are positively charged, neutrons are neutrally charged, and electrons have a negative charge.
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The given question is incomplete. The complete question is:
A hollow metal sphere has inner radius 'a' and outer radius 'b'. The hollow sphere has charge +2Q. A point charge +Q sits at the center of the hollow sphere. How much charge is on the inside surface of the hollow sphere?
Question 9 of 25
Describe the path of the light ray that hits a mirror after passing through its
focus.
OA. It reflects back through the focus.
B. It hits the mirror and reflects back exactly the way it came in.
C. It is refracted through the mirror.
D. It is reflected back parallel to the principal axis.
SUBMIT
The path taken by a light beam after passing through a mirror's focus is where it hits the mirror and reflects back in exactly the same direction as it went in.
What, when striking the surface, causes the light to reflect back?Specular reflection is the name for this. A smooth surface allows light to bounce back at the same angle that it was incident. Rays of light that are reflected off of a smooth surface go in that same direction.
Where does a light beam travel?The narrow beams of light that travel in straight lines along their courses as electromagnetic waves are known as rays. Though its path might be altered by reflection or refraction, light always moves in a straight line.
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Design a parallel RLC circuit (see (Figure 1)) with a resonant radian frequency of 5000 rad/s. Take that L 10 mH.a) Find the value of C Express your answer to three significant figures and include the appropriate units. C= 4.00 μFb) Find the value of R so that the response is critically damped. Express your answer to three significant figures and include the appropriate units R- 25.0 Ω
The value of R so that the response is critically damped using the equation is 25.0Ω.
What is Farads?Farads is the unit of measure for capacitance, which is the amount of electrical charge stored for a given voltage. Farads can be used to measure the amount of energy stored in a capacitor, which is made up of two conductive plates separated by an insulating material. The higher the capacitance, the more energy can be stored in a given capacitor. Farads are named after Michael Faraday, the British scientist who discovered the relationship between electricity and magnetism.
The resonant frequency of an RLC circuit is given by the equation:
ω_r=1/sqrt(LC)
where ω_r is the resonant frequency in rad/s, L is the inductance in Henries, and C is the capacitance in Farads.
Given the resonant frequency of 5000 rad/s and the inductance of 10 mH, we can calculate the capacitance as follows:
C=1/(ω_r^2*L)
C=1/(5000^2*0.01)
C=4.00μF
We can find the value of R so that the response is critically damped using the equation:
R=2*sqrt(L/C)
R=2*sqrt(0.01/4.00)
R=25.0Ω
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location of inhibitors bound to group iva phospholipase a2 determined by molecular dynamics and deuterium exchange mass spectrometry. t/f
Location of inhibitors bound to group iva phospholipase a2 determined by molecular dynamics and deuterium exchange mass spectrometry. (True)
Combining deuterium exchange mass spectrometry (DXMS) and molecular dynamics, we investigated the binding of group IVA (GIVA) phospholipase A2 (PLA2) inhibitors (MD). On the basis of deuterium exchange results, models of the GIVA PLA2 inhibitors pyrrophenone and the 2-oxoamide AX007 docked into the protein were created, and comprehensive molecular dynamics simulations were performed to determine protein–inhibitor interactions. The models demonstrate that both inhibitors interact with crucial residues that modify the deuterium exchange pattern in response to inhibitor binding. Pyrrophenone is primarily associated with the protein through contacts close to the active site, whereas oxoamide is primarily attached through contacts remote from the active site. We also compare the dynamics of the two inhibitor-bound complexes around the active site. It is possible to create better inhibitors against GIVA PLA2 by combining computational and experimental approaches to define more precise inhibitor binding locations.
Mass Spectrometry:
In order to determine the mass-to-charge ratio (m/z) of one or more molecules found in a sample, mass spectrometry is a valuable analytical instrument. The precise molecular weight of the sample's constituent parts can frequently be determined using these measures as well. Mass spectrometers are typically used to quantify known substances, identify novel compounds by molecular weight determination, and assess the structure and chemical characteristics of molecules.
∴ Location of inhibitors bound to group iva phospholipase a2 determined by molecular dynamics and deuterium exchange mass spectrometry. (True)
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according to the maxwellian speed distribution, as the temperature increases the number of molecules with speeds within a small interval: increases decreases increases at high temperatures and
According to the Maxwellian speed distribution, as the temperature increases, the number of molecules with speeds within a small interval decreases.
Temperature is a bodily quantity that expresses the perceptions of hotness and coldness. Temperature is measured by using a thermometer. Thermometers are calibrated in diverse temperature scales that have been trusted by various reference points and thermometric materials for definition.
Temperature plays a vital role in hospital treatment, food, drinks, and agriculture. Our health is often reliant upon the temperature in many methods as properly. Preserving the right temperature degrees in cold garage areas is crucial.
The SI unit of temperature as in line with the international machine of units is Kelvin that's represented by the symbol K.
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the 30kg girl pushes the 20kg boy, and he moves away at a speed of 2.0m/s. if momentum is conserved, what is the girls speed?
The initial momentum of the girl is conserved with the equal final velocity for both of them . Hence, the momentum of the girl is 60 kg m/s.
What is momentum?Momentum of a moving body is the product of velocity and mass of the body. Momentum is a vector quantity and is characterized by its magnitude and direction. The unit of momentum is Kg m/s.
During collision, the total momentum of a body is conserved. Therefore, total initial momentum of the colliding bodies is equal to the final momentum where they both move in equal velocity.
Here, the boy moves in 2 m/s. The velocity of the girl will be the same.
Hence, her momentum = mass × velocity
= 30 Kg × 2 m/s = 60 Kg m/s.
Therefore, the momentum of the girl is 60 kg m/s.
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A fisherman has caught a fish on his pole, and to keep the pole steady he has to apply an upward force of F2 = 235 N at an angle of 60.5° with respect to the pole (see figure). The length of his pole is 3.5 m, and he is holding it a distance 0.45 m from the end, where he is applying a downward force F1.
Randomized VariablesF2 = 235 N
θ = 60.5°
L = 3.5 m
d = 0.45 m
A fisherman has caught a fish on his pole, and to keep the pole steady he has to apply an upward force is [tex]=\quad m=(205-182.391[/tex]
What is force?
A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
[tex]\begin{aligned}& F_2=235 \mathrm{~N} \\& \theta=60.5^{\circ} \\& L=3.5\mathrm{~m} \\& d=0.45\mathrm{~m}\end{aligned}[/tex]
calculating torame about 'A'
For equilibrium[tex]$\sum \tau_A=0$[/tex]
$$[tex]$$\begin{aligned}& \Rightarrow \quad \vec{F} \times \vec{L}+\vec{F}_2 \times(\overrightarrow{L-d)}=0 \\& \Rightarrow \quad \vec{F}_1 \times \overrightarrow{L_1}=-\vec{F}_2(\overrightarrow{L-d}) \\& \Rightarrow \quad F_1 \cdot L \sin \theta=F_2 \cdot(L-\alpha) \sin \theta \\& \Rightarrow \quad F_1=F_2 \frac{(L-a)}{L} \\& \Rightarrow \quad F_1=235 \cdot \frac{(3.5-0.35)}{3.2} \\& F_1=182.58 \mathrm{~N} \\&\end{aligned}$$[/tex]
[tex]For equilibrium $\quad \Sigma$ fret $=0$$$\begin{aligned}& \Rightarrow \quad \overrightarrow{F_2}+\overrightarrow{F_1}+\overrightarrow{m_g}=\overrightarrow{0} \\& \Rightarrow \quad m g .=F_2-F_1 \\& \Rightarrow \quad m=\left|\frac{F_2-F_1}{g}\right| \\& \Rightarrow m=\frac{(205-182.591}{9.8} \\& m=2.288 \mathrm{~kg} \\&\end{aligned}$$[/tex]
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he is driving on a motorcycle at 18 m/s as he passes over the top of a hill whose radius of curvature is 142m
The magnitude of centripetal force is 684.50 N and the magnitude of normal force is 2258.5 N.
Force is an external influence that can change the velocity or motion of an object.
It can also be defined as the product of mass and acceleration.Mathematically, force F = m*aSpeed of the motorcycle = v = 18 m/s
Radius of curvature of the hill top = r = 142 m
Total mass of the motorcycle and driver = m = 300 kg
A centripetal force is a force acting on an object in a curvilinear motion toward the axis of rotation or center of curvature.
Mathematically, it is Fc = (mv²)/r
Fc = (300 * 18²) / (142)
Fc = 684.50 N
Normal force (N) acting on the motorcycle can be calculated by the equation:
Fc = mg - N
684.50 = (300 * 9.81) - N
N = 2943 - 684.5
N = 2258.5 N
Therefore the magnitude of centripetal force is 684.50 N and the magnitude of normal force is 2258.5 N.
The question is incomplete, the complete question is "he is driving on a motorcycle at 18 m/s as he passes over the top of a hill whose radius of curvature is 142m. The mass of the motorcycle and driver is 300 kg. Find the magnitudes of the following.
a) magnitude of centripetal force
b) magnitude of normal force
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A staging that weighs Wstaging supports a painter weighing 300 N. The reading on the left scale is 580 N and the reading on the right scale is 270 N. What is the weight of the staging?
The weight of the staging is 550N.
The weight of an object, the gravitational force caused by the presence of a large second object such as the Earth or the Moon.
The unit of measurement for weight is indeed a unit of force. This unit in the International System of Units (SI) is the Newton.
Given data : Weight of the painter ([tex]W_{p}[/tex]) = 300 N
Left scale's weight reading [tex](W_{L} )[/tex] = 580 N
Right scale's weight reading [tex](W_{R} )[/tex] = 270 N
To find the weight of the staging [tex](W_{s} )[/tex], we will set all the weight in the equilibrium.
Since the force of the staging and painter's weight is going downward we will denote them as negative. The opposite will be placed for the reading of weight on the left and right scale, which is positive.
[tex]-W_{p} -W_{s} +W_{L}+W_{R} = 0[/tex]
[tex]-300N-W_{s} +580N + 270N = 0\\[/tex]
[tex]W_{s}[/tex] [tex]= -300N+580N+270N[/tex]
[tex]W_{s}[/tex] [tex]= 550N[/tex]
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