Find the midpoint of the segment with the given endpoints.
(-7, -9) and (-2,7)

Answer:

-1/3

Step-by-step explanation:

this is the best answer

Answer:

In order for the function to be discontinuous at an asymptote, the curve needs to exist on both sides of the asymptote. If the curve only exists on one side of the asymptote, then there's no discontinuity at that point.

Step-by-step explanation:

Hey there!

The formula to find the perimeter of a rectangle is "P=2(l+w)".

Hope this helps!

Have a great day! :)

Answer:

formula to find the perimeter of rectangle is

hope it helps

stay safe healthy and happy.

Answer:

A = W² + 6W

Step-by-step explanation:

The width is W.

The length is 6 units greater than the width, so the length is W + 6.

The area is the product of the length and width.

A = (W + 6)W

A = W² + 6W

9514 1404 393

Answer:

  292 yd²

Step-by-step explanation:

We can find the area of the remaining L shape by subtracting the area of the 21×22 rectangle at lower left from the 26×29 overall rectangle.

  shape area = (26 yd)(29 yd) -(21 yd)(22 yd) = 754 yd² -462 yd²

  shape area = 292 yd²

__

Additional comment

The area of a rectangle is the product of its length and width.

There are many ways the area of this shape can be calculated. The area can be divided into two rectangles, two trapezoids, three rectangles, and other ways.

If you cut up the given shape into smaller pieces, you will generally need to know the widths of the arms of the L. One of those is shown as 7 yd. The other is 26-21 = 5 yd.

Using the method we did, we only needed the dimensions shown on the figure.

Answer:

you either need to score a perfect on one exam and get a 80 on the second or get two 90s on both exams.

Step-by-step explanation:

Answer:

0.60 or 60% is the answer!

Step-by-step explanation:

Hope I helped

5 students offers all the two subjects.

Student that offers Physic only = 15 students

Student that offers chemistry only  = 13 students

Students that offers only one subject = 28 students

Total student in the class = 35

20 offer physics.

18 offer chemistry

2 offer neither physics nor chemistry.

Therefore,

x = student that offer both subject

35 = 20 + 18 - x + 2

35 - 2 - 20 - 18 = -x

-5 = -x

x = 5

Therefore, 5 students offers all the two subjects.

Student that offers Physic only = 20 - 5 = 15

Student that offers chemistry only = 18 - 5 = 13

Students that offers only one subject = 13 + 15 = 28

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Answer:

Answer = he made 7,000 in July and sold 10 cars in august.

Step-by-step explanation:

Answer:

-1

Step-by-step explanation:

f(-1) = 2|-1| + 3(-1)

|-1| = 1

=> f(-1) = 2(1) - 3

=> f(-1) = 2 - 3

=> f(-1) = -1

Answer:

25d + 100

Step-by-step explanation:

I will call "d" the days passed

25d + 100

Answer:

x = 5

Step-by-step explanation:

x^2/(x + 5) = 25/(x+5)      Subtract the right side from both sides.

x^2/(x + 5) - 25/(x + 5) = 0

x^2 - 25

=======   = 0

x + 5

(x + 5)(x - 5)

============= = 0

(x + 5)

Cancel x + 5 in the numerator and denominator.

x - 5 = 0

x = + 5

Does it check?

x^2/(x + 5) = 25/(x + 5)

x = 5

5^2/(10) = 25/10

25/10 = 25/10 Yes it checks.

We need to find the equation which is equidistant to the given points.

[tex]A(-2,6,3)[/tex] and [tex]B(5,3,-3)[/tex]

This can be done using the distance formula.

Let us take a point [tex]P(x,y,z)[/tex] which is equidistant from both points so

[tex]\sqrt{(x+2)^2+(y-6)^2+(z-3)^2}=\sqrt{(x-5)^2+(y-3)^2+(z+3)^2}\\\Rightarrow y^2-12y+x^2+4x+z^2+49-6z=y^2-6y+x^2+z^2+6z+43-10x\\\Rightarrow 7x-3y-2z+1=0[/tex]

The required equation is [tex]7x-3y-2z+1=0[/tex]

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[tex]6\cdot\square=9\\\\\square=9:6\\\\\square=\frac{9}{6}\rightarrow\square=\frac{3}{2} \ (\text{devide 9 and 6 by 3})[/tex]

Answer:

The product of any rational number and any irrational number will always be an irrational number.

Step-by-step explanation:

Answer:

2x + 3 + 3x +12 + 90 = 180 (degree )

5x +105=180 (degree )

5x= 180-105 (degree )

5x = 75 (degree )

x = 75/5 (degree )

x = 15 #

therefore, 2x + 3= 2*15 + 3

=30+3

= 33#

3x + 12 = 3*15+12

= 45 +12

= 57#

The scaled factor is 3 for all of them.

Answer:

-18 is the right answer..

I think the answer is A and C!

Answer:

B) Keeping A constant and decreasing B

C) Increasing A and keeping B constant

Step-by-step explanation:

I did it on Khan Academy :)

Answer:

B. [tex] {a}^{ - 7 - 10} [/tex] (second option)

Step-by-step explanation:

[tex] \frac{ {a}^{ - 7} }{ {a}^{10} } [/tex]

[tex] {a}^{ - 7 - 10} [/tex]

[tex] - 7 - 10 = - (7 + 10) = - 17[/tex]

Answer:

18.63

Step-by-step explanation:

[tex] \frac{6}{10} = 0.6 \\ \frac{3}{100} = 0.03[/tex]

[tex]10 + 8 + 0.6 + 0.03 = 18.63[/tex]

Given Data : Length = (7p - 10q) and Breadth = (2p - 9q)

Calculation :

⟹ Perimeter = 2(Length + Breadth)

⟹ Perimeter = 2(7p - 10q + 2p - 9q)

⟹ Perimeter = 2(9p - 19q)

⟹ Perimeter = 18p - 38q centimetres

The required perimeter of the rectangle is 18p - 38q centimeters.

It is required to find the required perimeter of the rectangle.

A rectangle is a type of quadrilateral, whose opposite sides are equal and parallel. It is a four-sided polygon that has four angles, equal to 90 degrees. A rectangle is a two-dimensional shape.

Given:

width of a rectangle = (2p - 9q) centimeters,

length measures= (7p - 10q) centimeters.

We know that

⟹ Perimeter = 2(Length + Breadth)

By put the value width and length in perimeter we get,

⟹ Perimeter = 2(7p - 10q + 2p - 9q)

⟹ Perimeter = 2(9p - 19q)

⟹ Perimeter = 18p - 38q centimeters

Therefore, the required perimeter of the rectangle is 18p - 38q centimeters.

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Answer:

-29

Step-by-step explanation:

(-14) + (-15) =

-14 - 15 =

-29

Answer:

45000rupees

Step-by-step explanation:

cost of 1 litre of petrol=60rupees

cost of 750 litres of petrol=750×60rupees

=45000rupees

Answer:

Step-by-step explanation:

x - first

x + 12 - second

x + (x + 12) = 44

2x=44-12

x=16

first number is 16

second number is 16+12=28

two numbers are 16 and 28

16 and 28 are the required two numbers when one number exceeds another by 12 and their sum is 44

One number exceeds another by 12 and their sum is 44

We need to find the two numbers

Two expressions with equal sign is called equation.

Let x be the first number

x + 12 be the  second number

x + (x + 12) = 44

2x=44-12

x=16

Therefore first number is 16

second number is 16+12=28

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Step-by-step explanation:

[tex]w = x^4\sin(y^4z^3)[/tex]

The differential [tex]dw[/tex] is

[tex]dw = 4x^3\sin(y^4z^3)dx [/tex]

[tex]\:\:\:\:\:\:\:\:\:\:\:+ x^4\cos(y^4z^3)(4y^3z^3)dy [/tex]

[tex]\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:+ x^4\cos(y^4z^3)(3y^4z^2)dz[/tex]

Answer:

6 * 100 = 600

14 * 10  = 140

12 * 1    = 12

------------------------

752

Answer:

98376

Step-by-step explanation:

300000000000000000000000