Find the 5 data points needed for a box plot of the given data set: { 8, 19, 11, 20, 2, 14, 17, 9, 15}
Give the answers in order from least to greatest.
Data Point 1:
Data Point 2:
Data Point 3:
Data Point 4:
Data Point 5:
Answers
Answers:
Data Point 1: 2 Data Point 2: 8.5 Data Point 3: 14 Data Point 4: 18 Data Point 5: 20The boxplot is shown below.
=========================================
Explanation:
What your teacher wants is the five number summary.
This consists of:
MinQ1MedianQ3MaxGiven in that exact order.
The given data set is { 8, 19, 11, 20, 2, 14, 17, 9, 15}
This sorts to {2, 8, 9, 11, 14, 15, 17, 19, 20}
From this sorted set, we see that 2 is the smallest item. So this is the min value. This is data point 1.
The max is the largest item, which in this case is 20, so this value goes in the box for data point 5.
---------------------
Count out the number of values in the sorted set. You should count out n = 9 items.
Because n is odd, this means the median is in slot n/2 = 9/2 = 4.5 = 5
The value in the 5th slot is 14 which is the median (data point 3).
-----------------------
Once you determine the median, break the sorted set up like so
L = {2, 8, 9, 11}
U = {15, 17, 19, 20}
L is the lower set of values smaller than the median
U is the upper set of values larger than the median
The median itself is not part of set L and not part of set U either. It's ignored entirely from this point on.
From here, we find the middle values of L and U
You should find that the middle value of L is (8+9)/2 = 17/2 = 8.5 which is the value of Q1 (data point 2)
And also, the middle value of set U is (17+19)/2 = 36/2 = 18 which is the value of Q3 (data point 4)
-----------------------
To wrap everything up, we have this five number summary
Min = 2Q1 = 8.5Median = 14Q3 = 18Max = 20These will determine the features of the boxplot as shown below.
In this case, there are no outliers.
Related Questions
PLEASE HELP AND BE CORRECT BEFORE ANSWERING
Answers
9514 1404 393
Answer:
3
Step-by-step explanation:
The length of A'B' is 3 units.
The length of AB is 1 unit.
The scale factor is A'B'/AB = 3/1 = 3.
An oil tanker spills oil that spreads in a circular pattern whose radius increases at a rate of 15 ft/min. Let A be the area of the circle and r be the radius of the circle. How fast is the area increasing when the radius is 30 feet
Answers
Answer:
[tex]2827.4 \dfrac{ft}{s}[/tex]
Step-by-step explanation:
[tex] A = \pi r^2 [/tex]
[tex] \dfrac{dA}{dt} = 2 \pi r \dfrac{dr}{dt} [/tex]
[tex] \dfrac{dA}{dt} = 2 \times \pi \times 30~ft \times 15 \dfrac{ft}{s} [/tex]
[tex] \dfrac{dA}{dt} = 2827.4 \dfrac{ft}{s} [/tex]
What is the answer to this
Answers
Answer:
y = -1.5x - 1
Step-by-step explanation:
We can use the general equation of y = mx + c to form our linear equation as seen on this graph.
Choosing two points on the graph (I will choose 0,-1 and 2,-4) we can find the gradient, m, as the distance between these points
[tex]\frac{Rise}{Run} = \frac{(-1)-(-4)}{(0)-(2)} = \frac{3}{-2} =-1.5[/tex]
We can find the c value by seeing where the graph cuts through the y-axis
This point is -1
Therefore our equation is y = -1.5x - 1
Alternatively, you could write it as [tex]y= -\frac{3}{2} x - 1[/tex]
Answer:
y = -1.5x - 1
Find two positive integers such that the sum of the first number and four times the second number is 1000, and the product of the two numbers is as large as possible.
Answers
Answer:
The two numbers are:
x = 500
y = 125
Step-by-step explanation:
We want to find two numbers x and y, such that:
x + 4*y = 1000
f(x, y) = x*y is maximum.
From the first equation, we can isolate one of the variables to get
x = 1000 - 4y
now we can replace it in f(x, y):
x*y = (1000 - 4*y)*y = 1000*y - 4*y^2
So now we want to maximize the function:
f(y) =- 4*y^2 + 1000*y
where y must be an integer.
Notice that this is a quadratic equation with a negative leading coefficient (so the arms of the graph will open downwards), thus, the maximum will be at the vertex.
Remember that for a general quadratic equation:
y = a*x^2 + bx + c
the x-value of the vertex is:
x = -b/(2*a)
so, in the case of:
f(y) =- 4*y^2 + 1000*y
the y-value of the vertex will be:
y = -1000/(2*-4) = 1000/8 = 125
So we found the value of y.
now we can use the equation:
x = 1000 - 4*y
x = 1000 - 4*125 = 1000 - 500 = 500
x = 500
Then the two numbers are:
x =500
y = 125
Which equations are true for the values x,y,z? Select 3 options
Answers
Answer:
Step-by-step explanation:
Seeds are often treated with fungicides to protect them in poor-draining, wet environments. A small-scale trial, involving six treated and six untreated seeds, was conducted prior to a large-scale experiment to explore how much fungicide to apply. The seeds were planted in wet soil, and the number of emerging plants were counted. If the solution was not effective and five plants actually sprouted.
Required:
What is the probability that all five plants emerged from treated seeds?
Answers
Answer:
0.0076 = 0.76% probability that all five plants emerged from treated seeds
Step-by-step explanation:
The plants were chosen without replacement, which means that the hypergeometric distribution is used to solve this question.
Hypergeometric distribution:
The probability of x successes is given by the following formula:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
In which:
x is the number of successes.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this question:
6 + 6 = 12 seeds, which means that [tex]N = 12[/tex]
6 treated, which means that [tex]k = 6[/tex]
Five sprouted, which means that [tex]n = 5[/tex]
What is the probability that all five plants emerged from treated seeds?
This is P(X = 5). So
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 5) = h(5,12,5,6) = \frac{C_{6,5}*C_{6,0}}{C_{12,5}} = 0.0076[/tex]
0.0076 = 0.76% probability that all five plants emerged from treated seeds
Solve for x.
7(x+2) = 6(x+5)
O x=-44
O X=-16
O x= 44
O x= 16
Answers
Answer:
x = 16
Step-by-step explanation:
7(x + 2) = 6(x + 5)
First, to start solving this problem, we have to distribute the "7" to the "x + 2" in the parenthesis and the "6" to the "x + 5" in the parenthesis.
7x + 14 = 6x + 30
Next, let's subtract "6x" from both sides of this equation!
x + 14 = 30
Now, we have to subtract "14" from both sides of the equation.
x = 16
Lastly! Let's make sure our "x=" equation is correct by inputting our value into the "x" values.
7(16 + 2) = 6(16 + 5)
7(18) = 6(21)
126 = 126
Since our equations equal each other we know that our x-value is correct!
Hope this Helps! :)
Have any questions? Ask below in the comments and I will try my best to answer.
-SGO
hellppp................
Answers
Answer:
[tex]B)[/tex]
[tex](-1,1)(-3,3)\\\frac{3-1}{-3+1} =-1\\1=1+b\\b=0\\y=-x[/tex]
OAmayOHopeO
Whats The Correct Answer ?
Answers
it is claimed that proportion in favor of proportion A is greater than 60%. A sample of size 100 found 69 in favor. what is the alternative hypothesis, and what is (are) the critical value
Answers
Answer:
The alternative hypothesis is [tex]H_1: p > 0.6[/tex].
The critical value is [tex]Z_c = 1.645[/tex]
Step-by-step explanation:
It is claimed that proportion in favor of proportion A is greater than 60%.
This means that at the null hypothesis, we test if the proportion is of at most 60%, that is:
[tex]H_0: p \leq 0.6[/tex]
At the alternative hypothesis, we test if the proportion is more than 60%, that is:
[tex]H_1: p > 0.6[/tex]
What is (are) the critical value?
The critical value is the value of Z with a p-value 1 subtracted by the standard significance level of 0.05, since we are testing if the mean is more than a value, so, looking at the z-table, [tex]Z_c = 1.645[/tex]
Which of these shapes have the same area?
Answers
Answer:
wheres the picture?
Step-by-step explanation:
Question 9 Pls if anyone knows the answer that will be greatly appreciated :)
Answers
Answer:
All the angles on the bottom line are 60. The angles on the top line from left to right is 130, 60, 60, 130.
Step-by-step explanation:
A passenger car will go 455 miles on 17.5 gallons of gasoline in city driving what is the rate in miles per gallon ?
Answers
Answer:
26 gallons
Step-by-step explanation:
Take the miles and divide by the gallons
455 miles / 17.5 gallons
26 miles per gallon
SCALCET8 3.9.019. A man starts walking north at 2 ft/s from a point P. Five minutes later a woman starts walking south at 7 ft/s from a point 500 ft due east of P. At what rate are the people moving apart 15 min after the woman starts walking
Answers
Answer:
The solution is defined in the attached file please find it.
Step-by-step explanation:
Find the midpoint of the line segment with endpoints (7, -12) and (-5, -15).
Answers
Answer:
The midpoint is (1,-13.5)
Step-by-step explanation:
To find the x coordinate of the midpoint, add the x coordinates of the endpoints and divide by 2
(7+-5) /2 = 2/2 =1
To find the y coordinate of the midpoint, add the y coordinates of the endpoints and divide by 2
(-12+-15) /2 = -27/2 =-13.5
The midpoint is (1,-13.5)
Midpoint formula
(X1+x2/2, y1+y2/2)
7 8/6 = 9.3?
Please explain your answer
Answers
Answer:
7×(8/6)=9.33
Step-by-step explanation:
7 is whole number
8/6 is the fraction
8/6 is 1.333
so, 7×1.333=9.33
In an effort to cut costs and improve profits, any US companies have been turning to outsourcing. In fact, according to Purchasing magazine, 54% of companies surveyed outsourced some part of their manufacturing process in the past two to three years. Suppose 555 of these companies are contacted.
Required:
a. What is the probability that 338 or more companies outsourced some part of their manufacturing process in the past two or three years? Write your answer as a percentage rounded to two decimal places.
b. What is the probability that 285 or more companies outsourced some part of their manufacturing process in the past two or three years? Write your answer as a percentage rounded to two decimal places.
c. What is the probability that 48% or less of these companies outsourced some part of their manufacturing process in the past two or three years? Write your answer as a percentage rounded to two decimal places.
Answers
Answer:
a) 0.06% probability that 338 or more companies outsourced some part of their manufacturing process in the past two or three years.
b) 90.15% probability that 285 or more companies outsourced some part of their manufacturing process in the past two or three years.
c) 0.23% probability that 48% or less of these companies outsourced some part of their manufacturing process in the past two or three years.
Step-by-step explanation:
For questions a and b, the normal approximation to the binomial is used, while for question c, the central limit theorem is used.
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
Normal probability distribution
Problems of normally distributed distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
54% of companies surveyed outsourced some part of their manufacturing process in the past two to three years.
This means that [tex]p = 0.54[/tex]
555 of these companies are contacted.
This means that [tex]n = 555[/tex]
Mean and standard deviation: Normal approximation to the binomial:
[tex]\mu = E(X) = np = 555*0.54 = 299.7[/tex]
[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{555*0.54*0.46} = 11.74[/tex]
a. What is the probability that 338 or more companies outsourced some part of their manufacturing process in the past two or three years?
Using continuity correction, this is [tex]P(X \geq 338 - 0.5) = P(X \geq 337.5)[/tex], which is 1 subtracted by the p-value of Z when X = 337.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{337.5 - 299.7}{11.74}[/tex]
[tex]Z = 3.22[/tex]
[tex]Z = 3.22[/tex] has a p-value of 0.9994.
1 - 0.9994 = 0.0006
0.0006*100% = 0.06%
0.06% probability that 338 or more companies outsourced some part of their manufacturing process in the past two or three years.
b. What is the probability that 285 or more companies outsourced some part of their manufacturing process in the past two or three years?
Using continuity correction, this is [tex]P(X \geq 285 - 0.5) = P(X \geq 284.5)[/tex], which is 1 subtracted by the p-value of Z when X = 284.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{284.5 - 299.7}{11.74}[/tex]
[tex]Z = -1.29[/tex]
[tex]Z = -1.29[/tex] has a p-value of 0.0985.
1 - 0.0985 = 0.9015
0.9015*100% = 90.15%
90.15% probability that 285 or more companies outsourced some part of their manufacturing process in the past two or three years.
c. What is the probability that 48% or less of these companies outsourced some part of their manufacturing process in the past two or three years?
Now we use the sampling distribution of the sample proportions, which have:
[tex]\mu = p = 0.54[/tex]
[tex]s = \sqrt{\frac{0.54*0.46}{555}} = 0.0212[/tex]
The probability is the p-value of Z when X = 0.48. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.48 - 0.54}{0.0212}[/tex]
[tex]Z = -2.84[/tex]
[tex]Z = -2.84[/tex] has a p-value of 0.0023.
0.0023*100% = 0.23%
0.23% probability that 48% or less of these companies outsourced some part of their manufacturing process in the past two or three years.
5x³y³z³×6a³x³z²
Find the product
Answers
need assistance with this, thank you
Answers
Answer:
B. 1✓3 in.
Search It ok
I see the answer :)
I almost got the problem but the problem was the rounding. I believe I rounded right but it is still incorrect. Can someone please help me on the rounding portion of the question? Thank you for your help!!!
Answers
Answer: The answer that I got for z was 0.111575, which when you round it to the hundredths place would be 0.11
Which simplified equation is equivale to the equation shown below? 15x – 5 + x = -47
Answers
Answer:
[tex]15x - 5 + x = - 47 \\ 15 + x - 5 = - 47 \\ 16x - 5 = - 47 \\ 16x = - 47 \\ x = \frac{ -16x}{16} = \frac{ - 45}{16} \\ x = - \frac{21}{8} [/tex]
g Find an equation of the line with slope m that passes through the given point. Put the answer in slope-intercept form. (-4, 8), undefined slope Hint: Any line parallel to Y axis has undefined slope.
Answers
Answer:
The equation is x + 4 = 0.
Step-by-step explanation:
Point (-4 , 8)
A line parallel to the Y axis has slope is infinite.
The equation of line is
[tex]y - y' = m (x-x')\\\\y - 8 =\frac{1}{0}(x+4)\\\\x + 4 = 0[/tex]
One number is 4 greater than another. The product of the numbers is 21. Find the numbers.
One pair of numbers, both of which are positive, is
Answers
Answer:
7 and 3 are two numbers that work
Step-by-step explanation:
7-3=4
7×3=21
Express the solution graphically of -1/3(2x+1) <3
Answers
Answer:
The first picture is the solution that I worked out and the second is the graph of the two solutions.
The graph of the solution of inequality [tex]-\frac{1}{3} (2x+1) < 3[/tex] is as shown below.
What is inequality?"It is a mathematical statement of an order relationship (greater than, greater than or equal to, less than, or less than or equal to) between two numbers or algebraic expressions."
For given question,
We have been given a inequality [tex]-\frac{1}{3} (2x+1) < 3[/tex]
We solve above inequality.
[tex]\Rightarrow -\frac{1}{3} (2x+1) < 3\\\\\Rightarrow \frac{1}{3} (2x+1) > -3\\\\\Rightarrow 2x+1 > -9\\\\\Rightarrow 2x > -10\\\\\Rightarrow x > -5[/tex]
so, the solution of the inequality [tex]-\frac{1}{3} (2x+1) < 3[/tex] is all points on the X-axis which are greater than x = -5.
The graph of the solution of inequality [tex]-\frac{1}{3} (2x+1) < 3[/tex] is as shown below.
Learn more about the inequality here:
https://brainly.com/question/19003099
#SPJ2
help me with my work pls
Answers
Answer:
-75/4
Step-by-step explanation:
75 x 100 = 7500
4 x 100 = 400
A bottling machine fills soda bottles with an average of 12.000 ounces of soda. The standard deviation is 0.002 ounces. If the design specification for the fill weight of the bottles is 12.000 ounces plus or minus 0.015 ounces, calculate the process capability index of the machine. Group of answer choices Less than or equal to 1 More than 4 More than 2 but less than or equal to 3 More than 1 but less than or equal to 2
Answers
Answer:
the process capability index of the machine is 2.5
Option c) [More than 2 but less than or equal to 3] is the correct answer
Step-by-step explanation:
Given the data in the question;
process average ( x') = 12.000 ounces
standard deviation σ = 0.002 ounces
the design specification for the fill weight of the bottles is 12.000 ounces plus or minus 0.015 ounces.
so
Upper specification Limit USL = 12.000 + 0.015 = 12.015 ounces
Lower specification Limit LSL = 12.000 - 0.015 = 11.985 ounces
the process capability index of the machine will be;
Cp = ( process average - Lower specification Limit ) / 3σ
so we substitute
Cp = ( 12 - 11.985 ) / ( 3 × 0.002 )
Cp = 0.015 / 0.006
Cp = 2.5
Therefore, the process capability index of the machine is 2.5
Option c) [More than 2 but less than or equal to 3] is the correct answer
Find the slope and then an equation for each line.
Answers
and for 2 the slope is -2/-8 or 1/4 and the equation is y-0=1/4(x-0)
solve the inequality.. help me out asap plss
Answers
Answer:
[tex]x<\frac{6}{5}[/tex]
Refer to picture for number line
Step-by-step explanation:
To solve this inequality, we want to isolate the variable. We can do this my getting like terms onto one side
[tex]6x-7<2-\frac{3x}{2}[/tex] [add both sides by 7]
[tex]6x<9-\frac{3x}{2}[/tex] [add both sides by 3x/2]
[tex]6x+\frac{3x}{2}<9[/tex] [multiply both sides by 2]
[tex]12x+3x<18[/tex] [add]
[tex]15x<18[/tex] [divide both sides by 15]
[tex]x<\frac{18}{15}[/tex] [simplify]
[tex]x<\frac{6}{5}[/tex]
Now that we have out inequality, we want to graph it. Since we know that [tex]x<\frac{6}{5}[/tex], that means we have an open circle. Since x is less than, the arrow would be pointing left.
Can someone help me with this question plz
Answers
Answer:
Volume is 167.6 yd³
Step-by-step explanation:
[tex]{ \boxed{ \bf{volume = \frac{1}{3}\pi {r}^{2} h}}} \\ { \sf{volume = \frac{1}{3} \times 3.14 \times {(4)}^{2} \times 10}} \\ \\ { \sf{volume = 167.6 \: {yd}^{3} }}[/tex]
Bonnie volunteers to bring bags of candy to her child’s class for the Halloween party this year. She buys one bag of candy A containing 150 pieces of candy, one bag of candy B containing 210 pieces of candy, and one bag of candy C containing 330 pieces of candy. She needs to use all the candy to create identical treat bags. How many treat bags can Bonnie make so that each one has the same number and variety of candy? How many of each type of candy will be in each bag?
Answers
Answer:
345 bags and would each have 2
