Find the value of each measure.

Answer:

69.3

Step-by-step explanation:

if you put it into 2D, you get a right triangle with leg lengths 62 (vertical height) and 31 (1/2 the base's length). Using Pythagorean's Theorem you get sqrt((62^2)+(31^2))= 69.318. Rounding to the nearest tenth you get 69.3

Answer:

The answer is 12

Step-by-step explanation:

You see its because.

Answer:

?=12

Step-by-step explanation:

Using the Thalès's theorem:

[tex]\dfrac{6}{6+4}=\dfrac{?}{20} \\\\?*10=6*20\ (cross\ products)\\\\?=\dfrac{6*20}{10} \ dividing\ by\ 10\\\\?=12[/tex]

Answer:

27, 18

Step-by-step explanation:

Here's why

Answer:

40*8.5=340

6*90=540

total=880/2.5=352bags

Answer:

518

Step-by-step explanation:

solution:

=8^2^×1^+1+6^2^×1^-1

=8^3+6^1

=8^3+6

=8×8×8+6

=512+6

=518

-2a(a - d) + 2a(2a - 3d)

(-2a * a) + (-d * -2a) + (2a * 2a) + (2a * -3d)

-2a^2 + 2ad + 4a^2 - 6ad

(4a^2 - 2a^2) + (2ad - 6ad)

2a^2 - 4ad

---The above expression is simplified, though not fully. The below expression is fully simplified.

2a(a - 2d)

Hope this helps!

Answer:

Step-by-step explanation:

so you have divide  ok by my  and divide 5x1

Answer:

Step-by-step explanation:

let the height of the room(h) = x

Length(l) = 3*x = 3x

length = 2 * breadth

breadth(b) = length /2 = 3x/2

Cost of whitewashing the 4  walls = ₹ 7200

Area of 4 walls = 7200 ÷ 50 = 144 m²   ------(I)

Area of walls = 2lh + 2bh

                      = 2*3x*x + 2  *[tex]\frac{3x}{2}[/tex] * x

                       = 6x² + 3x²

                        = 9x²

9x² = 144    {From (I)}

x²  = 144/9

x²  = 16

x = [tex]\sqrt{16}=\sqrt{4*4}[/tex]

x = 4 m

height = 4 m

length = 3*4 = 12m

Breadth = [tex]\frac{3}{2}*4=3*2=6 \ m[/tex]

Area of floor = l*b

                    = 12 * 6

                    = 72 m²

Cost of carpeting the floor = 72 * 325 = ₹ 23400

Answer:

$19.68

Step-by-step explanation:

this is not really clearly defined.

I assume it means that they are buying the item, no matter how much it costs, and that the split ratio between them also remains the same no matter the actual cost.

x = what Marcia is paying

and 132 - 18% = 132 × (100 - 18) / 100 = 132×0.82 = 108.24

so,

x + x/2 + x/3 = 108.24

6x + 3x + 2x = 649.44

11x = 649.44

x = $59.04

Mario's part is x/3 = 59.04/3 = $19.68

Answer:

[tex]{18}[/tex]

Step-by-step explanation:

[tex] \sqrt{(2 - 5) {}^{2} + ( 2 - 5) {}^{2} } [/tex]

[tex] = \sqrt{( - 3) {}^{2} + ( - 3) {}^{2} } [/tex]

[tex] = \sqrt{9 + 9} [/tex]

[tex] = \sqrt{18}[/tex]

Answered by GAUTHMATH

Answer:

-2/5

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

A logarithmic function, log(x) has a domain x>0. For this logarithmic equation x+2>0, x>-2.

Answer:

The answer is 7.5

Answer:

Just use a calculator and wite the square root value in it

Step-by-step explanation:

Atempt this method with all options at last u will have ur answer

Answer

[ 1 by 2, -1 by 2 ]

Step-by-step explanation:

https://haygot.s3.amazonaws.com/questions/1118559_1200733_ans_2ec06a240d2240e49dc1c9fda7b41ef5.jpeg

Answer:

range { 1, ∞ }

Step-by-step explanation:

y = x² + 1

is a parabola with its vertex at (0, 1)

The range is { 1, ∞ }

Answer:

198 KM

Step-by-step explanation:

82.5KM/5.5L= 15KM per liter

13.2 x 15 = 198 KM

Answer:

12 minutes

Step-by-step explanation:

Given

[tex]s_1 = 10mi/h[/tex] --- walk speed

[tex]s_2 = 20mi/h[/tex] --- jog speed

[tex]d = 2\ miles[/tex] --- distance

Required

The time to walk the given distance

Time is calculated as:

[tex]Time = \frac{distance}{speed}[/tex]

In this case, the speed is the speed at which she walks.

So, we have:

[tex]Time = \frac{d}{s_1}[/tex]

Substitute known values

[tex]Time = \frac{2mi}{10mi/h}[/tex]

[tex]Time = 0.2hr[/tex]

Convert to minutes

[tex]Time = 0.2 * 60mins[/tex]

[tex]Time =12mins[/tex]

Answer:

x=0

x=6

x=-1

Step-by-step explanation:

x(x^2-5x-6)

x(x-6)(x+1)

x=0

x=6

x=-1

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Short answer: to solve this problem, follow directions.

Let c and p represent numbers of cakes and pies produced daily. Then the constraints are ...

  2c +3p ≤ 108 . . . . . . . . available hours of preparation time

  1c +0.5p ≤ 20 . . . . . . . available hours of decoration time

  p ≥ 0, c ≥ 0 . . . . . . . . . negative numbers of cakes or pies cannot be produced

__

It works well to let a graphing calculator do this.

The feasible region is the doubly-shaded area with vertices ...

  (0, 0), (0, 36), (3, 34), (20, 0)

__

Profit is $25 per cake and $12 per pie, so is ...

  p = 25c +12p

__

The attached table shows the profit for the various mixes of cakes and pies in the feasible region. The most profit is had by production of cakes only.

The maximum profit is $500 per day for production of 20 cakes.

_____

Additional comment

We have used x for cakes and y for pies in the attachment, because those are variables that the Desmos calculator prefers.

As is sometimes the case, the production point giving maximum profit leaves one of the resources (preparation time) only partially utilized.

Answer:

(1,2) is ordered pair to (-4,2).

Step-by-step explanation:

(1,2)

hora khoi thaha vayena hai

Answer:

y(x) = 2x+3

Step-by-step explanation:

the rule is y(x) = 2x+3

Answer:

70 days

Step-by-step explanation:

that is the procedure above

Answer:

A. 45%

Step-by-step explanation:

34/75=45 = 45%

Answer:

4w = -5-19

4w=-24

w=-6

hope that answers your question

good luck

9514 1404 393

Answer:

  7.56 cm

Step-by-step explanation:

The volume is given by the formula ...

  V = 1/3b²h . . . . where b is the base edge length, and h is the height.

Here we have V = 144 cm³, and b = h. Filling in these values and solving for h, we get ...

  144 cm³ = 1/3h³

  432 cm³ = h³

  h = ∛432 cm ≈ 7.55953 cm

The height of the pyramid is about 7.56 cm.

Answer:

[tex]7.56cm[/tex]

Step-by-step explanation:

Given that,

base length = Height

so,

[tex]volume = \frac{1}{3} {b}^{2} h \\ [/tex]

We can also write this as( according to this question)

[tex]v = \frac{1}{3} \times {b}^{2} \times b \\ v = \frac{ {b}^{3} }{3} [/tex]

let's solve

[tex]v = \frac{ {b}^{3} }{3} \\ 144 = \frac{ {b}^{3} }{3} \\ 144 \times 3 = {b}^{3} \\43 2 = {b}^{3} \\ \sqrt[3]{432} = b \\ b = 7.55[/tex]

[tex]base = height = 7.55cm \\ [/tex]

= 7.56cm

Answer:

Closed side up : 5/50

1/50 = open side up

44/50 = landing side

experimental probablity Formula:

no. of times event was conducted/ Total no. of times experiment was conducted.

Let's first start with open side up.

No. times it was conducted was 1.

Total no times experiment conducted:  50 times

1/50 = open side up

Closed side up

No. times it was conducted was 5

Total no times experiment conducted:  50 times

5/50

The same for landing on side :

44/50

Have a wonderful day!!

The experimental probability of each outcome (landing open side up, landing closed side up, and landing on its side) is  given as:

[tex]P_e(A) = \dfrac{1}{50} = 0.02\\\\P_e(B) = \dfrac{4}{50} = 0.08\\\\P_e(C) = \dfrac{44}{50} = 0.88\\\\[/tex]

Experimental probability calculates the probability of some event from the results of experiments.

For an event E, we get the experimental probability of that event

[tex]P_e(E) = \dfrac{\text{Number of times E occurred}}{\text{Number of times experiments was done}}[/tex]

where, [tex]P_e(E)[/tex] is denoting experimental probability of occurrence of E.

For the given case, if we name the events for results of tossing of paper cup as:

Then, as it is given that:

Number of times paper cup was tossed = 50

Thus, their experimental probabilities are obtained as:

[tex]P_e(A) = \dfrac{1}{50} = 0.02\\\\P_e(B) = \dfrac{4}{50} = 0.08\\\\P_e(C) = \dfrac{44}{50} = 0.88\\\\[/tex]

Learn more about experimental probability here:

https://brainly.com/question/2547434