Find the length of side xx in simplest radical form with a rational denominator.

g = -3,5

8 - |2g - 5| = 8 - |2 · (-3,5) - 5| =

= 8 - |-7 - 5| = 8 - |-12| = 8 - 12 = -4

Answer: 30 cm2

Step-by-step explanation:

branliest please

Answer:

30 cm^2

Step-by-step explanation:

The surface area of a rectangular prism is given by the formula:

2 (lw + hw + hl)

Substitute the fomrula with the given dimensions:

2 ([3 x 1] + [3 x 1] + [3 x 3])

= 2 (3 + 3 + 9)

= 2 (15)

= 30

Hope this helps!

Answer:

The combined mean can be calculated by plugging in our numbers into the formula given: [(57*82)+(23*63)/(57+23)]=76.5

Answer:

[tex]2^{\frac{1}{6} }[/tex]

Step-by-step explanation:

(2^1/3)^1/2 = 2^(1/3 x 1/2) =2^1/6

Answer:

this would be towards the front and the very end

ω in terms of m and k is expressed as  [tex]\omega = \sqrt{\frac{k}{m} }[/tex]

The given expression is as follows;

     [tex]T_s = 2\pi \sqrt{\frac{m}{k} } , \ \ \\\\ T_s = \frac{2\pi}{\omega}[/tex]

To find:

From the given expression above make ω the subject of the formula;

[tex]T_s = \frac{2\pi}{\omega} = 2\pi \sqrt{\frac{m}{k} } \\\\ \frac{2\pi}{\omega} = 2\pi \sqrt{\frac{m}{k} }\\\\ \frac{2\pi}{\omega} = \sqrt{4\pi^2\frac{m}{k} }\\\\square \ both \ sides \ of \ the \ equation;\\\\(\frac{2\pi}{\omega})^2 = 4\pi^2\frac{m}{k} \\\\\frac{4\pi^2}{\omega^2}= \frac{4\pi^2m}{k} \\\\\omega^2 4\pi^2m = k4\pi^2 \\\\divide \ both \ side \ by \ 4\pi ^2 \\\\\omega^2 m = k\\\\divide \ both \ sides \ by \ m\\\\\omega^2 = \frac{k}{m} \\\\[/tex]

[tex]take \ the \ square \ root \ of \ both \ sides \ of \ the \ equation\\\\\omega = \sqrt{\frac{k}{m} }[/tex]

Therefore, ω in terms of m and k is expressed as [tex]\omega = \sqrt{\frac{k}{m} }[/tex]

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Answer:

9/8 = n

Step-by-step explanation:

9 = 8n

Divide each side by 8

9/8 = 8n/8

9/8 = n

Answer:

0.583

Step-by-step explanation:

Use a caluclator

Answer:

1. irrational (it's pi. pi goes on forever.)

2. irrational (the ... shows that the number goes on forever.)

3. rational (it is a regular integer)

4. rational (it would be negative 3, an integer.)

5. real, irrational (square root 6 goes on forever, like every non-perfect square root)

6. real, rational, integer, natural, whole (regular counting number)

7. real, rational, integer, natural, whole (regular counting number, 4)

8. real, rational (the .11111... shows the number is a repeating, non terminating number, therefore it is rational and real.)

brainliest is very much appreciated!

Answer:

WO [tex]\sqrt{13}\ \ \ \frac{3}{2}[/tex]

OR [tex]\sqrt{13}\ \ \ - \frac{3}{2}[/tex]

RM [tex]\sqrt{13}\ \ \ \frac{3}{2}[/tex]

MW [tex]\sqrt{13}\ \ \ - \frac{3}{2}[/tex]

Step-by-step explanation:

One has to find the slope, and the distance between the successive points on the plane. Use the slope and distance formula to achieve this.

Slope formula:

[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Distance formula:

[tex]\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]

Remember, the general format for the coordinates of a point on a Cartesian coordinate plane is the following:

[tex](x,y)[/tex]

1. WO

Coordinates of point (W): (3, -5)

Coordinates of point (O): (6, -3)

Find the slope:

[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]\frac{(-5)-(-3)}{(3)-(6)}=\frac{-5+3}{3-6}=\frac{-2}{-3}=\frac{2}{3}[/tex]

Find the distance:

[tex]\sqrt{((-5)-(-3))^2+((3)-(6))^2}[/tex]

[tex]\sqrt{(-2)^2+(-3)^2}\\=\sqrt{4+9}\\=\sqrt{13}\\[/tex]

2. OR

Coordinates of point (O): (6, -3)

Coordinates of point (R): (4, 0)

Find the slope:

[tex]\frac{y_2-y_1}{x_2-x_1}\\=\frac{(0)-(-3)}{(4)-(6)}=\frac{3}{-2}=-\frac{3}{2}[/tex]

Find the distance:

[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]\sqrt{((0)-(-3))^2+((4)-(6))^2}=\sqrt{(3)^2+(2)^2}=\sqrt{9+4}=\sqrt{13}[/tex]

3. RM

Coordinates of point (R): (4, 0)

Coordinates of point (M): (1, -2)

Find the slope:

[tex]\frac{y_2-y_1}{x_2-x_1}\\=\frac{(0)-(-2)}{(4)-(1)}=\frac{2}{3}[/tex]

Find the distance:

[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]\sqrt{((-2)-(0))^2+((1)-(4))^2}=\sqrt{(-2)^2+(-3)^2}=\sqrt{4+9}=\sqrt{13}[/tex]

4. MW

Coordinates of point (M): (1, -2)

Coordinates of point (W): (3, -5)

Find the slope:

[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]=\frac{(-5)-(-2)}{(3)-(1)}=\frac{-3}{2}=-\frac{3}{2}[/tex]

Find the distance:

[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]=\sqrt{((3)-(1))^2+((-5)-(-2))^2}=\sqrt{(2)^2+(3)^2}=\sqrt{4+9}=\sqrt{13}[/tex]

Answer:

this is a 60 60 60 triangle, so one exterior angle is 120 degrees.

Step-by-step explanation:

hope it helps!

Answer:

13/50

Step-by-step explanation:

Answer:

26/100

Method:

Fractions are much like percents, as they are both out of 100. The 26% is 26%/100% (26/100)

Answer:

x=60°

Does the answer help you?

Answer:

x=60°

Step-by-step explanation:

Hi there!

We are given that <ABD and <DBC are complementary angles.

If two angles are complementary, it means that they add up to 90 degrees.

In that case, <ABD + <DBC=90°.

We're also given that m<ABD=30° and m<DBC=x.

Substituting those values into the equation will give us:

30°+x=90°.

Subtract 30° from both sides.

x=60°.

Hope this helps!

Answer:

Easy explanation:

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]

Answer:

Property : a^-b = 1/a^b

Using this property, we can rewrite the expression using positive exponents :

[tex]1. \frac{1}{9}*x^{-2} *y^{-1} =\frac{1}{9}\frac{1}{x^{2} } \frac{1}{y} =\frac{1}{9x^{2} y} \\2. a^{-5} a^{-8} =\frac{1}{a^{5}a^{8} } =\frac{1}{a^{13} }[/tex]

Answer:

Letter A is your answer

Step-by-step explanation:

mark me brainliest

Answer:

Step-by-step explanation:

[tex] \sqrt[3]{64} [/tex]

[tex] = \sqrt[3]{4 \times 4 \times 4} [/tex]

= 4 (Ans)

Answer:

Step-by-step explanation:

Step-by-step explanation:

The answer is mentioned above.

Hope it helps.

Answer:

[tex](2x-3)^{3}[/tex]

Step-by-step explanation:

2x * 2x * 2x would get the 8x^3

the -3 * -3 * -3  would get the -27

if you do all the other multiplications -36x^2 and 54 X would result

Answer:

Substitute in the y-value to the equation:

[tex]3x-y=18\\\\3x-27=18\\\\3x=18+27\\\\3x=45\\\\x=15[/tex]

Therefore, the value of x is 15.

Answer:

x=15

Step-by-step explanation:

3x - y = 18

Let y= 27

3x - 27 = 18

Add 27 to each side

3x-27+27 = 18+27

3x= 45

Divide each side by 3

3x/3 = 45/3

x = 15

Answer:

Ans ; 1) 7.8 , 2) 3.3×10³ , 3) 2.1 ×10‐³ , 4) 3.7

I hope I helped you^_^

Notice that

(x - 1)²/4 + (y + 2)²/9 = (2 sin(θ))²/4 + (3 cos(θ))²/9

… = sin²(θ) + cos²(θ)

… = 1

Solve for y in terms of x :

(x - 1)²/4 + (y + 2)²/9 = 1

(y + 2)²/9 = 1 - (x - 1)²/4

(y + 2)² = 9 - 9/4 (x - 1)²

y + 2 = ± √(9 - 9/4 (x - 1)²)

y + 2 = ± 3/2 √(4 - (x - 1)²)

y = -2 ± 3/2 √(4 - (x - 1)²)

In order for the square root to be defined, one needs

4 - (x - 1)² ≥ 0

(x - 1)² ≤ 4

-2 ≤ x - 1 ≤ 2

-1 ≤ x ≤ 3

so x must belong to the interval [-1, 3].

Answer:

[tex]{ \tt{ {3x}^{2}(5 {x}^{3} ) = 15 {x}^{5} }}[/tex]

Step-by-step explanation:

[tex]{ \sf{3 {x}^{2}(5 {x}^{3} )}} \\ = { \sf{ {x}^{5} (3 \times 5)}} \\ = { \sf{15 {x}^{5} }}[/tex]

Answer:

28.4 degrees

Step-by-step explanation:

sin(theta) = 20/42. theta=arcsin(10/21)=28.43

Answer:

x = 6[tex]\sqrt{3}[/tex]

Step-by-step explanation:

Using the Altitude- on- Hypotenuse theorem

( leg of large triangle)² = (part of hypotenuse below it) × (whole hypotenuse) , so

x² = 9 × (9 + 3) = 9 × 12 = 108 ( take square root of both sides )

x = [tex]\sqrt{108}[/tex] = [tex]\sqrt{36(3)}[/tex] = [tex]\sqrt{36}[/tex] × [tex]\sqrt{3}[/tex] = 6[tex]\sqrt{3}[/tex]

Answer:

C

Step-by-step explanation:

Given

10(3x + 2) > 7(2x - 4) ← distribute parenthesis on both sides

30x + 20 > 14x - 28 ( subtract 14x from both sides )

16x + 20 > - 28 ( subtract 20 from both sides )

16x > - 48 ( divide both sides by 16 )

x > - 3 → C

Step-by-step explanation:

+ Both equations

You will get : 5x=13 ; x=13/5

and put x to the first equation

2*13/5-y=4

y=6/5

(13/5;6/5)

Answer is C

Answer:

(x+2,y-4)

Step-by-step explanation:

The correct answer is (x+2, y-4)

The translation of ABCD to A'B'C'D' is given by (x + 2,y - 4).

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, translation, reflection and dilation.

Translation is the movement of a point either up, left, right or down.

ABCD has vertices at A(-6, 2), B(-5, 4), C(-2, 4) and D(1, 2). If ABCD is translated 4 units down and 2 units right, the new point is A'(-4, -2), B'(-3, 0), C'(0, 0) and D'(3, -2)

The translation of ABCD to A'B'C'D' is given by (x + 2,y - 4).

Find out more on transformation at: https://brainly.com/question/1548871