Find the length of side xx in simplest radical form with a rational denominator.

Answer:

B. x=4

Step-by-step explanation:

I hope this helps!

Answer:

18 pencils in 3 packs.

Step-by-step explanation:

Assuming that each pack will have the same amount of pencils. It is given that there are 36 pencils in all when one has 6 packs. Find the amount in each pack by dividing (total amount of pencils)/(amount of packs) = Amount of pencils per pack:

36/6 = 6

There are 6 pencils in each pack.

Now, Elsa wants to know how much pencils are in 3 packs. Multiply the amount of packs with the amount of pencils in each pack:

Total amount of pencils = amount of packs (3) x amount of pencils per pack (6)

                                       = 3 x 6

                                       = 18

There are 18 pencils in 3 packs.

~

Answer:

The answer is y= - ⅓x + 5 in slope intercept form and y-7 = - ⅓ (x + 6) in point slope form.

Answer: 60 miles

Step-by-step explanation:

Given

It takes ferry 2 hours to travel to town A and only [tex]1.5\ hr[/tex] to travel back to town B.

Speed of current is [tex]u=5\ mph[/tex]

Suppose the speed of the ferry is [tex]v[/tex] mph

Distance traveled in both the cases is same, but it took more time traveling to city A that is, ferry is moving upstream and downstream for returning time.

[tex]\Rightarrow 2(v-5)=1.5(v+5)\\\Rightarrow 2v-10=1.5v+7.5\\\Rightarrow 0.5v=17.5\\\Rightarrow v=35\ mph[/tex]

Distance between the towns is [tex]2\times (35-5)=60\ \text{miles}[/tex]

Answer:

The distance between the two towns is 60 miles.

Step-by-step explanation:

Let the distance between A and B is d.

A to B , t = 2 hour

B to A , t' = 1.5 hour

Speed of current, u = 5 mph

Let the speed of ferry is v.

distance = speed x time

d = (v - 5) x 2 = (v + 5) x 1.5

2 v - 10 = 1.5 v + 7.5

0.5 v = 17.5

v = 35 mph

So, the distance is

d = (35 - 5) x 2 = 60 miles.

X is a vertical angle to the angle marked as 100 degrees.

Vertical angles are the same so x = 100 degrees

Answer: 100 degrees

Answer:

[tex]2(6 + 4) - 3(5) \\ 12 + 8 - 15 \\ = 5[/tex]

Answer:

1

Step-by-step explanation:

2*6+4-3*5

12+4-15

16-15

1

Answer:

Profit obtained by X =  Rs. 2,976.64

Profit obtained by Y = Rs. 2,545.58

Profit obtained by Z = Rs. 2,777.78

Step-by-step explanation:

Total capital for the first 6 months = Rs 5000 + Rs.4500 + Rs.6500 = Rs. 16,000

Total capital for the next 3 months = Rs. 16,000+ Rs 5000 = Rs. 21,000

Total capital for the last 3 months of the year = Rs. 21,000 + (Rs 4500 * 2) = Rs. 30,000

Share of profit of each partner is the sum of all the ratios of his capital to total capital of the business at each point in time multiply by the ratio of the numbers of months covered by each capital to 12 months and then multiply by RS.8300.

Profit obtained by X = ((Rs 5000 / 16,000) * (6 / 12) * Rs. 8300) +  ((Rs 10,000 / 21,000) * (3 / 12) * Rs. 8300) + ((Rs 10,000 / 30,000) * (3 / 12) * Rs. 8300) =  Rs. 2,976.64

Profit obtained by Y = ((Rs 4500 / 16,000) * (6 / 12) * Rs. 8300) +  ((Rs 4500 / 21,000) * (3 / 12) * Rs. 8300) + ((Rs 13,500 / 30,000) * (3 / 12) * Rs. 8300) = Rs. 2,545.58

Profit obtained by Z = ((Rs 6500 / 16,000) * (6 / 12) * Rs. 8300) +  ((Rs 6500 / 21,000) * (3 / 12) * Rs. 8300) + ((Rs 6,500 / 30,000) * (3 / 12) * Rs. 8300) = Rs. 2,777.78

Confirmation of total profit shared = Rs. 2,976.64 + = Rs. 2,545.58 + Rs. 2,777.78 = Rs. 8,300

Answer:

i don't know how to work this

Answer:

x = [tex]\frac{3}{4}[/tex] , x = 20

Step-by-step explanation:

2([tex]\frac{3x-5}{x+2}[/tex] ) - 5 ([tex]\frac{x+2}{3x-5}[/tex] ) = 3

Multiply through by (x + 2)(3x - 5) to eliminate the fractions

2(3x - 5)² - 5(x + 2)² = 3(x + 2)(3x - 5) ← expand factors on both sides

2(9x² - 30x + 25) - 5(x² + 4x + 4) = 3(3x² + x - 10) ← distribute parenthesis

18x² - 60x + 50 - 5x² - 20x - 20 = 9x² + 3x - 30 ← simplify left side

13x² - 80x + 30  = 9x² + 3x - 30 ( subtract 9x² + 3x - 30 from both sides )

4x² - 83x + 60 = 0 factor by splitting the x- term

4x² - 80x - 3x + 60 = 0

4x(x - 20) - 3(x - 20) = 0

(4x - 3)(x - 20) = 0

Equate each factor to zero and solve for x

4x - 3 = 0 ⇒ 4x = 3 ⇒ x = [tex]\frac{3}{4}[/tex]

x - 20 = 0 ⇒ x = 20

Answer:

See Explanation

Step-by-step explanation:

Given

[tex]0 \to[/tex] Correct

[tex]1 \to[/tex] Defective

Required

The probability that the next is defective

The question is incomplete because the list of bottles that came out is not given.

However, the formula to use is:

[tex]Pr = Num ber\ o f\ d e f e c t i v e \div T o t a l\ b o t t l e s[/tex]

Take for instance, the following outcomes:

[tex]0\ 1\ 0\ 0\ 0\ 1\ 0\ 0\ 1\ 1\ 0\ 0\ 0\ 1[/tex]

We have:

[tex]Total = 14[/tex]

[tex]D e f e ctive = 9[/tex] --- i.e. the number of 0's

So, the probability is:

[tex]Pr = 9 \div 14[/tex]

[tex]Pr = 0.643[/tex]

Answer:

1/20

Step-by-step explanation:

000000000000100000

It is asking the probability of a defective bottle

there is one defective bottle out of 20

Answer:

9 possible values of length and breadth.

Step-by-step explanation:

Given that the area of the rectangle is 18cm² . And the lengths of the sides are whole numbers. We need to tell the possible dimensions of the rectangle .

Let :-

[tex]\rm\implies Length = x [/tex]

[tex]\rm\implies Breadth = y [/tex]

We know that :-

[tex]\rm\implies Area = length \times breadth [/tex]

[tex]\rm\implies Area = x y \\\\\rm\implies xy = 18cm^2 [/tex]

Now look out for the possible factors of 18 . That is , ( 1 × 18 ) , ( 2 × 9) , ( 3 × 6 ) , ( 6 × 3 ) , ( 9 × 2 ) , (18 × 1 ) . That is total 9 possible values .

[tex]\large\bold{\underline{\underline{ 4( {x - 7})^{2} }}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

[tex]4x {}^{2} - 56x + 196[/tex]

Take [tex]4[/tex] as the common factor.

[tex] = 4( {x}^{2} - 14x + 49)[/tex]

[tex] = 4( {x}^{2} - 7x - 7x + 49)[/tex]

Taking [tex]x[/tex] as common from first two terms and [tex]7[/tex] from last two terms, we have

[tex] = 4 \: [ x(x - 7) - 7(x - 7) ][/tex]

Taking the factor [tex](x-7)[/tex] as common,

[tex] = 4(x - 7)(x - 7)[/tex]

[tex] = 4( {x - 7})^{2} [/tex]

[tex]\bold{ \green{ \star{ \red{Mystique35}}}}⋆[/tex]

Answer:

True

Step-by-step explanation:

Yes! The diagonal of a rectangle is longer than any of its sides.

Consider PQRS as a rectangle. It is known to us that each interior angle of a rectangle measures 90°. Now, after making the diagonal of the rectangle PQRS, the rectangle has been split into 2 right-angled triangles i.e, ∆PRS and ∆RPQ. In the right angled triangle, hypotenuse is always the longest side. Here, in ∆PRS and ∆RPQ, the bases are RS and QP ; perpendiculars are PS and QR and both triangles' hypotenuse is PR. As, hypotenuse is always the longest side, so PR will be longer than RS,QP,PS and QR. Clearly, the diagonal of a rectangle is longer than any of its sides.

Answer:

In this exercise we need to solve the equation

3(x-2) = 2x + 6 - 2

We operate the parentheses and the right side

3(x-2) = 2x + 4

3x - 6 = 2x + 4

We add 6 to both sides

3x -6 + 6 = 2x + 4 + 6

3x = 2x + 10

We substract 2x

3x - 2x = 2x + 10 - 2x

x = 10

x = 10

Step-by-step explanation:

Answer:

I believe its the 1st answer.

Answer:

[tex]mDE=90[/tex]°

Step-by-step explanation:

In this problem, one is asked to find the measure of the arc in degrees. This problem provides one with a diagram since the center is unnamed, call the center point (O). One is given the information that angle (<DOE) has a measure of (90) degrees. One is asked to find the degree measure of the surrounding arc (DE).

The central angles theorem states that if an angle has its vertex on the center of a circle, the degree measure of the angle is equal to the degree measure of the surrounding arc. One can apply this here by stating the following:

[tex]m<DOE = mDE\\[/tex]

Substitute,

[tex]90=mDE[/tex]

Answer:

[tex]x = 0.143[/tex]

[tex]P(High\ |\ Cancer) = 0.215[/tex]

Not independent

Step-by-step explanation:

Given

See attachment for proper table

Solving (a): The missing probability

First, we add up the given probabilities

[tex]Sum = 0.242+0.047+0.079+0.391+0.098[/tex]

[tex]Sum = 0.857[/tex]

The total probability must add up to 1.

If the missing probability is x, then:

[tex]x + 0.857 = 1[/tex]

Collect like terms

[tex]x = -0.857 + 1[/tex]

[tex]x = 0.143[/tex]

Solving (b): P(High | Cancer)

This is calculated as:

[tex]P(High\ |\ Cancer) = \frac{n(High\ n\ Cancer)}{n(Cancer)}[/tex]

So, we have:

[tex]P(High\ |\ Cancer) = \frac{0.079}{0.242+0.047+0.079}[/tex]

[tex]P(High\ |\ Cancer) = \frac{0.079}{0.368}[/tex]

[tex]P(High\ |\ Cancer) = 0.215[/tex]

Solving (c): P(Leukemia) independent of P(High Wiring)

From the attached table

[tex]P(Leukemia\ n\ High\ Wiring) = 0.242[/tex]

[tex]P(Leukemia) = 0.242 + 0.391 =0.633[/tex]

[tex]P(High\ Wiring) = 0.242+0.047+0.079=0.368[/tex]

If both events are independent, then:

[tex]P(Leukemia\ n\ High\ Wiring) = P(Leukemia) * P(High\ Wiring)[/tex]

[tex]0.242 = 0.633 * 0.368[/tex]

[tex]0.242 \ne 0.232[/tex]

Since the above is an inequality, then the events are not independent

Answer:

90

Step-by-step explanation:

Answer:

x = -0.70,-2.212.

Step-by-step explanation:

(a) The quadratic equation is :

[tex]6x^2 + 17x + 9 = 0[/tex]

Here,

a = 6, b = 17, c = 9

Put all the values in the quadratic formula.

[tex]x=\dfrac{-17+\sqrt{17^2-4\times 6\times 9}}{2(6)},\dfrac{-17-\sqrt{17^2-4\times 6\times 9}}{2(6)}\\\\x=-0.70,-2.12[/tex]

So, the solution of the given equation are -0.70,-2.212.

(b) Equation is : [tex]4x^2 -4x + 1 = 0[/tex].

Here, a = 4, b = -4 and c = 1

So,

[tex]x=\dfrac{-(-4)+\sqrt{(-4)^2-4\times 4\times 1}}{2(4)},\dfrac{-(-4)-\sqrt{(-4)^2-4\times 4\times 1}}{2(4)}\\\\x=0.5,0.5[/tex]

Hence, this is the required solution.

Answer:

[tex]\frac{\sqrt{10} }{2}[/tex]

Step-by-step explanation:

on a 45 - 45 - 90 triangle if the sides are x then the hypotenuse is x[tex]\sqrt{2}[/tex]

so,

[tex]\sqrt{5}[/tex] = x[tex]\sqrt{2}[/tex]                  (Divide by [tex]\sqrt{2}[/tex] )

[tex]\frac{\sqrt{5} }{\sqrt{2} }[/tex] = x                        (rationalize the denominator)

[tex]\frac{\sqrt{5} }{\sqrt{2} }[/tex] · [tex]\frac{\sqrt{2} }{\sqrt{2} }[/tex] = [tex]\frac{\sqrt{10} }{\sqrt{4} }[/tex] = [tex]\frac{\sqrt{10} }{2}[/tex]

The length of side is √10/2

Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.

The given triangle is a 45-90-45 so if the sides are x then the hypotenuse will be x√2

From the figure the hypotenuse of triangle is √5

SO equation it to x√2

We get √5=x√2

Divide both sides by √2

√5/√2=x

As the denominator should be a whole number we have to rationalize the denominator.

Multiply numerator and denominator with √2

√5/√2×√√2/√2

√10/2

Hence, the length of side is √10/2

To learn more on trigonometry click:

https://brainly.com/question/25122835

#SPJ2

Answer:

Answer: The arc PS would be a minor arc · Step-by-step explanation: As a minor arc is one that is less that 180 degrees, it would be the only viable ...

Answer:

£0.80

Step-by-step explanation:

1 box of eggs: £2.40

2 packs of bacon: 2 * £2.60

2 tins of baked beans: 2x

Change: 80p

Total = 2x + £2.40 + £5.20 + £0.80

Total = 2x + £8.40

2x + £8.40 = £10

2x = £1.60

x = £0.80

Answer: £0.80

Answer:

17

Step-by-step explanation:

Answer:

Step-by-step explanation:   7  1  16   37

8/1     8 divided by 1

16/2   16 divided by 2

24/3   24 divided by 3       I could go on, but won't

Answer:

240

Step-by-step explanation:

well do *

so 8x6x5 = 240 there's your answer

Answer:

[tex]S.A=1/2(8+8)(9^{2})+8\times 6+8\times 5[/tex]

[tex]=26\times2+48+40[/tex]

[tex]=140 ~cm^{2}[/tex]

-------------------------

HOPE IT HELPS

HAVE A GREAT DAY!!

Answer:

True

Step-by-step explanation:

The equation of direct variation is

y = kx ← k is the constant of variation

To find k divide both sides by x

[tex]\frac{y}{x}[/tex] = k

That is the constant is the ratio of y- values to x- values

Step-by-step explanation:

4² = 16

5² = 25

16+25 = 41

41 is the answer.

Hope it helps! :)

Answer:

[tex]( {4}^{2} + {5}^{2} ) \\ (16 + 25) \\ = 41[/tex]

Given:

There are 35 times as many students at Wow University as teachers.

When all the students and teachers are seated in the 8544 seat auditorium, 12 seats are empty.

To find:

The total number of students.

Solution:

Let x be the number of teachers at Wow University. So, the number of student is :

[tex]35\times x=35x[/tex]

When all the students and teachers are seated in the 8544 seat auditorium, 12 seats are empty.

[tex]x+35x=8544-12[/tex]

[tex]36x=8532[/tex]

[tex]x=\dfrac{8532}{36}[/tex]

[tex]x=237[/tex]

The number of total students is:

[tex]35x=35(237)[/tex]

[tex]35x=8295[/tex]

Therefore, the total number of students is 8295.

Answer:

a. 18 percent

b. $90 billion

Step-by-step explanation:

a. Calculation to use Okun's law to determine the size of the GDP gap in percentage-point terms.

First step is to find the difference between ACTUAL RATE of unemployment and NATURAL RATE of unemployment

Difference=13%-4%

Difference= 9%

Based on the information above calculation we can see that the ACTUAL RATE of unemployment EXCEEDS the NATURAL RATE of unemployment by 9%, which indicates a CYCLICAL UNEMPLOYMENT.

Thus, According to Okun's law, this translates into an 18 % GDP gap in percentage-point terms (= 2 × 9%).

Therefore the the size of the GDP gap in percentage-point terms is 18 percent

b. Calculation to determine how much output is forgone because of cyclical unemployment

Forgone Output :

By applying Okun’s law we known that the GDP gap is 18%, which means that we are 18% below the GDP amount which is given as $500 billion,

Hence,

Output forgone = (18/100) ×$500 billion

Output forgone=0.18×$500 billion

Output forgone=$90 billion

Therefore the Forgone Output is $90 billion

Answer:

y = 3/2x -3

Step-by-step explanation:

The general equation of a straight line is;

y = mx + b

where m is slope and b is the y-intercept

Here, we can see that the graph intercepts the y-axis at the point y = -3

So b = -3

To get m, we can substitute any other point values on the plot

We can select (2,0)

So we have;

y = mx -3

0 = 2m -3

2m = 3

m = 3/2

so;

y = 3/2x -3