Find area of the cross section of the dam pictured below

Answer:

A. Correct: When we plug in g(x) for the x in f(x), we get H(x).

B. Correct: When we plug in g(x) for the x in f(x), we get H(x).

C. Correct: When we plug in g(x) for the x in f(x), we get H(x).

D. Correct: When we plug in g(x) for the x in f(x), we get H(x).

Step-by-step explanation:

Brainliest, please!

Answer:

A. 18

Step-by-step explanation:

the equation :

RF×RS = PR×RQ

16×9 = PR × 8

144 = PR×8

PR = 144/8

PR = 18

If the length of FR is 16 units then the length of PR is 18 units which is option A.

Circle is a figure whcih is having an arc showing points which are at equidistant from the centre point. The distance of arc from the centre point is known as radius.

From the rule of tangents and point outside the circle we can say that,

RF×RS = PR×RQ

16×9 = PR × 8

144 = PR×8

PR = 144/8

PR = 18 units

Hence if the length of FR is 16 units then the length of PR is 10 units.

Learn more about circle at https://brainly.com/question/24375372

#SPJ2

Answer:

x^2 -10x+2

Step-by-step explanation:

(3x^2 - 11x - 4) – (x – 2) (2x + 3)

FOIL

(3x^2 - 11x - 4) – (2x^2-4x+3x-6)

Combine like terms

(3x^2 - 11x - 4) – (2x^2 -x-6)

Distribute the minus sign

3x^2 - 11x - 4 – 2x^2 +x+6

Combine like terms

x^2 -10x+2

(h ,k) —> (2 , –5)

g(x)=3x²-12x+7 —> y= 3(x-2)²-5

y=a(x–h)²+k —> a= 3 , h=2 , k= –5

(h ,k ) —> (2, –5)

I hope I helped you^_^

Answer:

C, Option 2, or (2,-5)

Step-by-step explanation:

edge 2021

The probability that neither of them draws the Leeks card is P = 4/6 = 0.667

Here we can assume that all the cards have the same probability of being randomly drawn.

The cards are:

So we have 6 cards. We want to find the probability that neither contestant draws the "Leeks" card.

Sammy draws first, the probability of drawing the Leeks card will be equal to the quotient between the number of Leeks cards (one) and the total number of cards (6).

Then the probability of drawing the leeks card is p = 1/6

This means that the probability of NOT drawing the leeks card is:

q = 1 - 1/6 = 5/6.

Now draws Hanna, now there are 5 cards in the deck (because one was already drawn). With the same approach as before, the probability of drawing the Leeks card is p = 1/5, then the probability of NOT drawing the card is:

q = 1 - 1/5 = 4/5.

The joint probability (this is, the probability of both of these events to happen together) is just the product of the individual probabilities.

Then the probability that neither of them draws the Leeks card is:

P = (4/5)*(5/6) = 4/6 = 0.667

If you want to learn more about probability, you can read:

https://brainly.com/question/24349426

Answer:

The properties of right angle triangle are as follows

Answer:

x=17

Step-by-step explanation:

These are alternate interior angles and alternate interior angles are equal when the lines are parallel

9x+23= 10x+6

Subtract 9x from each side

9x+23 -9x= 10x-9x+6

23 = x+6

Subtract 6 from each side

23-6 = x+6-6

17 =x

Answer:

6 -8n

Step-by-step explanation:

2/3 (9-12n)

Distribute

2/3 *9 - 2/3 *12n

6 -8n

Answer:

The inequality is -3<x<3

Step-by-step explanation:

(-3,3)

Answer:

8

Step-by-step explanation:

By power of a point, (x-2)(x+13) = (x-3)(x+16). Solving, we find that x=11, so FG= 11-3 = 8

Using the domain concept, it is found that the domain of the function is: x is an element of all real numbers such that [tex]x \neq (-\frac{3}{2}, 4)[/tex], second option.

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The function is:

[tex]f(x) = \frac{2x}{2x^3 - 5x^2 - 12x} = \frac{2x}{x(2x^2 - 5x - 12)} = \frac{2}{2x^2 - 5x - 12}[/tex]

The points outside the domain are the zeros of [tex]2x^2 - 5x - 12[/tex], which we find solving a quadratic equation.

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Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]

[tex]\Delta = b^{2} - 4ac[/tex]

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[tex]2x^2 - 5x - 12[/tex] is a quadratic equation with [tex]a = 2, b = -5, c = -12[/tex].

[tex]\Delta = b^{2} - 4ac = (-5)^2 - 4(2)(-12) = 121[/tex]

[tex]x_{1} = \frac{-(-5) + \sqrt{121}}{2(2)} = 4[/tex]

[tex]x_{2} = \frac{-(-5) - \sqrt{121}}{2(2)} = -\frac{6}{4} = -\frac{3}{2}[/tex]

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The domain is: x is an element of all real numbers such that [tex]x \neq (-\frac{3}{2}, 4)[/tex], second option.

A similar problem is given at https://brainly.com/question/13136492

Answer:

Step-by-step explanation:

Using the domain concept, it is found that the domain of the function is: x is an element of all real numbers such that , second option.

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The domain of a function is all possible values that the input value x can assume.

The domain of a fraction is all real values of x except the zeros of the denominator.

----------------------

The function is:

The points outside the domain are the zeros of , which we find solving a quadratic equation.

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Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

.

This polynomial has roots  such that , given by the following formulas:

----------------------

is a quadratic equation with .

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The domain is: x is an element of all real numbers such that , second option.

A similar problem is given at brainly.com/question/13136492

Answer:

I think this is right for the 2nd problem

Step-by-step explanation:

a1=7+(3)(1)

Step 1: Simplify both sides of the equation.

a1=7+(3)(1)

a=7+3

a=(7+3)(Combine Like Terms)

a=10

a=10

Answer:

a=10

Answer:

Correct answer is A. Trust me

Step-by-step explanation:

Answer:

where is the figure without figure how to find out

Answer:

74 degrees

.................

Answer:

74

Step-by-step explanation:

BEC and CED form a straight line so they add to 180

BEC+CED = 180

106+ CED = 180

CED = 180-106

CED = 74

Answer:

73 1/3 %

Step-by-step explanation:

8 pieces were left

30-8 = 22 so 22 were consumed

22/30 is the percent consumed

.7333333

73.333333%

We know .333333333 is 1/3

73 1/3 %

Answer:

FG = 120 cm

Step-by-step explanation:

The explanation is in the picture!

Answer:

Bro what to do in this question. Hope you understand me

Answer:

7 pots of coffee (If you want to be precise its 6 2/3)

Step-by-step explanation:

So basically you need 10 cups of coffe in fifteen minutes, so 60/15=4 then time 10. so 40 is how much coffee you need in a hour, but we are solving the pot so 40/6= 6 2/3. but it says how many pots so we round it up so its 7. (Unless you wanna be precise)

Answer:

the cost of the tire=341.4$

Answer:

19

Step-by-step explanation:

Add 7 onto 12 to find answer.

Answer:

b = 19

Step-by-step explanation:

b = 12 + 7

Simplify 12+7 to 19.

Answer:

25

Step-by-step explanation:

product of 18 and -3=18*-3= -54

positive difference=52-29=23

(18x-3)+56+(52-29)

= -54 + 56 + 23

=25

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Explanation:

This figure is a kite since we have two pairs of adjacent sides that are congruent, but not all sides are the same length.

One property of kites is that the diagonals are always perpendicular (this applies to rhombuses as well). This means angle 3 is 90 degrees.

The measure of ∠3 is 90°

Because in a kite the diagonals bisects at 90°

Therefore ∠3 is 90°

Answered by Gauthmath must click thanks and mark brainliest

May be this.. you may find all the math answers in the app known as Gauth math so I would suggest you to download it .Thank you

Answer:

the required answer is 4√2+1/2√2

Answer:  [tex]\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)[/tex]

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

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Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

From there, we can then say the following:

[tex]\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}[/tex]