Find the value of b.

Answer:

When multiplying a number by a decimal less than one, the product will be smaller than the number being multiplied. This is because we are finding a fractional amount of a quantity. For example, 0.1 x 0.8 = 0.08, because the question is asking us to find one tenth of eight tenths.

Answer:

It will always be less than both.

Step-by-step explanation:

Multiplying by something smaller than 1 will always make the result smaller, so taking something like

0.8⋅0.5 means that we are taking half of 0.8

OR 45 of 0.5 (same thing)

either way it makes it smaller, which means we will get something smaller than both.

Answer:

3rd option, 2√10

Step-by-step explanation:

x²=4×10

or, x=√(4×10)

or, x=2√10

Answer: C, 2√10

Step-by-step explanation:

Answer:

A) (√3-√2)/(√3+√2)

Step-by-step explanation:

i think so

Answer:

rounded to the nearest ten thousand

2,034,627

2,030,000

Answer:

He has 4/35 of with money left

Step-by-step explanation:

1 - 3/5 - 2/7 = 4/35

This basically answers the question

Answer:

1..

solution....

here given

25cm

1m=100cm

now,

25/100=1/4

1:4

2....

(a+4)(a-4)

a^2-4^2

a^2-16

Step-by-step explanation:

hope it will help you

=========================================================

Explanation:

We can prove this by contradiction.

Let's say

and

A+B = C

We'll show that a contradiction happens based on this.

If A is rational, then A = p/q where p,q are two integers. The q cannot be zero.

If C is rational, then C = r/s for some other integers. We can't have s be zero.

Note the following

A+B = C

B = C - A

B = r/s - p/q

B = qr/qs - ps/qs

B = (qr - ps)/qs

B = (some integer)/(some other integer)

This shows B is rational. But this is where the contradiction happens: We stated earlier that B was irrational. A number cannot be both rational and irrational at the same time. The very definition "irrational" literally means "not rational".

In short, I've shown that if A+B = C such that A,C are rational, then B must be rational as well.

The template is

rational + rational = rational

Therefore, we've shown that if A is rational and B is irrational, then C cannot possibly be rational. C is irrational.

Another template is

rational + irrational = irrational

Answer:

(x , y )  -----> (x , y -4)

Step-by-step explanation:

There is no change in x-coordinate

Compare the y-coordinate of A(-4 , 7) and A'(-4 , 3)

7 + a = 3

    a = 3 - 7

   a = -4

y-coordinate of A' = y-coordinate of A  - 4

9514 1404 393

Answer:

  D (compute the mean)

Step-by-step explanation:

A box plot is a visual representation of the 5-number summary of a set of data. It is plotted against a number line.

The 5-number summary of the data set is most easily determined from an ordered set of the data, so ordering the data is usually the first step. Since the 5-number summary is plotted against a number line, the next steps are finding the 5-number summary, and creating a suitable number line.

__

The business of adding the data and dividing by the number of data items is a description of computing the mean of the data. That value is not part of the 5-number summary, and is not needed in the creation of the box plot.

Answer:

x = 17

Step-by-step explanation:

x ^2 = 8^2+ 15^2

√x^2 =√64+225

x=17

Answer:

17cm.

Step-by-step explaination:

The given triangle is a right angled triangle.

Using Pythagorean Theorem,

a² + b² = c²

Putting the given values in the equation;

(15)² + (8)² = c²

225 + 64 = c²

289 = c²

17² = c² (square root of 289 = 17)

17 = c

c = 17

Therefore, the missing side of the triangle is equal to 17 cm.

Answer:

2x-4(x+7)=2

Step-by-step explanation:

Peter's age:x.... twice age:2x

Phil's age:x+7...4times age:4(x+7)

Difference if ages is 2

Hence; 2x-4(x+7)=2

Answer:

Answer

4.9/5

38

loitzl9006

Ambitious

54 answers

6.5K people helped

Answer:

x=25

Step-by-step explanation:

we know that "x" is Peter's age

assume that "y" is Phil's age

In the sentence "Phil's age is 7 years more than 1/5 times than Peter's age" are two things: "Phil's age": y and "1/5 times Peter's age": 1/5 x

create equation with these two things

y = 1/5 x

including "7 years more"

many people make a lot of errors with it, they dont know: y+7 = 1/5 x or y=1/5 x + 7 ?

in order to avoid mistakes

read the sentence and point, which: y or 1/5 x is greater and smaller

"Phil's age is 7 years more than ..."

so y is greater, and 1/5 x smaller

y = 1/5 x

greater = smaller

we must add 7 to smaller number to make an equality

greater = smaller + 7

y = 1/5 x + 7

Second sentence:

"4 times Phil's age is 2 years less than twice Peter's age."

Two things: "4 times Phil's age": 4y and "twice Peter's age": 2x

4y = 2x

read the sentence once again

"4 times Phil's age is 2 years less than (...)" , so 4y - smaller, 2x - greater

4y = 2x

smaller = greater

including "2 years less" we add 2 to a smaller number

smaller + 2 = greater

4y + 2 = 2x

Substitute y=1/5 x + 7 to the equation 4y+2 = 2x

Step-by-step explanation:

Answer:

x + y = 320

8x + 5y = 1900

Step-by-step explanation:

The equation x + y = 320 represents how 320 tickets were sold in total, from combining the adult and child tickets sold.

Since adult tickets are $8 each, the money from adult ticket sales can be represented by 8x.

The money from child ticket sales can be represented by 5y.

The equation 8x + 5y = 1900 represents how $1900 worth of tickets were sold.

So, the system of equations for the situation is:

x + y = 320

8x + 5y = 1900

Answer:

y = 220

x = 100

Step-by-step explanation:

x + y = 320

8x + 5y = 1900

x = 320 - y

8(320 - y) + 5y = 1900

2560 - 8y + 5y = 1900

2560 -3y = 1900

-2560        -2560

-------------------------

   -3y = -660

   -----    -------

    -3        -3

      y = 220

x + 220 = 320

    -220   -220

----------------------

        x = 100

If it has infinite solutions

[tex]\boxed{\sf \dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}}[/tex]

[tex]\\ \sf\longmapsto \dfrac{2}{p+q}=\dfrac{3}{p+q-3}[/tex]

[tex]\\ \sf\longmapsto 2(p+q-3)=3(p+q)[/tex]

[tex]\\ \sf\longmapsto 2p+2q-6=3p+3q[/tex]

[tex]\\ \sf\longmapsto 2p-3p+2q-3q=6[/tex]

[tex]\\ \sf\longmapsto -p-q=6[/tex]

[tex]\\ \sf\longmapsto p+q=-6[/tex]

[tex]\\ \sf\longmapsto p=-6-q[/tex]

Take p as 1

Answer: To add or subtract radicals, the indices and what is inside the radical (called the radicand) must be exactly the same. If the indices and radicands are the same, then add or subtract the terms in front of each like radical. If the indices or radicands are not the same, then you can not add or subtract the radicals.

Answer:

combining like terms. if the radicand is the you can combine the radical. this is the same as combining variables as long as the variable is the same if that makes sense

Step-by-step explanation:

so like you can add 7a and 3a because they have the same variable a. you can combined 2 root 2 and 4 root 2 because the radicand is same <3

Answer:

Step-by-step explanation:

Let the number be x

14 ÷ x = [tex]\frac{14}{x}[/tex]

Answer:

14 / x

Step-by-step explanation:

quotient = /

14 = 14

a number = the variable, let's call it x

Brainliest please!

Answer:

CSA is 12.57

TSA is 18.85 .. i dont know what the question is asking..

I will recommend you to use TSA

Answer:

19ft

Step-by-step explanation:

Formula for surface area of the cylinder=2πr(r+h)

We have,

h=2ft

d=2ft

r=d/2=2/2=1ft

Now,

2πr(r+h)=2π*1(1+2)=2π*1*3=6π=18.8495559215

Rounding to the nearest tenth,

We get Surface area of the cylinder=19 ft

Answer:

A. -5

Step-by-step explanation:

First of all this is a line that shows a negative slope.

Secondly, the formula for slope is rise/ run.

5 is your rise and 1 is your run, therefore: -5/1

And this can be reduced to :  -5

Answer:

n>-4

Step-by-step explanation:

8+n>4

n>4-8

n>-4

Answer:

-4

Step-by-step explanation

Subtract 8 from 4 to get -4.

N = -4

God Bless.

Answer:

61

or

421

Step-by-step explanation:

Find the L.C.M. of 2,3,4,5,6 and add 1.

2| 2-3-4-5-6

-------------------  

2| 1-3-2-5-3

---------------------

3| 1-3-1-5-3

----------------------

5| 1-1-1-5-1

----------------------

 | 1-1-1-1-1-1

L.C.M.=2×2×3×5=60

reqd. number=60+1=61

if i distribute between 2,3,4,5,6 people then reqd number is 61

if Mia is also among those people or she gets also share

then the people are2,3,4,5,6 or 7

L.C.M. of 2,3,4,5,6,7=60×7=420

so reqd number is 420+1=421

Answer:

x^2 + 10

Step-by-step explanation:

f(x) = 2x ^ 2 + 3

g(x) = x ^ 2 - 7

(f - g)(x) =2x ^ 2 + 3 - (x ^ 2 - 7 )

Distribute the minus sign

             =2x ^ 2 + 3 - x ^ 2 + 7

Combine like terms

            = x^2 + 10

Answer:

it already is in that form

y = 6x

technically Y = 6x + 0 could be the answer...

but in math we tend to not rite "obvious"  information

to reduce clutter and confusion

+1[tex]x^{1}[/tex] is technically correct but we drop the + sign for positive numbers

and also drop the exponent if it is a 1 ... similarly

+1[tex]x^{1}[/tex] + 0 + 0 + 0  would also be silly and we don't write the zeros

+1[tex]x^{1}[/tex] + 0 + 0 + 0 = x

Step-by-step explanation:

Answer:

c.8,625grams of flour

4a. X=12

Y=30

Z=60

Step-by-step explanation:

For c. , You have to convert the mixed numbers to fractions.

2¾ cups of flour= 2×4=8

8+3=11

Answer: 11/4 (11 over 4)

You multiply the 2 (whole number) by the 4 (bottom number) and then you get *8*

You then take the 8 (which was your answer) and add 3. This will give you 11

You take the 4 and use it as your denominator (bottom number) for the 11. So no need to find a denominator, because you just use the 4

For the fruit cake, she uses *1½* cups of flour more than carrot cake

Calculation:

1½ converted to an improper fraction= 1×2=2

2+1=3

Answer: 3/2 (3 over 2)

"Customer orders *3* carrot cakes and *4* fruit cakes

How many cups of flour are required to bake for the cakes ordered by the customer?"

11/4÷3= 8,25grams

3/2÷4= 0,375grams

8,25+0,375=8,625grams in total

*Feel free to correct me as I might be wrong!*

Answer:

D

Step-by-step explanation:

The sum to n terms of an arithmetic sequence is

[tex]S_{n}[/tex] = [tex]\frac{n}{2}[/tex] [ 2a₁ + (n - 1)d ]

where a₁ is the first term and d the common difference

Here a₁ = - 94 and d = a₂ - a₁ = - 112 -  (- 94) = - 112 + 94 = - 18 , then

S₁₀ = [tex]\frac{10}{2}[/tex] [ (2 × - 94) + (9 × - 18) ]

     = 5(- 188 - 162)

     = 5 × - 350

     = - 1750

Answer:

1(6+13mn+7m^2n^2)

Step-by-step explanation:

The coefficients and variables in this equation have a common factor of 1, therefore the equation will go back to it's original state if you use 1 as the common factor.

I hope this helps and sorry if am wrong

Answer:

The probability of choosing a girl is 1/2.

The probability of choosing an A student who is a BOY is 5/28.

1/2 = 14/28, and 14/28 + 5/28 = 19/28. This can be simplified to 0.68

Thus, the answer is B. 0.68

Let me know if this helps!

The required probability of choosing a girl or an A student is 0.82. Option A   is correct.

Given that,
In a math class of 28 students, 14 boys and 14 are girls. On a unit test, 5 boys and 9 girls made an A grade.
A student is chosen at random from the class. What is the probability of choosing a girl or an A student is to be determined.

Probability can be defined as the ratio of favorable outcomes to the total number of events.

Total sample space = 28
Number of girls = 14
Number of boys = 14
Number of girls A grade student  = 9

probability of a girl = 14/28 = 0.5
probability of A grader girl  = 9 / 28 = 0.32
Now the probability of choosing a girl or an A grader girl student,
= 0.32 + 0.5
= 0.82

Thus, the required probability of choosing a girl or an A student is 0.82. Option A  is correct.

Learn more about probability here:

brainly.com/question/14290572

#SPJ5

Answer:

45 times 89

Step-by-step explanation:

The instuments are irrelevant and are only there to distract you.

Answer:

45 times 89 equals 4005

Step-by-step explanation:

Answer:

UWUNOE BRO HUUZEM HIHUDHS

Step-by-step explanation:

Answer:

[tex]344 {cm}^{2} [/tex]

Step-by-step explanation:

[tex]area \: of \: the \: square \\ = 40cm \times 40cm \\ = 1600 {cm}^{3} \\ [/tex]

[tex]area \: of \: the \: circle \\ = \pi {r}^{2} \\ = 3.14 \times {(20)}^{2} \\ = 3.14 \times 400 \\ = 1256 {cm}^{2} \\ [/tex]

[tex]area \: of \: shaded \: region \\ = 1600 {cm}^{2} - 1256 {cm}^{2} \\ = 344 {cm}^{2} \\ [/tex]