Find value of x of angles

Answer:

The lorry travels by 6 mph more than the expected speed.

Step-by-step explanation:

Velocity formula:

Velocity is distance divided by time, that is:

[tex]v = \frac{d}{t}[/tex]

Shortest route:

400 miles in 10 hours, which means that [tex]d = 400, v = 10[/tex]. So

[tex]v = \frac{d}{t} = \frac{400}{10} = 40[/tex]

In mph.

The lorry actually travels by a different route which increases the distance by 15%, but it still arrives in 10 hours.

Distance is multiplied by 100% + 15% = 115% = 1.15, so:

[tex]d = 1.15*400 = 460[/tex]

Then

[tex]v = \frac{d}{t} = \frac{460}{10} = 46[/tex]

46 mph

By how many more mph than the expected speed does the lorry travel?

46 - 40 = 6 mph

The lorry travels by 6 mph more than the expected speed.

Answer: 45 pencils were in the box originally

Step-by-step explanation:

Suppose there were x pencils in the box originally. Since 18 pencils is equal to 2/5 of the total number of pencils in the box originally, set 18 equal to 2/5x or

18=2/5x

Now solve

x = 18x5/2 = 45

Step-by-step explanation:

7x-21 = 5x +15

7x-5x = 15 + 21

2x = 36

x = 36/2

x = 18

Answer:

x=18

Step-by-step explanation:

Distribute 7 through the parentheses

7x-21=5(x+3)

Move the variable to the left -hand side and change its sign

7x-21-5x=15

Collect like terms

2x=15+21

divide both sides of the equation by 2

x=18

Answer:

It is possible, because the two shortest sides have to add up to be more than the longest side, and 8 + 12 = 20, which is more than the longest side of 17.

So yes, I agree with Bear.

Answer:

Equation = (x - 6 )² + ( y + 3 )² = 9

Step-by-step explanation:

The circle passes through ( 6, 0) and  ( 6 , -6)

They are the coordinates of the diameter.

Using this we can find the centre of the circle.

Find the centre of the circle.

Centre of the circle is the mid- point of (6, 0) and ( 6, -6)

      [tex]Centre = (\frac{x_1+x_2}{2} , \frac{y_1 + y_2}{2})[/tex]

                 [tex]=(\frac{6 + 6}{2}, \frac{0 + (-6)}{2})\\\\=(6, -3)[/tex]

Find the radius of the circle.

[tex]Radius = \frac{Diameter }{2}[/tex]

Diameter is the distance between the points (6 , 0) and ( 6, - 6)

[tex]Diameter = \sqrt{(x_2 - x_1)^2+ (y_2 - y_1)^2\\}[/tex]

               [tex]=\sqrt{(6-6)^2 + (-6 -0)^2}\\\\=\sqrt{0 + 36} \\\\= 6[/tex]

Therefore,

    [tex]Radius ,r = \frac{6}{2} = 3[/tex]

Standard equation of a circle:

[tex](x - a)^2 + (y - b)^2 = r^2 \ where \ (a , b) \ is \ the\ centre \ coordinates.[/tex]

Therefore , equation of the circle ;

                    [tex](x - 6)^2 + (y + 3)^2 = 3^2\\\\(x -6)^2 + (y + 3)^2 = 9[/tex]

Answer:

2.45.250- 94.750

= 92. 2975. this is the learners who got the admission

Answer:

1,50,500 students

Step-by-step explanation:

Hope this helps... vote as brainliest

Answer:

-4

Step-by-step explanation:

f(0)=(-2/3)(0) - 4

= - 4

Answer:

276 cm^2

Step-by-step explanation:

Separate figure into triangular and rectangular prisms.

SA of triangular prism (finding each area of a face and add them all up)

4 x 5 = 20 cm^2

13 x 4 = 52 cm^2

1/2 x 12 x 5 = 30 cm^2

1/2 x 12 x 5 = 30 cm^2

20 + 52 + 30 + 30 = 132 cm^2

SA of triangular prism is 132 cm^2

SA of rectangular prism (do the same thing):

12 x 4 = 48 cm^2

12 x 3 = 36 cm^2

12 x 3 = 36 cm^2

3 x 4 = 12 cm^2

3 x 4 = 12 cm^2

48 + 36 +36 + 12 + 12 = 144

Add the SA OF BOTH PRISMS:

144 + 132 = 276 cm^2

Answer:

B'(4, 0)

Step-by-step explanation:

B (1, 5)

it translated right 3 units => x'=x+3

down 5 units => y'= y-5

Answer:

m = 6

n = 2√3

Step-by-step explanation:

Reference angle = 30°

Hypotenuse = 4√3

Opposite = n

Adjacent = m

✔️To find m, apply CAH:

Cos θ = Adj/Hypo

Substitute

Cos 30° = m/4√3

4√3 × Cos 30° = m

4√3 × √3/2 = m (cos 30 = √3/2)

(4*3)/2 = m

6 = m

m = 6

✔️To find n, apply SOH:

Sin θ = Opp/Hypo

Substitute

Sin 30° = n/4√3

4√3 × Sin 30° = n

4√3 × ½ = n (Sin 30 = ½)

2√3 = n

n = 2√3

Answer:

Step-by-step explanation:

1. Do not see a figure, and unsafe to download and execute .docx.

2. Vectors LM<5,-5>, NM<3,3>, NL<2,-8>

Since LM.NM = 15-15 = 0, LM and NM are orthogonal, hence the given points form a right triangle.

3. A parallelogram has opposite sides parallel.

Slope PQ = (4-2) / (-1 - -6) = 2/5

Slope RS = (2-0) / (2- -3) = 2/5

Therefore PQ || RS

Slope PS = (2-0)/(-6- -3) = -2/3

Slope QR = (4-2)/(-1 -2) = -2/3

Therefore PS | QR

Since opposite sides are parallel, PQRS is a parallelogram

Answer:

Step-by-step explanation:

1. There are 31 complete are almost complete squares.

Top line is about 3.5 squares

Right side is about 1.8

Bottom about 3.5 and left side about 1.2.

Total approximately 41 square units.

2. If it is a right triangle then 2 sides will be perpendicular.

Slope of LM = (-1-4)/(3 +2 = -1

Slope of MN = (-4+1)/ -3 = -3/-3 = 1.

So as the product of the slope = -1 * 1 = -1 the angles between LM and MN is a right angle and LMN is a right triangle.

Answer

19.013.153,42629466 giây

Step-by-step explanati

van toc ánh sán  =299.792.458 m/s

s= v*t

t=s/v

t= 5.699.999.999.999.999/299.792.458= 19.013.153,42629466 giây

Answer:

Step-by-step explanation:

2x − y = 4

2x − 4 = y

y = 2x - 4

negative inverse of slope is perpendicular

y = -1/2 x - 4

~~~~~~~~~~~~~~~~~~~~~~~

point slope form  of a line

(-5, 1) & m = -1/2

1 = -1/2 (-5) + b

1 = 5/2 + b

b = -3/2

Final answer:  y = -1/2 x - 3/2

or if you prefer: 2y + x = -3

Answer:

2

Step-by-step explanation:

ordered pairs are

(2 , 3) = (x1 , y1)

(5 , 9) = (x2 , y2)

slope = y2 - y2 / x2 - x1

= 9 - 3 / 5 - 2

= 6 / 3

= 2

Answer and Step-by-step explanation:

The answer is the second answer choice. y = 2x + 1

By looking at the graph, we see that there is a y-intercept at (0, 1), and it has a positive slope of 2.

#teamtrees #PAW (Plant and Water)

9514 1404 393

Answer:

  21 1/3 grams

Step-by-step explanation:

The mass is the product of the volume and the density. The volume of a cube is the cube of its edge dimension.

  M = Vρ

  M = (4 cm)³×(3 g/cm³) = 64/3 g

The mass of the cube is 64/3 = 21 1/3 grams.

9514 1404 393

Answer:

  d, b, c, a, e

Step-by-step explanation:

The order of the letters in the congruence statement tells you ...

  ΔQOP ≅ ΔABC

  ∠Q ≅ ∠A

  ∠O ≅ ∠B ≅ 115°

  ∠P ≅ ∠C

  QO ≅ AB = 5 m

  OP ≅ BC = 8 m

  PQ ≅ CA

Answer:

A= ~2.55

Step-by-step explanation:

Using Pemdos, or gemdos, you can find you do the exponent first

4^2 = 16

then to everything else in left to right order since they're all multiplication or division

22/7 = ~3.14 * 13 = ~40.86/16 = ~2.55

(I'm using "~" to mean about/rounded to)

Answer:

False

Step-by-step explanation:

3a + bc = 16.

Let a=4 b=6 c=3

3(4) + 6*3 = 16

Multiply

12+18 =16

30 = 16

False

Answer:

False!

Step-by-step explanation:

There is no a variable that is given, though I'm going to assume you mean that x=4 is supposed to be a=4. If I'm mistaken, there isn't much to say about whether the statement is true or false, because there's no false statement as it'd give you a=? and you can't prove or disprove this information without more information.

If my assumption is correct, we'll first start solving this problem by substituting in the variables, which would give us: 3(4)+(6)(3)=16

Then, we'll evaluate 3(4) first, because of order of operations, which gives us 12. To reiterate the problem, we now have: 12+(6)(3)=16 From here, we can already tell this is going to be a false statement, as there is no way 6 times anything but zero will give a sum less than 6, but if you didn't catch that, we can continue with our next step.

Evaluate (6)(3) in order to get 18, in order to get: 12+18=16

And finally, we'll add. 12+18 is 30, which as we know, is not equal to 16, so that makes this statement false. 30≠16

Answer:

(a):

Dannette                   Alphonso

[tex]\bar x_D = 4.33[/tex]                    [tex]\bar x_A = 5.17[/tex]

[tex]M_D = 2.5[/tex]                    [tex]M_A = 5[/tex]

[tex]\sigma_D = 3.350[/tex]                  [tex]\sigma_A = 1.951[/tex]

[tex]IQR_D = 7[/tex]                  [tex]IQR_A = 1.5[/tex]

(b):

Measure of center: Median

Measure of spread: Interquartile range

(c):

There are no outliers in Dannette's dataset

There are outliers in Alphonso's dataset

Step-by-step explanation:

Given

See attachment for the appropriate data presentation

Solving (a): Mean, Median, Standard deviation and IQR of each

From the attached plots, we have:

IQR_A = 1.5 ---- Dannette

[tex]A = \{3,4,4,4,4,5,5,5,5,6,6,11\}[/tex] ---- Alphonso

n = 12 --- number of dataset

Mean

The mean is calculated

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x_D = \frac{1+1+1+1+2+2+3+7+8+8+9+9}{12}[/tex]

[tex]\bar x_D = \frac{52}{12}[/tex]

[tex]\bar x_D = 4.33[/tex] --- Dannette

[tex]\bar x_A = \frac{3+4+4+4+4+5+5+5+5+6+6+11}{12}[/tex]

[tex]\bar x_A = \frac{62}{12}[/tex]

[tex]\bar x_A = 5.17[/tex]  --- Alphonso

Median

The median is calculated as:

[tex]M = \frac{n + 1}{2}th[/tex]

[tex]M = \frac{12 + 1}{2}th[/tex]

[tex]M = \frac{13}{2}th[/tex]

[tex]M = 6.5th[/tex]

This implies that the median is the mean of the 6th and the 7th item.

So, we have:

[tex]M_D = \frac{2+3}{2}[/tex]

[tex]M_D = \frac{5}{2}[/tex]

[tex]M_D = 2.5[/tex] ---- Dannette

[tex]M_A = \frac{5+5}{2}[/tex]

[tex]M_A = \frac{10}{2}[/tex]

[tex]M_A = 5[/tex]  ---- Alphonso

Standard Deviation

This is calculated as:

[tex]\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}[/tex]

So, we have:

[tex]\sigma_D = \sqrt{\frac{(1 - 4.33)^2 +.............+(9- 4.33)^2}{12}}[/tex]

[tex]\sigma_D = \sqrt{\frac{134.6668}{12}}[/tex]

[tex]\sigma_D = 3.350[/tex] ---- Dannette

[tex]\sigma_A = \sqrt{\frac{(3-5.17)^2+............+(11-5.17)^2}{12}}[/tex]

[tex]\sigma_A = \sqrt{\frac{45.6668}{12}}[/tex]

[tex]\sigma_A = 1.951[/tex] --- Alphonso

The Interquartile Range (IQR)

This is calculated as:

[tex]IQR =Q_3 - Q_1[/tex]

Where

[tex]Q_3 \to[/tex] Upper Quartile       and        [tex]Q_1 \to[/tex] Lower Quartile

[tex]Q_3[/tex] is calculated as:

[tex]Q_3 = \frac{3}{4}*({n + 1})th[/tex]

[tex]Q_3 = \frac{3}{4}*(12 + 1})th[/tex]

[tex]Q_3 = \frac{3}{4}*13th[/tex]

[tex]Q_3 = 9.75th[/tex]

This means that [tex]Q_3[/tex] is the mean of the 9th and 7th item. So, we have:

[tex]Q_3 = \frac{1}{2} * (8+8) = \frac{1}{2} * 16[/tex]           [tex]Q_3 = \frac{1}{2} * (5+6) = \frac{1}{2} * 11[/tex]

[tex]Q_3 = 8[/tex] ---- Dannette                 [tex]Q_3 = 5.5[/tex] --- Alphonso

[tex]Q_1[/tex] is calculated as:

[tex]Q_1 = \frac{1}{4}*({n + 1})th[/tex]

[tex]Q_1 = \frac{1}{4}*({12 + 1})th[/tex]

[tex]Q_1 = \frac{1}{4}*13th[/tex]

[tex]Q_1 = 3.25th[/tex]

This means that [tex]Q_1[/tex] is the mean of the 3rd and 4th item. So, we have:

[tex]Q_1 = \frac{1}{2}(1+1) = \frac{1}{2} * 2[/tex]                  [tex]Q_1 = \frac{1}{2}(4+4) = \frac{1}{2} * 8[/tex]

[tex]Q_1 = 1[/tex] --- Dannette                   [tex]Q_1 = 4[/tex] ---- Alphonso

So, the IQR is:

[tex]IQR = Q_3 - Q_1[/tex]

[tex]IQR_D = 8 - 1[/tex]                                     [tex]IQR_A = 5.5 - 4[/tex]

[tex]IQR_D = 7[/tex] --- Dannette                      [tex]IQR_A = 1.5[/tex] --- Alphonso

Solving (b): The measures to compare

Measure of  center

By observation, we can see that there are outliers is the plot of Alphonso (because 11 is far from the other dataset) while there are no outliers in Dannette plot (as all data are close).

Since, the above is the case; we simply compare the median of both because it is not affected by outliers

Measure of  spread

Compare the interquartile range of both, as it is arguably the best measure of spread, because it is also not affected by outliers.

Solving (c): Check for outlier

To check for outlier, we make use of the following formulas:

[tex]Lower =Q_1 - 1.5 * IQR[/tex]

[tex]Upper =Q_3 + 1.5 * IQR[/tex]

For Dannette:

[tex]Lower = 1 - 1.5 * 7 = -9.5[/tex]

[tex]Upper = 8 + 1.5 * 7 = 18.5[/tex]

Since, the dataset are all positive, we change the lower outlier to 0.

So, the valid data range are:

[tex]Valid = 0 \to 18.5[/tex]

From the question, the range of Dannette's dataset is: 1 to 9. Hence, there are no outliers in Dannette's dataset

For Alphonso:

[tex]Lower = 4 - 1.5 * 1.5 =1.75[/tex]

[tex]Upper = 5.5 + 1.5 * 1.5 =7.75[/tex]  

So, the valid data range are:

[tex]Valid = 1.75\to 7.75[/tex]

From the question, the range of Alphonso's dataset is: 3 to 11. Hence, there are outliers in Alphonso's dataset

Answer:

CLAE

Step-by-step explanation:

1=43

2=28

3=24

4=83

Answer:

33.51 cubic inches

Step-by-step explanation:

Formula for volume of a sphere is V= 4 /3 · π · r3

We know the diameter is 4, and the radius is half the diameter, so the radius is 2.

V = 4 /3 · π · [tex]2^{3}[/tex]

≈ 33. 51032

Rounded to the nearest hundreth is 33.51.

Answer:

Step-by-step explanation:

Answer:

i believe x is 16.1

Step-by-step explanation:

hope this helps

ok check image file in the image is answers with color code

Answer:

1/2

Step-by-step explanation:

numbers taken = 1 to 40

multiples of 2 are = {2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40}

so there are 20 favourable  outcomes.

probability = 20/40

=1/2

for multiples of 3

multiples = {3,6,9,12,15,18,21,24,27,30,33,36,39}

there are 13 favourable outcomes

probability = 13/40

since there is no 13/40 the answer should be the probability of multiples of 2 i.e 1/2

Answer:

See below.

Step-by-step explanation:

Problem 2.

Left figure: 2 sides and included angle: SAS

Middle figure: 2 angles and included side: ASA

Right figure: 3 sides: SSS

Problem 3.

CPCTC = corresponding parts of congruent triangles are congruent

12z - 21 = 92

12z - 21 + 21 = 92 + 21

12z = 113

z = 113/12

Answer:

A U B={1,2,3,4,5,6,7,8,9,10} represents A union B

(includes all the members of set Sand the members of set Bout together, do not repeat anyone that comes twice)

A n B={1,4} represents A interception B( this refers to the members that sets A and B have in common)

Answer:

A ∪ B = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 }

Step-by-step explanation:

A = { 1 , 3 , 4 , 5 , 7 , 9 }

B = { 1 , 2 , 4 , 6 , 8 , 10 }

A ∪ B = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 }

           It represents the whole numbers between 0 and 11

          [ A ∪ B is the elements of both A and B , without any repetition ]    

A ∩ B = { 1 , 4 }

            It represents the common numbers in both A and B