find the area of the rectangle whose dimensions are 9cm and 8cm.

Answer:

Find the GCD (or HCF) of numerator and denominator

GCD of 63 and 9 is 9

Divide both the numerator and denominator by the GCD

63 ÷ 9

9 ÷ 9

Reduced fraction:  

7/1

Therefore, 63/9 simplified to lowest terms is 7/1.

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Using exterior angle property, we have 97+4x+7=17x+13. 13x=91, x=7

Answer:

x ≈ -0.73151

Step-by-step explanation:

Answer:

its 5/4! haha i used to be good at this when i was in 6th grade:)

Answer:

+1/2

Step-by-step explanation:

its the negative reciprocal

Answer:

201, 206, 216, 228, 240

Step-by-step explanation:

Step-by-step explanation:

since Chelsea can paint in 9hrs and Greg in 7, add the hrs and divide by 2 i.e (9+7)/2 =8 hrs

~10 hrs

MARK AS BRAINLIEST PLEASE

They could complete the job together in 2.4 days

The known parameters are;

The number of days it would take Michelle to complete the landscaping job = 6 days

The number of days it would take Danielle to complete the landscaping job = 4 days

The unknown parameter;

The number of days can the job be completed if they work together

The process of finding the solution;

The rate at which Michelle works = 1/6 of the landscaping work per day

The rate at which Danielle works = 1/4 of the landscaping work per day

Method;

Find their combined work rate, from which the time would take them to complete the job together can be found

Let, C, represent their combined work rate

Therefore, we have;

C = (1/6 + 1/4) = 5/12 of the landscaping (work) job/(per) day

The number of days they could complete the, 1, job = 1 job(work)/(5/12 (work)job/day) = 12/5 days = 2.4 days

∴ The number of days they could complete the job together = 2.4 days.

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Answer:

Hi I'm going to answer the question is 0

Step-by-step explanation:

-2x(-8)(10x+1)=0

Multiply -2 times -8 is 16

16x(10x+1)=0

Use the distributive property to multiply 16x by 10x+1

[tex] {160}^{2} + 16 = 0 \\ [/tex]

Factor out x.

x(160x+16)=0

To find equation solutions, solve x=0 and 160x+16=0

x=0

x=

[tex] - \frac{1}{10} [/tex]

Answer:

The vertex is at (2,1)

Step-by-step explanation:

The vertex form of a quadratic is

y = a(x-h)^2 +k  where (h,k) is the vertex

f(x) = 3(x - 2)^2 + 1.

The vertex is at (2,1)

Answer:

Step-by-step explanation:

there is no number of 7 or greater.

P(≥7)=0/6=0

Answer:

B. y= 6x2, y= -4.5x2, y= -x2

Step-by-step explanation:

y = 6x2, y = −4.5x2, y = −x2

This should be correct )

To solve this problem you must keep on mind the following information: By definition, a quadratic function has the following form:  

 y=ax^{2}+bx+c


Where a
 is the leading coefficient.

If the leading coeficient is closer to zero, the parabola is widest,if it has a larger positive or negative value, the parabola is narrowest.

Therefore, by knowing the information above, you have that the answer is:

y=- x^{2}  \\ y=-4.5 x^{2}  \\ y=6 x^{2}

Cheese required for 1 pizza = ½ pound

So, cheese required for 19 pizzas

= 19 × ½ pounds

= 19/2 pounds

= 9½ pounds

So, Hailey needs 9½ pounds of cheese to make 19 pizzas.

The solution is 9.5 pounds

The number of pounds of cheese Hailey need to make 19 pizzas is 9.5 pounds

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the number of pounds of cheese for 19 pizzas be A

Now , the equation will be

The number of pounds of cheese for 1 pizza = 1/2 pounds

So , the number of pounds of cheese for 19 pizzas = 19 x number of pounds of cheese for 1 pizza

Substituting the values in the equation , we get

The number of pounds of cheese for 19 pizzas = 19 x ( 1/2 )

The number of pounds of cheese for 19 pizzas = 19/2

The number of pounds of cheese for 19 pizzas = 9.5 pounds

Therefore , the value of A is 9.5 pounds

Hence , the number of pounds of cheese is 9.5 pounds

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Answer:

A. 29.91

Step-by-step explanation:

tan(x) = opposite leg / adjacent leg

tan(41) = 26 / x

0.869... = 26/x

26 / 0.869... = x

x = 29.91...

Answer:

(x - 2)

Step-by-step explanation:

Given expression is,

[tex]\frac{x^3+3x^2-4x-12}{x^2+5x+6}[/tex]

We have to find the quotient.

x² + 5x + 6) x³ + 3x² - 4x - 12(x - 2

                   x³ + 5x² + 6x

                       -2x² - 10x - 12

                       -2x² - 10x - 12

                                    0

Therefore, quotient of the given expression will be (x - 2).

Answer:

X - 2

Step-by-step explanation:

Answer:

Step-by-step explanation:

The best answer from the choices provide is x = -1 or x = -1

Given the expression

[tex]x^2 + 2x + 1 = 0[/tex]

Factorizing the given expression

[tex](x^2 +x)+(x + 1) = 0\\[/tex]

Factor out the common variable from both brackets

[tex]x(x+1)+1(x+1)=0\\(x+1)(x+1)=0\\x+1 \ and \ x+1=0\\x =0-1 \ and \ x=0-1\\x=-1 \ and \ x =-1[/tex]

Hence the best option is x = -1 or x = -1

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The solutions for [tex]f(x) = x^{2}+2\cdot x + 1 = 0[/tex] are [tex]x_{1} = x_{2} = -1[/tex].

We can estimate the roots by a numerical approach, which consists in evaluating the quadratic function ([tex]f(x) = x^{2}+2\cdot x + 1 = 0[/tex]) for a set of values of [tex]x[/tex]. We consider the set of values between [tex]-4\le x \le 4[/tex]:

[tex]\,\,\,\,\,\,x \,\,\,\,\,\,\,\,f(x)\\-4\,\,\,\,\,\,\,\,\,\,\,\,9\\-3\,\,\,\,\,\,\,\,\,\,\,\,4\\-2\,\,\,\,\,\,\,\,\,\,\,\,1\\-1\,\,\,\,\,\,\,\,\,\,\,\,0\\.\,\,\,0\,\,\,\,\,\,\,\,\,\,\,\,\,1\\.\,\,\,1\,\,\,\,\,\,\,\,\,\,\,\,\,4\\.\,\,\,2\,\,\,\,\,\,\,\,\,\,\,\,\,9\\.\,\,\,3\,\,\,\,\,\,\,\,\,\,\,\,\,16\\.\,\,\,4\,\,\,\,\,\,\,\,\,\,\,\,\,25\\[/tex]

According to the previous input, we conclude that roots of the quadratic formula are [tex]x_{1} = x_{2} = -1[/tex].

The solutions for [tex]f(x) = x^{2}+2\cdot x + 1 = 0[/tex] are [tex]x_{1} = x_{2} = -1[/tex].

Answer:

B.5: 5^2(-3)(+7)

Step-by-step explanation:

1. 5 is the HCF of the three numbers, so it goes outside the brackets. 5(^4+4^3−21^2).

2. ^2 is also a factor, so now its 5^2(^2+4-21)

3. Factor by Grouping 5^2(^2−3+7−21)

4. Factor by Grouping 5^2((−3)+7(−3))

5. Factor by Grouping 5^2(−3)(+7)

Thats your final answer.

Step-by-step explanation:

the scanned description is very hard to understand.

so I think what happened :

16x² - 9 = 16

then the first error :

sqrt(16x²) - sqrt(9) = sqrt(16)

that is wrong, as you cannot split a + or - operation inside a sqrt function into + or - separate sqrt results of the parts.

so, correctly, the only possible transformation involving sqrt for both sides :

sqrt(16x² - 9) = sqrt(16)

but it would be even easier to clean up the various constant numbers with each other.

so,

16x² - 9 = 16

16x² = 25

and now we trashes the square root

sqrt(16x²) = sqrt(25)

4x = 5

x = 5/4 or x = -5/4

and I cannot see or understand for my life what the second equation was, as Daniel did something wrong, so I cannot deduct the original equation out of a supposedly wrong

y³ - 1 = 7

Answer:

Step-by-step explanation:

I would begin by distributing the L. It will be easier in the end to do it this way. There are a couple of ways you can do this, but distribution is the easiest. After you distribute the L you have

T = 2L + LRS

Next subtract the 2L to get

T - 2L = LRS. Lastly, to isolate the R, divide away the LS to get

[tex]\frac{T}{LS}-\frac{2L}{LS}[/tex] = R  In that second term, the L's cancel each other out, leaving us with

[tex]\frac{T}{LS}-\frac{2}{S}[/tex] = R

Answer:

x=y=-2

Step-by-step explanation:

Comparing these ordered pairs, we will get

4^(1/x)=1/2 and 9^(1/y)=1/3

x=-2 and y=-2

Answer:

x = y = - 2

Step-by-step explanation:

Using the rule of radicals/ exponents

[tex]a^{\frac{m}{n} }[/tex] = [tex]\sqrt[n]{a^{m} }[/tex] , [tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex] , [tex](a^m)^{n}[/tex] = [tex]a^{mn}[/tex]

Given

[tex]\sqrt[x]{4}[/tex] = [tex]\frac{1}{2}[/tex] , then

[tex]\sqrt[x]{2^{2} }[/tex] = [tex]\frac{1}{2}[/tex]

[tex]2^{\frac{2}{x} }[/tex] = [tex]2^{-1}[/tex]

Since the bases on both sides are equal, both 2 , then equate exponents

[tex]\frac{2}{x}[/tex] = - 1 ( multiply both sides by x )

2 = - x , that is

x = - 2

Similarly

[tex]\sqrt[y]{9}[/tex] = [tex]\frac{1}{3}[/tex] , then

[tex]\sqrt[y]{3^{2} }[/tex] = [tex]\frac{1}{3}[/tex]

[tex]3^{\frac{2}{y} }[/tex] = [tex]3^{-1}[/tex]

Equating the exponents gives

[tex]\frac{2}{y}[/tex] = - 1 ⇒ - y = 2 ⇒ y = - 2

Answer:

y = [tex]\frac{v-6}{3x}[/tex]

Step-by-step explanation:

[tex]3xy+6=v\\3xy=v-6\\y=\frac{v-6}{3x}[/tex]

Answer:

x = 26

Step-by-step explanation:

sin x =4/9

Take the inverse sin of each side

sin ^-1 (sin x) = sin^-1(4/9)

x=26.38779

To the nearest degree

x = 26

Answer:

Slope = -2

Step-by-step explanation:

The coefficient next to x is indicative of the equation's slope.

Answer:

slope = gradient

straight line equation is y = mx + c

where m is gradient therefore answer is -2

Answer:

that is the thousands place value.

the place value of 3 in 3546.= 3000

Answer:

=5×12÷[-12÷{15+(-9)}]

=5×12÷[-12÷6]

=5×12÷(-2)

=-30

Step-by-step explanation:

Using Pythagorean theorem

[tex]\\ \sf\longmapsto BC^2=AB^2+AC^2[/tex]

[tex]\\ \sf\longmapsto BC^2=7^2+3^2[/tex]

[tex]\\ \sf\longmapsto BC^2=49+9[/tex]

[tex]\\ \sf\longmapsto BC^2=58[/tex]

[tex]\\ \sf\longmapsto BC=\sqrt{58}[/tex]

answer is 19

the explanation is in the attachment

The answer is

i) - c

ii) - b

iii) - b

iv) - a

v) -  d