Answer:
Step-by-step explanation:
[tex]\frac{34-40}{8}= -.75[/tex]
Which of the following expressions are equivalent?
I. 5a6
II. 30a
III. a6 + a6 + a6 + a6 + a6
IV. 6a5
Answer:
5а⁶=а⁶+а⁶+а⁶+а⁶+а⁶
~~~~~~~~
Can someone please help me with this
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Answer:
21. D
22. C
Step-by-step explanation:
21. The expansion of the given expression is ...
[tex]\displaystyle -\frac{1}{2}\left(-\frac{3}{2}x+6x+1\right)-3x=\frac{3}{4}x-3x-\frac{1}{2}-3x\\\\=\left(\frac{3}{4}-3-3\right)x-\frac{1}{2}=\boxed{-5\frac{1}{4}x-\frac{1}{2}}[/tex]
__
22. The least likely team to make the championship game is the one with the lowest probability.
3/8 < 1/2 < 2/3 < 4/5
The Bulldogs are least likely to play in the championship game.
Lines of symmetry give e the answer
Answer:
4
Step-by-step explanation:
There are 4 reflectional symmetry
A physical trainer decides to collect data to see if people are actually weight changing weight during the shelter in place. He believes there will not be a meaningful change in weight due to the shelter in place order. He randomly chooses a sample of 30 of his clients. From each client, he records their weight before the shelter in place order, and again 10 days after the order. A summary of the data is below.
The trainer claims, "on average, there is no difference in my clients' weights before and after the shelter in place order." Select the pair of hypotheses that are appropriate for testing this claim.
H0: µd = 0
H1: µd < 0 (claim)
H0: µd = 0 (claim)
H1: µd ≠ 0
H0: µd ≠ 0 (claim)
H1: µd = 0
H0: µd = 0 (claim)
H1: µd > 0
H0: µd = 0
H1: µd > 0 (claim)
H0: µd = 0
H1: µd ≠ 0 (claim)
H0: µd = 0 (claim)
H1: µd < 0
H0: µd ≠ 0
H1: µd = 0 (claim)
b) Select the choice that best describes the nature and direction of a hypothesis test for this claim.
This is a right-tail t-test for µd.
This is a right-tail z-test for µd.
This is a two-tail t-test for µd.
This is a two-tail z-test for µd.
This is a left-tail t-test for µd.
This is a left-tail z-test for µd.
c) Find the standardized test statistic for this hypothesis test. Round your answer to 2 decimal places.
d) Find the P-value for this hypothesis test. Round your answer to 4 decimal places.
e) Using your previous calculations, select the correct decision for this hypothesis test.
Fail to reject the alternative hypothesis.
Reject the alternative hypothesis.
Fail to reject the claim.
Reject the claim.
Fail to reject the null hypothesis.
Reject the null hypothesis.
f) Consider the following statements related to the trainer's claim. Interpret your decision in the context of the problem (ignoring the claim) and interpret them in the context of the claim.
Answer:
H0: µd = 0 (claim)
H1: µd ≠ 0
This is a two-tail t-test for µd
Step-by-step explanation:
This is a paired (dependent) sample test, with its hypothesis is written as :
H0: µd = 0
H1: µd ≠ 0
From the equality sign used in the hypothesis declaration, a not equal to ≠ sign in the alternative hypothesis is used for a two tailed t test
The data isn't attached, however bce the test statistic cannot be obtained. However, the test statistic formular for a paired sample is given as :
T = dbar / (Sd/√n)
dbar = mean of the difference ; Sd = standard deviation of the difference.
What are the new vertices of quadrilateral KLMN if the quadrilateral is translated two units to the right and four units upward?
A)
K′ = (–2,0), L′ = (1,0), M′ = (1,–3), N′ = (–2,–3)
B)
K′ = (–2,2), L′ = (1,2), M′ = (1,–1), N′ = (–2,–1)
C)
K′ = (–0,0), L′ = (3,0), M′ = (3,–1), N′ = (0,–1)
D)
K′ = (–2,–2), L′ = (1,–2), M′ = (1,–5), N′ = (–2,–5)
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Answer:
B) K′ = (–2,2), L′ = (1,2), M′ = (1,–1), N′ = (–2,–1)
Step-by-step explanation:
Translation 2 units right adds 2 to the x-coordinate.
Translation 4 units upward adds 4 to the y-coordinate.
The translation can be represented by the relation ...
(x, y) ⇒ (x +2, y +4)
__
You can choose the correct answer by looking at the translation of K.
K(-4, -2) ⇒ K'(-4+2, -2+4) = K'(-2, 2) . . . . . matches choice B
Find an equation of the line through the given pair of points. (-7,-5) and (-1,-9) The equation of the line is (Simplify your answer. Type an equation using x and y as the variables. Use integers or fractions for any numbers in the equation.) please help
Answer:
The equation of the line is y = -2/3x - 29/3
Step-by-step explanation:
The slope of these points (-7,-5) and (-1,-9) is m = -2/3
Once you plug that into the y = mx + b equation, you can see that the y-intercept is -29/3.
Put all of that into the y = mx + b equation and you'll get --> y = -2/3x - 29/3
The diagram shows APQR. Which term describes point S?
Answer:
c) centroid
Step-by-step explanation:
The times to complete an obstacle course is normally distributed with mean 87 seconds and standard deviation 7 seconds. What is the probability that a randomly selected finishing time is greater than 80 seconds? Use the empirical rule
The probability that a randomly selected finishing time is greater than 80 seconds is 0.84.
How to calculate the probability?Mean = 87
Standard deviation = 7
We convert this to standard normal as
P( X < x) = P( Z < x - Mean / SD)
Since, 80 = 87 - 7
80 is one standard deviation below the mean.
Using the empirical rule, about 68% of data falls between 1 standard deviation of the mean. So, 32% is outside the 1 standard deviation of the mean, and 16% is outside to either side.
We have to calculate P( X > 80) = ?
That is probability of all values excluding lower tail of the distribution.
P(X > 80) = 68% + 16%
= 84%
= 0.84
Learn more about probability on:
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Suppose that one state’s license plates consist of 1 digit followed by 4 letters followed by 2 digits. How many such plates can the state issue?
Answer:
The state can issue 456,976,000 license plates.
Step-by-step explanation:
For digits, it is assumed that we can use 0-9. Thus, there are 10 options for each slot with a digit.
For letters, it is assumed that we can use the 26 letters of the alphabet (i.e. A through Z). Thus, there are 26 options for each slot with a letter.
For this particular problem, the slot method can be used. Assuming that repetition of letters/digits is allowed:
[tex]\frac{10}[/tex] [tex]\frac{26}[/tex] [tex]\frac{26}[/tex] [tex]\frac{26}[/tex] [tex]\frac{26}[/tex] [tex]\frac{10}[/tex] [tex]\frac{10}[/tex]
= 10*26*26*26*26*10*10
=456,976,000.
Therefore, the state can issue 456,976,000 license plates.
x(x+3)(x+3)=0 Plz I need this fast!
Answer:
x=0,-3
Step-by-step explanation:
x(x+3)(x+3)=0
Using the zero product property
x=0 x+3=0 x+3 =0
x=0 x=-3 x=-3
What is 9,000,000 + 8,000 + 90,000,000 + 100 + 2 + 90,000 + 90 in standard form?
Answer:
9×10^7 + 9×10^6 + 9×10^4 + 8×10^3 + 1 ×10^2 + 9×10 + 2
please mark this answer as brainlist
what is 4 and 5???????
Answer:
586 cm^3 and 486 in^2
Step-by-step explanation:
4) The volume of the triangular prims is (1/2)*(a*c*h) = 0.5*(8*9*16)=586 cm^3
5) Wrapping paper needed is equal to the surface area of the cube, 6s^2=486 in^2
Tyra has recently inherited $5400, which she wants to deposit into an IRA account. She has determined that her two best bets are an account that compounds semi-
annually at an annual rate of 3.1 % (Account 1) and an account that compounds continuously at an annual rate of 4 % (Account 2).
Step 2 of 2: How much would Tyra's balance be from Account 2 over 3.7 years? Round to two decimal places.
The focus here is the use of "Compounding interest rate" and these entails addition of interest to the principal sum of the deposit.
Tyra will definitely prefer the Account 2 over the Account 1 Tyra balance from account 2 over 3.7 years is $6,261.37
The below calculation is to derive maturity value when annual rate of 3.1% is applied.
Principal = $5,400
Annual rate = 3.1% semi-annually for 1 years
A = P(1+r/m)^n*t where n=1, t=2
A = 5,400*(1 + 0.031/2)^1*2
A = 5,400*(1.0155)^2
A = 5,400*1.03124025
A = 5568.69735
A = $5,568.70.
In conclusion, the accrued value she will get after one years for this account is $5,568.70,
- The below calculation is to derive maturity value when the amount compounds continuously at an annual rate of 4%
Principal = $5,400
Annual rate = 4% continuously
A = P.e^rt where n=1
A = 5,400 * e^(0.04*1)
A = 5,400 * 1.04081077419
A = 5620.378180626
A = 5620.378180626
A = $5,620.39.
In conclusion, the accrued value she will get after one years for this account is $5,620.39.
Referring to how much would Tyra's balance be from Account 2 over 3.7 years. It is calculated as follows:
Annual rate = 4% continuously
A = P.e^rt where n=3.7
A = 5,400 * e^(0.04*3.7)
A = 5,400 * e^0.148
A = 5,400 * 1.15951289636
A = 6261.369640344
A = $6,261.37
Therefore, the accrued value she will get after 3.7 years for this account is $6,261.37
Learn more about Annual rate here
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Which proportion could be used to determine if the figure ms represent a dilation
Step-by-step explanation:
Three-halves = 4 = 6
HOPE SO IT HELP'S YOU
A pole that is 3 m tall casts a shadow that is 1.23 m long. At the same time, a nearby building casts a shadow that is 42.75 m long. How tall is the building? round your answer to the nearest meter.
Answer:
Hello,
Just using the theorem of Thalès,
Step-by-step explanation:
Let say h the hight of the building
[tex]\dfrac{h}{3} =\dfrac{42.75}{1.23}\\\\h=104.268296...\approx{104(m)}[/tex]
Thank you guys fir the help
Jorge plans to paint a bedroom wall that is shaped like a trapezoid. The bottom edge of the wall is 22.5 feet long, and the top edge of the wall is 9.5 feet long. If the wall is 8 feet tall, what is the area of the wall? Round your answer to the nearest hundredth if necessary.
5 2/10 x -10 1/3
WILL GIVE BRAINLIEST!!!
Answer:
[tex]106 \frac{3}{5}[/tex]
Explanation:
Convert any mixed numbers to fractions.
Reduce fractions where possible.
Then your initial equation becomes:
[tex]\frac{26}{5} \times \frac{-31}{3}[/tex]
Next, apply the fractions formula for multiplication. Formula below:
[tex]\dfrac{a}{b} \times \dfrac{c}{d} = \dfrac{a \times c}{b \times d}[/tex]
[tex]= \frac{26 \times -41}{5 \times 2}= \frac{-1066}{10}[/tex]
Simplifying -1066/10, (you can do this by using division) the answer is:
[tex]106 \frac{3}{5}[/tex]
Answer:
-3 1/3
Step-by-step explanation:
5 2/10 x -10 1/3
10/10 x -10/3
1 x-10/3
-10/3
-3 1/3
your question is unclear. I think I understand it correctly
What percent is modeled by the grid?
A grid model with 100 squares. 33 squares are shaded.
23%
30%
33%
40%
Answer
33 percent
Step-by-step explanation:
Answer:
33 squares are shaded 23%
Step-by-step explanation:
I hope this answer works out for you if it doesn't I'm really sorry have a great day
The The Laplace Transform of a function , which is defined for all , is denoted by and is defined by the improper integral , as long as it converges. Laplace Transform is very useful in physics and engineering for solving certain linear ordinary differential equations. (Hint: think of as a fixed constant) 1. Find (hint: remember integration by parts)
Answer:
a. L{t} = 1/s² b. L{1} = 1/s
Step-by-step explanation:
Here is the complete question
The The Laplace Transform of a function ft), which is defined for all t2 0, is denoted by Lf(t)) and is defined by the improper integral Lf))s)J" e-st . f(C)dt, as long as it converges. Laplace Transform is very useful in physics and engineering for solving certain linear ordinary differential equations. (Hint: think of s as a fixed constant) 1. Find Lft) (hint: remember integration by parts) A. None of these. B. O C. D. 1 E. F. -s2 2. Find L(1) A. 1 B. None of these. C. 1 D.-s E. 0
Solution
a. L{t}
L{t} = ∫₀⁰⁰[tex]e^{-st}t[/tex]
Integrating by parts ∫udv/dt = uv - ∫vdu/dt where u = t and dv/dt = [tex]e^{-st}[/tex] and v = [tex]\frac{e^{-st}}{-s}[/tex] and du/dt = dt/dt = 1
So, ∫₀⁰⁰udv/dt = uv - ∫₀⁰⁰vdu/dt w
So, ∫₀⁰⁰[tex]e^{-st}t[/tex] = [[tex]\frac{te^{-st}}{-s}[/tex]]₀⁰⁰ - ∫₀⁰⁰ [tex]\frac{e^{-st}}{-s}[/tex]
∫₀⁰⁰[tex]e^{-st}t[/tex] = [[tex]\frac{te^{-st}}{-s}[/tex]]₀⁰⁰ - ∫₀⁰⁰ [tex]\frac{e^{-st}}{-s}[/tex]
= -1/s(∞exp(-∞s) - 0 × exp(-0s)) + [tex]\frac{1}{s}[/tex] [[tex]\frac{e^{-st} }{-s}[/tex]]₀⁰⁰
= -1/s[(∞exp(-∞) - 0 × exp(0)] - 1/s²[exp(-∞s) - exp(-0s)]
= -1/s[(∞ × 0 - 0 × 1] - 1/s²[exp(-∞) - exp(-0)]
= -1/s[(0 - 0] - 1/s²[0 - 1]
= -1/s[(0] - 1/s²[- 1]
= 0 + 1/s²
= 1/s²
L{t} = 1/s²
b. L{1}
L{1} = ∫₀⁰⁰[tex]e^{-st}1[/tex]
= [[tex]\frac{e^{-st} }{-s}[/tex]]₀⁰⁰
= -1/s[exp(-∞s) - exp(-0s)]
= -1/s[exp(-∞) - exp(-0)]
= -1/s[0 - 1]
= -1/s(-1)
= 1/s
L{1} = 1/s
Can someone help me with this
Answer:
Step-by-step explanation:
If two triangles have two congruent sides and a congruent non included angle, then triangles are not necessarilly congruent.
The width of a rectangle is three units less than the length if the area is 28 square units then find the dimensions of the rectangle
Let
width be xLength=x+3ATQ
[tex]\\ \sf \longmapsto Area=Length\times Width[/tex]
[tex]\\ \sf \longmapsto x(x+3)=28[/tex]
[tex]\\ \sf \longmapsto x^2+3x=28[/tex]
[tex]\\ \sf \longmapsto x^2+3x-28=0[/tex]
[tex]\\ \sf \longmapsto x^2+7x-4x-28=0[/tex]
[tex]\\ \sf \longmapsto x(x+7)-4(x+7)=0[/tex]
[tex]\\ \sf \longmapsto (x-4)(x+7)=0[/tex]
[tex]\\ \sf \longmapsto x=4\:or\:x=-7[/tex]
Ignore negative value[tex]\\ \sf \longmapsto Width=4units[/tex]
[tex]\\ \sf \longmapsto Length=4+3=7units[/tex]
In ∆ ABC,AD is the altitude from A to BC .Angle B is 48°,angle C is 52° and BC is 12,8 cm. Determine the length of AD
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Answer:
7,6 cm
Step-by-step explanation:
The law of sines can be used to find the length AB.
AB/sin(C) = BC/sin(A)
A = 180° -48° -52° = 80°
AB = BC·sin(C)/sin(A) = 12,8·sin(52°)/sin(80°)
The sine function can be used to find AD from AB.
AD/AB = sin(48°)
AD = AB·sin(48°) = 12,8·sin(48°)sin(52°)/sin(80°)
AD ≈ 7,61 cm
__
The dimension of interest is ha in the attachment, the height from vertex A.
(a − 1/a)^2 − (a + 1/a)^2 =
(A) 4
(B) -4
(C) 2
(D) -2
(E) 2a
Answer:
(B) -4
Step-by-step explanation:
so, do the multiplications and see :
(a - 1/a)² = a² - 2×a/a + 1/a² = a² - 2 + 1/a²
(a + 1/a)² = a² + 2×a/a + 1/a² = a² + 2 + 1/a²
now we need to subtract the second from the first :
(a² - 2 + 1/a²) - (a² + 2 + 1/a²) =
= a² - 2 + 1/a² - a² - 2 - 1/a² = -4
and that's it !
For a given function ƒ(x) = x2 – x + 1, the operation –ƒ(x) = –(x2 – x + 1) will result in a
A) reflection across the x-axis.
B) horizontal shrink.
C) reflection across the y-axis.
D) vertical shrink.
Given:
The function is:
[tex]f(x)=x^2-x+1[/tex]
To find:
The result of the operation [tex]-f(x)=-(x^2-x+1)[/tex].
Solution:
If [tex]g(x)=-f(x)[/tex], then the graph of f(x) is reflected across the x-axis to get the graph of g(x).
We have,
[tex]f(x)=x^2-x+1[/tex]
The given operation is:
[tex]-f(x)=-(x^2-x+1)[/tex]
So, it will result in a reflection across the x-axis.
Therefore, the correct option is A.
Answer:
A) reflection across the x-axis.
Step-by-step explanation: I took the test
A card is drawn from a well shuffled deck of 52 cards what is the probability of drawing an ace or a six
Answer:
8/52
Step-by-step explanation:
The first thing to do is write it out;
How many aces are in a deck and how many sixes?
There are 4 of each so, 4+4 = 8 therefore our beginning ratio will be;
8/52 cards are going to be an ace or a six.
The sum of two numbers is 21. Five times the first number added to 2 times the second number is 66. Find the two numbers.
If you were asked to measure the success of a campaign to fight for human rights, what criteria would you use?
Step-by-step explanation:
Many factors would be used to assess the effectiveness of a human rights campaign, including the following:
Social Influence. Direct Interpersonal Reach. Participant Observation. Reputation. Volume of Search & Interest. Website Traffic.
National Research.
(2i+1)/(1+i) is equal to
Answer:
Step-by-step explanation:
(1 + 2i) / (1 + i) Rationalize the denominator.
(1 + 2i)(1+i) / (1 + i)(1-i) Remove the brarckets
(1 + i + 2i - 2) / (1 - i + i - i^2) Combine
-1 + 3i / (2) i^2 = - 1 in the denominator
help with q25 please. Thanks.
First, I'll make f(x) = sin(px) + cos(px) because this expression shows up quite a lot, and such a substitution makes life a bit easier for us.
Let's apply the first derivative of this f(x) function.
[tex]f(x) = \sin(px)+\cos(px)\\\\f'(x) = \frac{d}{dx}[f(x)]\\\\f'(x) = \frac{d}{dx}[\sin(px)+\cos(px)]\\\\f'(x) = \frac{d}{dx}[\sin(px)]+\frac{d}{dx}[\cos(px)]\\\\f'(x) = p\cos(px)-p\sin(px)\\\\ f'(x) = p(\cos(px)-\sin(px))\\\\[/tex]
Now apply the derivative to that to get the second derivative
[tex]f''(x) = \frac{d}{dx}[f'(x)]\\\\f''(x) = \frac{d}{dx}[p(\cos(px)-\sin(px))]\\\\ f''(x) = p*\left(\frac{d}{dx}[\cos(px)]-\frac{d}{dx}[\sin(px)]\right)\\\\ f''(x) = p*\left(-p\sin(px)-p\cos(px)\right)\\\\ f''(x) = -p^2*\left(\sin(px)+\cos(px)\right)\\\\ f''(x) = -p^2*f(x)\\\\[/tex]
We can see that f '' (x) is just a scalar multiple of f(x). That multiple of course being -p^2.
Keep in mind that we haven't actually found dy/dx yet, or its second derivative counterpart either.
-----------------------------------
Let's compute dy/dx. We'll use f(x) as defined earlier.
[tex]y = \ln\left(\sin(px)+\cos(px)\right)\\\\y = \ln\left(f(x)\right)\\\\\frac{dy}{dx} = \frac{d}{dx}\left[y\right]\\\\\frac{dy}{dx} = \frac{d}{dx}\left[\ln\left(f(x)\right)\right]\\\\\frac{dy}{dx} = \frac{1}{f(x)}*\frac{d}{dx}\left[f(x)\right]\\\\\frac{dy}{dx} = \frac{f'(x)}{f(x)}\\\\[/tex]
Use the chain rule here.
There's no need to plug in the expressions f(x) or f ' (x) as you'll see in the last section below.
Now use the quotient rule to find the second derivative of y
[tex]\frac{d^2y}{dx^2} = \frac{d}{dx}\left[\frac{dy}{dx}\right]\\\\\frac{d^2y}{dx^2} = \frac{d}{dx}\left[\frac{f'(x)}{f(x)}\right]\\\\\frac{d^2y}{dx^2} = \frac{f''(x)*f(x)-f'(x)*f'(x)}{(f(x))^2}\\\\\frac{d^2y}{dx^2} = \frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2}\\\\[/tex]
If you need a refresher on the quotient rule, then
[tex]\frac{d}{dx}\left[\frac{P}{Q}\right] = \frac{P'*Q - P*Q'}{Q^2}\\\\[/tex]
where P and Q are functions of x.
-----------------------------------
This then means
[tex]\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2} + \left(\frac{f'(x)}{f(x)}\right)^2 + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2}{(f(x))^2} +\frac{(f'(x))^2}{(f(x))^2} + p^2\\\\\frac{f''(x)*f(x)-(f'(x))^2+(f'(x))^2}{(f(x))^2} + p^2\\\\\frac{f''(x)*f(x)}{(f(x))^2} + p^2\\\\[/tex]
Note the cancellation of -(f ' (x))^2 with (f ' (x))^2
------------------------------------
Let's then replace f '' (x) with -p^2*f(x)
This allows us to form ( f(x) )^2 in the numerator to cancel out with the denominator.
[tex]\frac{f''(x)*f(x)}{(f(x))^2} + p^2\\\\\frac{-p^2*f(x)*f(x)}{(f(x))^2} + p^2\\\\\frac{-p^2*(f(x))^2}{(f(x))^2} + p^2\\\\-p^2 + p^2\\\\0\\\\[/tex]
So this concludes the proof that [tex]\frac{d^2y}{dx^2} + \left(\frac{dy}{dx}\right)^2 + p^2 = 0\\\\[/tex] when [tex]y = \ln\left(\sin(px)+\cos(px)\right)\\\\[/tex]
Side note: This is an example of showing that the given y function is a solution to the given second order linear differential equation.
