Find the value of x. Round to the nearest tenth.

15.9
12.4
12.8
16.3

Answer:

The correct option is;

B. s ≥ 12 - t, s ≤ 30 - t, s ≤ 24 - 0.66·t

Step-by-step explanation:

The given parameters are;

The number of T-shirts, t, and shorts, s, Tim must design a day = 12

The maximum number of T-shirts and shorts Tim can design a day = 30

The maximum number of hours Tim can work = 18 hours

Therefore, we have;

The number of shorts Tim designs in a day is ≥ The minimum number of T-shirts and shorts Tim must design a day less the number of T-shirts Tim designs

Which gives;

s ≥ 12 - t

Also the number of shorts Tim designs in a day is ≤ The maximum number of T-shirts, and shorts, Tim can design a day less the number of T-shirts Tim designs

Which gives;

s ≤ 30 - t

The number of 45 minute period for the design of shorts in 18 hours = 18×60/45 = 24

The fraction of 36 minutes in 45 minutes = 36/45 = 0.667

Therefore we have;

The number of shorts Tim designs in a day is ≤ The number of 45 minute periods in 18 hours less the number of 36 minutes periods used to design T-shirts

Which gives;

s ≤ 24 - 0.66·t

The correct option is s ≥ 12 - t, s ≤ 30 - t, s ≤ 24 - 0.66·t.

Answer:

B. s> 12-tss 30 - t Ss 24 -0.66t, s 2 0; t> 0

Step-by-step explanation:

Hope this helps!!

Answer:

[tex] \boxed{13}[/tex]

Step-by-step explanation:

Arranging the data in ascending order:

8 , 8 , 10 , 11 , 13 , 13 ,13 , 14 , 14 , 15 , 16 , 17 , 18 , 18 ,

In the case of discrete data, mode can be found just by inspection, i.e just by taking an item with highest frequency.

Here, 13 has the highest frequency

So, Mode = 13

Extra information

Mode

The mode of a set of data is the value with the highest frequency. A distribution that has two modes is called bimodal. The mode of a set of data is denoted by Mo.

Hope I helped!

Best regards!

Answer:

[tex] \boxed{\sf {18}^{2} + {24}^{2} = {x}^{2}} [/tex]

To Find:

Length of hypotenuse of the right triangle i.e. x

Step-by-step explanation:

Pythagoras theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides”.

[tex] \therefore [/tex]

[tex] \sf \implies {18}^{2} + {24}^{2} = {x}^{2} [/tex]

Answer:

18²+24²=x²

Step-by-step explanation:

to answer this question you must know Pythagorean theorem

a^ 2+b^2 =c^2

a and b stands for the sides with length 24 and 18 and c stands for the HYPOTENUSE . so the correct answer for the above question is 18²+24²=x²

======================================================

Explanation:

The given exterior angle 97 is adjacent to the interior angle 180-97 = 83. This is the base angle of the isosceles triangle. The other base angle is directly above it. The base angles are always opposite the congruent sides.

The missing interior angle (adjacent to the blue angle x) is unknown, so we'll call it angle y. This angle adds to the other two base angles (83 each) to get a sum of 180. Adding any three interior angles of a triangle always gets you 180

y+83+83 = 180

y+166 = 180

y = 180-166

y = 14

Angle x and y are supplementary. They form a 180 degree angle

x+y = 180

x = 180-y

x = 180-14

x = 166

As you can see, the base angles combine to form the exterior angle we're after. This is because of the remote interior angle theorem.

Answer:

5(12 : 3) -8

Step-by-step explanation

when you solve the first half of the equation you get 1.

so 9-1 is 8.

Answer:

≈ 36.1%

Step-by-step explanation:

In any circle the following ratio is equal

[tex]\frac{arc}{circmference}[/tex] = [tex]\frac{centralangle}{360}[/tex] = [tex]\frac{130}{360}[/tex] , thus

percentage = [tex]\frac{130}{360}[/tex] × 100% ≈ 36.1%

an arc measuring 130° is approximately 36.11% of the circumference of the circle.

To find the percentage of the circumference that an arc measuring 130° represents, we need to calculate the ratio of the arc length to the circumference of the circle and then convert it to a percentage.

The circumference of a circle is given by the formula C = 2πr, where r is the radius of the circle.

Let's assume the radius of the circle is r.

The circumference of the circle is C = 2πr.

To find the length of the arc corresponding to 130°, we need to calculate the fraction of the total angle (360°) that 130° represents:

Fraction of the angle = (130° / 360°) = (13/36).

Since the fraction of the angle is equal to the fraction of the arc length to the circumference, the length of the arc can be calculated as:

Arc length = Fraction of the angle * Circumference = (13/36) * (2πr).

Now, to find the percentage of the circumference that the arc length represents, we divide the arc length by the circumference and multiply by 100:

Percentage = (Arc length / Circumference) * 100

Percentage = [(13/36) * (2πr)] / (2πr) * 100

Percentage = (13/36) * 100

Percentage = 36.11%

Therefore, an arc measuring 130° is approximately 36.11% of the circumference of the circle.

Learn more about arc length here

https://brainly.com/question/10266974

#SPJ2

Answer:

Hey there!

6(x-5)

6(7-5)

6(2)

12

Hope this helps :)

Answer:

12

Step-by-step explanation:

Replace x by 7 in 6(x-5) to be able to evaluate the expression.

● 6(x-5)

● 6(7-5)

● 6 × 2

● 12

So the expression is equal to 12 when x=7

Answer:

3053.5517 cm^3 ; 1/8

Step-by-step explanation:

Given the following :

Volume (V) of sphere = (4/3)πr^3 where r = radius

Diameter of sphere = 18 ; radius(r) = diameter / 2 = 18/2 = 9cm

V = (4/3) × π × 9^3

V = 1.3333 × π × 729

V = 3053.5517 cm^3

When diameter(d) is reduced to half

d = d/2

Volume (V1) of sphere with diameter 'd' =

V1 = (4/3)π(d/2)^3

Volume (V2) of sphere with diameter 'd' reduced to half, d = d/2, d/2 * 1/2 = d/4

V2 = (4/3)π(d/4)^3

V1 / V2 = [(4/3)π(d/2)^3] / [(4/3)π(d/4)^3]

V1 / V2 = (d/2)^3 / (d/4)^3

V1 / V2 = [d^3 / 2^3] / [d^3 / 4^3]

V1 / V2 = 8 / 64

V1 / V2 = 1 / 8

Answer:

first blank is 972

second blank is 1/8

yup

Step-by-step explanation:

Answer:

the value of x = 9  and y =11.

Given the system of equation:

12x + 4y =152                  .......[1]

32x + 12y = 420              ......[2]

Multiply equation [1] by 3 we get;

Using distributive property:  

            ......[3]

On solving equation [2] and [3] simultaneously we get;

x = 9

Substitute the value of x= 9 in [1] to solve for y;

108 + 4y = 152

Subtract 108 from both sides we have;

108 + 4y -108 = 152- 108

Simplify:

4y = 44

Divide both sides by 4 we get;

Simplify:

y= 11

therefore, the value of x = 9  and y =11.

Answer: 0

Work Shown:

Factors of 48 = {1, 2, 3, 4, 6, 8, 12, 16, 24, 48}

Erase the odd numbers of that list to get {2, 4, 6, 8, 12, 16, 24, 48}

Then highlight stuff that is greater than 24, and less than 48 at the same time.

No factors fit this description since 24 cannot be larger than itself, and 48 cannot be smaller than itself.

Answer: 0

Step-by-step explanation:

There is no number greater than 24 and less than 48.

Answer:

the percentage share for BBC2 remained almost the same at about 11 % each year

if you look at the chart the BBC2 almost remains stable between 10 and 12 %

1980 ( between 39 and 51)

1985 ( between 37 and 49 ) and so on

( these numbers are not exactly the same , it is about or approximately)

Answer:

354.20 + 50.60w ≥ 1099.51

Step-by-step explanation:

354.20 + 50.60w ≥ 1099.51

Answer:

[tex]\frac{5}{9}[/tex]

Step-by-step explanation:

Using the rules of exponents/ radicals

[tex]a^{\frac{m}{n} }[/tex] ⇔ [tex]\sqrt[n]{a^{m} }[/tex] , [tex]a^{0}[/tex] = 1

[tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex]

Given

[tex]27^{-\frac{2}{3} }[/tex] × [tex]25^{\frac{1}{2} }[/tex] × [tex]5^{0}[/tex]

= [tex]\frac{1}{27^{\frac{2}{3} } }[/tex] × [tex]\sqrt{25}[/tex] × 1

= [tex]\frac{1}{9}[/tex] × 5 × 1

=[tex]\frac{5}{9}[/tex]

Step-by-step explanation: look so if you have

shcool A its 8v+4b=12

and

School B: 12v+4b= 16

since both classes used 4 busses we can use elimination by subtracting the A class Equation from the b class equation to solve from v for its value Then, use either equation and the now found value for v to solve for b.

You should find part of the process to be

12v+4b-(8v+4b)=12-16 which shows the van holds only a few people even before continuing the solution.

Answer -4

Answer:

x= -11

Step-by-step explanation:

the coefficient is variable that appears before a number . bearing this in mind, the coefficient of x is therefore 2 .

the value of x is:

>32+2x=10

>2x=10-32

>2x= -22

>x= -11

Answer:

Step-by-step explanation:

Coefficient of x = 2

32 + 2x  = 10

Subtract 32 from both side

32 + 2x -32 = 10 - 32

              2x =  - 22

Divide both sides by 2

            2x/2 = -22/2

x = -11

Answer:

Step-by-step explanation:

Adding both equations

4x+5y+5y-4x=19+38

10y = 57

y= 5.7

Subtracting equation i from ii

5y-4x-4x-5y=38-19

-8x=9

x= -0.9

Answer:

The total number of cups in arranged in an hexagonal area = 19 cups

Step-by-step explanation:

The pack the most circles within an area, the arrangement with the densest packing is the hexagonal lattice structure similar to the bee's honeycomb as has been proved Gauss and Fejes Toth.

Therefore, we pack the circles in an hexagonal lattice structure in an assumed hexagonal area where we have;

The longest straight line is five cups the next on either side are four cups and the final line on either side has three cups

The total number of cups = 3 + 4 + 5 + 4 + 3 = 19 cups

The total number of cups = 19 cups.

Answer:

STEP 1: Find the circumference:

Circumference = 2πr

Circumference = 2π(14) = 28π cm

............................................................................................

STEP 2: Find the length of the arc:

Length of the arc = 36/360 x 28π

Length of the arc = 8.8 cm

.............................................................................................

Answer: The length of the arc is 8.8 cm

............................................................................................

hope it helpssss

Mark it as brilliant answer plzzz

ФωФ

Answer:

27°

Step-by-step explanation:

arc length = circumference × fraction of circle

let x be the central angle, then

2πr × [tex]\frac{x}{360}[/tex] = 6.6

2 × [tex]\frac{22}{7}[/tex] × 14 × [tex]\frac{x}{360}[/tex] = 6.6

88 ×[tex]\frac{x}{360}[/tex] = 6.6 ( multiply both sides by 360 )

88x = 2376 ( divide both sides by 88 )

x = 27

Thus central angle is 27°

Answer: x = 3

Step-by-step explanation:

Sqrt(x+7) - 1  = x

Sqrt(x+7) = x + 1

x+7 = x^2 + 1

x = x^2 - 6

x=3

50 plants total, 40% are vegetables

40% = 40/100 = 0.40

40% of 50 = 0.40*50 = 20

Answer:

[tex]\huge\boxed{f = 5\ Hz}[/tex]

Step-by-step explanation:

Given:

Time period = T = 0.2 sec

Required:

Frequency = f = ?

Formula:

f = 1/T

Solution:

f = 1/0.2

f = 5 Hertz

Answer:

[tex] \boxed{\sf Frequency \ (f) \ of \ the \ wave = 5 \ Hz} [/tex]

Given:

Time Period (T) = 0.2 s

To Find:

Frequency (f) of the wave

Step-by-step explanation:

[tex] \sf Frequency (f) = \frac{1}{Time Period (T)} [/tex]

[tex] \sf f = \frac{1}{0.2} [/tex]

[tex] \sf f = \frac{1}{0.2} \times \frac{10}{10} [/tex]

[tex] \sf f = \frac{10}{2} [/tex]

[tex] \sf f = \frac{ \cancel{2} \times 5}{ \cancel{2}} [/tex]

[tex] \sf f = 5 \: Hz[/tex]

Answer:

[tex]\dfrac{1}{6561}[/tex]

Step-by-step explanation:

Given the expression [tex][(2^{-2})(3^{4})]^{-3} * [(2^{-3})(3^2)]^{2}[/tex], Using the laws of indices to simplify the expression. The following laws will be applicable;

[tex]a^m*a^n = a^{m+n}\\(a^m)^n = a^{mn}\\[/tex]

[tex]a^{-m} = 1/a^m[/tex]

Given [tex][(2^{-2})(3^{4})]^{-3} * [(2^{-3})(3^2)]^{2}[/tex]

open the parenthesis

[tex]= (2^{-2})^{-3}(3^{4})^{-3}* (2^{-3})^2(3^2)^2\\\\= 2^{-2*-3}* 3^{4*-3} * 2^{-3*2} * 3^{2*2}\\\\= 2^6 * 3^{-12} * 2^{-6} * 3^4\\\\collecting \ like \ terms\\\\= 2^6 * 2^{-6} * 3^{-12} * 3^4\\\\= 2^{6-6} * 3^{-12+4}\\\\= 2^0 * 3^{-8}\\\\= 1 * \frac{1}{3^8}\\ \\= \frac{1}{6561}[/tex]

Answer:

Your answer is correct

Step-by-step explanation:

SAS triangle is proven through b option.

Hope this helps....

Have a nice day!!!!

Answer:

C. [tex]x[/tex] and $(x-6)$

Step-by-step explanation:

The roots of the quadratic equation are $0$ and $6$.

Hence the equation is $(x-0)(x-6)=x(x-6)$

Answer:

See below

Step-by-step explanation:

Answer:

5x(25)

Step-by-step explanation:

Answer:

G

Step-by-step explanation:

let his fixed price be x and his hourly fee be y;

270 = 4y + x

420 = 7y + x

x is common in both equations

equate the two;

x = 270-4y and x = 420-7y

270-4y = 420-7y

3y = 150

y = 50

x = 270-4*50

x = 70

Answer:

f(x) = 5 * ( 8/5) ^x

Step-by-step explanation:

f(x) = a b^x

Let x = 0

5 = a * b^0

5 = a*1

a = 5

Let x = 1

8 = 5 * b^1

Divide each side by 5

8/5 = b

f(x) = 5 * ( 8/5) ^x

Answer:

Below

Step-by-step explanation:

All figures are squares. The area of a square is the side times itself

Let A be the area of the big square and A' the area of the small one in all the 5 exercices

51)

● (a) = A - A'

A = c^2 and A' = d^2

● (a) = c^2 - d^2

We can express this expression as a product.

● (b) = (c-d) (c+d)

■■■■■■■■■■■■■■■■■■■■■■■■■■

52)

● (a) = A-A'

A = (2x)^2 = 4x^2 and A'= y^2

● (a) = 4x^2 - y^2

● (b) = (2x-y) ( 2x+y)

■■■■■■■■■■■■■■■■■■■■■■■■■■

53)

● (a) = A-A'

A = x^2 and A' = y^2

● (a) = x^2-y^2

● (b) = (x+y) (x-y)

■■■■■■■■■■■■■■■■■■■■■■■■■■

54)

● (a) = A-A'

A = (5a)^2 = 25a^2 and A' =(2b)^2= 4b^2

● (a) = 25a^2 - 4b^2

● (a) = (5a-2b) (5a+2b)

■■■■■■■■■■■■■■■■■■■■■■■■■■

55)

● (a) = A - 4A'

A = (3x)^2 = 9x^2 and A'= (2y)^2 = 4y^2

● (a) = 9x^2 - 4 × 4y^2

● (a) = 9x^2 - 16y^2

● (a) = (3x - 4y) (3x + 4y)

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Answer:

The total amount left by Manavi and Kuber is: (1) 399

Step-by-step explanation:

Manavi

saving account +  amount spent at the mall:  1/'2 + 1/4 =  3/4

left over: 1 - 3/4 = 4-3/4 = 1/4

1260 ( 1/4) = 315

The total leftover for Manavi is Rs.315.

Now do the same steps with Kuber.

Kuber

saving account +  amount spent at the mall: 1/3+ 3/5 = 14/15

left over: 1- 14/15 = 15-14/15 = 1/15

1260 (1/15) = 84

The total leftover for Kuber is Rs.84.

Lastly, just add both left over amount together.

315+84 = 399

The total amount left by Manavi and Kuber is: (1) 399