Find the missing number.

____ × 7 = 91

please help me

The answer to part A is correct. You basically have to find the area of that L shape, and subtract off the area of the shaded trapezoid.

To get part B, you need to find the perimeter. This is because the trim runs along the bottom edge of the wall. Refer to the diagram below. Adding up the exterior sides gets us:

12+12+4+8+8+4 = 48

So she needs 48 meters of trim.

I'm not sure what your teacher means by "what assumptions do you make". If your teacher is referring to something like making room for a door, then we'll have to subtract some value from that 48. The problem with this though is that we don't have any clue how wide the door is. So you'll have to ask your teacher for clarification.

Luckily, this value 48 is an overestimate of the amount of trim Jennifer needs to buy. In my opinion, it's better to overestimate than underestimate, which saves from having to make another trip to the hardware store.

Answer:

x=80°

Step-by-step explanation:

Triangles always add up to 180°.

As you have 2 angles, you would have to add them together and then take it away from 180° to get your answer.

50+50=100°

180-100=80°

Hope this helps :)

Answer:

x = 80°

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for x

x = 180° - (50 + 50)° = 180° - 100° = 80°

Answer:

136

Step-by-step explanation:

Surface area=2*(lb+bh+lh)

=2*(12+42+14)=2*68=136

Mark Brainliest if correct:

x = -2, 9

Step-by-step explanation:

x2: x + 2 = 0

x = -2

x1: x - 9 = 0

x = 9

x = -2, 9

Answer:

300 raisins

Step-by-step explanation:

sum the parts of the ratio, 3 + 27 = 30 parts

Divide the total by 30 for the value of one part of the ratio.

3000 ÷ 30 = 100 ← value of 1 part of the ratio , then

3 parts = 3 × 100 = 300 ← number of raisins in a box

Answer:

I HOPE IT WILL HELP

EXPLANATION IS IN THE PHOTO .

Answer:

domain : {3,4,6}

range: {1,5,9}

Answer:

1. Given

2. Vertical angle theorem

3. AB≅DB, EB≅CB, m<ABC≅m<DBE

4. △ABC ≅ △DBE

Hope this helps :D

[tex] \large\color{lime}\boxed{\colorbox{black}{Answer : - }}[/tex]

We know that, in ∆ABC,

∠A+∠B+∠C = 180°

But the triangle is right angled at C

ie., ∠C = 90°

Therefore, ∠A+∠B+ 90° = 180°

⇒ ∠A + ∠B = 90°

Therefore, cos(A + B) = cos 90º = 0

Answer:

[tex] \frac{21}{4} + \frac{35}{8} \\ = \frac{77}{8} \\ = 9 \frac{5}{8} [/tex]

Step-by-step explanation:

(-1,0),m=2

(1-7),m=12

m=-4,(-1,-4)

Answer:

A = 216.24 km²

Step-by-step explanation:

Step-by-step explanation:

we see, for x=-1 we get 3³

x=0 we get 3²

x=1 we get 3¹

so the function is definitely a 3 to the power of x version.

but we need to adapt the exponent a bit and correct x, so that at least for these 3 values of x the result is "running backwards".

the easiest way : 2-x as exponent.

it fits.

for x=-1 we get 2 - -1 = 3 as exponent.

for x=0 we get 2-0 = 2 as exponent.

for x=1 we get 2-1 = 1 as exponent.

so, the exponential function passing through these 3 points is

[tex]f(x) = {3}^{2 - x} [/tex]

Answer:

see explanation

Step-by-step explanation:

Given

f(x) = [tex]3^{x}[/tex] , then

f(x + 1) = [tex]3^{x+1}[/tex] = [tex]3^{x}[/tex] × 3

Then

f(x) + f(x + 1)

= [tex]3^{x}[/tex] + 3. [tex]3^{x}[/tex] ← factor out [tex]3^{x}[/tex] from each term

= [tex]3^{x}[/tex] (1 + 3)

= 4. [tex]3^{x}[/tex]

= 4f(x)

Answer:

<5 and <6 are supplementary angles

<1 and <6 are vertical angles

Answer:

x=1°.

see the IMAGE FOR SOLUTION

============================================================

Explanation:

We'll use the distance formula here. Rather than compute the distance d based on two points given, we'll go in reverse to use the given distance d to find what the coordinate must be to satisfy the conditions.

We're given that d = 5

The first point is [tex](x_1,y_1) = (5,2)[/tex] and the second point has coordinates of [tex](x_2,y_2) = (x,5)[/tex] where x is some real number.

We'll plug all this into the distance formula and solve for x.

[tex]d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\5 = \sqrt{(5-x)^2+(2-5)^2}\\\\5 = \sqrt{(5-x)^2+(-3)^2}\\\\5 = \sqrt{(5-x)^2+9}\\\\\sqrt{(5-x)^2+9} = 5\\\\(5-x)^2+9 = 5^2\\\\(5-x)^2+9 = 25\\\\(5-x)^2 = 25-9\\\\(5-x)^2 = 16\\\\5-x = \pm\sqrt{16}\\\\5-x = 4 \ \text{ or } \ 5-x = -4\\\\-x = 4-5 \ \text{ or } \ -x = -4-5\\\\-x = -1 \ \text{ or } \ -x = -9\\\\x = 1 \ \text{ or } \ x = 9\\\\[/tex]

This means that if we had these three points

Then segments AB and AC are each 5 units long.

Answer:

c = 12

Step-by-step explanation:

i'm Attaching the work

Answer:

W

Step-by-step explanation:

I done it before

Answer:

113.1 cm²

Step-by-step explanation:

V = [tex]\frac{1}{3}[/tex] [tex]\pi[/tex] r² h

h = 12 cm , r = 3 cm , [tex]\pi[/tex] = [tex]\frac{22}{7}[/tex]

V ≈ 113.1 cm²

The question is incomplete, the complete question is;

A factory produces 1,250,000 toys each year. The number of toys is expected to increase by about 150% per year. Which model can be used to find the number of toys being produced, n (in millions), in t years?

A. n= 2.5(1.5)/t, t cannot = 0

B. n= 1.5t^2 + 1.25

C. n= 1.5t + 1.25

D. n= 1.25(2.5^t)

Answer:

D. n= 1.25(2.5^t)

Step-by-step explanation:

This is an exponential growth problem. In mathematics, for an exponential growth problem;

P = Po(1 + r)^t

Where;

P= amount at time t

Po =initial amount

r= rate

t= time

In the context of the question we have;

n= 1.25(1 + 150/100)^t

n= 1.25(2.5)^t

9514 1404 393

Answer:

Step-by-step explanation:

Let r, c, h represent the numbers of meals eaten in a restaurant, car, and at home, respectively. The problem statement tells us of the relations ...

  r + c + h = 193

  -r + c + h = 15

  r + 0c -h = 30

Add the last two equations:

  (-r +c +h) +(r -h) = (15) +(30)

  c = 45

Add the first two equations:

  (r + c + h) +(-r + c + h) = (193) +(15)

  2c +2h = 208

  h = 104 -c = 59 . . . . solve for h, substitute for c

The last equation can be used to find r.

  r = 30 +h = 30 +59 = 89

89 meals are eaten in a restaurant; 45 meals in a car; and 59 at home.

Answer:

1. 3 yards= 9 feet

2. 78 cups=5 gallons

3. 72 inches = 2 yards

4. 80 ounces = 5 pounds

5. 84 inches = 7 feet

6. 24 feet = 8 yards

7. 40 pints = 5 gallons

8. 16 cups = 5 quarts

9. 144 inches = 4 yard

10. 48 ounces = 3 pounds

Answer:

27 litros de leche de búfalo equivalen a 45.9 litros de leche de vaca.

Step-by-step explanation:

Sabiendo que un litro de leche de búfala equivale a 1.7 litros de leche de vaca, podemos calcular el equivalente de capacidad de la vaca para 27 litros de leche de búfala mediante Regla de Tres Simple:

[tex]x = 27\,L\times \frac{1.7\,L}{1\,L}[/tex]

[tex]x = 45.9\,L[/tex]

27 litros de leche de búfalo equivalen a 45.9 litros de leche de vaca.

Answer:

(8 × 2) × 6 = 8 × (2 × 6) represents associative property of whole number.

Answer:

Step-by-step explanation:

[tex]\displaystyle \Large \boldsymbol{} \tt a) \ 3-2x=3(x+4)-x-1\\\\3-2x=3x+12-x-1 \\\\3-12+1=3x+2x-x \\\\4x=-8 \\\\\boxed{ \tt x=-2} \\\\\\b) \ 5x\underline{(x-1)}-4\underline{(x-1)}=0 \\\\\\(5x-4)(x-1)=0 \Longrightarrow \boxed{ \tt x_1=0.8 \ \ ; \ \ x_2=1}[/tex]

Answer:

Step-by-step explanation:

r = d/2

r = 2.4 m/2 = 1.2

h = 1.8

pi = 3.14

Volume = pi * r^2 * h

Volume = 3.14 * 1.2^2 * 1.8

Volume = 8.139

Volume = 8 to the nearest m^3

Answer:

Answer

5.0/5

2

poojamaurya21

Virtuoso

133 answers

14.9K people helped

Answer:

): "x2" was replaced by "x^2". 4 more similar replacement(s).

Step by step solution :

Step 1 :

Step 2 :

Pulling out like terms :

2.1 Pull out like factors :

x6 - x5 + x4 - x3 + x2 - x =

x • (x5 - x4 + x3 - x2 + x - 1)

2.2 Factor x5 - x4 + x3 - x2 + x - 1

Try to factor this 6-term polynomial into (2-term) • (3-term)

Begin by splitting the 6-term into two 3-term polynomials:

-x2 + x - 1 and x5 - x4 + x3

Next simplify each 3-term polynomial by pulling out like terms:

-1 • (x2 - x + 1) and x3 • (x2 - x + 1)

Note that the two simplified polynomials have x2 - x + 1 in common

Now adding the two simplified polynomials we get

(x3 - 1) • (x2 - x + 1)

[tex]\\ \sf\longmapsto 2(5m-4)-3(m-5)^2[/tex]

[tex]\\ \sf\longmapsto 10m-8-3(m^2-10m+5^2)[/tex]

[tex]\\ \sf\longmapsto 10m-8-3(m^2-10m+25)[/tex]

[tex]\\ \sf\longmapsto 10m-8-3m^2+30m-75[/tex]

[tex]\\ \sf\longmapsto -3m^2+30m+10m-75-8[/tex]

[tex]\\ \sf\longmapsto -3m^2+40m-83[/tex]