Find the domain and range of the relation: {(–20, 11), (6, –8), (1, –20), (–13, 13)}

Find The Domain And Range Of The Relation: {(20, 11), (6, 8), (1, 20), (13, 13)}

Answers

Answer 1

Answer:

D: {-20, -13, 1, 6}

R: {-20, -8, 11, 13}

Step-by-step explanation:

Given the relation, {(–20, 11), (6, –8), (1, –20), (–13, 13)}, all x-values (inputs) make up the domain of the relation while all y-values make up the range of the relation.

Therefore:

Domain: {-20, -13, 1, 6}

Range: {-20, -8, 11, 13}


Related Questions

Need help
Identify the domain of the function shown in the graph

Answers

Answer:

B

Step-by-step explanation:

A simple random sample of students could be achieved by stopping every other student who enters the library.
a. True
b. False

Answers

True simple random sample of student could be achieved by stopping every other student who enters the library

Please Help
Solve 3(x+2)-4x=8

Answers

Hello!

3(x + 2) - 4x = 8 <=>

<=> 3x + 6 - 4x = 8 <=>

<=> -x + 6 = 8 <=>

<=> -x = 8 - 6 <=>

<=> -x = 2 <=>

<=> x = -2

Good luck! :)

3(x+2)-4x=8
3x+6-4x=8
-x+6=8
-x=2
x= -2

please help to solve this in written format

Answers

Answer:

50 dozen total

Step-by-step explanation:

8/12 & 10/12.... average 9/12

11/12 - 9/12 =

2/12x = 100

2x = 1200

x = 600/12

50 dozen total

A section of a deck is shaped like a trapezoid. For this section, the length of one base is 23 feet, and the length of the other base is 50 feet. The height is 20 feet. What is the area of this section of the deck?

The area for the section of the deck is ____ ft

Answers

Answer:

Area of a trapezoid= (big base+small base)/2 x height

A=(67+54)/2 x 18

A=60.5 x 18

A=1089  

ASK YOUR TEACHER A 12-sided die can be made from a geometric solid called dodecahedron. Assume that a fair dodecahedron is rolled. (a) What is the probability of getting a number less than 10 on a single roll

Answers

9514 1404 393

Answer:

  3/4

Step-by-step explanation:

Assuming the faces are numbered 1 to 12, there are 9 faces with values less than 10. Since the outcomes are equally probable and mutually exclusive, the probability of any of the 9 is the sum of their individual probabilities:

  P(n < 10) = 9×1/12 = 9/12 = 3/4

You have to find the value of k

Answers

Answer:

115

Step-by-step explanation:

use the discriminant to determine the number of solutions to the quadratic equation −6z2−10z−3=0. What are the real solutions and complex solutions?

Answers

Answer:

Step-by-step explanation:

-6z²-10z-3=0

multiply by -1

6z²+10z+3=0

disc .=b²-4ac=10²-4×6×3=100-72=28≥0

also it is not a perfect square.

so roots are real,irrational and different.

[tex]z=\frac{-6 \pm\sqrt{28} }{2 \times 6} \\=\frac{-6 \pm 2 \sqrt{7}}{12} \\=\frac{-3 \pm\sqrt{7} }{6}[/tex]

Problem is in the picture below

Answers

Answer:

90 maybe is a correct answer

Answer:

Y=40°

Step-by-step explanation:

VUW~YXZ

VWU~YZX

YXZ+XYZ+YZX=180°

70°+XYX+70°=180°

140°+XYZ=180°

XYZ=180°-140°

XYZ=40°

The Power in a circuit is given by the formula P=I^{2}R, where I is the Current and R is the Resistance. If the Resistance is always constant at 500, the Current is 1, and dI/dt = -0.5, then dP/dt = -500.

True or false and please show work. Thank you

Answers

True

Step-by-step explanation:

[tex]P(t) = I^2(t)R[/tex]

Taking the derivative of P(t) with respect to time,

[tex]\dfrac{dP(t)}{dt} = 2I(t)\dfrac{dI(t)}{dt}R[/tex]

[tex]\:\:\:\:\:\:\:\:= 2(1)(-0.5)(500) = -500[/tex]

Joe bought 200 masks and each mask costs Rs.5. How much did he pay altogether?
pls write the steps how to do if you I will give 5 star

Answers

Given:

total number of masks= 200cost of 1 mask= Rs. 5

so, total cost fir 200 masks=

200×5

= 1000

therefore, Joe paid Rs. 1000 altogether.

He bought 200 masks.
And 1 mask costs Rs. 5. So for the equation you do...

1 mask = Rs. 5
200 masks = x(unknown)

➡️ x = Rs. 5 * 200 masks/ 1 mask

➡️ x = 1,000/1

➡️ x = Rs. 1,000

Which set of statements shows the correct steps to find 45 percent of 75?

A.
Write 45 percent as 9 ´ 5 percent, and write 5 percent as StartFraction 1 Over 20 EndFraction. Then, find StartFraction 1 Over 20 EndFraction of 75: 75 times StartFraction 1 Over 20 EndFraction = StartFraction 75 Over 20 EndFraction = 3.75. Multiply 3.75 by 9 to get 33.75. So, 45 percent of 75 is 33.75.
B.
Write 45 percent as 9 ´ 5 percent, and write 5 percent as One-half. Then, find One-half of 75: 75 times one-half = StartFraction 75 Over 2 EndFraction = 33.75. Multiply 33.75 by 9 to get 303.75. So, 45 percent of 75 is 303.75.
C.
Write 45 percent as StartFraction 1 Over 45 EndFraction. Then, find StartFraction 1 Over 45 EndFraction of 75: 75 times StartFraction 1 Over 45 EndFraction = StartFraction 75 Over 45 EndFraction = 1.67. So, 45 percent of 75 is 1.67.
D.
Write 45 percent as StartFraction 1 Over 4.5 EndFraction. Then, find StartFraction 1 Over 4.5 EndFraction of 75: 75 times StartFraction 1 Over 4.5 EndFraction = StartFraction 75 Over 4.5 EndFraction = 16.7. So, 45 percent of 75 is 16.7.

Answers

Pls the answer is

D

Thank you

You are welcome

Answer:

d

Step-by-step explanation:

im smart

Assume that the breaking system of a train consists of two components connected in series with both of them following Weibull distributions. For the first component the shape parameter is 2.1 and the characteristic life is 100,000 breaking events. For the second component the shape parameter is 1.8 and characteristic life of 80,000. Find the reliability of the system after 2,000 breaking events:

Answers

Answer:

0.9984

Step-by-step explanation:

we have shape parameter for the first component as 2.1

characteristics life = 100000

for this component

we have

exp(-2000/100000)².¹

= e^-0.0002705

= 0.9997

for the second component

shape parameter = 1.8

characteristic life = 80000

= exp(-2000/80000)¹.⁸

= e^-0.001307

= 0.9987

the reliability oif the system after 2000  events

= 0.9987 * 0.9997

= 0.9984

Mr johnson sells erasers for $3 each. He sold 96 erasers last week and he sold 204 erasers this week.

A. $300 B $600 C $100 D $900

Answers

I believe your answer is D.) $900

204 + 96 = 300

300 x 3 = 900

I hope this is correct and helps!

Jan is as old as Gary was 15 years ago. Six years from now, Gary will be twice as old as Jan will be then. How old is Gary now?

Answers

Answer:

Gary is now 24years

Step-by-step explanation:

let the age of Jan be x and that of Gary be x+15

in six years time they will be as follows

Jan =x+6

Gary=x+15+6=x+21

2(x+6)=x+21

2x+12=x+21

collect the like terms

2x-x=21-12

x=9

Gary =9+15=24years

1. Which of the following is equivalent to 7a4 + 3a"?
O (7+3)a4+4
O (7-3)a+
O (743)a+
O (7.3)a4+4

Answers

Both the question and options given doesn't seem to be properly formatted. A well formatted form of the question is written in the comment section below.

Answer:

10a^4

Step-by-step explanation:

Given the expression :

7a^4+3a^4

The sum of the expression given above could be taken directly Since the power of each individual value is the same.

7a^4+3a^4

Adding the coefficients

(7+3)a^4

10a^4

For what values of the variable, do the following fractions exist: y^2-1/y+y/y-3

For what values of the variable, do the following fractions exist: b+4/b^2+7

For what values of the variable, do the following fractions exist: a/a(a-1)-1

PLEASE HELP NEED ANSWER ASAPPPP!!!! WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWERRRR!!!

Answers

Answer:

Remember that the division by zero is not defined, this is the criteria that we will use in this case.

1) [tex]\frac{y^2 - 1}{y} + \frac{y}{y - 3}[/tex]

So the fractions are defined such that the denominator is never zero.

For the first fraction, the denominator is zero when y = 0

and for the second fraction, the denominator is zero when y = 3

Then the fractions exist for all real values except for y = 0 or y = 3

we can write this as:

R / {0} U { 3}

(the set of all real numbers except the elements 0 and 3)

2) [tex]\frac{b + 4}{b^2 + 7}[/tex]

Let's see the values of b such that the denominator is zero:

b^2 + 7 = 0

b^2 = -7

b = √-7

This is a complex value, assuming that b can only be a real number, there is no value of b such that the denominator is zero, then the fraction is defined for every real number.

The allowed values are R, the set of all real numbers.

3) [tex]\frac{a}{a*(a - 1) - 1}[/tex]

Again, we need to find the value of a such that the denominator is zero.

a*(a - 1) - 1 = a^2 - a - 1

So we need to solve:

a^2 - a - 1 = 0

We can use the Bhaskara's formula, the two values of a are given by:

[tex]a = \frac{-(-1) \pm \sqrt{(-1)^2 + 4*1*(-1)} }{2*1} = \frac{1 \pm \sqrt{5} }{2}[/tex]

Then the two values of a that are not allowed are:

a = (1 + √5)/2

a = (1 - √5)/2

Then the allowed values of a are:

R / {(1 + √5)/2} U {(1 - √5)/2}

Simplify this math problem show Your work

Answers

9514 1404 393

Answer:

  (p -9q)/(4p² +12pq)

Step-by-step explanation:

The least common denominator will be the product of the denominators.

  [tex]\dfrac{-3}{4p}+\dfrac{1}{p+3q}=\dfrac{-3(p+3q)+1(4p)}{(4p)(p+3q)}=\boxed{\dfrac{p-9q}{4p^2+12pq}}[/tex]

At an intersection, the red light times are normally distributed with a mean time of 3 minutes and a standard deviation of 0.25 minutes. Approximately what percent of red lights last between 2.5 and 3.5 minutes? (2 points)

Answers

Answer:

95.4%

Step-by-step explanation:

Z(low)=-2 0.022750132

Z(upper)=2 0.977249868

Ralph bought a computer monitor with an area of 384 square inches. The length of the monitor is six times the quantity of five less than half its width.

Answers

Answer:

eh width = 103.5 inches

Step-by-step explanation:

x = width

Length = (x/2 - 5 )*6

so 384=x+3x-30

414=4x

x=414/4=103.5 inches

Questions 24-25. In 1963, postage was 5 cents per ounce. In 1981, postage was 18 cents per ounce.
If the trend had continued through to 2015, what would the postage per ounce be?
(round to the nearest central

The answer posted "42.55" is incorrect.

Answers

Answer:

The postage per ounce would be of $2.02.

Step-by-step explanation:

Exponential model:

The postage, in t years after 1963, follows the following format:

[tex]P(t) = P(0)(1+r)^t[/tex]

In which P(0) is the initial value and r is the growth rate, as a decimal.

In 1963, postage was 5 cents per ounce.

This means that [tex]P(0) = 5[/tex]

So

[tex]P(t) = P(0)(1+r)^t[/tex]

[tex]P(t) = 5(1+r)^t[/tex]

In 1981, postage was 18 cents per ounce.

This means that [tex]P(1981 - 1963) = P(18) = 18[/tex]. We use this to find r. So

[tex]P(t) = 5(1+r)^t[/tex]

[tex]18 = 5(1+r)^{18}[/tex]

[tex](1+r)^{18} = \frac{18}{5}[/tex]

[tex]\sqrt[18]{(1+r)^{18}} = \sqrt[18]{3.6}[/tex]

[tex]1 + r = (3.6)^{\frac{1}{18}}[/tex]

[tex]1 + r = 1.0738[/tex]

So

[tex]P(t) = 5(1.0738)^t[/tex]

If the trend had continued through to 2015, what would the postage per ounce be?

2015 - 1963 = 52, so this is P(52).

[tex]P(52) = 5(1.0738)^{52} = 202[/tex]

202 cents, so $2.02.

Help me please I need help 6

Answers

Answer:

69.6

Step-by-step explanation:

sin 55 = x / 85

0.8191520443 = x / 85

x = 69.6

O EXPONENTAL AND LOGARITHMIC FUNCTIONS
Finding the initial or final amount in a word problem on...
An initial amount of money is placed in an account at an interest rate of 2% per year, compounded continuously. After two years, there is $1269.79 in the
account. Find the initial amount placed in the account. Round your answer to the nearest cent.

Answers

Answer:

$ 1220.00

Step-by-step explanation:

1269.79 = A [tex]e^{.02 * 2}[/tex]

1269.79 /A = [tex]e^{.04}[/tex]

ln(1269.79 /A) = .04 ln(e)

ln(1269.79 /A) = .04

1269.79 /A = [tex]e^{.04}[/tex]

1269.79 /A = 1.0408

A =  1269.79 / 1.0408

$ 1220.00

Suppose that you are interested in determining the average height of a person in a large city. You begin by collecting the heights of a random sample of 196 people from the city. The average height of your sample is 68 inches, while the standard deviation of the heights in your sample is 7 inches. The standard error of your estimate of the average height in the city is

Answers

Answer:

The standard error of your estimate of the average height in the city is 0.5 inches.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

You begin by collecting the heights of a random sample of 196 people from the city.

This means that [tex]n = 196[/tex]

The standard deviation of the heights in your sample is 7 inches.

This means that [tex]\sigma = 7[/tex]

The standard error of your estimate of the average height in the city is

[tex]s = \frac{\sigma}{\sqrt{n}} = \frac{7}{\sqrt{196}} = 0.5[/tex]

The standard error of your estimate of the average height in the city is 0.5 inches.

Identify the transformation that occurs to create the graph of h(x).
H(x)=f(x+3)

Answers

Answer: The graph moved left 3 units.

(x, y) = (x - 3, y)

Choose the correct answers for (a) the total installment price, (b) the carrying charges, and (c) the number of months needed to save money at the monthly rate to buy the item for its cash price.
A bunk bed with a cash price of $1,998, at $143 per month for 15 months

Answers

Answer:

$2,145 ; $147 ; 14 months

Step-by-step explanation:

Given that :

The cash price, that is, the amount that would be paid if customer is to pay the entire amount item is worth at once = $1998

Monthly payment = $143

Period = 15 months

The total installment price ; total amount paid on a monthly pay for 15 months :

(monthly payment * period)

($143 * 15)

= $2,145

The carrying charge :

Installment pay - Cash amount

$(2,145 - 1,998)

= $147

The number of month needed to save at Monthly rate to buy item at it's cash price :

Cash price / monthly payment

$1998 / $143

= 13.97

= 14 months

So for this problem I got 0.00023833 however it is not accepting my answer. If I rounded 4 decimal places it would be 0.000. How would I go about this problem? Can someone please help?

Answers

Answer:

0.0002

Step-by-step explanation:

4 decimal places means tenths, hundredths, thousandths, and ten thousandths places. If we count 4 decimal places, we come to 0.0002. The number next to it, 3, rounds down, so the answer should be 0.0002.

Two systems of equations are given below. For each system, choose the best description of its solution.

x - 5y = 5
-x + 5y = -5

a. The system has no solution.
b. The system has a unique solution:
(x,y) = _______
c. The system has infinitely many solutions. They must satisfy the following equation:
y = ________

Answers

Answer:

Infinitely many solutions.

They must satisfy [tex]y = \frac{1}{5}(x - 5)[/tex]

Step-by-step explanation:

Given

[tex]x - 5y = 5[/tex]

[tex]-x + 5y = -5[/tex]

Required

The best description

Add both equations

[tex]x - x - 5y + 5y = 5 - 5[/tex]

[tex]0+0 =0[/tex]

[tex]0 = 0[/tex] ---- this means that the system has infinitely many solutions.

Make y the subject in: [tex]-x + 5y = -5[/tex]

Add x to both sides

[tex]5y = x - 5[/tex]

Divide through by 5

[tex]y = \frac{1}{5}(x - 5)[/tex]

Hence, they must satisfy: [tex]y = \frac{1}{5}(x - 5)[/tex]

Fifteen dozen eggs were needed for baking four wedding cakes. The first cake
needed one dozen eggs, and each successive cake needed twice as many eggs as the
previous cake. How many eggs were used to make the fourth cake?

Answers

Answer:

96 eggs

Step-by-step explanation:

A dozen is equal to 12 eggs, so 15 dozen is equal to 180 eggs

(Because 15*12 = 180)

We already know how many eggs are required for the 1st cake: 12 eggs.

Then it says "each successive cake needs twice as many eggs as the previos cake".

(Successive means the cake directly after the previous cake)

Here's how we find the number of eggs needed for the 2nd cake:

The 1st cake needed 12 eggs, and because the 2nd cake is directly after the 1st cake, we are going to need two times the amount of 12 eggs.

This equation represents the above scenario:

12*2 = 24

So we need 24 eggs for the 2nd cake.

Now we repeat this process for the 3rd cake, finding twice the amount of eggs from the 2nd cake to find the amount of eggs needed for the 3rd cake:

24*2 = 48

And we repeat it once more for the 4th cake, using the eggs from the 3rd cake:

48*2 = 96

So here's the list of how many eggs are required for each of the cakes:

1st cake: 12

2nd cake: 24

3rd cake: 48

4th cake: 96

If you add all the eggs from each of the cakes, you will get 180, which is the number of eggs needed for all four cakes. So our answer is correct.

Hope this helps (●'◡'●)

if you subtract 1/2 from a number and multiply the result by 1/2 you get 1/8. What is the no.

Answers

Step-by-step explanation:

1/6

1/6- 1/2 = 1/4

1/4*1/2= 1/8

The number is 3/4


Step by step

1/(N-1/2)•1/2=1/8
2/N-1/2=1/8 divided 1/2 But the 1/2 in the other side by dividing
3/ N-1/2=1/4
4/N=1/4+1/2
5/N=3/4
If you check
3/4-1/2=1/4
1/4•1/2=1/8


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