Find the sum of 8a –2b + 3c and –3a +4b –3c
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[tex]\\ \rm\hookrightarrow (x,y)=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)[/tex]

[tex]\\ \rm\hookrightarrow (x,y)=\left(\dfrac{15+1}{2},\dfrac{9-9}{2}\right)[/tex]

[tex]\\ \rm\hookrightarrow (x,y)=\left(\dfrac{16}{2},\dfrac{0}{2}\right)[/tex]

[tex]\\ \rm\hookrightarrow (x,y)=(8,0)[/tex]

Answer:

[tex]mid \: point \: for \: x = \frac{x1 + x2}{2} \\ = \frac{15 + 1}{2} = \frac{16}{2} = 8 \\ mid \: point \: for \: y = \frac{y1 + y2}{2} \\ = \frac{ - 9 + 9}{2} \\ = \frac{0}{2} \\ = 0then \: (x \: y) = (8 \: 0) \\ thank \: you[/tex]

Answer:

Answer is 41.4 ft

Step-by-step explanation:

formula for triangle is 1/2 base x height

1/2x4.6x18

=4.6x9

=41.4

so the area = 41.4 ft

[tex] \sqrt{11} \: lies \: between \: 3 \: and \: 4[/tex]

Answer:

Lies between 3&4

See THE IMAGE FOR SOLUTION

Answer:

L,J, and K are collinear

Step-by-step explanation:

Answer:

cos6x.

Step-by-step explanation:

We use the identity

cosAcosB - sinAsinB = cos(A+B)

so cos5xcosx - sin5xsinx = cos(5x + x)

= cos6x.

second choice i’m prolly wrong

Hi ;-)

[tex]3\cdot\boxed9=9\cdot3[/tex]

Answer:

3 × 9 = 9 × 3

Step-by-step explanation:

Answer:

0.36

Step-by-step explanation:

Answer:

54ab

Step-by-step explanation:

the only two factors of 54ab^2 and 54ab is 1 and 54ab and the greatest of that would be 54ab.

Answer:

answer is 19.1

Step-by-step explanation:

answer is 19.1

Step-by-step explanation:

the answer is in the image above

Answer:

quadrilateral has 4 sides

so 104°+40°+110°+x=360°

254°+x=360°

collect like terms

x=360-254

x= 106

;- x=106

which is (c)

Answer:

x = 106°

Step-by-step explanation:

Using the angle marked 110° as my starting point,

One can use angles on a straight line sum up to 180° to find the angle that adds up to 110° which makes it 180,

thus 70°.

moving on,

tackling with the angle marked 40°, Using the fact that angles on a straight line sum up to 180°, the angle obtained will be 140° (40° + a = 180, a = 180° -40°, a = 140°)

Using the angle marked 104°, Just like the previous one Using the principle that angles on a straight line sums up to 180°, then the unknown angle will be 76°.

Finding all the other interior angles angles in the quadrilateral except the angle in line with the x,

the next step to take is to add up all the angles Using any variable and equate it to 360°

why? angles in this type of quadrilateral equals 360,

That is,

140° + 76° + 70° + y = 360

286 + y= 360

y = 360 - 286

y = 74

The final step now is to use the principle, ( angles on a straight line sums up to 180)

74° + x = 180

x = 180 - 74

x = 106°

Answer:

B

Step-by-step explanation:

This is a linear function that continues both ways infinitely.

Answer:

B

Step-by-step explanation:

The domain of the function is all real numbers.

Answer:

Step-by-step explanation:

Its like doing a long division with base 10 numbers:

           1110    <----------- Quotient

101)1001010

        101

         1000

            101

               111

                101

                  100

So the answer is 1110 remainder 100.

We can confirm this by converting to decimal numbers

1001010 = 74 and 101 = 5.

74 / 5 = 14 remainder 4.

Answer:

[tex]\displaystyle \theta = \left\{\frac{7\pi}{6}, \, \frac{3\pi}{2}, \frac{11\pi}{6}\right\}[/tex]

Step-by-step explanation:

We want to solve the equation:

[tex]2\sin ^2 \theta + 3\sin \theta + 1 = 0[/tex]

In the interval [0, 2π).

Notice that this is in quadratic form. Namely, by letting u = sin(θ), we acquire:

[tex]\displaystyle 2u^2 + 3u + 1 = 0[/tex]

Factor:

[tex]\displaystyle (2u+1)(u+1) = 0[/tex]

By the Zero Product Property:

[tex]\displaystyle 2u + 1 = 0\text{ or } u + 1 = 0[/tex]

Solve for each case:

[tex]\displaystyle u = -\frac{1}{2} \text{ or } u = -1[/tex]

Back-substitute:

[tex]\displaystyle \sin \theta = -\frac{1}{2} \text{ or } \sin \theta =-1[/tex]

Use the Unit Circle. Hence, our three solutions in the interval [0, 2π) are:

[tex]\displaystyle \theta = \left\{\frac{7\pi}{6}, \, \frac{3\pi}{2}, \frac{11\pi}{6}\right\}[/tex]

Answer: $1500

Step-by-step explanation:

Given information

Number of puppies = 6

Cost of each puppy = $250

Given expression deducted from the question

Total cost = number of puppies × cost of each

Substitute values into the expression

Total cost = 6 × 250

Simplify by multiplication

Total cost = [tex]\boxed{1500}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

The integers are

1st: n

2nd: n + 1

3rd: n + 2

The words in the problem statement translate into

2(n + 1) = 3(n + 2) + 6

Solve for n.

2n + 2 = 3n + 12

n = -10

n + 1 = -9

n + 2 = -8

Step-by-step explanation:

Answer:

[tex] \frac{ {12}^{8} }{ {12}^{4} } \\ = \frac{ {12}^{4} \times {12}^{4} }{ {12}^{4} } \\ = {12}^{4} =20736 \\ thank \: you[/tex]

Here's the solution :

[tex] \hookrightarrow \dfrac{12 {}^{8} }{ {12}^{4} } [/tex]

[tex] \hookrightarrow 12 {}^{8} \times {12}^{ - 4} [/tex]

[tex] \hookrightarrow12 {}^{4} [/tex]

Answer:

A

Step-by-step explanation:

If you look at the number of dots in each circle, it is increased by 1 every picture so if we have 4 in the third circle, then we will have 5 in the fourth picture. Option A is the only option that contains 5 dots.

Best of Luck!

Answer:

f(4)=-10

x=0 if g(x)=2

i hope you will understand it

Step-by-step explanation:

Hi there!

Given;

f(x) = 17x + 9

h(x) = 4x

To find: f(x)-h(x)

f(x)-h(x)= 17x + 9 - 4x

= 13x + 9

Therefore, f(x)-h(x) = 13x + 9.

Hope it helps!

Answer:

80

Good luck :)

Answer:

80

Step-by-step explanation:

[tex]\sqrt{a} * \sqrt{b} = \sqrt{ab}[/tex]

[tex]\sqrt{6400}[/tex]

6400 = 2 * 2 * 2 * 2 * 2 * 2 * 2 *2 * 5 * 5

          = 2^8 * 5^2

2^4 * 5

16*5 = 80

Answer:

Here is your answer...

Hope it helps

Answer:

5.5

Step-by-step explanation:

3x + 15 - 7x = -7

-4x + 15 = -7

-4x = -7 -15

-4x = -22

x = -22/-4 = 5.5

Answer:

sandwich and drink only (no dessert)

so 4 x 6 = 24

you have 24 different combinations you can do

hope this helps

Step-by-step explanation:

Answer:

hi,

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}a&=&3*\vec{i}-4\vec{j}\\b&=&2*\vec{i}-5\vec{j}\\c&=&\lambda*\vec{i}+\mu*\vec{j}\\\end{array}\right.\\\\\\\lambda*c=2a+3b\\=2*(3*\vec{i}-4\vec{j})+3*(2*\vec{i}-5\vec{j})\\=12*\vec{i}-23\vec{j}\\=\lambda*(\lambda*\vec{i}+\mu*\vec{j})\\\\\\\left\{\begin{array}{ccc}\lambda^2&=&12\\\lambda*\mu&=&-23\end{array}\right.\\\\\\\left\{\begin{array}{ccc}\lambda&=&2\sqrt{3}\\\mu&=&\dfrac{-23*\sqrt{3} }{6} \\\end{array}\right.\\[/tex]