Find the number.
Less than 100
Odd number
Multiple of 5
Divisible by 3
Whose digit sum is an odd number

Answer:

4x - 12 = 84

Step-by-step explanation:

The last answer choice is correct because when you cross-multiply:

you get 4x - 12 = 84.

Therefore, the last option is correct.

Answer:

D would be the answer (4x-12=84)

Step-by-step explanation:

4/7=12/x-3

=>1/7=3/x-3

=>x-3=21

Multiplying both sides by 4

4(x-3)=4x21

=>4x-12=84

Hope this helped :)

Answer:

27

Step-by-step explanation:

6/4 = 1.5

1.5 * 18 = 27

Answer:

1/2 + 1/2 = 1

1/4 + 1/4 = 1/2

So you would walk 1/2 mile in 1 hour

Answer:

1/2

Step-by-step explanation:

1/4*2  multiply 1/4 by 2 because its you walk 1/4 in half a hour so times that by 2 for a full hour.

Answer:

No

Step-by-step explanation:

The answer is to find the sum of each number, because factors are pulling out from total numbers, but when multiplying you don't need to pull out anything so it would be number

Yep!!! Your correct

Answer:

4/5w=8

cross multiply

8×52/w=4

40w=4

w=4/40

w=0.1

Answer:

3, 4, 5 and 5, 12, 13

Step-by-step explanation:

The square of the largest side is equal to the sum of the squares of the other 2 sides.

5² = 3² + 4²

13² = 5² + 12²

The 2 triplets are (3, 4, 5 ) and (5, 12, 13)

Answer:

first put 2 in the numerator for the first blank and 2/9 in the second blank

Step-by-step explanation:

1/3 equals 3/9 and 3/9-1/9=2/9

Answer:

[tex]\frac{3}{9}[/tex]

Step-by-step explanation:

Answer:

It's the left graph, y = f(x)

Step-by-step explanation:

If you find the x-intercepts, you'd solve (2-3x)/x = 0. This means you'd really solve 2-3x=0, which gives you x=3/2.

So the graph must have an x-intercept at (1.5, 0). Only f(x) has that.

[tex]y=\frac{2-3x}{x}[/tex]

Vertical asymptote[tex]\Rightarrow x=0[/tex]

[tex]2-3x=0\\\Rightarrow 3x=2\\\Rightarrow x=\frac{2}{3}[/tex]

Zeroes [tex]x=\frac{2}{3}[/tex]

[tex]\Rightarrow[/tex]graph cuts [tex]x-axis[/tex] at [tex]x=\frac{2}{3}[/tex]

Horizontal asymptote[tex]=\frac{coefficient \ of \ higest \ degree \ term \ in \ numerator}{coefficient \ of \ higest \ degree \ term \ in \ denominator}[/tex]

[tex]y=\frac{-3}{1}[/tex]

 [tex]=-3[/tex]

Horizontal asymptote[tex]y=-3[/tex]

[tex]\therefore[/tex] Given graph is [tex]y=f(x)[/tex]

Answer:

2n-3

Step-by-step explanation:

three less so -3

Julie runs three less than 2 times what Hannah ran

Hannah ran n miles

so Julie ran three less than 2n

Answer:

[tex]\left \{ {{y=x; \ \ x\le 0} \atop {y=4+ \frac12x;\ \ x>0}} \right.[/tex]

Step-by-step explanation:

If you look at the graph you see that:

before 0, the graph has same y as it has x, or y=x.

after 0, the graph starts at 4, and increases by 1 every 2 steps horizontally, or has a slope of 1/2.

Finally, the 0 has to be included in the blue part of the graph based on where the solid dot is.

Step-by-step explanation:

f(x) = -3x - 8

f(-3) = -3(-3) - 8

f(-3) = 9 - 8

f(-3) = 1

Answer:

9/4

hope it helps.................

Answer:

Move it to the right by 3 spaces.

Step-by-step explanation:

10^3 is 1000

On a number line the negative numbers are on the left and the positive numbers are on the right. So since the exponent is a positive 3 we move it to the right by 3 spaces to get 140

Answer:

x = -.1715 ≈ - .172    or x = -5.83

Step-by-step explanation:

x² + 6x + 1 = 0

x² + 6x = -1

Complete the square   Add to both sides (1/2 of the x-term, then square it.)

x² + 6x + 9  = -1 + 9

(x + 3)(x + 3) = 8

(x + 3)² = 8

[tex]\sqrt{(x + 3)^{2}[/tex]  = [tex]\sqrt{8}[/tex]

 x + 3 = ±  [tex]\sqrt{8}[/tex]

  x = -3 ± [tex]\sqrt{8}[/tex]

   x = -3 + [tex]\sqrt{8}[/tex]   or x = -3 - [tex]\sqrt{8}[/tex]

   x = -.1715 ≈ - .172    or x = -5.83

Answer:

Step-by-step explanation:

a. [tex]\left(5\times \:10^3\right)\left(9\times \:10^7\right)[/tex]

[tex]5\times 10^3 = 5000\\\\5000\times \:9\times \:10^7[/tex]

[tex]\mathrm{Multiply\:the\:numbers:}\:5000\times \:9=45000[/tex]

[tex]=45000\times \:10^7[/tex]

b. [tex]\left(7\times 10^5\right)\div \left(2\times 10^2\right)[/tex]

[tex]\left(7\times 10^5\right)\div \left(2\times 10^2\right)=\frac{7\times \:10^5}{2\times \:10^2}[/tex]

[tex]\frac{10^5}{10^2} = 10^3[/tex]

[tex]\frac{7\times \:10^3}{2}[/tex]

[tex]\mathrm{Factor}\:\: 10^3 : 2^3\times5^3[/tex]

[tex]\frac{7\times \:2^3\times \:5^3}{2}[/tex]

[tex]\frac{2^3}{2}=2^2[/tex]

[tex]7\times \:2^2\times \:5^3=3500[/tex]

Answer:

101

HOPE THIS HELPS

- Todo ❤️

Step-by-step explanation:

Suplemetary angles

180-79=101

Answer:

Step-by-step explanation:

Here we need to find a 3rd degree polynomial that has only two distinct zeros:  {-3, 8}.  

Focusing on the zero x = 8 and assuming that this 8 has a multiplicity of 2, we come up with the following polynomial in which the factor x - 8 shows up twice:

f(x) = a(x - 8)(x - 8)(x + 3), or f(x) = a(x - 8)^2(x + 3)

One such polynomial is thus

f(x) = a(x - 8)^2(x + 3), where 'a' is a constant coefficient.  This polynomial has a double zero at x = 8 and a third zero at x = -3.

Step-by-step explanation:

The polynomial has degree 3 and two zeros: - 3 and 8.

Since it has degree 3 it should have 3 zero's.

Two possible scenarios

1. -3 has multiplicity of two:

2. 8 has multiplicity of two:

Answer:

the value of x is 12

......

Answer:

i think the answer should be 8

Step-by-step explanation:

Answer:

here the answer is 24

Step-by-step explanation:

answerrrrrerrr issss hereeeeeee

Answer:

0

Step-by-step explanation:

4 multiply by x(3) = 12

6 multiply by y(2) = 12

12 -12 =0

Answer:

20400

Step-by-step explanation:

its 2.03x10x10x10x10 so first ten: 20.4 and ten: 204 3rd ten: 2040 last ten :20400

Answer:

1/6

Step-by-step explanation:

questions which include 'of 'usually means "×" (multiplication sign) so when u multiply them it gives 1/6

Answer:

104

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

Answer:

3 i belive  100 pecent tho

Step-by-step explanation:

Answer:

1.) x = 2

2.) x = 5

3.) x = 9

4.) x = 0

Step-by-step explanation:

1.) -3x - 8 = -14

-3x = -6

x = 2

2.) 4x - 6 = 14

4x = 20

x = 5

3.) -3 - 3x = -30

-3x = -27

x = 9

4.) -5x + 5 = 5

-5x = 0

x = 0

Answer:

4 3/4

Step-by-step explanation:

8 1/2=8 2/4

8 2/4-3 3/4= 4 3/4

Answer:

(by using the first principle of differentiation)

We have the "Limit definition of Derivatives":

[tex]\boxed{\mathsf{f'(x)= \lim_{h \to 0} \{\frac{f(x+h)-f(x)}{h} \} ....(i)}}[/tex]

Here, f(x) = sec x, f(x+h) = sec (x+h)

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \{\frac{sec(x+h)-sec(x)}{h} \} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{1}{cos(x+h)} -\frac{1}{cos(x)} \} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{cos(x)-cos(x+h)}{cos(x)cos(x+h)} \} }[/tex]

[tex]\boxed{\mathsf{cos\:A-cos\:B=-2sin(\frac{A+B}{2} )sin(\frac{A-B}{2} )}}[/tex]

=> cos(x) - cos(x+h) = -2sin{(x+x+h)/2}sin{(x-x-h)/2}

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{2sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{sin(\frac{h}{2} )}{h} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{2sin(\frac{h}{2} )}{h} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{1\times sin(\frac{h}{2} )}{\frac{h}{2} } }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: 1 }[/tex]

Substituting 0 for h and h/ 2

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+0)}{cos(x+0)cos(x)} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)cos(x)} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)}\times \frac{1}{cos x} }[/tex]

[tex]\implies \mathsf{f'(x)= tan(x)\times sec(x) }[/tex]

Hence, we got

[tex]\underline{\mathsf{\overline{\frac{d}{dx} (sec(x))=sec(x)tan(x)}}}[/tex]

-  - - - -  - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

(by using other standard derivatives)

[tex] \boxed{ \mathsf{ \frac{d}{dx} ( \sec \: x) = \sec x \tan x }}[/tex]

We have a standard derivative for variables in x raised to an exponent:

[tex] \boxed{ \mathsf{ \frac{d}{dx}(x)^{n} = n(x)^{n - 1} }}[/tex]

Therefore,

[tex] \mathsf{ \frac{d}{dx}( \cos x)^{ - 1} = - 1( \cos \: x) ^{( - 1 - 1} } \\ \implies \mathsf{\ - 1( \cos \: x) ^{- 2 }}[/tex]

[tex] \implies \: \mathsf{ - \frac{1}{ (\cos x) {}^{2} } }[/tex]

The process of differentiating doesn't just end here. It follows chain mechanism, I.e.,

while calculating the derivative of a function that itself contains a function, the derivatives of all the inner functions are multiplied to that of the exterior to get to the final result.

[tex] \implies \mathsf{ - \frac{1}{ (\cos x )^{2} } \times ( - \sin x) }[/tex]

[tex] \implies \mathsf{ \frac{ \sin x }{ \cos x } \times ( \frac{1}{cos x} ) }[/tex]

[tex] \implies \mathsf{ \tan x \times \sec x }[/tex]

= sec x. tan x