The real part of the particular solution to the differential equation is [tex](1/30)Re(e^(3it))(sin(3t) - cos(3t))[/tex]
The real part of the particular solution to the differential equation:
[tex]\frac{d^2y}{dt^2} +3\frac{dy}{dt} +7y = e^(3it)[/tex]
First, we assume a particular solution of the form:
[tex]y(t) = Bcos(3t) + Csin(3t)[/tex]
where B and C are real fractions.
Taking the first and second derivatives of y(t), we get:
[tex]\frac{dy}{dt} = -3Bsin(3t) + 3Ccos(3t)[/tex]
[tex]\frac{d^2y}{dt2} = -9Bcos(3t) - 9Csin(3t)[/tex]
Substituting these into the differential equation, we get:
[tex](-9Bcos(3t) - 9Csin(3t)) + 3(-3Bsin(3t) + 3Ccos(3t)) + 7(Bcos(3t) + Csin(3t)) = e^(3it)[/tex]
Simplifying and collecting terms, we get:
[tex](-9B + 21C)*cos(3t) + (-9C - 9B)*sin(3t) = e^(3it)[/tex]
Comparing the coefficients of cos(3t) and sin(3t), we get:
[tex]-9B + 21C = Re(e^(3it))[/tex]
[tex]-9C - 9B = 0[/tex]
Solving for B and C, we get:
[tex]B = -C[/tex]
[tex]C = (1/30)*Re(e^(3it))[/tex]
Therefore, the particular solution is:
[tex]y(t) = -Ccos(3t) + Csin(3t) = (1/30)Re(e^(3it))(sin(3t) - cos(3t))[/tex]
A differential equation is a mathematical equation that relates a function to its derivatives. It is a powerful tool used in many fields of science and engineering to describe how physical systems change over time. The equation typically includes the independent variable (such as time) and one or more derivatives of the dependent variable (such as position, velocity, or temperature).
Differential equations can be classified based on their order, which refers to the highest derivative present in the equation, and their linearity, which determines whether the equation is a linear combination of the dependent variable and its derivatives. Solving a differential equation involves finding a function that satisfies the equation. This can be done analytically or numerically, depending on the complexity of the equation and the available tools.
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Calculate Suppose that on each of the
4,500 dives Alvin has made, a new pilot and two new scientists were on board.
How many scientists have seen the
deep ocean through Alvin's windows? How
many people, in total, traveled in Alvin?
The calculation shows that 9,000 scientists have seen the deep ocean through Alvin's windows; and
a total of 13,500 people have traveled in Alvin over the course of its 4,500 dives.
What is the explanation for the above calculation?1) If on each of the 4,500 dives Alvin carried a new pilot and two new scientists, then the total number of scientists who have seen the deep ocean through Alvin's windows is:
4,500 dives x 2 scientists per dive = 9,000 scientists
Therefore, 9,000 scientists have seen the deep ocean through Alvin's windows.
2) To calculate the total number of people who traveled in Alvin, we can add the number of pilots and scientists on each dive and multiply by the number of dives:
4,500 dives x (1 pilot + 2 scientists)
= 4,500 x 3
= 13,500 people
Therefore, a total of 13,500 people have traveled in Alvin over the course of its 4,500 dives.
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MR. Swanson wants to buy some mugs as gifts on his trip to California.There are three gifts shops, and each is offering a different deal. Which gift shop has the best deal for mugs
Answer: The one that has the best deals.
Step-by-step explanation:
on saturday a local hamburger shop sold a combined total of 416 hamburgers and cheeseburgers.the number of cheeseburgers sold was three times the number of hamburgers sold. how many hamburgers were sold?
Answer: Let x be the number of hamburgers sold.
Then, the number of cheeseburgers sold is 3x.
The total number of burgers sold is x + 3x = 4x.
Given that the total number of burgers sold is 416, we have:
4x = 416
x = 416/4
x = 104
Therefore, 104 hamburgers were sold.
Step-by-step explanation:
Find the center of mass of a thin plate of constant density delta covering the given region. The region bounded by the parabola y = 3x - x^2 and the line y = -3x The center of mass is. (Type an ordered pair.)
The center of mass of a thin plate of constant density covering the given region is (1.8, 3.6).
To find the center of mass, we must calculate the weighted average of all the points in the region. The region is bounded by the parabola y = 3x - x² and the line y = -3x.
We must calculate the integral of the region and divide by the total mass. The mass is equal to the area times the density, .
The integral of the region is calculated using the limits of the two curves, yielding a final integral of 32/15. Dividing this integral by the density gives the total mass, and multiplying by the density gives us the center of mass, (1.8, 3.6).
We can also find the center of mass by calculating the moments of the plate about the x-axis and y-axis.
The moment about the x-axis is calculated by finding the integral of the parabola and line using the x-coordinate, and the moment about the y-axis is calculated by finding the integral of the parabola and line using the y-coordinate. Once the moments are found, we can divide each moment by the total mass to get the center of mass.
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At noon, ship A is 50 nautical miles due west of ship B. Ship A is sailing west at 16 knots and ship B is sailing north at 15 knots. How fast (in knots) is the distance between the ships changing at 6 PM? (Note: 1 knot is a speed of 1 nautical mile per hour. )
The speed (in knots) at which the distance between the ships A and B is changing at 6 PM is given as 36 knots or 36 nautical miles per hour.
Consider that the ship A is in the west direction and the ship B is in the north direction and both the ships are in regular motion of speed which is 16 knots and 15 knots and the distance between them is 50 nautical miles.
Using the Pythagoras theorem, the relation of the distance x which represents the distance between ships at 6PM to the distances that each ship has travelled can be given as follows:
x^2 = (50 + 16t)^2 + (15t)^2
where, t is the number of hours that has passed since noon.
Differentiating both sides of the above equation with respect to time, we get:
2x*(dx/dt) = 2(50 + 16t)*(16) + 2*(15t)*(15)
t = 6, at 6 PM, therefore substituting the value and solving, we get:
2x(dx/dt) = 2[(50 + 16(6)]*(16) + 2*[15(6)]*(15)
2x(dx/dt) = 4194
dx/dt = 2097/x
Now substituting the value of x that corresponds to 6 PM:
x^2 = (50 + 16(6))^2 + (15(6))^2
x^2 = 3385
x = √3385 ≅ 58.19
Putting this value in dx/dt, we get:
dx/dt = 2097/58.19 ≅ 36.00 knots
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4x 2 +6x−13=3x 2 to the nearest tenth.
The solutions to the equation are x = -4 and x = 1.
What is quadratic formula?The quadratic formula, which is often employed in the disciplines of mathematics, physics, engineering, and other sciences, is a potent tool for resolving quadratic problems. We must first get the values of a, b, and c from the quadratic equation in order to apply the quadratic formula. To get the answers for x, we then enter these values as substitutes in the formula and simplify.
The given equation is 4x² + 6x - 13 = 3x².
Rearranging the equation we have:
x² + 6x - 13 = 0
The quadratic formula is given as:
x = (-b ± √(b² - 4ac)) / 2a
Substituting the values of a = 1, b = 6, and c = -13.
x = (-6 ± √(6² - 4(1)(-13))) / 2(1)
x = (-6 ± √(100)) / 2
x = (-6 ± 10) / 2
x = -8/2 or x = 2/2
x = -4 or x = 1
Hence, the solutions to the equation are x = -4 and x = 1
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A train leaves the station traveling north at 85 km/h. Another train leaves at the same time and travels south at 95 km/h. How long will it take before the trains are 990 km apart
First before two trains were [tex]990[/tex] kilometers apart, it will require [tex]5.5[/tex] hours.
What is the mathematical formula for train?Train speed is calculated as total distance traveled divided by travel time. The time it takes for two trains to pass each other is equal to (a+b) / (x+y) if the lengths of the trains, say a or b, are known and they are going at speeds of y and x, respectively.
What fuels trains use?Typically, a locomotive fueled by electricity or diesel powers trains. If there are several route networks, complicated signaling methods are used. One of the quickest forms of land transportation is rail.
[tex]distance = rate * time[/tex]
distance between trains [tex]= (85 km/h) * t + (95 km/h) * t[/tex]
distance between trains [tex]= (85 + 95) km/h * t[/tex]
distance between trains [tex]= 180 km/h * t[/tex]
Now, we can set up an equation to solve for the time it takes for the trains to be [tex]990[/tex] km apart:
[tex]180 km/h * t = 990 km[/tex]
[tex]t = 990 km / 180 km/h[/tex]
[tex]t = 5.5[/tex] hours
Therefore, it will take [tex]5.5[/tex] hours before the two trains are [tex]990[/tex] km apart.
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Simplify to an expression involving a single trigonometric function with no fractions.
cos(−x)+tan(−x)sin(−x)
Sec x is the simplified expression cos(−x)+tan(−x)sin(−x) involving a single trigonometric function with no fractions.
The functions of an angle in a triangle are known as trigonometric functions, commonly referred to as circular functions. In other words, these trig functions provide the relationship between a triangle's angles and sides. There are five fundamental trigonometric functions: sine, cosine, tangent, cotangent, secant, and cosecant.
The Given expression is
cos(−x)+tan(−x)sin(−x)
Now,
cos(−x) + tan(−x)sin(−x)
= cos x + (- tan x) (- sin x)
= cos x + tan x * sin x
= cos x + (sin x / cos x) * sin x
= (cos²x + sin²x) / cos x ( As sin²x + cos²x = 1)
= 1/ cos x
= sec x (As sec x = 1/cos x)
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Select the correct answer. Which graph represents this equation? A. The graph shows an upward parabola with vertex (minus 3, minus 4.5) and passes through (minus 7, 3.5), (minus 6, 0), (0, 0), and (1, 3.5) B. The graph shows an upward parabola with vertex (3, minus 4.5) and passes through (minus 1, 3.5), (0, 0), (6, 0), and (7, 3.5) C. The graph shows an upward parabola with vertex (minus 2, minus 6) and passes through (minus 5, 7), (minus 4, 0), (0, 0), and (1, 7) D. The graph shows an upward parabola with vertex (2, minus 6) and passes through (minus 1, 7), (0, 0), (4, 0), and (5, 7)
Answer:
A
Step-by-step explanation:
Evaluate the expression
z + 3x4
A. 27
B. 32
C. 56
D. 1,304
The value of the expression z + 3x4 using arithmetic operation where z = 15, is 27. The answer is A) 27.
The given expression is z + 3x4, where z = 15. To evaluate this expression, we substitute 15 for z and perform the multiplication. First, we multiply 3 and 4, which gives us 12. Then, we add 15 and 12 to get the final result of 27.
z + 3x4 = 15 + 3x4
= 15 + 12
= 27
Therefore, the value of the expression when z = 15, is 27. In other words, using arithmetic operation of multiplication and addition, which gives us the final answer of 27. So, the correct answer is option A).
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____The given question is incomplete , the complete question is given below:
Evaluate the expression, where z = 15
z + 3x4
A. 27
B. 32
C. 56
D. 1,304
Masons backyard deck is rectangular. The width is 12 feet less than the length. The perimeter is 64 feet. What is the length?
As Masons backyard deck is rectangular, the length of the deck is 22 feet.
Let's start by using algebra to solve for the length of the rectangular deck.
Let L be the length of the deck.
Then, the width of the deck is L - 12.
The perimeter is the sum of all four sides, so we have:
Perimeter = 2L + 2(L - 12) = 64
Simplifying the equation, we get:
2L + 2L - 24 = 64
Combining like terms, we get:
4L - 24 = 64
Adding 24 to both sides, we get:
4L = 88
Dividing both sides by 4, we get:
L = 22
Therefore, the length of the deck is 22 feet.
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Anyone know the answer?
As a result, the Styrofoam collar has a volume of roughly 179.594 cubic inches.
what is volume ?The quantity of space occupied by a three-dimensional object is measured by its volume. Units like cubic meters (m3), cubic centimeters (cm3), or cubic inches (in3) are frequently used to quantify it. Depending on the shape of the item, different formulas can be used to determine its volume. For instance, the volume of a cube can be calculated by multiplying its length, breadth, and height, while the volume of a cylinder can be calculated by dividing the base's area (typically a circle) by the cylinder's height.
given
We must apply the calculation for the volume of a cone's frustum in order to determine the volume of the Styrofoam collar:
[tex]V = (1/3)\pi h(R^2 + Rr + r^2)[/tex]
where h is the height of the frustum, r is the small radius, and R is the large radius.
Given the numbers, we can determine:
R = 5 in.
3 centimeters is r.
24 inches tall
With these numbers entered into the formula, we obtain[tex]V = (1/3)\pi (24)(5^2 + 5*3 + 3^2)\\\\ 179.594 cubic inches[/tex]
As a result, the Styrofoam collar has a volume of roughly 179.594 cubic inches.
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Grace wants to buy a jump rope that costs $7, a board game that costs $10, and a playground ball that costs $4. She has saved $10 from her allowance, and her uncle gave her $3. How much more money does Grace need to buy the jump rope, the game, and the ball?
Grace need to buy the jump rope, the game, and the ball $8.
$7 will get you a jump rope.
$10 will get you a board game.
$4 will get you a playground ball.
total amount to be spent: $7 + $10 + $4 = $21
She has ten dollars.
$3 was all her uncle gave her.
13 dollars are all she has.
She needed $8, therefore 21 - 13 = $8.
a sum of money awarded as compensation, a bounty, or to cover costs. a wage that comes with a cost-of-living supplement. especially: a regular amount set aside for household or personal costs.
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A system of equations is shown below.
y=4x
y=x-6
what is the x-value in the solution to the system?
Answer: x = -2
Step-by-step explanation:
Since both equations are in the y-slope form,
we can use substitution for y in finding x.
Hence,
4x=x-6
4x-x=x-x-6
Subtract x from both sides to get x on one side and integer on one side.
[tex]\frac{3x}{3} =\frac{-6}{3}[/tex]
Divide 3 to find the value of x
x=-2
Convince Me! How does the unit rate describe Sergio's cycling speed? How is the unit rate helpful in determining how much farther Sergio must cycle in a given amount of time each time he increases his target speed?
The unit rate is a helpful tool for comparing speeds and calculating distances traveled in a given amount of time.
What is the formula for Speed?The formula for speed is: speed = distance / time where "distance" is the distance traveled by an object and "time" is the duration of travel. This formula can be used to calculate the speed of an object if the distance it has traveled and the time it took to travel that distance are known. It can also be used to calculate the distance traveled by an object if its speed and the time it traveled at that speed are known.
In the given question,
The unit rate describes Sergio's cycling speed by giving the distance he travels in a given amount of time, which is 6 miles per hour. This means that for every hour he cycles, he travels a distance of 6 miles.
By expressing Sergio's cycling speed as a unit rate, we can easily compare it to other speeds and determine how long it will take him to travel a certain distance.
For example, if Sergio increases his target speed to 8 miles per hour, we can use the unit rate to calculate how much farther he must cycle in a given amount of time.
If he wants to cycle for 2 hours, we know that he will travel 6 x 2 = 12 miles at his original speed of 6 miles per hour.
If he wants to cycle for the same 2 hours at a speed of 8 miles per hour, we can use the unit rate to calculate that he will travel 8 x 2 = 16 miles.
This means that he must cycle an additional 4 miles to reach his target distance.
Overall, the unit rate is a helpful tool for comparing speeds and calculating distances traveled in a given amount of time.
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Determine whether the following subsets are subspaces of the given vector spaces or not.text Is end text W subscript 2 equals open curly brackets space p equals a subscript 2 t squared plus a subscript 1 t plus a subscript 0 space element of space straight double-struck capital p subscript 2 space left enclose space a subscript 0 equals 2 space end enclose close curly brackets space space text a subspace of the vector space end text space straight double-struck capital p subscript 2 ?(Note: space straight double-struck capital p subscript 2 is the set of all 2nd degree polynomials with the usual polynomial addition and scalar multiplication with reals.)Answer 1text Is end text W subscript 1 equals open curly brackets open square brackets table row a b c row d 0 0 end table close square brackets space element of space M subscript 2 x 3 space end subscript space left enclose space b equals a plus c space end enclose close curly brackets space text a subspace of the vector space end text space space M subscript 2 x 3 space end subscript?(Note: space M subscript 2 x 3 space end subscript is the set of all 2x3 matrices with the standart matrix addition and scalar multiplication with reals.)
Yes, W_2 = {p_2 = a_2t_2 + a_1t + a_0 ∈ ℙ_2 | a_0 = 2} is a subspace of the vector space ℙ_2.
Yes, W_1 = {[a b c; d 0 0] ∈ M_{2x3} | b = a + c} is a subspace of the vector space M_{2x3}.
Vector spaces are closed under vector addition and scalar multiplication, and in this case, ℙ_2 is the set of all 2nd degree polynomials with the usual polynomial addition and scalar multiplication with reals.
Vector spaces are closed under vector addition and scalar multiplication, and in this case, M_{2x3} is the set of all 2x3 matrices with the standard matrix addition and scalar multiplication with reals.
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Suppose an angle has a measure of 140 degrees a. If a circle is centered at the vertex of the angle, then the arc subtended by the angle's rays is______ times as long as 1/360th of the circumference of the circle. b. A circle is centered at the vertex of the angle, and 1/360th of the circumference is 0.06 cm long. What is the length of the arc subtended by the angle's rays? _______ cmc. Another circle is centered at the vertex of the angle. The arc subtended by the angle's rays is 70 cm long. - 1/360th of the circumference of the circle is _____ cm long. - Therefore the circumference of the circle is _______ cm
If an angle of measurement of 140° then; a circle is centered at the vertex of the angle, then the arc subtended by the angle's rays is 0.0233 cm times as long as 1/360th of the circumference of the circle. Also if a circle is centered at the vertex of the angle, and 1/360th of the circumference is 0.06 cm long then length of the arc subtended by the angle's rays 8.4 cm. Another circle is centered at the vertex of the angle then arc subtended by the angle's rays is 70 cm long,Therefore the circumference of the circle is 180 cm.
a.) To find the fraction of the circle's circumference subtended by the angle's rays, we divide the angle measure by 360 degrees:
fraction of circle's circumference = 140/360
Simplifying this fraction, we get:
fraction of circle's circumference = 7/18
To find the length of the arc subtended by the angle's rays, we multiply the fraction of the circle's circumference by the circumference of the circle. Let's call the circumference of the circle "C":
length of arc = (7/18)*C
We're also told that the length of 1/360th of the circumference is equal to 0.06 cm. So, we can write:
(1/360)*C = 0.06
Multiplying both sides by 360, we get:
C = 360*0.06 = 21.6 cm
Now, we can substitute this value of C into the expression for the length of the arc:
length of arc = (7/18)*C
length of arc = (7/18)*(21.6)
length of arc = 8.4 cm (rounded to one decimal place)
Therefore, the length of the arc subtended by the angle's rays is 8.4 cm.
b.) We're given that 1/360th of the circumference of the circle is 0.06 cm long. To find the length of the arc subtended by the angle's rays, we need to multiply 140/360 by 0.06:
length of arc = (140/360)*0.06
length of arc = 0.0233 cm (rounded to four decimal places)
Therefore, the length of the arc subtended by the angle's rays is approximately 0.0233 cm.
c.) We're told that the length of the arc subtended by the angle's rays is 70 cm. To find the circumference of the circle, we need to find the length of 1/360th of the circumference first. We can do this by dividing 70 by 1/360:
(1/360)*C = 70
Multiplying both sides by 360, we get:
C = 70*360 = 25,200 cm
Therefore, the circumference of the circle is 25,200 cm. We can also verify this by dividing the length of the arc by the fraction of the circumference subtended by the angle's rays:
length of arc = (7/18)*C
C = (18/7)*length of arc
C = (18/7)*70
C = 180 cm (rounded to one decimal place)
This is a different value than we got earlier, so we need to check our calculations. It turns out that the previous calculation was incorrect - we made a mistake when multiplying 7/18 by 21.6. The correct calculation gives us:
length of arc = (7/18)*C
length of arc = (7/18)*(21.6)
length of arc = 8.4 cm (rounded to one decimal place)
Now, we can calculate the circumference of the circle:
length of arc = (7/18)C
C = (18/7) *length of arc
C = (18/7) *70
C = 180 cm (rounded to one decimal place)
Therefore, the circumference of the circle is 180 cm.
Also, If an angle of measurement of 140° then; a circle is centered at the vertex of the angle, then the arc subtended by the angle's rays is 0.0233 cm times as long as 1/360th of the circumference of the circle.
b. A circle is centered at the vertex of the angle, and 1/360th of the circumference is 0.06 cm long.The length of the arc subtended by the angle's rays 8.4 cm
c. Another circle is centered at the vertex of the angle.
The arc subtended by the angle's rays is 70 cm long,Therefore the circumference of the circle is 180 cm.
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use a direct proof to show that every odd integer is the difference of two squares. [hint: find the difference of the squares of k 1 and k where k is a positive integer.]
Yes, every odd integer can be written as the difference of two squares.
To prove this, let k be a positive integer. Then the difference of the squares of k+1 and k is (k+1)² - k² = (k+1)(k+1) - k(k) = k² + 2k + 1 - k² = 2k + 1, which is an odd integer. Thus, every odd integer can be written as the difference of two squares.
To prove this, we first chose a positive integer, k. We then found the difference of the squares of k+1 and k to be (k+1)² - k² = (k+1)(k+1) - k(k) = k² + 2k + 1 - k² = 2k + 1. Since 2k + 1 is an odd integer, it follows that every odd integer is the difference of two squares.
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Many bank accounts never go below zero. But some banks will allow a negative balance, at least for a short time, called an overdraft. It means someone has taken out, or 'drafted', more money than was in the account to begin with. Jose's account has gone into overdraft. His balance is $-27.14. To get back to a positive balance, he plans to deposit money at a steady rate of $35.03 per week. How much will be in his account after 7 weeks?
Answer:
yo your dûmb asl
Step-by-step explanation:
y=x^2+7x-3
complete the square to re-write the quadratic function in vertex form.
pls help
Answer:
Y=x^2+7x-3
complete the square to re-write the quadratic function in vertex form.
pls help
Step-by-step explanation:
To complete the square, we need to add and subtract a constant term inside the parentheses, which when combined with the quadratic term will give us a perfect square trinomial.
y = x^2 + 7x - 3
y = (x^2 + 7x + ?) - ? - 3 (adding and subtracting the same constant)
y = (x^2 + 7x + (7/2)^2) - (7/2)^2 - 3 (the constant we need to add is half of the coefficient of the x-term squared)
y = (x + 7/2)^2 - 49/4 - 3
y = (x + 7/2)^2 - 61/4
So the quadratic function in vertex form is y = (x + 7/2)^2 - 61/4, which has a vertex at (-7/2, -61/4).
5. Find x and h.
x =
h =
Using pythagoras' theorem in the right-angled triangle
x = 3 andh = 3√3What is a right-angled triangle?A right-angled triangle is a polygon with 3 sides in which one angle is a right angle
Now, since we have 3 triangles, using Pythagoras' theorem in all three triangles, we have
h² + (12 - x)² = 12² - 6² (1)
Also, h² + x² = 6² (2)
So, h² + (12 - x)² = 12² - 6²
h² + (12 - x)² = 144 - 36
h² + (12 - x)² = 108 (3)
From equation (2), h² = 36 - x²
Substituting this into equation (3), we have that
h² + (12 - x)² = 108 (3)
36 - x² + (12 - x)² = 108 (3)
Expanding the brackets, we have that
36 - x² + 144 - 24x + x² = 108
36 + 144 - 24x = 108
180 - 24x = 108
-24x = 108 - 180
-24x = -72
x = -72/-24
x = 3
Since h² = 36 - x²
h = √(36 - x²)
So, substituting the value of x = 3 into the equation, we have that
h = √(36 - x²)
h = √(36 - 3²)
h = √(36 - 9)
h = √27
h = 3√3
So,
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Determine the degree of the Maclaurin polynomial required for the error in the approximation of the function at the indicated value of x to be less than 0.001. f(x) = - " x+1' PA approximate f(0.2)
To determine the degree of the Maclaurin polynomial required for the error in the approximation of the function f(x) = -x+1 at the indicated value of x to be less than 0.001, we can use the formula: N ≥ ln(error)/ln(absolute value of x) + 1.
For our given function, the error is 0.001, and the value of x is 0.2. Plugging these values into the formula, we get: N ≥ ln(0.001)/ln(0.2) + 1, which is equivalent to N ≥ 6.64 + 1 = 7.64. Therefore, we need the degree of the Maclaurin polynomial to be 7.64 in order for the error in the approximation of the function at the indicated value of x to be less than 0.001.
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Square root of За^2/10b^6
The simplified square expression for[tex]\sqrt{3a^2/10b^6}[/tex] is [tex]|3a| / (\sqrt{10} * b^{3})[/tex].
What is square root ?
In mathematics, the square root of a number is a value that, when multiplied by itself, gives the original number. For example, the square root of 9 is 3, because 3 x 3 = 9.
The square root is denoted by the symbol √, also known as the radical symbol. For instance, the square root of 16 is written as √16 = 4.
The square root can be used to solve various types of equations, including quadratic equations and problems involving areas and volumes. It is also used in various fields such as physics, engineering, and finance.
According to the question:
To simplify the expression [tex]\sqrt{3a^{2}/10b^6}[/tex], we can first separate the numerator and denominator inside the square root:
[tex]\sqrt{3a^2/10b^6} = \sqrt{3a^2}/\sqrt{10b^6}[/tex]
Next, we can simplify the square root of the numerator:
[tex]\sqrt{3a^2} = |3a|,[/tex] where |За| represents the absolute value of За.
Finally, we can simplify the square root of the denominator by factoring out the perfect square[tex]b^2[/tex]:
[tex]\sqrt{10b^6} = \sqrt{10} * \sqrt{b^6} = \sqrt{10} * b^{3}[/tex]
Substituting these values back into the original expression, we get:
[tex]\sqrt{3a^2/10b^6} = |3a| / \(sqrt{10} * b^3[/tex]
Therefore, the simplified expression for[tex]\sqrt{3a^2/10b^6}[/tex] is [tex]|3a| / (\sqrt{10} * b^{3})[/tex].
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mai has a jar of quarters and dimes. she takes at least 10 coins out of the jar and has less than $2.00. write a system of inequalities that represents the number of quarters, `x`, and the number of dimes, `y`, that mai could have.
The system of inequalities that represents the number of quarters, x, and the number of dimes, y, that Mai could have is given by:
x + y ≥ 10 and 0.25x + 0.1y < 2
These are the two systems of inequalities that represent the number of quarters, x, and the number of dimes, y, that Mai could have.
Let x be the number of quarters and y be the number of dimes that Mai has. Then, the system of inequalities can be represented as:
Thus, the first inequality is x + y ≥ 10.
Also, Mai has less than $2.00, therefore, the second inequality is 0.25x + 0.1y < 2. The value of x and y are assumed to be non-negative integers.+
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plsss help theorical probability
calculate the theoretical probability of a 1 eyed, 1 horned, flying, purple, people eater
The theoretical probability for the 1 horned, 1 eyed, flying, people eater purple is found to be 1/120.
Explain about the theoretical probability?Experimental Probability: Based on actual results rather than mathematical calculations, the experimental probability of an occurrence is the likelihood that the event will actually occur.
Theoretical Probability: Considering that the event is ideal, the theoretical chance that it will occur is the theoretically ideal probability of a specific result. The flaws in the system are not taken into consideration by theoretical probability.
Theoretical Probability = Number of favorable outcomes / Number of possible outcomes.
The given probability are;
1 eyed - 3/41 horned - 1/5flying - 2/3 purple -3/8 people eater - 1/2Let P(E) be the theoretical probability 1 horned, 1 eyed, flying, people eater purple.
Then,
P(E) = 3/4 * 1/5* 2/3* 3/8* 1/2
P(E) = 1/120
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xavier is a teacher and takes home 90 papers to grade over the weekend. he can grade at a rate of 6 papers per hour. how many papers would xavier have remaining to grade after working for 12 hours?
The number of papers xavier have remaining after working for 12 hours is 18
How many papers would xavier have remainingXavier can grade 6 papers per hour, so in 12 hours he can grade:
6 papers/hour x 12 hours = 72 papers
Therefore, after working for 12 hours, Xavier would have
90 - 72 = 18 papers remaining to grade.
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If x=3, solve for y
y=2*3^(3)
Answer:
54
Step-by-step explanation:
Answer:
y=54
as x=3
so y=2*x^3
y= 2*3^3
y=2*27
y=54
22) i) A cuboid has dimensions 60cm x 24cm x 30cm. How many small cubes with side 5cm can be placed in the given cuboid?
Answer:
345.6
Or 345 full cubes
Step-by-step explanation:
To answer this question we first need to find the volume of the cuboid!
To find volume we use the equation...
area of cross-section × heightor l × w × hFor the cuboid we are given the dimensions 60, 24 and 30 so we just need to multiply them...
60 × 24 × 30 = 43200We now need to the the volume of the cube which we can just do by cubing the value given
5³ = 125We now need to divide the two results together to find out how many cubes would fit...
43200 ÷ 125 = 345.6Or 345 full cubesHope this helps, have a lovely day!
Most people can roll their tongues, but many can’t. The ability to roll the tongue is genetically determined. Suppose we are interested in determining what proportion of students can roll their tongues. We test a simple random sample of 400 students and find that 317 can roll their tongues. The margin of error for a 95% confidence interval for the true proportion of tongue rollers among students is closest to
0.008.
0.02.
0.03.
0.04.
0.208.
The proportion of students who can roll their tongues will be estimated and the margin of error for a 95 percent confidence interval for the true proportion of tongue rollers among students will be determined. There were 317 tongue rollers out of a sample of 400 students.
As a result, the sample proportion is 317/400 = 0.7925.
We'll compute the margin of error next. The margin of error (E) for a 95 percent confidence interval is:
E = zα/2 * sqrt[p(1 - p) / n]
where zα/2 is the z-score that corresponds to the level of confidence α/2, p is the sample proportion, and n is the sample size.
E = 1.96 * sqrt[0.7925 * (1 - 0.7925) / 400]E
= 1.96 * sqrt[0.7925 * 0.2075 / 400]E
= 1.96 * sqrt(0.00040875)E
= 1.96 * 0.0202E
= 0.0395
The margin of error is approximately 0.04 or 4 percent. Hence, the correct option is 0.04.
The margin of error for a 95% confidence interval for the true proportion of tongue rollers among students is closest to 0.04
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Calculate (3.7 x 10¹⁴) + (9 × 10¹²) Give your answer in standard index form.
Answer:3.79*10^14
Step-by-step explanation:
370000000000000+9000000000000=379000000000000
=3.79 x 10^14
Answer:
(3.79×10^14)
Step-by-step explanation:
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