Answer:
Step-by-step explanation:
arrange the data from ascending to descending order
2,5,6,10,13,16,26,26,26,27,30
Median=N+1/2 (N means no of data)
=11+1/2
=12/2
=6 th term
=16
rangle = highest value - lowest value
=30-2
=28
HELP ASAP NEED HELP. WILL GIVE BRAINIEST AND 100 POINTS.
Algebra 1
Use the function f(x) = 4x^2 - 7x - 15 to answer the questions.
Part a: completely factor f(x).
Part b: what are the x-intercepts of the graph of f(x)? Show your work.
Part C: describe the end behavior of the graph of f(x). Explain.
Part D: what are the steps you would use to graph f(x)? Justify that you can use the answers obtained in part B and part C to draw the graph.
Answer:
A: [tex]f(x)=(4x+5)(x-3)[/tex]
B: [tex](-\frac{5}{4} , 0)[/tex] and [tex](3, 0)[/tex]
C: They are parallel, which means they have no endpoint.
ILL BRAINLIEST YOU IF YOU HELP ME PLEASE
Answer:
B
Step-by-step explanation:
They are alternate interior angles so that means they are equal
4x - 30 = 2x
2x = 30
x = 15
if a - 4b =18, what is the value of 3^a/81^b?
Answer:
[tex]3 {}^{a - 4b} = 3 {}^{18} [/tex]
The value of the equation 3ᵃ / 81ᵇ = 3¹⁸
What is an Equation?
Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given data ,
Let the equation be represented as A
Now , the value of A is
a - 4b = 18 be equation (1)
Now , the value of the equation 3ᵃ / 81ᵇ = A
On simplifying the equation , we get
81ᵇ = 3⁴ᵇ
And , 3ᵃ / 81ᵇ = 3ᵃ / 3⁴ᵇ
On further simplification , we get
3ᵃ / 3⁴ᵇ = 3ᵃ⁻⁴ᵇ
And , substituting the values from equation (1) , we get
3ᵃ⁻⁴ᵇ = 3¹⁸
Hence , the equation is 3ᵃ⁻⁴ᵇ = 3¹⁸
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Translate into an inequality.
Negative nine is greater than or equal to the sum of two-fifths times a number and seven
Answer:
-9 ≥ (2/5x) + 7Step-by-step explanation:
the sign must have a line underneath itself to show that it can be equal and unequal. 2/5 times a number (from my understanding) is 2/5 times a variable, plus 7.
Translation into inequality of negative nine is greater than or equal to the sum of two-fifths times a number, and seven is -9 ≥ (2/5x) + 7.
What is inequality?The relationship between two non-equal values is defined by inequalities. Equal does not mean unequal, though. In most cases, the "not equal sign" is used.
Negative nine is greater than or equal to the sum of two-fifths times a number, and seven can be written as,
-9 ≥ (2/5x) + 7
Therefore, Translation into inequality of negative nine is greater than or equal to the sum of two-fifths times a number, and seven is -9 ≥ (2/5x) + 7.
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It cost Josiah $4.48 to send 112 text messages. What is the cost of sending text
messages, in dollars per text?
Answer:
4 cents
Step-by-step explanation:
4.48 divided by 112 = 0.04
The number -2 is a solution to which of the following inequalities?
x + 7 > 5
-3 x < 1
x - 7 < -4
Answer:
The answer is the third one, x - 7 < 4
Step-by-step explanation:
I need help with this quickly, I only have a couple hours left before homework is gone.
last day of school is tomorrow....
please answer quickly..
It only has one x intercept
Step-by-step explanation: when you graph it there is only one point where the line meets the x intercept
Can someone tell the answer, no one else seemed to know it.
Answer:
it is right bro x+ 2 .......mark me brainiest please
Sam built a ramp to a loading dock. The ramp has a vertical support 2 m from the base of the loading dock and 3m from the base of the ramp. If the vertical support is 1.2 m in height, what is the height of the loading dock?
Answer:
tan angle = x/5.
Step-by-step explanation:
If I understand your description,
tan angle at bottom of ramp = 1.2/3.
Then tan angle = x/5.
Check my thinking.
How do you perform constructions related to circles? What theorems and explanations can be used to justify these constructions? How do you perform constructions related to circles? What theorems and explanations can be used to justify these constructions?
Answer and explanation:
To construct a circle, draw a line that represents the diameter of the circle. Bisect the line so that it is a perpendicular bisector of the diameter of the circle. Place your compass at the bisection point/midpoint and draw an arc or better still the whole circle.
Theorem: the perpendicular bisector of a chord passes through the center of a circle.
Note: a diameter of a circle is a chord that passes through the center of a circle.
Please help!!!!!!
Which of these are examples of mutually beneficial interactions? Choose all that apply.
A. Ants living in special hollow thoms in a tree rush out and sting plant-eaters.
B. An orchid grows high in a tree to get more sunlight, but it does not affect the tree.
c. Wolves eat the deer that cannot run as fast as the other deer.
D. A bee gets nectar and pollen from the clover flowers in a meadow.
E. A tick bites a dog and drinks the dog's blood.
Answer:
A. The tree provides shelter for the ants, and the ants help the tree to stay alive
slope:1/6 point: (24 ,4)
Answer:
y -4 = 1/6(x-24)
y = 1/6x -2
Step-by-step explanation:
We can point slope form
y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line
y -4 = 1/6(x-24)
Or we can write slope intercept form
y = mx+b where m is the slope and b is the y intercept
Substituting the points
4 = 1/6(24)+b
4 = 6+b
4-6 = b
-2 =b
y = 1/6x -2
Answer:
[tex]y = mx + c \\ 4 = (\frac{1}{6} \times 24) + c \\ 4 = 4 + c \\ c = 0 \\ y = \frac{1}{6} x[/tex]
work out the circumfrance of this cirlce take pi to be 3.142 and write down all the digits given by your calculator raduis 10cm
Answer:
[tex]C=68.4[/tex]
Step-by-step explanation:
[tex]Circumference=2\pi r[/tex]
Pi = 3.142
r (radius) = 10 cm
[tex]C=2(3.142)(10)[/tex]
[tex]C=(6.84)(10)[/tex]
[tex]C=68.4[/tex]
Therefore, circumference of a circle with 10 cm radius is 68.4.
I hope this helps......
please solve asap in my math final
find the value of x show ur work
Answer:
Step-by-step explanation:
43 + 24 + 57 + x = 180 degree (being sum of interior angles of a triangle)
124 + x = 180
x = 180 - 124
x = 56 degree
in small triangle
57 + 24 + z = 180 degree (sum of interior angles of a triangle )
81 + z = 180
z = 180 - 81
z = 99 degree
in big triangle
x + 43 + y = 180 degree (sum of interior angles of a triangle )
56 + 43 + y = 180
99 + y =180
y = 180 - 99
y = 81 degree
The value of x= 56°
Hope it helps you...
Simplify √49 + [√81 - x(9x = 14)]
[tex]\longrightarrow{\green{- 9 {x}^{2} + 14x + 16}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
[tex] \sqrt{49} + [ \sqrt{81} - x \: (9x - 14) ] \\ \\ = \sqrt{7 \times 7} + [ \sqrt{9 \times 9} - 9 {x}^{2} + 14x] \\ \\ = \sqrt{( {7})^{2} } + [ \sqrt{ ({9})^{2} } - 9 {x}^{2} + 14x ] \\ \\ (∵ \sqrt{ ({x})^{2} } = x ) \\ \\ = 7 + (9 - 9 {x}^{2} + 14x) \\ \\ = 7 + 9 - 9 {x}^{2} + 14x \\ \\ = - 9 {x}^{2} + 14x + 16[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}[/tex]
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.
y=-16x^2+232x+134
Answer:
Step-by-step explanation:
when it touch the ground,y=0
-16x²+232x+134=0
-16(x²-29/2 x+(-29/4)²-(-29/4)²)=-134
-16(x-29/4)²-16(-861/16)=-134
-16(x-29/4)²+861=-134
-16(x-29/4)²=-134-861
(x-29/4)²=-995/-16=995/16
x-29/4=±√995/4
rejecting negative sign
x=29/4+√995/4=(29+√995)/4≈15.14 second
Evaluate 2(4 - 1) Ο Α. 36 ОВ. 60 O C. 30 O D. 18
please help
Answer:
D
Step-by-step explanation:
2*3^2
2*9
18
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {D. \:18}}}}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
[tex]2 \: ( \: {4 - 1} \: )^{2} [/tex]
[tex] = 2\: (\: {3} \: )^{2} [/tex]
[tex] = 2 \: ( \: 3 \times 3 \: )[/tex]
[tex] = 2 \times 9[/tex]
[tex] = 18[/tex]
Note:-[tex]\sf\pink{PEMDAS\: rule.}[/tex]
P = Parentheses
E = Exponents
M = Multiplication
D = Division
A = Addition
S = Subtraction
[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}[/tex]
The actual amount in a 12-ounce container of a certain brand of orange juice is normally distributed with mean μ = 12.34 ounces and standard deviation σ = 0.04 ounce. What percentage of the juice bottles contain between 12.24 and 12.30 ounces of orange juice?
Answer:
15.25%
Step-by-step explanation:
The actual amount in a 12-ounce container of a certain brand of orange juice is normally distributed with mean μ = 12.34 ounces and standard deviation σ = 0.04 ounce. What percentage of the juice bottles contain between 12.24 and 12.30 ounces of orange juice?
We solve using the z score formula
z-score is is z = (x-μ)/σ,
where x is the raw score
μ is the population mean = μ = 12.34 ounces
σ is the population standard deviation = σ = 0.04 ounce
For x = 12.24
z = 12.24 - 12.34/0.04
z = -2.5
Probability value from Z-Table:
P(x = 12.24) = 0.0062097
For x = 12.30
z= 12.30 - 12.34/0.04
z = -1
Probability value from Z-Table:
P(x = 12.30) = 0.15866
Hence, the probability of the juice bottles contain between 12.24 and 12.30 ounces of orange juice
P(x = 12.30) - P(x = 12.24)
= 0.15866 - 0.0062097
= 0.1524503
Therefore, the percentage of the juice bottles contain between 12.24 and 12.30 ounces of orange juice is calculated as:
= 0.1524503 × 100
= 15.24503%
= 15.25%
Given that a*b = 2a - 3b, then 2*(-3) =
Answer:
2*(-3)= -6
Step-by-step explanation:
I do not see how "a*b=2a-3b" would change the fact 2 times negative 3 is -6
Factor this polynomial expression. 2X2 + 12x + 18
A. 2(x+3)(x+3)
B. 2(x - 3)(x-3)
c. 2(x+3)(x - 3)
D. (2x + 9)(x+2)
[tex]\longrightarrow{\green{A.\:2 \: ( x + 3)(x + 3) }}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
[tex]2 {x}^{2} + 12x + 18[/tex]
Taking 2 as common factor, we have
[tex] = 2 \: ( {x}^{2} + 6x + 9) \\ = 2 \: ( {x}^{2} + 3x + 3x + 9)[/tex]
Next, we take [tex]x[/tex] as common from first two terms and 3 from last two terms,
[tex] = 2 \: [x(x + 3) + 3(x + 3)][/tex]
Taking the factor [tex](x+3)[/tex] as common,
[tex] = 2 \: ( x + 3)(x + 3)[/tex]
[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35}}}}}[/tex]
a regular polygon has a perimeter of 40 cm and a apothem of 6 cm. find the polygons area
Answer:
a = 120 cm²
Step-by-step explanation:
n = number of sides
edge length
40/n
divide the polygon into n congruent triangles
a = (1/2)(edge * apothem) * number of triangles
a = (1/2)(40/n)(6) * n
n cancels out
a = (1/2)(40)(6)
a = 120 cm²
Which statements about the factors of the terms in the expression 12 x + 18 x y minus 24 y are true? Select three options.
The factors common to 12x and 18xy are 1, 2, 3, 6, x, and y.
The factors common to 12x and 18xy are 1, 2, 3, 6, and x.
The factors common to 12x and 24y are 1, 2, 3, 4, 6, and 12.
The GCF of the expression is 6xy.
The GCF of the expression is 6.
Answer:
i think the answer is Options B, C and E holds.
Step-by-step explanation:
this makes options B and C a choice:
Given the expression: 12x+18xy-24y
Factors of 12x=1,2,3,4,6,12 and x
Factors of 18xy=1,2,3,6,9,18,x and y.
Factors of 24y=1,2,3,4,6,8,12,24 and y.
next for E this is why its a choice:
12x+18xy-24y=6(2x+3xy-4y)
Answer:
bce
Step-by-step explanation:
20 POINTS
The function f(x)=45x represents the number of jumping jacks j(x) you can do in x minutes. How many jumpibg jacks can you do in 10 minutes
Answer:
450 jumping jacks
Step-by-step explanation:
f(10) = 45 (10)
45 * 10 is just 450 :)
Answer:
450.
Step-by-step explanation:
f(10) = 45 * 10 = 450 jumping jacks.
(1.8x10^5)divided by(3x10^6) in standard form?
Answer:
0.06
Step-by-step explanation:
Given data:
[tex]1.8(10^{5})[/tex] divided by 3×[tex]10^{6}[/tex]
Now,
[tex]\frac{(1.8)10^{5} }{3(10^{6}) } \\=0.6(10^{5-6} )\\=0.6(10^{-1} )\\=0.06[/tex]
Answer will be 0.06
The correct standard form is 0.06.
1.8 x 10⁵ divided by 3 x 10⁶
(10)ᵃ × (10)ᵇ = (10)ᵃ⁺ᵇ
(10)ᵃ ÷ (10)ᵇ = (10)ᵃ⁻ᵇ
(1.8 x 10⁵)/3 x 10^6 = 6 x 10⁻²
6/10² = 0.06
Therefore, the standard form is 0.06.
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I need help please and thank you!!
Answer:
Option 4
Step-by-step explanation:
2x² + 32 = 0
2x² = -32
x² = -16
sqrt(-16) got no real solution. (no real number multiplied by itself will be negative)
Can someone help ?! Please
Answer:
A
Step-by-step explanation:
A prime number only has 2 factors, that is
1 and the number itself
factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
factors of 22 are 1, 2, 11, 22
factors of 33 are 1, 3, 11, 33
factors of 37 are 1, 37
Therefore 37 is a prime number
Please HELP WITH THIS !!!
Solve the quadratic equation by using a graphic approach. Round your answer to the hundredths place.
x² - 2x - 4= 0
a. x= 3.24 or x = -1.24
c. x = 4.24 or x = -0.24
b. x = 2.73 or x = -0.73
d. x= 5.24or x = -1.24
Pls explain I’m having a hard time understanding the lesson
Answer:
x = 3.24, x = -1.24
Step-by-step explanation:
The standard form for a quadratic equation is [tex]ax^2+bx+c=0[/tex]. For your equation a = 1, b = -2, c = -4. The quadratic formula you will be using is [tex]x=\frac{-b\pm \sqrt{b^{2} -4ac} }{2a}[/tex].
Plug in a = 1, b = -2, and c = -4 into the formula.
[tex]=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-4\right)}}{2\cdot \:1}[/tex]
We'll do the top part first:
[tex]\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-4\right)}[/tex]
Apply rule [tex]- (-a) = a[/tex]
[tex]=\sqrt{\left(-2\right)^2+4\cdot \:1\cdot \:4}[/tex]
Apply exponent rule [tex](-a)^{n} =a^n[/tex] if [tex]n[/tex] is even
[tex](-2)^2=2^2[/tex]
[tex]=\sqrt{2^2+4\cdot \:1\cdot \:4}[/tex]
Multiply the numbers
[tex]=\sqrt{2^2+16}[/tex]
[tex]2^2=4[/tex]
[tex]=\sqrt{4+16}[/tex]
Add
[tex]=\sqrt{20}[/tex]
The prime factorization of 20 is [tex]2^2*5[/tex]
20 divides by 2. 20 = 10 * 2
[tex]=2*10[/tex]
10 divides by 2. 10 = 5 * 2
[tex]=2* \:2*5[/tex]
2 & 5 are prime numbers so you don't need to factor them anymore
[tex]=2*2*5[/tex]
[tex]=2^2*5[/tex]
[tex]=\sqrt{2^2\cdot \:5}[/tex]
Apply radical rule [tex]\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}[/tex]
[tex]=\sqrt{5}\sqrt{2^2}[/tex]
Apply radical rule [tex]\sqrt[n]{a^{n} } =a[/tex]; [tex]\sqrt{2^2} =2[/tex]
[tex]=2\sqrt{5}[/tex]
[tex]=\frac{-\left(-2\right)\pm \:2\sqrt{5}}{2\cdot \:1}[/tex]
Because of the [tex]\pm[/tex] you have to separate the solutions so that one is positive and the other is negative.
[tex]x=\frac{-\left(-2\right)+2\sqrt{5}}{2\cdot \:1},\:x=\frac{-\left(-2\right)-2\sqrt{5}}{2\cdot \:1}[/tex]
Positive x:
[tex]\frac{-\left(-2\right)+2\sqrt{5}}{2\cdot \:1}[/tex]
Apply rule [tex]-(-a)=a[/tex]
[tex]=\frac{2+2\sqrt{5}}{2\cdot \:1}[/tex]
Multiply
[tex]=\frac{2+2\sqrt{5}}{2}[/tex]
Factor [tex]2+2\sqrt{5}[/tex] and rewrite it as [tex]=2\cdot \:1+2\sqrt{5}[/tex]. Factor out 2 because it is the common term. [tex]=2\left(1+\sqrt{5}\right)[/tex].
[tex]=\frac{2\left(1+\sqrt{5}\right)}{2}[/tex]
Divide 2 by 2
[tex]x=1+\sqrt{5}[/tex] or [tex]x=3.24[/tex] (You'll probably have to use a calculator for the square root of 5)
^Repeating the process of positive x for negative x in order to get [tex]x=1-\sqrt{5}[/tex] or [tex]x=-1.24[/tex]
When should a heart rate monitor be used?
Answer:
There are two simple, compelling reasons to use a heart-rate monitor: to train and race at the best pace for you. The table below shows you how to find your perfect paces for: (1) the three most important workouts in any training program; and (2) the four most popular road-race distances.
Step-by-step explanation:
Hope this helps :)
If two lines are intersected by a third line, is the third line necessarily a transversal?
No, The third line does not necessarily be a transversal.
What is Equation of line?
The equation of line with slope 'm' and y intercept at point 'b' is given as;
⇒ y = mx + b
Given that;
Two lines intersected by a third line.
Since, When two lines are parallel to each other and two lines intersected by a third line then, third lines are transversal.
So, Here it is not given two lines are parallel.
Thus, Third line is not necessarily a transversal.
Hence, The third line does not necessarily be a transversal.
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