Find the 5th (not fourth) of given geometric sequence. 2000, 1000, 500,...

The equation that matches the problem is: Total pizzas = 4 × (3/4). Hayden's family should order 3 whole pizzas.

To solve this problem, we need to find the total number of pizzas needed for Hayden's family. Since each person eats 3/4 of a pizza, we can multiply this fraction by the number of people in the family:

Total pizzas = 4 × (3/4) = 12/4 = 3

Therefore, Hayden's family should order 3 whole pizzas.

As for the picture, imagine a circle representing a whole pizza. Divide it into four equal parts to represent each person's portion (3/4). Repeat this division three times to represent the three pizzas needed.

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Answer:

Assuming the base number is 1, if it becomes 5 then it is stretched. If the number become 1/5(less than 1) it is called compressed.

Step-by-step explanation:

Answer:

There is significant evidence to conclude that carina e in New section is greater than 42.3

Step-by-step explanation:

Given :

Sample variance, s² = 48.3

Population variance, σ² = 42.3

Sample size, n = 28

α = 0.05

The hypothesis :

H0 : σ² = 42.3

H0 : σ² > 42.3

The test statistic, χ² : (n-1)*s²/σ²

χ² = [(28 - 1) * 48.3] / 42.3

χ² = (27 * 48.3) / 42.3

χ² = 1304.1 / 42.3

χ² = 30.829787

χ² = 30.830

The Critical value at α = 0.05 ; df = (28-1) = 27

Critical value(0.05, 27) = 27.587

Reject H0 if χ² statistic > Critical value

Since, 30.830 > 27.587 ; Reject H0 ; and conclude that variance in the new section is greater than 42.3

We know

[tex]\boxed{\sf P(x,y)=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)}[/tex]

[tex]\\ \sf\longmapsto p(x,y)=\left(\dfrac{3(7)+5(-1)}{3+5},\dfrac{3(7)+5(1)}{3+5}\right)[/tex]

[tex]\\ \sf\longmapsto p(x,y)=\left(\dfrac{21-5}{8},\dfrac{21+5}{8}\right)[/tex]

[tex]\\ \sf\longmapsto p(x,y)=\left(\dfrac{16}{8},\dfrac{26}{8}\right)[/tex]

[tex]\\ \sf\longmapsto p(x,y)=\left(2,\dfrac{13}{4}\right)[/tex]

m:n=3:5

We know

[tex]\boxed{\sf M(x,y)=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)}[/tex]

[tex]\\ \sf\longmapsto M(x,y)=\left(\dfrac{3(7)+5(-1)}{3+5},\dfrac{3(7)+5(1)}{3+5}\right)[/tex]

[tex]\\ \sf\longmapsto M(x,y)=\left(\dfrac{21-5}{8},\dfrac{21+5}{8}\right)[/tex]

[tex]\\ \sf\longmapsto M(x,y)=\left(\dfrac{16}{8},\dfrac{26}{8}\right)[/tex]

[tex]\\ \sf\longmapsto M(x,y)=\left(2,\dfrac{13}{4}\right)[/tex]

In an arithmetic sequence, every pair of consecutive terms differs by a fixed number c, so that the n-th term [tex]a_n[/tex] is given recursively by

[tex]a_n=a_{n-1}+c[/tex]

Then for n ≥ 2, we have

[tex]a_2=a_1+c[/tex]

[tex]a_3=a_2+c = (a_1+c)+c = a_1 + 2c[/tex]

[tex]a_4=a_3+c = (a_1 + 2c) + c = a_1 + 3c[/tex]

and so on, up to

[tex]a_n=a_1+(n-1)c[/tex]

Given that [tex]a_3=126[/tex] and [tex]a_{64}=3725[/tex], we can solve for [tex]a_1[/tex]:

[tex]\begin{cases}a_1+2c=126\\a_1+63c=3725\end{cases}[/tex]

[tex]\implies(a_1+63c)-(a_1+2c)=3725-126[/tex]

[tex]\implies 61c = 3599[/tex]

[tex]\implies c=59[/tex]

[tex]\implies a_1+2\times59=126[/tex]

[tex]\implies a_1+118 = 126[/tex]

[tex]\implies \boxed{a_1=8}[/tex]

Answer:

Step-by-step explanation:

5t² + 4t = 5t² + 4 if and only if t=1.

A zero coefficient makes the value of the term equal to zero.

Answer: 5t to the second power and 5t to the second power. I don't know the answer to b.

Step-by-step explanation:

Answer:

A) quadratic

Step-by-step explanation:

ax2 + bx+c=0

Since the highest power of the equation is 2

A) quadratic -2

B) quartic- 4

C) linear- 1

D) cubic-3

Answer:

C. 11x² - 3x

Step-by-step explanation:

(12x² - 5x) - (x² - 2x)

12x² - 5x - x² + 2x

12x - x² - 5x + 2x

11x² - 3x

Answer:

the number before the first variable (first term)

Step-by-step explanation:

this appears to be an incomplete question. The numerical coefficient of a term is the number before the variable.

the constant is the number without a variable.

9514 1404 393

Answer:

Step-by-step explanation:

Let g represent the age of the garden. Then the age of the tree is 15g. The sum of their ages is ...

  g +15g = 128

  16g = 128 . . . . . collect terms

  g = 128/16 = 8 . . . . divide by the coefficient of g

The garden is 8 years old; the tree is 120 years old.

Answer:

Complementary angle

<y+61° =90°

<y = 90°- 61°

<y =29°

I Hope this helps.

Answer:

201.088 cubic units

Step-by-step explanation:

Given data

height= 12 units

radius= 4 units

The expression for the volume of a cone is given as

Volume = 1/3*πr^2h

Substitute the given data to find the volume of the cone

Volunme= 1/3* 3.142* 4^2* 12

Volume = 1/3* 3.142* 16*12

Volume= 1/3* 603.264

Volume= 201.088 cubic units

Yes, The collection of nice Nepali songs is a set​.

A set is a collection of items where there are operations such as:

Union of sets, the intersection of sets, and the complement of sets.

We have,

A set would have a finite or infinite number of elements, depending on the number of songs in the collection.

Nepali songs refer to a specific, well-defined collection of songs that satisfy certain criteria (such as being popular, culturally significant, or critically acclaimed).

so,

It can be considered a set.

Thus,

Yes, The collection of nice Nepali songs is a set​.

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Answer:

D

Step-by-step explanation:

use the formula for this

The area of the shaded region between the two z-scores is 0.4263.

The z-scores in the diagram are -1.0 and 1.0. The z-score of -1.0 represents a point that is 1 standard deviation below the mean, and the z-score of 1.0 represents a point that is 1 standard deviation above the mean.

The shaded region represents the area under the standard normal curve between the two z-scores. This area is equal to the probability that a standard normal variable will take on a value between -1.0 and 1.0.

To find the area of the shaded region, we can use a z-table. A z-table is a table that shows the area under the standard normal curve for different z-scores.

Looking up the z-scores of -1.0 and 1.0 in the z-table, we find that the area between the two z-scores is 0.4263.

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Step-by-step explanation:

You didn't put the graph, but you can compare between your graphs and the picture.

Brainliest please

The graph that represents this inequality y ≥ 4x − 3 is attached below.

If the equation or inequality contains variable terms, then there might be some values of those variables for which that equation or inequality might be true. Such values are called solution to that equation or inequality. Set of such values is called solution set to the considered equation or inequality.

We are given that the inequality is;

y ≥ 4x − 3

The slope of the inequality is 4.

The equation of the red line is y = 4x − 3  

The shading is above the line and the line is solid, that means  y is greater than or equal 4x − 3

The graph of this inequality y ≥ 4x − 3 is attached below.

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Answer:

sorry I don't know the answer

Answer:

For the equation y=log(x-k), the domain depends on the value of K. Sliding K moves the left bound of the domain interval. The range and the right end behavior stay the same. For the equation y=log x+k, the domain is fixed, starting at an x-value of 0. The vertical asymptote is also fixed. The range of the equation depends on K.

Step-by-step explanation:

Step-by-step explanation:

a)

For each value of x, we need to solve for y.

Our equation is x² -2. This means that we multiply x by itself ( x * x = x²), and then subtract that value by 2.

Here is a list of the unfilled answers:

x = -2:

-2²-2 = -2 * -2 -2 = 4-2 = 2. -2 * -2 = 4 because two negatives multiplied together makes a positive.

x=-1:

-1²-2 = 1 -2 = -1

x=1

1²-2 = 1-2= -1

x=3:

3²-2  = 9-2 = 7

b)

In this graph, the y represents the vertical part and x represents the horizontal. For each value of y, there is a horizontal line that can be drawn. For example, when y=0, the bolded horizontal line near the bottom of the graph represents that. We then need to find the points on the line representing x²-2 where it touches the horizontal line of y=0. This happens when x=-1.5 and x=1.5, as it is between the positive/negative 1 and 2 values of x

Answer:

3/11

Step-by-step explanation:

Answer:

The slope, m is -3

[tex]{ \tt{ = \frac{3 - 0}{0 - 1} }} \\ = - 3[/tex]

The y-intercept is b = 3

Symbol of inequality:

[tex]{ \tt{x \geqslant 1}} \\ or : \\ { \tt{y \geqslant 3}}[/tex]

Answer:

y = 2x + 10

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 2 , then

y = 2x + c ← is the partial equation

To find c substitute (- 4, 2 ) into the partial equation

2 = - 8 + c ⇒ c = 2 + 8 = 10

y = 2x + 10 ← equation of line

Answer:

ik only 1 of them and i dont even know if this is correct...

a) A

Answer:

y = 2x.

Step-by-step explanation:

The slope = (6 - (-4))/(3 - (-2))

= (6 + 4)/(3+2)

= 10/5

= 2.

Using this and the point (3, 6) we have:

y - 6 = 2(x - 3)

y = 2x - 6 + 6

y = 2x.

Answer:

VERY NICE RACK U HAVE MAM

Step-by-step explanation:

Answer:

Its a

Step-by-step explanation:

found on another thing and im taking test

Solution :

Given :

2y''' + 15y'' + 24y' + 11y= 0

Let x = independent variable

[tex](a_0D^n + a_1D^{n-1}+a_2D^{n-2} + ....+ a_n) y) = Q(x)[/tex]  is a differential equation.

If [tex]Q(x) \neq 0[/tex]

It is non homogeneous then,

The general solution  = complementary solution + particular integral

If Q(x) = 0

It is called the homogeneous then the general solution =  complementary solution.

2y''' + 15y'' + 24y' + 11y= 0

[tex]$(2D^3+15D^2+24D+11)y=0$[/tex]

Auxiliary equation,

[tex]$2m^3+15m^2+24m +11 = 0$[/tex]

-1  | 2    15    24     11

    | 0   -2    - 13    -11  

      2    13    11       0

∴ [tex]2m^2+13m+11=0[/tex]

The roots are

[tex]$=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$[/tex]

[tex]$=\frac{-13\pm \sqrt{13^2-4(11)(2)}}{2(2)}$[/tex]

[tex]$=\frac{-13\pm9}{4}$[/tex]

[tex]$=-5.5, -1$[/tex]

So, [tex]m_1, m_2, m_3 = -1, -1, -5.5[/tex]

Then the general solution is :

[tex]$= (c_1+c_2 x)e^{-x} + c_3 \ e^{-5.5x}$[/tex]

Given:

A man owns 3/4 of the share of a business and sells 1/3 of his  shares for Bir 10,000.

To find:

The value of the business in Bir.

Solution:

Let x be the value of the business.

It is given that a man owns 3/4 of the share of a business and sells 1/3 of his  shares for Bir 10,000.

[tex]x\times \dfrac{3}{4}\times \dfrac{1}{3}=10000[/tex]

[tex]x\times \dfrac{1}{4}=10000[/tex]

Multiply both sides by 4.

[tex]x=4\times 10000[/tex]

[tex]x=40000[/tex]

Therefore, the value of the business is 40,000 Bir.

Answer:

72 in. sq.

Step-by-step explanation:

6 x 6 = 36

6 x 6 = 36 / 2 = 18

6 x 6 = 36 / 2 = 18

18 + 18 + 36 = 72.

Hope this helps!

If there is something wrong just let me know.

Answer:

5 cm

Step-by-step explanation:

V = l*w*h

360 = l*8*9

360= 72l

Divide each side by 72

360/72 = 72l/72

5=l

Answer:

[tex]length = 5cm[/tex]

Step-by-step explanation:

[tex]volume \: = l \times b \times h \\ l = \frac{v}{b \times h} \\ l = \frac{360 {cm}^{3} }{9cm \times 8cm} \\ l = \frac{360}{72} \\ l = 5cm[/tex]

Hope this helps you.

have a nice day!