Find the measure of

Answer:

The percentage of people who prefer football is approximately the same for the right- and left-handed groups.

Step-by-step explanation:

The bar for the right-handed group representing soccer is between 10% and 20% (below 20%) while the bar for the left-handed group representing soccer is at 20%.

Percentage of left-handed group of people who prefer soccer is higher than the right-handed group who prefer soccer. Therefore, they don't have the same percentage.

Answer:

D

Step-by-step explanation:

;)

Answer:

16 is answer

Step-by-step explanation:

3(2)^2+4(1)^2= 3(4)+4(1)=12+4=16

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Answer:

  x^2/1 +y^2/81 = 1

Step-by-step explanation:

We know that the equation of a unit circle is ...

  x^2 +y^2 = 1 . . . . . equation of a unit circle

We also know that replacing x with x/a in a function will expand the graph by a factor of 'a'. Similarly, replacing y with y/b will do the same in the vertical direction.

An ellipse is a circle that has had different expansion factors applied along its different axes. Here, the given points tell us the center of the ellipse is (0, 0), and that it has been expanded by a factor of 9 in the y-direction and a factor of 1 in the x-direction This means the equation for it would be ...

  (x/1)^2 +(y/9)^2 = 1 . . . . . equation for desired ellipse

In the required form, this is ...

  [tex]\dfrac{x^2}{1}+\dfrac{y^2}{81}=1[/tex]

Answer:

The cube root parent function:

Horizontally stretched by a factor of 4:

Translated 5 units right:

Translated 3 units up:

9514 1404 393

Answer:

  C(-1, -4)

Step-by-step explanation:

We want ...

  AC/CB = 1/5

  5(C-A) = B-C . . . . multiply by 5CB

  6C = B +5A . . . . . add 5A-C

  C = (B +5A)/6 . . . divide by 6

  C = ((4, 6) +5(-2,-6))/6 = (4-10,6-30)/6 = (-6, -24)/6

  C = (-1, -4)

Step-by-step explanation:

s=12km t=15m

15m--> km= 15/60= 0,25h

V=s/t

V=12km/0,25h

V= 48 km/h

Answer: plz marl brainilist

3966

Step-by-step explanation:

(98 × 63 - 32 × 69

98 * 63) - (32 * 69)

Step-by-step explanation:

[tex] \frac{ {c}^{2} - 4 }{c + 3} [/tex]

[tex] \frac{(c - 2)(c + 2)}{(c + 3)} [/tex]

Answer:

28 blue marbles

Step-by-step explanation:

yellow: blue

8               4

To get to 56 yellow marbles multiply by 7  

yellow: blue

8*7           4*7

56             28

There will be 28 blue marbles

Answer:

X = 64

Step-by-step explanation:

All of the angles are right angles (because of the square at one of the angles shown above). This means each angle equals 90 degrees. If X + 26 = 90, then X = 64 because 90 - 26 = 64. I hope this helps!

Answer: X = 64

Step-by-step explanation:

Answer:

2x-3

Step-by-step explanation:

f(x) = 3x-1

g(x)= x+2

(f-g) (x) = 3x-1 - (x+2)

Distribute the minus sign

             = 3x-1 -x-2

 Combine like terms

               = 3x-x -1-2

                =2x -3

The correct answer to the given question is "[tex]\bold{392.47\ < \mu <\ 427.53}[/tex],[tex]\bold{0.28 \ < P <\ 0.34}[/tex], and for Interpret results go to the C part.

Following are the solution to the given parts:

A)

[tex]\to \bold{(n) = 16}[/tex]

[tex]\to \bold{(\bar{X}) = 410}[/tex]

[tex]\to \bold{(\sigma) = 40}[/tex]

In the given question, we calculate [tex]90\%[/tex] of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

[tex]\to \bold{\bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}}[/tex]

[tex]\to \bold{C.I= 0.90}\\\\\to \bold{(\alpha) = 1 - 0.90 = 0.10}\\\\ \to \bold{\frac{\alpha}{2} = \frac{0.10}{2} = 0.05}\\\\ \to \bold{(df) = n-1 = 16-1 = 15}\\\\[/tex]

Using the t table we calculate [tex]t_{ \frac{\alpha}{2}} = 1.753[/tex]  When [tex]90\%[/tex] of the confidence interval:

[tex]\to \bold{410 \pm 1.753 \times \frac{40}{\sqrt{16}}}\\\\ \to \bold{410 \pm 17.53\\\\ \to392.47 < \mu < 427.53}[/tex]

So [tex]90\%[/tex] confidence interval for the mean weight of shipped homemade candies is between [tex]392.47\ \ and\ \ 427.53[/tex].

B)

[tex]\to \bold{(n) = 500}[/tex]

[tex]\to \bold{(X) = 155}[/tex]

[tex]\to \bold{(p') = \frac{X}{n} = \frac{155}{500} = 0.31}[/tex]

Here we need to calculate [tex]90\%[/tex] confidence interval for the true proportion of all college students who own a car which can be calculated as

[tex]\to \bold{p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}}[/tex]

[tex]\to \bold{C.I= 0.90}[/tex]

[tex]\to\bold{ (\alpha) = 0.10}[/tex]

[tex]\to\bold{ \frac{\alpha}{2} = 0.05}[/tex]

Using the Z-table we found [tex]\bold{Z_{\frac{\alpha}{2}} = 1.645}[/tex]

therefore [tex]90\%[/tex] the confidence interval for the genuine proportion of college students who possess a car is

[tex]\to \bold{0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}}\\\\ \to \bold{0.31 \pm 0.034}\\\\ \to \bold{0.276 < p < 0.344}[/tex]

So [tex]90\%[/tex] the confidence interval for the genuine proportion of college students who possess a car is between [tex]0.28 \ and\ 0.34.[/tex]

C)

Learn more about confidence intervals:  

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Answer:

384

Step-by-step explanation:

Answer:

384 words

Step-by-step explanation:

Number of words typed in 1 minute = 48

So, number of words typed in 8 minutes

= Number of words typed in 1 minute × 8

= 48 × 8

= 384

So, Curtis types 384 words in 8 minutes.

Answer:

Hypotenuse = XY = 17 cm

Base = YZ = 15 cm

Perpendicular = XZ = 8 cm

Step-by-step explanation:

Given:

[tex]A=1.5\:\text{cm}^2×\left(\frac{1\:\text{m}^2}{10^4\:\text{cm}^2}\right)=1.5×10^{-4}\:\text{m}^2[/tex]

[tex]d = 2.0\:\text{mm} = 2.0×10^{-3}\:\text{mm}[/tex]

The charge stored in a capacitor is given by [tex]Q = CV.[/tex] In the case of a parallel-plate capacitor, its capacitance C is given by

[tex]C = \epsilon_0\dfrac{A}{d}[/tex]

where [tex]\epsilon_0[/tex] = permittivity of free space. The amount of charge stored in the capacitor is then

[tex]Q = \left(\epsilon_0\dfrac{A}{d}\right)V[/tex]

[tex]\:\:\:\:\:=\left[\dfrac{(8.85×10^{-12}\:\text{F/m})(1.5×10^{-4}\:\text{m}^2)}{(2.0×10^{-3}\:\text{m})}\right](12\:\text{V})[/tex]

[tex]\:\:\:\:\:=8.0×10^{-12}\:\text{C}[/tex]

Answer:

See explanation

Step-by-step explanation:

Given

[tex]A = (-1,1)[/tex]

[tex]B = (3,3)[/tex]

[tex]C =(4,-2)[/tex]

Solving (a): [tex]P(0,0) \to Q(1,3)[/tex]

This means that:

[tex](x,y) \to (x+1,y+2)[/tex]

So, we have:

[tex]A = (-1,1)[/tex]

[tex]A' = (-1 + 1,1+2)[/tex]

[tex]A' = (0,3)[/tex]

[tex]B = (3,3)[/tex]

[tex]B'= (3 + 1,3+2)[/tex]

[tex]B'= (4,5)[/tex]

[tex]C =(4,-2)[/tex]

[tex]C' = (4+1,-2+1)[/tex]

[tex]C' = (5,-1)[/tex]

Solving (b): [tex]P(0,-1) \to Q(4,-2)[/tex]

This means that:

[tex](x,y) \to (x+4,y-1)[/tex]

So, we have:

[tex]A = (-1,1)[/tex]

[tex]A' = (-1+4,1-1)[/tex]

[tex]A' = (3,0)[/tex]

[tex]B = (3,3)[/tex]

[tex]B'= (3+4,3-1)[/tex]

[tex]B'= (7,2)[/tex]

[tex]C =(4,-2)[/tex]

[tex]C' = (4+4,-2-1)[/tex]

[tex]C' = (8,-3)[/tex]

Solving (c): [tex]P(-1,-2) \to Q(-2,-2)[/tex]

This means that:

[tex](x,y) \to (x-1,y)[/tex]

So, we have:

[tex]A = (-1,1)[/tex]

[tex]A' = (-1-1,1)[/tex]

[tex]A' = (-2,1)[/tex]

[tex]B = (3,3)[/tex]

[tex]B'= (3-1,3)[/tex]

[tex]B'= (2,3)[/tex]

[tex]C =(4,-2)[/tex]

[tex]C'= (4-1,-2)[/tex]

[tex]C'= (3,-2)[/tex]

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Answer:

  (c)  On a coordinate plane, a dashed straight line has a positive slope and goes through (0, negative 4) and (3, negative 2). Everything to the left of the line is shaded.

Step-by-step explanation:

The x-coefficient is positive, so we can determine the shading from ...

  2x ... < ... (pay attention to the x-term and the inequality symbol)

That is, the solution region will have x values that are less than those on the (dashed) boundary line. Lower x-values are to the left, hence shading is on the left side of the boundary. (That's all you need to know here to make the correct choice.)

_____

Additional comment

If the choices are "above" or "below", then you will want to look at the y-term and the inequality symbol. If the coefficient of the variable of interest is negated (as it is for y here), then you need to consider the inequality symbol reversed: -y < ...   ⇔   y > .... Here, that means the shading is above the line. Since the slope of the line is positive, "left" and "above" are the same thing.

Answer:

c

Step-by-step explanation:

E2021

Geometric figures are basically figures that have a boundary. The geometric figures and their real life examples are:

To determine the real life object of each geometric figure, we simply identify objects that have similar features as the geometric figure.

For instance, a rectangular prism has 6 rectangular faces; building blocks, some gift box and cabinets also have 6 rectangular faces.

So, these three real life objects can be used as examples of a rectangular prism.

When the above explanation is applied to the other geometric figures, we come up with the following list:

Read more about geometric figures at:

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In the photo are a couple possible answers you could use.

Answer:

The company should use a mean of 12.37 ounces.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The distribution for the amount of beer dispensed by the machine follows a normal distribution with a standard deviation of 0.17 ounce.

This means that [tex]\sigma = 0.17[/tex]

The company can control the mean amount of beer dispensed by the machine. What value of the mean should the company use if it wants to guarantee that 98.5% of the bottles contain at least 12 ounces (the amount on the label)?

This is [tex]\mu[/tex], considering that when [tex]X = 12[/tex], Z has a p-value of [tex]1 - 0.985 = 0.015[/tex], so when [tex]X = 12, Z = -2.17[/tex].

Then

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-2.17 = \frac{12 - \mu}{0.17}[/tex]

[tex]12 - \mu = -2.17*0.17[/tex]

[tex]\mu = 12 + 2.17*0.17[/tex]

[tex]\mu = 12.37[/tex]

The company should use a mean of 12.37 ounces.

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Answer:

  2.244

Step-by-step explanation:

Your answer looks like it may have a transcription error.

The period is reasonably computed as the difference of the x-values of the given points:

  period = 4.114 -1.870 = 2.244 . . . seconds

Answer:

a. The average number of hashtags used in a social media post from a marketing agency is different than 7 hashtags.

Step-by-step explanation:

A social media platform states that a social media post from a marketing agency has 7 hashtags, on average.

This means that at the null hypothesis, we test if the mean is 7, that is:

[tex]H_0: \mu = 7[/tex]

A digital marketing specialist studying social media advertising believes the average number of hashtags used in a post from a marketing agency is different than the number stated by the social media platform.

Keyword is different, so at the null hypothesis, we test if the mean is different of 7, that is:

[tex]H_1: \mu \neq 7[/tex]

Thus, the correct answer is given by option a.

Given:

The five number summary of two data sets are given as:

a) 0, 4, 12, 14, 20

b) 2, 8, 14, 18, 20

To find:

The range for the outliers.

Solution:

We know that,

An observation is considered an outlier if it is below [tex]Q_1-1.5(IQR)[/tex]

An observation is considered an outlier if it is above [tex]Q_3+1.5(IQR)[/tex]

Where, IQR is the interquartile range and [tex]IQR=Q_3-Q_1[/tex].

The five number summary of two data sets are given as:

0, 4, 12, 14, 20

Here, [tex]Q_1=4[/tex] and [tex]Q_3=14[/tex].

Now,

[tex]IQR=14-4[/tex]

[tex]IQR=10[/tex]

The range for the outliers is:

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[4-1.5(10),14+1.5(10)][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[4-15,14+15][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[-11,29][/tex]

An observation is considered an outlier if it is below -11.

An observation is considered an outlier if it is above 29.

The five number summary of two data sets are given as:

2, 8, 14, 18, 20

Here, [tex]Q_1=8[/tex] and [tex]Q_3=18[/tex].

Now,

[tex]IQR=18-8[/tex]

[tex]IQR=10[/tex]

The range for the outliers is:

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[8-1.5(10),18+1.5(10)][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[8-15,18+15][/tex]

[tex][Q_1-1.5(IQR),Q_3+1.5(IQR)]=[-7,33][/tex]

An observation is considered an outlier if it is below -7.

An observation is considered an outlier if it is above 33.

Answer:

x = 15.92

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp / adj

tan 53 = x / 12

12 tan 53 = x

x=15.92453

Rounding to the nearest hundredth

x = 15.92

Answer:

15.92

Step-by-step explanation:

Answer:-10

-3+-4+-3

-3-4=-7

-7+-3=-7-3

=-10

Answer:

4.5%

Step-by-step explanation:

The tax rate=(2152.6/47800)*100=4.5%

Answer:

n ≥  3

Step-by-step explanation:

Applying the remainder term in evaluating the minimum order of the Taylor polynomial

absolute error ≤ 10^-2

[tex]\sqrt{1.06}[/tex]

∴ n ≥   ?

The remainder term is the leftover term after computation ( dividing one polynomial with another )

attached below is the detailed solution

The minimum order of the Taylor polynomial, n≥3

Taylor polynomial is a series of functions that has an infinite sum of terms that are expressed in terms of the function's derivatives.

[tex]\rm f(a)+\frac{f'(a)}{1!} (x-a)+\frac{f''(a)}{2!} (x-a)^{2} +....,[/tex]

Applying the Taylor series polynomial, the minimum order of the Taylor polynomial, centered at 0

[tex]\rm f(0)+\frac{f'(0)}{1!} (x-0)+\frac{f''(0)}{2!} (x-0)^{2} +....,[/tex]

f(x) = [tex]\sqrt{x+1}[/tex]

[tex]f'(x)=\frac{1}{2}[/tex]

[tex]f''(x)=3/8[/tex]

substituting in the Taylors series

T(x) = [tex]1+\frac{x}{2} -\frac{x^{2} }{8} +\frac{x^{3} }{16}[/tex]......

T(0.06) = [tex]1+\frac{0.06}{2} -\frac{0.06^{2} }{8} +\frac{0.06^{3} }{16}...[/tex]

T(0.06) =1.03

f(0.06) =

[tex]\sqrt{0.06+1}\\= 1.03[/tex]

Therefore, the minimum order of the Taylor polynomial, n≥3

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Answer:

Step-by-step explanation:

Slope of the given line: m=4/3

Slope of the perpendiclar : m'=-3/4 (the inverse of the opposed of m)

Equation of the perpendiclar line: (passing through (-7,2))

[tex]y-2=(x+7)*\dfrac{-3}{4} \ or\\\\ y=-\dfrac{3x}{4} -\dfrac{13}{4}[/tex]

Answer:

Length:8

Width:5.5

Step-by-step explanation:

We're given area = 44m^2, and the formula for the area of a rectangle is the length multiplied by the width. So,

A = L * w = 44

We're given that the length is 3m shorter than 2 times the width, which is 2w - 3. "2w" is the same as "2 times the width", and the 3 is subtracted because it says 3m shorter than 2 times the width. So L = 2w - 3, and we can substitute that into our equation above.

(2w - 3)(w) = 44

2w^2 - 3w - 44 = 0

Use the quadratic formula here.

x = {3 ± √(-3)^2 - 4(-44)(2)}/2(2)

= {3 ± √9 + 352}/4

= (3 ± 19)/4

You'll get two answers, but remember, we're measuring the length of the sides of shapes, so it has to be positive. It's impossible to have negative lengths, so we're going to stick with the (3 + 19)/4 answer, which is 22/4, which is 5.5. However, we are not finished yet. This is just the width. Now we need to plug it into the equation for length, which was 2w - 3

2(5.5) - 3 = 11 - 3 = 8

The length is 8m and the width is 5.5m.

Answer:

(-3, -6)

Step-by-step explanation:

always start from the origin! Hope this helps!