Find the area of the shape shown below.
2
2
2
2
2
units

Find The Area Of The Shape Shown Below.22222units

Answers

Answer 1

Answer:

8

Step-by-step explanation:

khan

Answer 2

Answer:

8

Step-by-step explanation:


Related Questions

What is the solution to this system of equations?
5x + 2y = 29
x + 4y= 13

Answers

Answer:

x = 4.5

y = 3.25

Step-by-step explanation:

Use elimination

5x + 2y = 29

x + 4y = 13 (-5)

4y(-5) = 13(-5)

2y = 29

-20y = -65

y = 3.25

Sub it back into the equation

5x + 6.50 = 29

5x = 22.5

x = 4.5

Given \qquad m \angle LONm∠LONm, angle, L, O, N is a straight angle. \qquad m \angle MON = 8x - 13^\circm∠MON=8x−13 ∘ m, angle, M, O, N, equals, 8, x, minus, 13, degrees \qquad m \angle LOM = 7x - 17^\circm∠LOM=7x−17 ∘ m, angle, L, O, M, equals, 7, x, minus, 17, degrees Find m\angle MONm∠MONm, angle, M, O, N:

Answers

Answer:

[tex] \boxed{99°}[/tex]

Step-by-step explanation:

m<MON = 8x - 13°

m<LOM = 7x - 17°

To find : m <MON

First, we have to find the value of x :

Create an equation

[tex] \mathrm{8x - 13 + 7x - 17 = 180}[/tex] ( sum of angle in straight line )

Collect like terms

[tex] \mathrm{15x - 13 - 17 = 180}[/tex]

Calculate

[tex] \mathrm{15x - 30 = 180}[/tex]

Move constant to R.H.S and change its sign

[tex] \mathrm{15x = 180 + 30}[/tex]

Calculate the sum

[tex] \mathrm{15x = 210}[/tex]

Divide both sides of the equation by 15

[tex] \mathrm{ \frac{15x}{15} = \frac{210}{15} }[/tex]

Calculate

[tex] \mathrm{x = 14}[/tex]

Now, let's find the value of m<MON

[tex] \mathrm{8x - 13}[/tex]

Plug the value of x

[tex] \mathrm{ = 8 \times 14 - 13}[/tex]

Calculate the product

[tex] \mathrm{ = 112 - 13}[/tex]

Calculate the difference

[tex] \mathrm{ = 99}[/tex] °

Hope I helped!

Best regards!

Answer:

48

Step-by-step explanation:

because i say so


Evaluate the expression below for x =4 and y = 5.
x2 + 3(x + y)
When x = 4 and y = 5, x2 + 3(x + y)= |
(Type an integer or a decimal.)

Answers

Answer:

positive 35

Step-by-step explanation:

x2 + 3(x + y)        given

4(2) + 3(4+5)         problem

4(2) + 3(9)

8 + 27= 35

(x-yi)(3+5i) is the conjugate of 6+24i

Answers

Answer:

x=-3

y=3

(-3-3i)(3+5i)

Step-by-step explanation:

[tex](x-yi)(3+5i)\\=3x+5xi-3yi+5y\\=(3x+5y)+(5x-3y)i\\[/tex]

and we have that must equal

6-24i

3x+5y=6

5x-3y=-24 and if we work it we found out that the solutions are

x=-3 and

y=3

is this right? someone please check?

Answers

Answer:

The answer looks correct.

Step-by-step explanation:

All the other option doesn't match the above question's statement.

The last answer is the correct (in my opinion)

Answer:

Absolutely Correct

Step-by-step explanation:

Based on the definition of midpoint;

It is equidistant from both endpoints, and it is the centroid both of the segment and of the endpoints.

meaning the distance from the midpoint to one end is the same as the distance to the other end

PLS HELP!! Consider the exponential functions f, g, and h, defined as shown. Determine which function or functions have each key feature. Drag the tiles to the correct boxes. Not all tiles will be used.

Answers

Answer:

1) increases on all interval of x = only g(x)

2) approaches an integer as x approaches -∞ = only f(x)

3) y-intercept at (0, 4) = only g(x)

4) x-intercept at (1, 0) = f(x) and h(x)

Step-by-step explanation:

1) The functions that increases on all interval of x are;

f(x) = -2(3)ˣ + 6 decreases on all interval of x

The function g(x) which is 4 × 4ˣ  increases on all interval of x

The function h(x) is observed to be decreasing as x increases, therefore, the only function that increases on all interval of x = g(x)

2) The function that approaches an integer as x approaches -∞ = -2(3)ˣ + 6

-2(3)ˣ + 6 approaches 6 as x approaches -∞ which is only f(x)

3) The functions that have a y-intercept at (0, 4) is only g(x)

4) The function that have a x-intercept at (1, 0) are f(x) and h(x).

Answer:

A) f(x) and g(x)

B) only g(x)

C) All three functions

D) f(x) and h(x)

Step-by-step explanation:

In my uploaded image on the test I have gotten C) wrong but if you graph all three functions, you can see that all three functions have the same style of -∞

end behavior so I think that would be the most logical answer.

A lawn-mowing company is trying to grow its business. It had 18 clients when they started its business and wants to increase by 4 new clients each week. Use an arithmetic sequence to write a function to represent this real-world situation and determine the range of the function for the first four weeks of data.

Answers

Answer: y=18+4x

Step-by-step explanation:  Let y stand for the number of customers the business has in total, and x stand for the number of weeks that have passed. If the business increases by 4 clients per week as described by the scenario, then the range will go as followed: 18, 22, 26, 30...

Today I would like for you to work one of the following problems and explain your process/reasoning clearly and thoroughly.

Answers

Answer:

Step-by-step explanation:

A line from the center of the circle to bisect  a chord is perpendicular to the chord.

Therefore, OA⊥ AS

Join O & R

OR is radius of the circle

ΔOAR is right angled triangle.

Use Pythagorean theorem to find OR

OR² = OA² + RA²

       = 3² + 4²

       = 9 +16

OR² = 25

OR = √25

OR = 5 cm

OP  is radius. Therefore, OP = OR = 5 cm

PA = OP + OA

     = 5 + 3

PA = 8 cm


In comparing two distributions, which attribute would you not compare?
A. Shape
B. Center
C. Marginal frequency
D. Spread

Answers

Answer:

The correct option is;

C. Marginal frequency

Step-by-step explanation:

The objective of comparison of two distributions is to check the significant difference from each other

The general measures used to compare the difference between distributions are the measures of centers such as the mean, the measures of spread such as the standard deviation and the shape of the compared distribution curves

Marginal frequencies are the values found in the total row and total column portion of a two way frequency distribution table

The marginal frequency is used to calculate the marginal relative frequency

The values of the marginal frequency, which is a sum, does not characterize the details of a distribution to a large extent.

Answer:

C. Marginal frequency

Step-by-step explanation:

Jared and Zach are practicing their free throws. Jared attempted x shots and made 75% of them. Zach attempted 10 more shots than Jared did and made 80% of them. Together, they made a total of 101 shots. Which equation represents this situation?

Answers

0.75x+0.8(x + 10) = 101

Answer:

0.75x+0.8(x+10)=101

Step-by-step explanation:

Jared attempted x shots and made 75% of them, or 0.75x. Zach attempted 10 more shots than Jared did, which is represented as x + 10. He made 80% of them, or 0.8(x + 10). Together, they made 101 shots. So, add the two expressions and set the sum equal to 101:

0.75x + 0.8(x + 10) = 101.

hello, i need help pleaseeeeeeeeeeeeeeee

Answers

Answer:

f₁(x) = -3x + 2

f₂(x) = x - 4

f₃(x) = x + 8

f₄(x) = -2x - 6

f₅(x) = -3x

Step-by-step explanation:

1). Since function f₁ (blue line) passes through a point (0, 2) and (-2, 8)

Let the equation of the blue line is,

y = mx + b

Since slope of the line 'm' = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

m = [tex]\frac{8-2}{-2-0}[/tex]

m = -3

Y-intercept 'b' = 2

Therefore, equation of the line will be,

y = -3x + 2

Linear function representing the line will be,

f₁(x) = -3x + 2

2). Let the equation of the red line passing through (0, -4) and (2, -2) is,

y = mx + b

Slope of the line 'm' = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

m = [tex]\frac{-4+2}{0-2}[/tex]

m = 1

y-intercept 'b' = -4

Therefore, the linear function will be,

f₂(x) = x - 4

3). Let the equation of the green line passing through (-6, 2) and (-2, 6) is,

y = mx + b

Slope of the line 'm' = [tex]\frac{6-2}{-2+6}[/tex]

m = 1

y-intercept 'b' = 8

Therefore, linear function will be,

f₃(x) = x + 8

4). Let the equation of the yellow line passing through (-6, 6) and (-4, 2) is,

y = mx + b

Slope of the line = [tex]\frac{6-2}{-6+4}[/tex]

m = -2

y-intercept of the line 'b' = -6

Therefore, function representing the line will be,

f₄(x) = -2x - 6

5). Let the equation of the pink line is passing through (0, 0) and (-2, 6) is,

y = mx + b

Since the line is passing through origin, y-intercept 'b' = 0

Slope of the line = [tex]\frac{6-0}{-2-0}[/tex]

m = -3

Therefore, equation of the linear function will be,

f₅(x) = -3x

The teacher wants to make a fruit punch for the class party. She needs 30 quarts of juice. If there are 15 kids bringing in juice, how many pints should each person bring?

Answers

Answer:

4 pints

Step-by-step explanation:

30 quarts ÷ 15 kids = 2 quarts per kid

there are 2 pints in a quart so..

2 quarts per kid x 2 pints per quarter = 4 pints

A trader bought a bag for 125gh cedis. he later sold it at a profit of 30%. What is his selling price

Answers

Answer:

162.5 Cedis

Step-by-step explanation:

Cost Price= 125

Profit % = 30%

Selling price=?

Selling price= Cost price+ profit

Profit = ?

[tex]profit \% = \frac{profit}{cost \: price} \times 100[/tex]

[tex]30 \% = \frac{x}{125} \times 100[/tex]

[tex]30 \% = \frac{100x}{125} \\ 30 \times 125 = 100x[/tex]

[tex]3750 = 100x \\ \frac{3750}{100} = \frac{100x}{100} \\ x = 37.5[/tex]

Profit = 37.5 gh Cedis

Selling price= 125+37.5

Selling price= 162.5 gh Cedis

The selling price of a bag is 162.5Cedis.

It is required to find the selling price.

What is profit?

The profit is defined as the amount gained by selling a product, and it should be more than the cost price of the product.

Given that :

Let the profit be x.

Cost Price= 125

Profit % = 30%

profit%=profit/cp*100

30=profit/125*100

3750=100x

x=37.5

profit=37.5

Selling price= Cost price+ profit

Selling price=125+37.5

Selling price=162.5ghcedis

So, the selling price of a bag is 162.5Cedis.

Learn more about profit here:

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Solve two-step equations. -5/2 a + 5 = 25

Answers

Answer:

a = -8

Step-by-step explanation:

-5/2 a + 5 = 25

Subtract 5 from each side

-5/2 a + 5-5 = 25-5

-5/2 a = 20

Multiply each side by -2/5

-2/5 *-5/2 a = 20*-2/5

a = -8

Help now for brainliest,5stars and thanks.Find the values of x in the range 0≤x≤180° for which 15sin^2 x+11cox-17=0

Answers

Answer:

[tex]\bold{x = 66.42^\circ, 70.53^\circ}[/tex]

Step-by-step explanation:

Given equation is:

[tex]15sin^2 x+11cosx-17=0[/tex]

To find:

Values of [tex]x[/tex] in the range [tex]0^\circ\leq x\leq180^\circ[/tex].

Solution:

First of all, let us recall one identity of square of sine and square of cosine.

Sum of square of sine of an angle and square of cosine of the same angle is equal to 1.

[tex]\bold{sin^2\theta+cos^2\theta=1}[/tex]

So

Putting [tex]sin^2x=1-cos^2x[/tex] in the given equation.

[tex]15(1-cos^2x)+11cosx-17=0\\\Rightarrow 15-15cos^2x+11cosx-17=0\\\Rightarrow -15cos^2x+11cosx-2=0\\\Rightarrow 15cos^2x-11cosx+2=0\\\Rightarrow 15cos^2x-5cosx-6cosx+2=0\\\Rightarrow 5cosx(3cosx-1)-2(3cosx-1)=0\\\Rightarrow (5cosx-2)(3cosx-1)=0\\\Rightarrow cosx=\dfrac{2}{5}, \dfrac{1}{3}[/tex]

So, in the range [tex]0^\circ\leq x\leq180^\circ[/tex]

[tex]\bold{x = 66.42^\circ, 70.53^\circ}[/tex]

What is the center of the circle with the equation (x+4)2 + (y - 2)2 = 16?

Answers

Answer:

The center of the circle is

( - 4 , 2)

Step-by-step explanation:

Equation of a circle is given by

(x - h)² + ( y - k)² = r²

where r is the radius

(h, k) is the center of the circle

The center of a circle is given by

( - h , - k)

From the question equation of the circle is

( x + 4)² + ( y - 2)² = 16

Comparing with the general equation above

( h , k) = ( 4 , - 2)

The center of the circle is

( - h , - k) = ( - 4 , -(-2))

We have the final answer as

( - 4 , 2)

Hope this helps you

Someone pls help . Thank you sm☄️ .

Answers

Answer:

1) 3 is the Coefficient.

2) 10 is the constant.

3) 10.8 is the ans.

Write each fraction as a decimal and a percent. A) 7/8 B) 9/75 C/ 120/75​

Answers

Answer:

A) 0.875, 87.5%

B) 0.12, 12%

C) 1.6, 160%

Step-by-step explanation:

Answer:

A) 0.875, 87.5%

B) 0.001, 0.1%

C) 1.6, 160%

Step-by-step explanation:

I honestly just used a calculator, but it could also be solved using the butterfly technique. For percentages just move the decimal to the left two places.

find the interquartile range for the data {5, 7, 9, 5, 6, 6, 6, 11, 11, 3, 3}

Answers

Answer:

4

Step-by-step explanation:

i dont really know how to explain i used an algebra calculator

.You deposit $200 in an account earning 3.5% simple interest. How long will it take for the
balance of the account to be $221?

Answers

Answer:

3 times the percent for the balance to be $221

Step-by-step explanation:

6x-1=11 solve equation

Answers

Answer:

x = 2

Step-by-step explanation:

6x-1=11

Add 1 to each side

6x-1+1=11+1

6x = 12

Divide by 6

6x/6 = 12/6

x = 2

Answer:

x = 2

Step-by-step explanation:

[tex]6x-1=11 \\\\Collect \: like \:terms\\\\6x = 11+1\\\\Simplify\\\\6x =12\\\\Divide\:both\:sides\:by\:6\\\\\frac{6x}{6} = \frac{12}{6}\\ x = 2[/tex]

Find the value of y.
148°
y
x
y = [?]°

Answers

Answer:

y=90 degree

Step-by-step explanation:

bcz this triangle is drawn in the semi-circle and the greatest angle of triangle in a semi-circle is always right angle.


Ebola has an Ro of 2. How
many third-wave cases can
doctors expect?

Answers

Answer:

4 I guess

Step-by-step explanation:

Because

3-1=2

2^2=2*2=4

Kyle rides his bicycle 15 mph for 2 hours how far does he travel

Answers

━━━━━━━☆☆━━━━━━━

▹ Answer

30 miles

▹ Step-by-Step Explanation

Multiply mph by hours:

15 mph * 2 hrs = 30 miles

Hope this helps!

CloutAnswers ❁

━━━━━━━☆☆━━━━━━━

Kelli swam upstream for some distance in one hour. She then swam downstream the same river for the same distance in only 6 minutes. If the river flows at 5 km/hr, how fast can Kelli swim in still water?

Answers

Answer:

6.11km/hr

Step-by-step explanation:

Let the speed that Kelli swims be represented by Y

Speed of the river = 5km/hr

Distance = Speed × Time

Kelli swam upstream for some distance in one hour

Swimming upstream takes a negative sign, hence:

1 hour ×( Y - 5) = Distance

Distance = Y - 5

She then swam downstream the same river for the same distance in only 6 minutes

Downstream takes a positive sign

Converting 6 minutes to hour =

60 minutes = 1 hour

6 minutes =

Cross Multiply

6/60 = 1/10 hour

Hence, Distance =

1/10 × (Y + 5)

= Y/10 + 1/2

Equating both equations we have:

Y - 5 = Y/10 + 1/2

Collect like terms

Y - Y/10 = 5 + 1/2

9Y/10 = 5 1/2

9Y/ 10 = 11/2

Cross Multiply

9Y × 2 = 10 × 11

18Y = 110

Y = 110/18

Y = 6.1111111111 km/hr

Therefore, Kelli's can swim as fast as 6.11km/hr still in the water.

PT.1     Kelli swam upstream for some distance in one hour. She then swam downstream the same river for the same distance in only 6 minutes. If the river flows at 5 km/hr, how fast can Kelli swim in still water?

Choose the most logical value for the variable to represent.

Let x = Kelli's swimming speed in still water

PT.2    Which expression represents the distance Kelli traveled upstream?

1(x – 5)

PT.3     Which expression represents the distance Kelli traveled downstream?

0.1(x + 5)

PT.4     Solve the equation x – 5 = 0.1(x + 5) for x. Round your answer to the nearest hundredth.  Kelli can swim about 6.11  km/hour.

how many words can be formed by using the W,X,Y,Z if repetitions is not allowed?
- 30
- 24
- 18
- 12

Answers

Answer:

24

Step-by-step explanation:

What you have here is a permutation, seeing as each element can only be used once.

We have 4 letters initially, so we can choose any 1 as our first letter. We have 4 choices for our first letter

However, once we choose our first letter, we can't use it anymore, so, for our second letter, we can only choose from the remaining 3 letters.

Furthermore, once we choose our second letter, we can only choose our 3rd letter from the remaining two letters we didn't choose yet.

Finally, our last letter will always be the one we didn't choose the last 3 times. So there is only one choice here.

Going off of this, we have four choices for the 1st letter, three choices for the 2nd letter, two choices for the 3rd letter, and one choice for the 4th letter

The way to calculate how many permutations we have without repetition is using factorials

N!

Where N is the number of elements you have.

In this case, it would be 4!

4! is 4 * 3 * 2 * 1

Which equals 24

If you notice, each number in 4! is the number of options we have for each choice. 4, then 3, and so on

explain how the phrase oh heck another hour of algebra can help a student recall the trigonometric ratios​

Answers

Answer:

its a mnemonic

Oh  Heck  Another  Hour Of  Algebra

(O = opposite side, H = hypotenuse ) = sine

(A = adjacent side,  H = hypotenuse ) = cosine

(O = opposite side,  A = adjacent ) = tangent

Find the midpoint of the segment below and enter its coordinates as an ordered pair. If necessary, express coordinates as fractions, using the slash mark (/) for the fraction bar. (-12, -3) (3, -8)

Answers

Answer:

[tex]=\left(-\frac{9}{2},\:-\frac{11}{2}\right)[/tex]

Step-by-step explanation:

[tex]\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\\\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(-12,\:-3\right),\:\left(x_2,\:y_2\right)=\left(3,\:-8\right)\\\\=\left(\frac{3-12}{2},\:\frac{-8-3}{2}\right)\\\\=\left(-\frac{9}{2},\:-\frac{11}{2}\right)[/tex]

Drag each label to the correct location on the table. Each label can be used more than once. A cross country coach records the number of miles his athletes on the Junior Varsity and Varsity teams ran today and displays the data in the provided dot plots. Given the shape of each distribution, determine which measures of center and spread are appropriate for him to use to summarize the data from each team. mean mean interquartile range interquartile range standard deviation standard deviation median median

Answers

Answer:

a.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.

b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed.

For the Junior Varsity Team, the mean would be the appropriate measure of the center since the data is symmetric or well-proportioned .

What is median?

Median represents the middle value of the given data when arranged in a particular order.

Since the data for the Junior Varsity Team is symmetric or well-proportioned, the mean would be the best way to determine the center, and standard deviation, which also measures the center and how far the values deviate from the mean, should be used to determine the spread.

The median could be utilized for the Varsity Team since the data is not evenly distributed and skewed to the left, and it does not take into account outliers.

We can use the interquartile range (IQR) to quantify the spread of the data because IQR does not take into account the skewed data.

Therefore, the varsity squad competes in intercollegiate or international competitions on behalf of the high school or institution while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.

Learn more about the Varsity team here

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Simplify. Can you explain it also?
[tex] \frac{9 {c}^{3} {de}^{2} }{12 {c}^{2}d {e}^{3} }[/tex]

Answers

Answer:

The answer is

[tex] \frac{3c}{4e}[/tex]

Step-by-step explanation:

[tex] \frac{9 {c}^{3}d {e}^{2} }{12 {c}^{2} d {e}^{3} } [/tex]

To solve the fraction reduce the fraction with d

That's we have

[tex] \frac{9 {c}^{3} {e}^{2} }{12 {c}^{2} {e}^{3} } [/tex]

Next simplify the expression using the rules of indices to simplify the letters in the fraction

For c

Since they are dividing we subtract the exponents

We have

[tex] {c}^{3} \div {c}^{2} = {c}^{3 - 2} = c^{1} = c[/tex]

For e

[tex]e^{2} \div {e}^{3} = e^{2 - 3} = {e}^{ - 1} = \frac{1}{e} [/tex]

Substituting them into the expression we have

[tex] \frac{9c}{12e} [/tex]

Reduce the fraction by 3

We have the final answer as

[tex] \frac{3c}{4e} [/tex]

Hope this helps you

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