Find csc0

Please Help!!!!!

Find Csc0Please Help!!!!!

Answers

Answer 1
Answer:  -5/4

=======================================================

Explanation:

The terminal point is at (x,y) = (3,-4)

Apply the pythagorean theorem to find that x^2+y^2 = r^2 solves to r = 5. This is the length of the hypotenuse.

Then we can determine the cosecant of the angle theta using the formula below

csc(theta) = hypotenuse/opposite

csc(theta) = r/y

csc(theta) = 5/(-4)

csc(theta) = -5/4

Side note: csc = 1/sin

Answer 2
-5/4 maybe is the correct answer

Related Questions

Instructions: Find the value of x
I’ll mark brainliest please help

Answers

The little lines theu each section are telling you all those sections are identical, which mean they are the same length.

You are told one section is 10, which means x is also 10

X = 10

Use the substitution method to solve the system of equations. Choose the correct ordered pair. 4(x + 4) = 8(y + 2); 18y - 22 = 3x + 2​

Answers

x = 30

y = 2

Get the explanation from the image I have shared.

Hope it helps you

Simplify the expression.

4(11 + 7) ÷ (7 – 5)

Answers

Answer:

36

Step-by-step explanation:

4(11 + 7) ÷ (7 – 5)

4 * 18 ÷ 2

=36

Which expression are greater than 1/2? Choose all the apply

Answers

Answer:

25/30

5/8

Step-by-step explanation:

Which fraction is it out of all of these 6/14,5/8,25/30,or 3/6?

to determine which fractions are greater than 1/2, convert the fractions to decimals

to convert to decimals, divide the numerator by the denominator

1/2 = 0.5  less than half

6/14 = 0.43 less than half

5/8 = 0.625 greater than half

25 / 30 = 0.83 greater than half

3 / 6 = 0.5 equal to half

Find the value of x in the given figure using properties of parallel lines.

Answers

Answer:

x =42

Step-by-step explanation:

x and 138 are same side interior angles.  Same side interior angles are supplementary when the lines are parallel

x+138 = 180

x = 180-138

x =42

Answer:

42°

Step-by-step explanation:

138° + x = 180°

180° - 138° = 42°

At Dubai English School, 549 students use buses to go to school. If this number is 75% of the total school enrollment, then how many students are enrolled in total?

Answers

732 is the answer have a nice day and I hope you pass your exam or complete your homework

Part A: Factor x2b2 − xb2 − 6b2. Show your work.

Part B: Factor x2 + 4x + 4. Show your work.

Part C: Factor x2 − 4. Show your work

Answers

Answer:

A.2b2(x2-x-3)

B.x2+2x+2x+4

=x(x+2)+2(x+2)

=(x+2)(x+2)

C.x2-2^2

=(x+2)(x+2)

What is the value of x for x +20 x=22

Answers

Answer:

x(1+20)=22

21x=22

x= 22/21

x= 1.05

Step-by-step explanation:

Answer:

2!!!

Step-by-step explanation:

the person is wrong.. 2+20=22

A fair charges an admission fee of 4 dollars for eacg person. Let C be the cost of admission in dollars for P people. Write an equation relating C to P. Then graph your equation using the axes

Answers

Answer:

Equation is C = 4P

Graph is shown below

============================================================

Explanation:

The equation is C = 4P since it costs $4 per person. We just multiply 4 with the number of people (P) to get the cost (C).

Let's say 0 people show up, so that means C = 4*P = 4*0 = 0

The input P = 0 leads to the output C = 0. This is basically the same as saying x = 0 leads to y = 0. The point (0,0) is on the graph.

Repeat for P = 1 and you'll find that C = 4. This is the same as x = 1 leading to y = 4. The point (1,4) is on the graph.

If you keep going for various values of P, you'll get corresponding values of C. It turns out that all you need are 2 points to graph this line. Plot (0,0) and (1,4) on the same xy grid. Draw a line through them to complete the graph.

The graph is shown below.

Suppose the weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams. The weights of oranges are also normally distributed with a mean of 131 grams and a standard deviation of 20 grams. Amy has an apple that weighs 90 grams and an orange that weighs 155 grams.

Required:
a. Find the probability a randomly chosen apple exceeds 100 g in weight.
b. What weight do 80% of the apples exceed?

Answers

Answer:

a) 0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b) The weight that 80% of the apples exceed is of 78.28g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams.

This means that [tex]\mu = 85, \sigma = 8[/tex]

a. Find the probability a randomly chosen apple exceeds 100 g in weight.

This is 1 subtracted by the p-value of Z when X = 100. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{100 - 85}{8}[/tex]

[tex]Z = 1.875[/tex]

[tex]Z = 1.875[/tex] has a p-value of 0.9697

1 - 0.9696 = 0.0304

0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b. What weight do 80% of the apples exceed?

This is the 100 - 80 = 20th percentile, which is X when Z has a p-value of 0.2, so X when Z = -0.84.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.84 = \frac{X- 85}{8}[/tex]

[tex]X - 85 = -0.84*8[/tex]

[tex]X = 78.28[/tex]

The weight that 80% of the apples exceed is of 78.28g.

Is 69 square routed a even number

Answers

No it is not, the square root is 8.3

Find Length of x line OR

Answers

ATQ:-

Both figures r similar (given )

so :-

[tex] \frac{5}{2.5} = \frac{3}{1.5} = \frac{2}{1} = \frac{4}{x} \\ \frac{2}{1} = \frac{4}{x} \\ \frac{ \cancel{2}}{1} = \frac{ \cancel{4}^ { \tiny{2}}}{x} \\ x = 2 \: \: ans[/tex]

3. Betty rode her bike down a block that was 50 meters long. How many millimeters did she ride?​

Answers

Answer:

50,000 millimeters

Step-by-step explanation:

Hope this helps : ) I have no explanation but it's correct

A researcher has obtained the number of hours worked per week during the summer for a sample of 15 students. 40 25 35 30 20 40 30 20 40 10 30 20 10 5 20 Using this data set, compute the following: a. Median b. Mean c. Mode d. 40th percentile e. Range f. Sample variance g. Standard deviation

Answers

Answer:

Mean = 25

Median = 25

Mode = 6

Step-by-step explanation:

Given the data :

Using calculator :

Mode = highest occurring data point

Range = max - min = 40 - 5 = 35

Sample variance = 128.57 (calculator)

Sample standard deviation = sqrt(variance) = 11.34

Which relationship is always true for the angles x,y and z of triangle ABC

Answers

Answer:

B. y + z = x

Step-by-step explanation:

x is an exterior angle of the triangle.

y and z are the opposite angles opposite the exterior angle.

The exterior angle theorem of a triangle states that the measure of an exterior angle equals the measure of the sum of the two angles opposite the exterior angle.

Thus:

y + z = x

Which statements are true of the given function?
Check all that apply.

Answers

9514 1404 393

Answer:

  B, E

Step-by-step explanation:

The table tells you that f(0) = 3/2. (0 is found in the x-column; 3/2 is found in the f(x) column.)

__

You can find f(4) by evaluating the formula.

  f(4) = 1/2·4 +3/2 = 4/2 +3/2

  f(4) = 7/2 . . . . agrees with last answer choice

Answer:

A ,B and E ;)

Step-by-step explanation:

7. Find the length of X (in the picture) plssss I need help. (GIVING PPINTS AND BRAINLY)​

Answers

Answer:

[tex] \frac{8}{5} = \frac{4}{x} \\ 8x = 20 \\ x = 2.5[/tex]

Answer:

here the resize factor is 5/8

so we need to calculate

x = 4 *5/8

= 20/8

= 2.5

I assume you get the basic idea from the other question you posted.

What is the probability of rolling a number less than or equal to 8 with the
sum of two dice, given that at least one of the dice must show a 6?

Answers

Answer:

I hope this helps

the outcomes are the compulsory 6, and 1 or 2

Step-by-step explanation:

[tex] \frac{3}{6} \\ \frac{1}{2} or \: 0.5[/tex]

CAN SOMEONE PLEASE HELP ME GOOD, I need this to graduate ): 5. Given that AABC - ADEC, find the
value of x.

Answers

Answer:

ans: 4

Step-by-step explanation:

corresponding sides are proportional since given triangle are similar triangle, I.e

(4/5.5) = { (2x+8)/(6x-2)}

8/11 = ( x+ 4 ) / ( 3x - 1 )

8( 3x - 1 )= 11( x + 4 )

24x - 8 = 11x + 44

13x = 52

x = 4

ANSWER ASAP IM TIMED 30 POINTS

Which shape below will form a tessellation?

A. regular heptagons

B. regular pentagons

C. regular octagons

D. regular hexagons

Answers

Answer:

Step-by-step explanation:

D ANSWER D

Answer:

d

Step-by-step explanation:

How do you solve x[tex]x^{2} +4x+3=0[/tex]?

Answers

Answer:

[tex]{ \tt{ {x}^{2} + 4x + 3 = 0}} \\ { \tt{(x + 1)(x + 3) = 0}} \\ \\ { \tt{x = - 1 \: \: and \: \: - 3}}[/tex]

If the set of values in the table represents points on a line, what is the value of a?

Answers

Answer:

3

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

just did it

Are these triangles congruent?

Answers

Answer:

yes...

Step-by-step explanation:

its a congrate triangle

Yes the triangles are congruent because they have the same sides but not the same lengths and width.

In a regression analysis involving 30 observations, the following estimated regressionequation was obtained.y^ =17.6+3.8x 1 −2.3x 2 +7.6x 3 +2.7x 4​For this estimated regression equation SST = 1805 and SSR = 1760. a. At \alpha =α= .05, test the significance of the relationship among the variables.Suppose variables x 1 and x 4 are dropped from the model and the following estimatedregression equation is obtained.y^ =11.1−3.6x 2​ +8.1x 3For this model SST = 1805 and SSR = 1705.b. Compute SSE(x 1 ,x 2 ,x 3 ,x 4 )c. Compute SSE (x2 ,x3 ) d. Use an F test and a .05 level of significance to determine whether x1 and x4 contribute significantly to the model.

Answers

Answer:

(a) There is a significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]

(b) [tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]

(c) [tex]SSE_{(x_2,x_3)} = 100[/tex]

(d) [tex]x_1[/tex] and [tex]x_4[/tex] are significant

Step-by-step explanation:

Given

[tex]y = 17.6+3.8x_1 - 2.3x_2 +7.6x_3 +2.7x_4[/tex] --- estimated regression equation

[tex]n = 30[/tex]

[tex]p = 4[/tex] --- independent variables i.e. x1 to x4

[tex]SSR = 1760[/tex]

[tex]SST = 1805[/tex]

[tex]\alpha = 0.05[/tex]

Solving (a): Test of significance

We have:

[tex]H_o :[/tex] There is no significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]

[tex]H_a :[/tex] There is a significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]

First, we calculate the t-score using:

[tex]t = \frac{SSR}{p} \div \frac{SST - SSR}{n - p - 1}[/tex]

[tex]t = \frac{1760}{4} \div \frac{1805- 1760}{30 - 4 - 1}[/tex]

[tex]t = 440 \div \frac{45}{25}[/tex]

[tex]t = 440 \div 1.8[/tex]

[tex]t = 244.44[/tex]

Next, we calculate the p value from the t score

Where:

[tex]df = n - p - 1[/tex]

[tex]df = 30 -4 - 1=25[/tex]

The p value when [tex]t = 244.44[/tex] and [tex]df = 25[/tex] is:

[tex]p =0[/tex]

So:

[tex]p < \alpha[/tex] i.e. [tex]0 < 0.05[/tex]

Solving (b): [tex]SSE(x_1 ,x_2 ,x_3 ,x_4)[/tex]

To calculate SSE, we use:

[tex]SSE = SST - SSR[/tex]

Given that:

[tex]SSR = 1760[/tex] ----------- [tex](x_1 ,x_2 ,x_3 ,x_4)[/tex]

[tex]SST = 1805[/tex]

So:

[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4)} = 1805 - 1760[/tex]

[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]

Solving (c): [tex]SSE(x_2 ,x_3)[/tex]

To calculate SSE, we use:

[tex]SSE = SST - SSR[/tex]

Given that:

[tex]SSR = 1705[/tex] ----------- [tex](x_2 ,x_3)[/tex]

[tex]SST = 1805[/tex]

So:

[tex]SSE_{(x_2,x_3)} = 1805 - 1705[/tex]

[tex]SSE_{(x_2,x_3)} = 100[/tex]

Solving (d): F test of significance

The null and alternate hypothesis are:

We have:

[tex]H_o :[/tex] [tex]x_1[/tex] and [tex]x_4[/tex] are not significant

[tex]H_a :[/tex] [tex]x_1[/tex] and [tex]x_4[/tex] are significant

For this model:

[tex]y =11.1 -3.6x_2+8.1x_3[/tex]

[tex]SSE_{(x_2,x_3)} = 100[/tex]

[tex]SST = 1805[/tex]

[tex]SSR_{(x_2 ,x_3)} = 1705[/tex]

[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]

[tex]p_{(x_2,x_3)} = 2[/tex]

[tex]\alpha = 0.05[/tex]

Calculate the t-score

[tex]t = \frac{SSE_{(x_2,x_3)}-SSE_{(x_1,x_2,x_3,x_4)}}{p_{(x_2,x_3)}} \div \frac{SSE_{(x_1,x_2,x_3,x_4)}}{n - p - 1}[/tex]

[tex]t = \frac{100-45}{2} \div \frac{45}{30 - 4 - 1}[/tex]

[tex]t = \frac{55}{2} \div \frac{45}{25}[/tex]

[tex]t = 27.5 \div 1.8[/tex]

[tex]t = 15.28[/tex]

Next, we calculate the p value from the t score

Where:

[tex]df = n - p - 1[/tex]

[tex]df = 30 -4 - 1=25[/tex]

The p value when [tex]t = 15.28[/tex] and [tex]df = 25[/tex] is:

[tex]p =0[/tex]

So:

[tex]p < \alpha[/tex] i.e. [tex]0 < 0.05[/tex]

Hence, we reject the null hypothesis

17.
What is the value of the expression
2a + 5b + 3c for a = 12, b = 6, and
C=3?
A 10
B 21
C49
D 63

Answers

D. 63

2a+5b+3c

2(12)+5(6)+3(3)

24+30+9=63

Hope this helps! :)

Oakley babysits on weekends. He charges a flat fee of $12, plus an additional $5 for each hour that he babysits. How much money would Oakely make if he babysits for 4 hours?

Answers

Answer:

32

Since theres a flat fee he automatically starts at 12 since he gets 5 every hour for 4 hours (5×4) ending up at 20. You add the total and the flat fee 20+12= 32

Answer:

$32

Step-by-step explanation:

First you must set up the equation.

A flat fee of $12 means it will be added and $5 each hour for 4 hours so 5 will be multiplied by 4.

$12 + $5 * 4

12 + 5 * 4 (or 12 + (5 * 4), whatever makes you remember it better)

Remember PEMDAS (Parentheses, Exponents, Multiplication, Divisiom, Addition, Subtraction)

Multiplication comes before Addition so you get 12 + 20

12 + 20 = 32

Remember to put units, so you would get $32.

On a coordinate plane, a parabola opens up. It goes through (negative 3.25, 5), has a vertex of (1.75, negative 2.75), and goes through (6.25, 5). Solid circles appear on the parabola at (negative 3, 4), (0, negative 2), (1.75, negative 2.75), (3, negative 2), (6, 4).
Which is f(6) for the quadratic function graphed?

–2
–0.5
1.5
4

Answers

Answer:

-2

Step-by-step explanation:

/jwkkskjdkdiifididirit

Answer:

4

Step-by-step explanation:

Find the sum of: 7a² - 9a + 5 and 11a + a² + 8​

Answers

Answer:

Add them:

Squares to squares, a to and number to number:

8a^2+3a+13

The simplified sum of the given expressions 7a² - 9a + 5 and 11a + a² + 8​ is 8a² + 2a + 13.

To find the sum of the expressions 7a² - 9a + 5 and 11a + a² + 8, we simply combine like terms.

The given expressions contain terms with different powers of "a."

Combining the terms with the same powers, we have:

7a² + a² = 8a² (the coefficient for the "a²" term is 7 + 1 = 8)

-9a + 11a = 2a (the coefficient for the "a" term is -9 + 11 = 2)

Finally, we combine the constant terms:

5 + 8 = 13

Putting it all together, the sum of the expressions 7a² - 9a + 5 and 11a + a² + 8 is:

8a² + 2a + 13

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An expression is shown below:

3(m + 5 + 9m)

Part A: Write two expressions that are equivalent to the given expression. (3 points)

Part B: Show that one of your expressions in Part A is equivalent to the given expression using algebraic properties. Explain which properties you used. (4 points)

Part C: Show that your other expression from Part A is equivalent to the given expression by substituting a number for m. (3 points)

Answers

The answers are as follows part A = 30m+15  part B =3m+15+27m

and partC = 30m+15

What is an expression?

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition,substraction, multiplication and division.

Part A:- Two expressions that are equivalent to the given expressions are:-

3m   +   15   +   27m

30m  +   15

Part B:  Show that one of your expressions in Part A is equivalent to the given expression using algebraic properties.

3  (  m   +   5    +   9m   )

Open the bracket by multiplying 3 by what is in the bracket

3m   +   15   +   27m

Part C: Show that your other expression from Part A is equivalent to the given expression by substituting a number for m.

3   (  m    +   5   +   9m  )

Open the bracket by multiplying 3 by what is in the bracket

3m    +    15    +     27m

Collect like terms together

3m    +     27m  +   15

=   30m   +    15

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If the first and last terms of a trinomial are perfect squares, the trinomial is a perfect square
trinomial.
True
O False

Answers

Answer:

A trinomial is a perfect trinomial if the first and last terms are positive, perfect squares and the middle term is twice the product of their square roots.

Therefore, if you mean perfect as in positive, the answer is True.

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