Answer:
D: {-20, -13, 1, 6}
R: {-20, -8, 11, 13}
Step-by-step explanation:
Given the relation, {(–20, 11), (6, –8), (1, –20), (–13, 13)}, all x-values (inputs) make up the domain of the relation while all y-values make up the range of the relation.
Therefore:
Domain: {-20, -13, 1, 6}
Range: {-20, -8, 11, 13}
Need help
Identify the domain of the function shown in the graph
Answer:
B
Step-by-step explanation:
A simple random sample of students could be achieved by stopping every other student who enters the library.
a. True
b. False
Please Help
Solve 3(x+2)-4x=8
Hello!
3(x + 2) - 4x = 8 <=>
<=> 3x + 6 - 4x = 8 <=>
<=> -x + 6 = 8 <=>
<=> -x = 8 - 6 <=>
<=> -x = 2 <=>
<=> x = -2
Good luck! :)
please help to solve this in written format
Answer:
50 dozen total
Step-by-step explanation:
8/12 & 10/12.... average 9/12
11/12 - 9/12 =
2/12x = 100
2x = 1200
x = 600/12
50 dozen total
A section of a deck is shaped like a trapezoid. For this section, the length of one base is 23 feet, and the length of the other base is 50 feet. The height is 20 feet. What is the area of this section of the deck?
The area for the section of the deck is ____ ft
Answer:
Area of a trapezoid= (big base+small base)/2 x height
A=(67+54)/2 x 18
A=60.5 x 18
A=1089
ASK YOUR TEACHER A 12-sided die can be made from a geometric solid called dodecahedron. Assume that a fair dodecahedron is rolled. (a) What is the probability of getting a number less than 10 on a single roll
9514 1404 393
Answer:
3/4
Step-by-step explanation:
Assuming the faces are numbered 1 to 12, there are 9 faces with values less than 10. Since the outcomes are equally probable and mutually exclusive, the probability of any of the 9 is the sum of their individual probabilities:
P(n < 10) = 9×1/12 = 9/12 = 3/4
You have to find the value of k
Answer:
115
Step-by-step explanation:
use the discriminant to determine the number of solutions to the quadratic equation −6z2−10z−3=0. What are the real solutions and complex solutions?
Answer:
Step-by-step explanation:
-6z²-10z-3=0
multiply by -1
6z²+10z+3=0
disc .=b²-4ac=10²-4×6×3=100-72=28≥0
also it is not a perfect square.
so roots are real,irrational and different.
[tex]z=\frac{-6 \pm\sqrt{28} }{2 \times 6} \\=\frac{-6 \pm 2 \sqrt{7}}{12} \\=\frac{-3 \pm\sqrt{7} }{6}[/tex]
Problem is in the picture below
Answer:
90 maybe is a correct answer
Answer:
Y=40°
Step-by-step explanation:
VUW~YXZ
VWU~YZX
YXZ+XYZ+YZX=180°
70°+XYX+70°=180°
140°+XYZ=180°
XYZ=180°-140°
XYZ=40°
The Power in a circuit is given by the formula P=I^{2}R, where I is the Current and R is the Resistance. If the Resistance is always constant at 500, the Current is 1, and dI/dt = -0.5, then dP/dt = -500.
True or false and please show work. Thank you
True
Step-by-step explanation:
[tex]P(t) = I^2(t)R[/tex]
Taking the derivative of P(t) with respect to time,
[tex]\dfrac{dP(t)}{dt} = 2I(t)\dfrac{dI(t)}{dt}R[/tex]
[tex]\:\:\:\:\:\:\:\:= 2(1)(-0.5)(500) = -500[/tex]
Joe bought 200 masks and each mask costs Rs.5. How much did he pay altogether?
pls write the steps how to do if you I will give 5 star
Given:
total number of masks= 200cost of 1 mask= Rs. 5so, total cost fir 200 masks=
200×5
= 1000
therefore, Joe paid Rs. 1000 altogether.
Which set of statements shows the correct steps to find 45 percent of 75?
A.
Write 45 percent as 9 ´ 5 percent, and write 5 percent as StartFraction 1 Over 20 EndFraction. Then, find StartFraction 1 Over 20 EndFraction of 75: 75 times StartFraction 1 Over 20 EndFraction = StartFraction 75 Over 20 EndFraction = 3.75. Multiply 3.75 by 9 to get 33.75. So, 45 percent of 75 is 33.75.
B.
Write 45 percent as 9 ´ 5 percent, and write 5 percent as One-half. Then, find One-half of 75: 75 times one-half = StartFraction 75 Over 2 EndFraction = 33.75. Multiply 33.75 by 9 to get 303.75. So, 45 percent of 75 is 303.75.
C.
Write 45 percent as StartFraction 1 Over 45 EndFraction. Then, find StartFraction 1 Over 45 EndFraction of 75: 75 times StartFraction 1 Over 45 EndFraction = StartFraction 75 Over 45 EndFraction = 1.67. So, 45 percent of 75 is 1.67.
D.
Write 45 percent as StartFraction 1 Over 4.5 EndFraction. Then, find StartFraction 1 Over 4.5 EndFraction of 75: 75 times StartFraction 1 Over 4.5 EndFraction = StartFraction 75 Over 4.5 EndFraction = 16.7. So, 45 percent of 75 is 16.7.
Pls the answer is
D
Thank you
You are welcome
Answer:
d
Step-by-step explanation:
im smart
Assume that the breaking system of a train consists of two components connected in series with both of them following Weibull distributions. For the first component the shape parameter is 2.1 and the characteristic life is 100,000 breaking events. For the second component the shape parameter is 1.8 and characteristic life of 80,000. Find the reliability of the system after 2,000 breaking events:
Answer:
0.9984
Step-by-step explanation:
we have shape parameter for the first component as 2.1
characteristics life = 100000
for this component
we have
exp(-2000/100000)².¹
= e^-0.0002705
= 0.9997
for the second component
shape parameter = 1.8
characteristic life = 80000
= exp(-2000/80000)¹.⁸
= e^-0.001307
= 0.9987
the reliability oif the system after 2000 events
= 0.9987 * 0.9997
= 0.9984
Mr johnson sells erasers for $3 each. He sold 96 erasers last week and he sold 204 erasers this week.
A. $300 B $600 C $100 D $900
I believe your answer is D.) $900
204 + 96 = 300
300 x 3 = 900
I hope this is correct and helps!
Jan is as old as Gary was 15 years ago. Six years from now, Gary will be twice as old as Jan will be then. How old is Gary now?
Answer:
Gary is now 24years
Step-by-step explanation:
let the age of Jan be x and that of Gary be x+15
in six years time they will be as follows
Jan =x+6
Gary=x+15+6=x+21
2(x+6)=x+21
2x+12=x+21
collect the like terms
2x-x=21-12
x=9
Gary =9+15=24years
1. Which of the following is equivalent to 7a4 + 3a"?
O (7+3)a4+4
O (7-3)a+
O (743)a+
O (7.3)a4+4
Both the question and options given doesn't seem to be properly formatted. A well formatted form of the question is written in the comment section below.
Answer:
10a^4
Step-by-step explanation:
Given the expression :
7a^4+3a^4
The sum of the expression given above could be taken directly Since the power of each individual value is the same.
7a^4+3a^4
Adding the coefficients
(7+3)a^4
10a^4
For what values of the variable, do the following fractions exist: y^2-1/y+y/y-3
For what values of the variable, do the following fractions exist: b+4/b^2+7
For what values of the variable, do the following fractions exist: a/a(a-1)-1
PLEASE HELP NEED ANSWER ASAPPPP!!!! WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWERRRR!!!
Answer:
Remember that the division by zero is not defined, this is the criteria that we will use in this case.
1) [tex]\frac{y^2 - 1}{y} + \frac{y}{y - 3}[/tex]
So the fractions are defined such that the denominator is never zero.
For the first fraction, the denominator is zero when y = 0
and for the second fraction, the denominator is zero when y = 3
Then the fractions exist for all real values except for y = 0 or y = 3
we can write this as:
R / {0} U { 3}
(the set of all real numbers except the elements 0 and 3)
2) [tex]\frac{b + 4}{b^2 + 7}[/tex]
Let's see the values of b such that the denominator is zero:
b^2 + 7 = 0
b^2 = -7
b = √-7
This is a complex value, assuming that b can only be a real number, there is no value of b such that the denominator is zero, then the fraction is defined for every real number.
The allowed values are R, the set of all real numbers.
3) [tex]\frac{a}{a*(a - 1) - 1}[/tex]
Again, we need to find the value of a such that the denominator is zero.
a*(a - 1) - 1 = a^2 - a - 1
So we need to solve:
a^2 - a - 1 = 0
We can use the Bhaskara's formula, the two values of a are given by:
[tex]a = \frac{-(-1) \pm \sqrt{(-1)^2 + 4*1*(-1)} }{2*1} = \frac{1 \pm \sqrt{5} }{2}[/tex]
Then the two values of a that are not allowed are:
a = (1 + √5)/2
a = (1 - √5)/2
Then the allowed values of a are:
R / {(1 + √5)/2} U {(1 - √5)/2}
Simplify this math problem show Your work
9514 1404 393
Answer:
(p -9q)/(4p² +12pq)
Step-by-step explanation:
The least common denominator will be the product of the denominators.
[tex]\dfrac{-3}{4p}+\dfrac{1}{p+3q}=\dfrac{-3(p+3q)+1(4p)}{(4p)(p+3q)}=\boxed{\dfrac{p-9q}{4p^2+12pq}}[/tex]
At an intersection, the red light times are normally distributed with a mean time of 3 minutes and a standard deviation of 0.25 minutes. Approximately what percent of red lights last between 2.5 and 3.5 minutes? (2 points)
Answer:
95.4%
Step-by-step explanation:
Z(low)=-2 0.022750132
Z(upper)=2 0.977249868
Ralph bought a computer monitor with an area of 384 square inches. The length of the monitor is six times the quantity of five less than half its width.
Answer:
eh width = 103.5 inches
Step-by-step explanation:
x = width
Length = (x/2 - 5 )*6
so 384=x+3x-30
414=4x
x=414/4=103.5 inches
Questions 24-25. In 1963, postage was 5 cents per ounce. In 1981, postage was 18 cents per ounce.
If the trend had continued through to 2015, what would the postage per ounce be?
(round to the nearest central
The answer posted "42.55" is incorrect.
Answer:
The postage per ounce would be of $2.02.
Step-by-step explanation:
Exponential model:
The postage, in t years after 1963, follows the following format:
[tex]P(t) = P(0)(1+r)^t[/tex]
In which P(0) is the initial value and r is the growth rate, as a decimal.
In 1963, postage was 5 cents per ounce.
This means that [tex]P(0) = 5[/tex]
So
[tex]P(t) = P(0)(1+r)^t[/tex]
[tex]P(t) = 5(1+r)^t[/tex]
In 1981, postage was 18 cents per ounce.
This means that [tex]P(1981 - 1963) = P(18) = 18[/tex]. We use this to find r. So
[tex]P(t) = 5(1+r)^t[/tex]
[tex]18 = 5(1+r)^{18}[/tex]
[tex](1+r)^{18} = \frac{18}{5}[/tex]
[tex]\sqrt[18]{(1+r)^{18}} = \sqrt[18]{3.6}[/tex]
[tex]1 + r = (3.6)^{\frac{1}{18}}[/tex]
[tex]1 + r = 1.0738[/tex]
So
[tex]P(t) = 5(1.0738)^t[/tex]
If the trend had continued through to 2015, what would the postage per ounce be?
2015 - 1963 = 52, so this is P(52).
[tex]P(52) = 5(1.0738)^{52} = 202[/tex]
202 cents, so $2.02.
Help me please I need help 6
Answer:
69.6
Step-by-step explanation:
sin 55 = x / 85
0.8191520443 = x / 85
x = 69.6
O EXPONENTAL AND LOGARITHMIC FUNCTIONS
Finding the initial or final amount in a word problem on...
An initial amount of money is placed in an account at an interest rate of 2% per year, compounded continuously. After two years, there is $1269.79 in the
account. Find the initial amount placed in the account. Round your answer to the nearest cent.
Answer:
$ 1220.00
Step-by-step explanation:
1269.79 = A [tex]e^{.02 * 2}[/tex]
1269.79 /A = [tex]e^{.04}[/tex]
ln(1269.79 /A) = .04 ln(e)
ln(1269.79 /A) = .04
1269.79 /A = [tex]e^{.04}[/tex]
1269.79 /A = 1.0408
A = 1269.79 / 1.0408
$ 1220.00
Suppose that you are interested in determining the average height of a person in a large city. You begin by collecting the heights of a random sample of 196 people from the city. The average height of your sample is 68 inches, while the standard deviation of the heights in your sample is 7 inches. The standard error of your estimate of the average height in the city is
Answer:
The standard error of your estimate of the average height in the city is 0.5 inches.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
You begin by collecting the heights of a random sample of 196 people from the city.
This means that [tex]n = 196[/tex]
The standard deviation of the heights in your sample is 7 inches.
This means that [tex]\sigma = 7[/tex]
The standard error of your estimate of the average height in the city is
[tex]s = \frac{\sigma}{\sqrt{n}} = \frac{7}{\sqrt{196}} = 0.5[/tex]
The standard error of your estimate of the average height in the city is 0.5 inches.
Identify the transformation that occurs to create the graph of h(x).
H(x)=f(x+3)
Answer: The graph moved left 3 units.
(x, y) = (x - 3, y)
Choose the correct answers for (a) the total installment price, (b) the carrying charges, and (c) the number of months needed to save money at the monthly rate to buy the item for its cash price.
A bunk bed with a cash price of $1,998, at $143 per month for 15 months
Answer:
$2,145 ; $147 ; 14 months
Step-by-step explanation:
Given that :
The cash price, that is, the amount that would be paid if customer is to pay the entire amount item is worth at once = $1998
Monthly payment = $143
Period = 15 months
The total installment price ; total amount paid on a monthly pay for 15 months :
(monthly payment * period)
($143 * 15)
= $2,145
The carrying charge :
Installment pay - Cash amount
$(2,145 - 1,998)
= $147
The number of month needed to save at Monthly rate to buy item at it's cash price :
Cash price / monthly payment
$1998 / $143
= 13.97
= 14 months
So for this problem I got 0.00023833 however it is not accepting my answer. If I rounded 4 decimal places it would be 0.000. How would I go about this problem? Can someone please help?
Answer:
0.0002
Step-by-step explanation:
4 decimal places means tenths, hundredths, thousandths, and ten thousandths places. If we count 4 decimal places, we come to 0.0002. The number next to it, 3, rounds down, so the answer should be 0.0002.
Two systems of equations are given below. For each system, choose the best description of its solution.
x - 5y = 5
-x + 5y = -5
a. The system has no solution.
b. The system has a unique solution:
(x,y) = _______
c. The system has infinitely many solutions. They must satisfy the following equation:
y = ________
Answer:
Infinitely many solutions.
They must satisfy [tex]y = \frac{1}{5}(x - 5)[/tex]
Step-by-step explanation:
Given
[tex]x - 5y = 5[/tex]
[tex]-x + 5y = -5[/tex]
Required
The best description
Add both equations
[tex]x - x - 5y + 5y = 5 - 5[/tex]
[tex]0+0 =0[/tex]
[tex]0 = 0[/tex] ---- this means that the system has infinitely many solutions.
Make y the subject in: [tex]-x + 5y = -5[/tex]
Add x to both sides
[tex]5y = x - 5[/tex]
Divide through by 5
[tex]y = \frac{1}{5}(x - 5)[/tex]
Hence, they must satisfy: [tex]y = \frac{1}{5}(x - 5)[/tex]
Fifteen dozen eggs were needed for baking four wedding cakes. The first cake
needed one dozen eggs, and each successive cake needed twice as many eggs as the
previous cake. How many eggs were used to make the fourth cake?
Answer:
96 eggs
Step-by-step explanation:
A dozen is equal to 12 eggs, so 15 dozen is equal to 180 eggs
(Because 15*12 = 180)
We already know how many eggs are required for the 1st cake: 12 eggs.
Then it says "each successive cake needs twice as many eggs as the previos cake".
(Successive means the cake directly after the previous cake)
Here's how we find the number of eggs needed for the 2nd cake:
The 1st cake needed 12 eggs, and because the 2nd cake is directly after the 1st cake, we are going to need two times the amount of 12 eggs.
This equation represents the above scenario:
12*2 = 24
So we need 24 eggs for the 2nd cake.
Now we repeat this process for the 3rd cake, finding twice the amount of eggs from the 2nd cake to find the amount of eggs needed for the 3rd cake:
24*2 = 48
And we repeat it once more for the 4th cake, using the eggs from the 3rd cake:
48*2 = 96
So here's the list of how many eggs are required for each of the cakes:
1st cake: 12
2nd cake: 24
3rd cake: 48
4th cake: 96
If you add all the eggs from each of the cakes, you will get 180, which is the number of eggs needed for all four cakes. So our answer is correct.
Hope this helps (●'◡'●)
if you subtract 1/2 from a number and multiply the result by 1/2 you get 1/8. What is the no.
Step-by-step explanation:
1/6
1/6- 1/2 = 1/4
1/4*1/2= 1/8