Answer:
D
Step-by-step explanation:
The midpoint is the average of the 2 endpoints, that is
midpoint = [tex]\frac{-7+12}{2}[/tex] = [tex]\frac{5}{2}[/tex] = 2.5 → D
In a class of 75 students, the number of girls is just half that of the
number of boys. How many girls are there in the class? How many
boys are there in the class?
Answer:
25 girls and 50 boys
Step-by-step explanation:
let x be the number of boys
let x/2 be the number of girls
x + x/2 = 75
3x/2 = 75
3x = 150
x = 50
there are 50 boys and 50/2 = 25 girls.
check:
50 + 25 = 75
Please read below. Thank you.
Answer:
desmos .com
Step-by-step explanation:
Answer: See the graph below
Step-by-step explanation:
Concept:
Formula for circle: (x - k )² + (y - h)² = r²
Center = (k, h)
Radius = r
**Disclaimer** variables used can be different
------------------------------------------------------------------------
Solve:
Given: (x - 2)² + (y + 3)² = 16
Center = (2, -3)
Radius = √16 = 4
Hope this helps!! :)
Please let me know if you have any questions
Which pair shows equivalent expressions?
O 2x+10=-2(x-5)
O-2(x+5)=2x-10
0 -2x-10=-2(x+5)
O -2(x-5)=-2x-10
Answer:
O-2(x+5)=2x-10
Explanation
O-2(x+5)=2x-10
SOLUTION
-2x(x)= -2x
-2x+5 = -10
Help me please please help me please
Answer:
the first one...
the cost of renting the ally for 14 hours
Step-by-step explanation:
Answer:
the first one
the number of dollars it costs to rent the bowling lane for14 hours
What is “8 - 4(-x + 5)” equivalent too?
Answer:
4x -12
Step-by-step explanation:
8 - 4(-x + 5)
Distribute
8 -4(-x) -4(5)
8 +4x -20
4x -12
answer 4( - 3 + x)
factor expression 4(2 - ( - x + 5)4(2 + x - 5)answer
[tex]4( - 3 + x)[/tex]
simplify the expression[tex]8 - 4( - x + 5)[/tex]
answer
[tex] - 12 + 4x[/tex]
A mine extracts 2 metric tons of coal in an hour. The mine uses ton of the extracted coal every hour to generate electricity for the mine and sells the rest. If t is the number of hours spent mining, which expression represents the amount of ore sold? How much ore can the mine sell after extracting ore for 12 hours?
Answer:
A
Step-by-step explanation:
Got it right!! <3
Pls mark brainliest ^^
Find the area of the image below
Answer:
0 because there is no image....
Mr. Mark's class has 32 students in which 20 are girls. What is the ratio of the girls to the boys?
Hello!
32 students (girls+boys)
20 (girls)
32-20 = 12 (boys)
The ratio of girls to the boys
= 20:12
= 5:3
D is the answer.
Good studies!
If anyone knows pls answer
Answer:
1
Step-by-step explanation:
Danny, a grade 10 math student, completed the following chart. Review Danny's work. If there
are errors, explain, and correct them.
Natural
Whole
Integers
Rational
Irrational
Real
-3
32
711
125
143/125
7.17...
Answer:
[tex]\begin{array}{ccccccc}&Natural&Whole &Integer&Rational&Irrational&Real\\-3\dfrac{3}{9}&&&& \checkmark&&\checkmark\\\sqrt{11} &&&&&\checkmark &\checkmark\\125&\checkmark&\checkmark&\checkmark&\checkmark&&\checkmark\\4\cdot \sqrt[3]{125} &\checkmark&\checkmark&\checkmark&\checkmark&&\checkmark\\7.\overline {17} &&&& \checkmark&&\checkmark\end{array}[/tex]
Step-by-step explanation:
The given numbers and their categories are;
1) [tex]-3\dfrac{3}{9}[/tex] is not a natural number, because, natural numbers are whole number positive integers. It is not an integer, because it is a fraction.
It is a real number, because it has no imaginary part and it is a rational number because it can be expressed as a fraction
2) √11 is not a rational number, because it cannot be expressed as a fraction, and it is real number because it has no imaginary parts.
Therefore, is an irrational and real number
3) 125; The options selected are correct
4) 4·∛125 = 4 × 5 = 20; The options selected are correct
5) 7.[tex]\overline {17}[/tex] = 710/99; Therefore, 7.[tex]\overline {17}[/tex] is a rational number and it is also a real number as all natural, whole, integers, rational, and irrational numbers are real numbers
We get;
[tex]\begin{array}{ccccccc}&Natural&Whole &Integer&Rational&Irrational&Real\\-3\dfrac{3}{9}&&&& \checkmark&&\checkmark\\\sqrt{11} &&&&&\checkmark &\checkmark\\125&\checkmark&\checkmark&\checkmark&\checkmark&&\checkmark\\4\cdot \sqrt[3]{125} &\checkmark&\checkmark&\checkmark&\checkmark&&\checkmark\\7.\overline {17} &&&& \checkmark&&\checkmark\end{array}[/tex]
Find the value of x.
A. 99
B. 9
C. 90
D. 11
ILL GIVE BRAINLIEST
Answer:
B) 9
Step-by-step explanation:
Because there's a square between the 2 angles, that means these angles are complementary (angles that add up to 90°). So:
5x - 9 + 6x = 90
11x - 9 = 90
11x = 90 + 9
11x = 99
x = 9
Answer:
B.9
Step-by-step explanation:
The way to solve this is by noticing that these angles are complementary(they add up to 90 degrees). So you add the equations together and equal them to 90. 5x-9+6x=90.Then you solve to find that x=9.
40 points Please help!!!
What is the volume of this regular prism?
48.55 cubic inches
55.8 cubic inches
9.7 cubic inches
24.28 cubic inches
Answer:
V = 24.28 in ^3
Step-by-step explanation:
The area of the base is
A =5/2 × s × a where s is the side length and a is the apothem
A = 5/2 ( 2.13) * .87
A = 4.63275
The volume is
V = Bh where B is the area of the base and h is the height
V = 4.63275 ( 5.24)
V =24.27561 in^3
Rounding to the hundredth
V = 24.28 in ^3
what are the values of angles G and H?
Answer:
G = 78°
H = 98°
Step-by-step explanation:
Opposite angles in a cylic quadrilateral are supplementary. Therefore:
G + E = 180°
Substitute
8x + 1 + 11x + 8 = 180°
Add like terms
19x + 9 = 180°
19x + 9 - 9 = 180° - 9
19x = 171
19x/19 = 171/19
x = 9
G = 8x + 1
Plug in the value
G = 8(9) + 1 = 73°
H + F = 180° (opposite angles of a cyclic quadrilateral is equal?
Plug in the values
6y - 4 + 5y - 3 = 180°
Add like terms
11y - 7 = 180
11y = 180 + 7
11y = 187
y = 187/11
y = 17
H = 6y - 4
Plug in the value of y
H = 6(17) - 4
H = 98°
The density of water is 1 gram per cubic centimeter. A more dense object will sink, and a less dense object will float. Will a marble with a radius of 1.4 cm and a mass of 9 grams sink or float in water? The marble will (float/sink) because the density of the marble is about (0.71, 0.78, 1.28, 1.40) grams per cubic centimeter.
Answer:
sink at 1.28 g/cm^3
v = 4/3 [tex]\pi r^{3}[/tex]
v = 4/3 [tex]\pi 1.4^{3}[/tex]
v =11.49 /9 =1.28
Step-by-step explanation:
How many three-digit numbers can you make if you are not allowed to use any other digits except 4 and 0?
Answer:
There is a slight problem with this question
Do numbers starting with "0" count as a digit position
I would say no, thus the answer is 4...
if you are allowed to use 0 then the answer is 8
in other words if the question was using only 4's and 1's then the answer would be 8
Step-by-step explanation:
000
004
040
044
400
404
440
444
Can someone help me with this math homework please!
1. a= 19
2.2 ( second option)
3.C
4D
The number of cities in a region over time is represented by the function C(x)=2.9(1.05)^x. The approximate number of people per city is represented but the function P(x)=(1.05)^3x+5
Which Function best describes T(x), the approximate population in the region?
HELP!!! PLS
Answer:
B. [tex]T(x) = 2.9\cdot (1.05)^{4\cdot x + 5}[/tex]
Step-by-step explanation:
The approximate population in the region is the product of the number of cities in a region and the approximate number of people per city, that is:
[tex]T(x) = C(x)\cdot P(x)[/tex] (1)
If we know that [tex]C(x) = 2.9\cdot (1.05)^{x}[/tex] and [tex]P(x) = (1.05)^{3\cdot x + 5}[/tex], then the formula for the approximate population in the region is:
[tex]T(x) = [2.9\cdot (1.05)^{x}]\cdot [(1.05)^{3\cdot x + 5}][/tex]
[tex]T(x) = 2.9\cdot (1.05)^{4\cdot x + 5}[/tex]
Hence, correct answer is B.
If in the equation [ 4/t-1 = 2/w-1 ] t ≠ 1 and w ≠ 1, then t =
a) 2w-1
b) 2(w-1)
c) x-2
d) 2w
t=2w-1
OPTION A is the correct answer...
Using the Factor Theorem, which of the polynomial functions has the zeros 3, radical 5, and negative radical 5?
A. f (x) = x3 – 3x2 + 5x + 15
B. f (x) = x3 + 3x2 – 5x + 15
C. f (x) = x3 – 3x2 – 5x + 15
D. f (x) = x3 + 3x2 – 5x – 15
Answer:
f (x) = x3 – 3x2 – 5x + 15
Step-by-step explanation:
i just took the test
The required polynomial is [tex]\bold{f(x)=x^{3}-3x^{2}-5x+15}[/tex]
The correct answer is an option (C)
What is polynomial?"It is an algebraic expression that consist of variables and coefficients."
What is a factor theorem?"It describes the relationship between the root of a polynomial and a factor of the polynomial.""This theorem states that - If f(x) is a polynomial of degree n ≥ 1 and ‘a’ is any real number, then, (x - a) is a factor of f(x), if f(a) = 0"For given question,
The polynomial function has the zeros 3, radical 5, and negative radical 5.
The polynomial function has zeros 3, √5, -√5
This means the factors of the polynomial function are (x - 3), (x - √5) and (x - (-√5)) = (x + √5).
Using the Factor theorem the polynomial function would be,
[tex]\Rightarrow f(x)=0\\\\\Rightarrow (x - 3)\times (x - \sqrt{5} )\times (x + \sqrt{5} ) = 0\\\\\Rightarrow (x-3)\times (x^{2} - (\sqrt{5} )^{2} )=0\\\\\Rightarrow (x-3)\times (x^{2} - 5)=0\\\\\Rightarrow x \times (x^{2} - 5) - 3\times (x^{2} - 5) =0\\\\\Rightarrow x^{3}-5x-(3x^{2}-15)=0\\\\\Rightarrow x^{3}-3x^{2}-5x+15=0[/tex]
Therefore, the required polynomial is [tex]\bold{f(x)=x^{3}-3x^{2}-5x+15}[/tex]
The correct answer is an option (C)
Learn more about the factors of the polynomial here:
https://brainly.com/question/26354419
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Find questions attached.
Show workings.
Answer:
a. The required proof is obtained from triangles OAB and ABC formed by joining AB and that we have;
A[tex]\hat O[/tex]B + 2∠C = 180°, 2·A[tex]\hat P[/tex]B + 2∠C = 180°
∴ A[tex]\hat O[/tex]B = 2·A[tex]\hat P[/tex]B
b. i) P[tex]\hat S[/tex]S = P[tex]\hat R[/tex]Q, given that angles subtended by the same arc or chord are equal, therefore, in ΔPQS, we have;
[tex]\left | PS \right |[/tex] = [tex]\left |PQ \right |[/tex]
ii) S[tex]\hat Q[/tex]P = 45°, [tex]S\hat R Z[/tex] =90°
Step-by-step explanation:
a. The given parameters are;
The center of the circle is point O
Points on the circumference of the circle = A, B, and P
Required to be proved, A[tex]\hat O[/tex]B = 2·A[tex]\hat P[/tex]B
Let ∠O represent A[tex]\hat O[/tex]B and let ∠P' represent A[tex]\hat P[/tex]B
We draw a line from the center O to the point P, and a line joining points A and B on the circumference of the circle
In ΔOAB, we have;
∠O + 2∠C = 180° (The sum of the interior angles of a triangle)
In ΔAPB, we have;
∠P' + ∠(C - a) + ∠(P' + C + a) = 180°
∴ 2·∠P' + 2·∠C = 180°
Therefore, by addition property of equality, we get;
∠O = 2·∠P'
Therefore;
A[tex]\hat O[/tex]B = 2·A[tex]\hat P[/tex]B
b. i) The given parameters are;
Points on the circle = P, Q, R, and S
P[tex]\hat Q[/tex]S = P[tex]\hat R[/tex]Q
According to circle theory, the angles which an arc or chord subtends in a given segment are equal, therefore;
P[tex]\hat S[/tex]S = P[tex]\hat R[/tex]Q
Therefore, P[tex]\hat S[/tex]S = P[tex]\hat Q[/tex]S by transitive property of equality
P[tex]\hat S[/tex]S and P[tex]\hat Q[/tex]S are base angles of ΔPQS, given that P[tex]\hat S[/tex]S = P[tex]\hat Q[/tex]S, we have;
ΔPQS is an isosceles triangle with base QS and therefore, the sides PS and PQ are the equal sides
Therefore, we have;
[tex]\left | PS \right |[/tex] = [tex]\left |PQ \right |[/tex]
ii) Given that SQ is the diameter of the circle, we have by circle theorem, the angle subtended on the circumference by the diameter = 90°
∴ [tex]S\hat PQ[/tex] = 90°
From (i), we have that P[tex]\hat S[/tex]S = P[tex]\hat Q[/tex]S, therefore, in triangle ΔPQS, we have;
[tex]S\hat PQ[/tex] + P[tex]\hat S[/tex]S + S[tex]\hat Q[/tex]P = 180°
Therefore;
90° + P[tex]\hat S[/tex]S + S[tex]\hat Q[/tex]P = 180°
P[tex]\hat S[/tex]S + S[tex]\hat Q[/tex]P = 180° - 90° = 90°
P[tex]\hat S[/tex]S = P[tex]\hat Q[/tex]S, therefore, P[tex]\hat S[/tex]S + S[tex]\hat Q[/tex]P = 2·S[tex]\hat Q[/tex]P
P[tex]\hat S[/tex]S + S[tex]\hat Q[/tex]P = 2·S[tex]\hat Q[/tex]P = 90°
S[tex]\hat Q[/tex]P = 90°/2 = 45°
S[tex]\hat Q[/tex]P = 45°
Similarly, given that SQ is the diameter, of the circle the angle [tex]S\hat R Q[/tex] formed by jointing S to Q is 90°
[tex]S\hat R Q[/tex] = 90°
[tex]S\hat R Q \ and \ S\hat R Z[/tex] are angles on a straight line and are therefore, supplementary, therefore;
[tex]S\hat R Z[/tex] = 180° - [tex]S\hat R Q[/tex]
[tex]S\hat R Z[/tex] = 180° - 90° = 90°
[tex]S\hat R Z[/tex] =90°.
Find the sum of a geometric series of which a1=7, n=4 and r=3
Answer:
280
Step-by-step explanation:
Use the formula: (a((r^n)-1))/(r-1)
= (7((3^4)-1))/(3-1)
The sum of the given geometric series is 280.
We have given that,
a1=7, n=4 and r=3
We have to determine the sum of a geometric series
What is the formula sum of the geometric series?[tex]S_n=(a((r^n)-1))/(r-1)[/tex]
[tex]= (7((3^4)-1))/(3-1)[/tex]
[tex]=280[/tex]
Therefore the sum of the given geometric series is 280.
To learn more about the geometric series visit:
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help help help pls pls
Answer:
see explanation
Step-by-step explanation:
Under a clockwise rotation about the origin of 90°
a point (x, y ) → (- y, x ) , then
(3, 3 ) → (- 3, 3 )
(3, 4 ) → (- 4, 3 )
(5, 3 ) → (- 3, 5 )
A car travelling at v kilometers per hour will need a stopping distance, d, in meters without skidding that can be modelled by the function d=0.0067v2+0.15v. Determine the speed at which a car can be travelling to be able to stop within 37m.
I’m need of serious help!
Answer:
v = 14 km/h
Step-by-step explanation:
d = 0.0067[tex]v^{2}[/tex] + 0.15v
differentiate the function with respect to v to have;
d = 0.0134v - 0.15
given that the distance without skidding = 37 m (0.037 km) , then;
0.037 = 0.0134v - 0.15
0.0134v = 0.037 + 0.15
= 0.187
v = [tex]\frac{0.187}{0.0134}[/tex]
= 13.9552
v = 14 km/h
The speed of the car travelling would be 14 km/h to be able to stop within 37m.
The square root of 0.25 is 0.5 which is a greater number. Give another number whose square root is larger than the number and explain why.
Answer:
Another example of a number who's square root is greater than the number is [tex]\sqrt{0.49}[/tex] which is 0.7
Step-by-step explanation:
This square root is larger than the number because it is a decimal. When you multiply a decimal by a decimal, the decimal point becomes greater. For example: 0.7 multiplied by 0.7 equals 0.49 which has 2 decimal places, while 0.7 only has one.
Find the special product:
(r + 5)^2
Answer:
i am not sure about this answer but i got r^2+10r+25
What is the simplest version of 9/16×4/18
Answer:
1/8
Step-by-step explanation:
9/16 * 4/18
Rewriting
9/18 * 4/16
9/18 = 1/2 and 4/16 = 1/4
1/2 * 1/4
1/8
Answer:
[tex]\frac{1}{8}[/tex]
Step-by-step explanation:
[tex]\frac{9}{16}[/tex] x [tex]\frac{4}{18}[/tex] = [tex]\frac{(9)(4)}{(16)(18)}[/tex]
[tex]\frac{(9)}{(18)}[/tex] = [tex]\frac{1}{2}[/tex]
[tex]\frac{4}{16}[/tex] = [tex]\frac{1}{4}[/tex]
[tex]\frac{(1)(1)}{(2)(4)}[/tex] = [tex]\frac{1}{8}[/tex]
which of the following equations have complex roots?
9514 1404 393
Answer:
B. 3x² +2 = 0
Step-by-step explanation:
The equation of A has a couple of real roots. We're pretty sure there are complex numbers that will satisfy this equation, but we don't know how to find them. (We suspect a typo, and that the equation is supposed to be 2x² +1 = 7x, which has only real roots.)
__
The equation of B can be rewritten as ...
x² = -2/3
This will have complex roots.
__
The discriminants of both equations C and D are positive, so those have only real roots.
2x² -5x -1 ⇒ d = (-5)² -4(2)(-1) = 33
3x² -6x -1 ⇒ d = (-6)² -4(3)(-1) = 48
Find the line’s slope and a point on the line
Y-4=-3/4(x+5)
Answer:
The slope is -3/4 and a point on the line is (-5,4)
Step-by-step explanation:
This equation is in point slope form
y -y1 = m(x-x1)
where m is the slope and (x1,y1) is a point on the line
Y-4=-3/4(x+5)
Y-4=-3/4(x - -5)
The slope is -3/4 and a point on the line is (-5,4)
Find the equation of the line passing through the point (-3.6, 2.1) and parallel
to the line 4.9x + 5.4y = 3
Answer:
y = -4.9/5.4x - 1.17
Step-by-step explanation:
First let's convert the equation to standard form of y = mx + b.
4.9x + 5.4y = 3
Subtract 4.9x from both sides.
5.4y = -4.9x + 3
Divide each term by 5.4.
y = -4.9/5.4x + 0.56
If two lines are parallel to each other, they have the same slope slopes.
The first line is y = -4.9/5.4x + 0.56. Its slope is -4.9/5.4. A line parallel/perpendicular to this one will also have a slope of -4.9/5.4.
Plug this value (-4.9/5.4) into your standard point-slope equation of y = mx + b.
y = -4.9/5.4x + b
To find b, we want to plug in a value that we know is on this line: in this case, it is (-3.6, 2.1). Plug in the x and y values into the x and y of the standard equation.
2.1 = -4.9/5.4(-3.6) + b
To find b, multiply the slope and the input of x (-3.6)
2.1 = 3.27 + b
Now, subtract 3.27 from both sides to isolate b.
-1.17 = b
Plug this into your standard equation.
y = -4.9/5.4x - 1.17
This equation is parallel/perpendicular to your given equation (y = -4.9/5.4x + 0.56) and contains point (-3.6, 2.1)
Hope this helps!
Two corresponding sides of similar triangles have the lengths 6 cm and 16 cm. What is the ratio, expressed as a decimal?
Answer: 16:81
Step-by-step explanation:
