Answer: (-2x-10y)-(-4x-3y)
-2x-10y-(-4x-3y)
-2x-10y+4x+3y
-2x+4x-10y+3y
-2x+4x-10y+3
Answer =2x-7y
Step-by-step explanation:
Which pair of expressions below are equivalent?
a. 7(2n) and 9
b. 3n + 5n and 15n
c. 4(2n-6) and 8n - 24
d. 7(2n) and 72n
Answer:
The answer is C
Hope this helped!
Which of the following are true of linear functions? Select all that apply.
There is exactly one output for each input.
The graph of a linear function is a straight line.
A linear function can cross the y-axis in two places.
A linear function has a constant rate of change.
A linear function must cross the x-axis.
Answer:
"there is exactly one output for each input" is cotrrect
"the graph of a linear function" is correct
Step-by-step explanation:
[tex]4 \sqrt{(3x}^{3} [/tex]
write in exponential form
Answer:
[tex]4(3x)^{\frac{3}{2} }[/tex]
Step-by-step explanation:
What is the value of (–7 + 3i) – (2 – 6i)?
–9 + 9i
–9 – 3i
–5 – 3i
–5 + 9i
Answer:
- 9 + 9i
Step-by-step explanation:
(- 7 + 3i) - (2 - 6i)
- 7 + 3i - 2 + 6i
- 7 - 2 + 9i
- 9 + 9i
El primer día de la tormenta de nieve hubo 9,2 centímetros de nieve. Durante el segundo día de la tormenta, cayeron otros 18,2 centímetros. Si la nevada total durante la tormenta de nieve de tres días fue de 39,1 centímetros, ¿cuánta nieve cayó el tercer día?
Answer:
11.7
Step-by-step explanation:
39.1 - 9.2 = 29.9
29.9 - 18.2 = 11.7
Prove the formula that:
((∃x)(F(x)∧S(x))→(∀y)(M(y)→W(y)))∧((∃y)(M(y)∧¬W(y)))
⇒(∀x)(F(x)→¬S(x))
Step-by-step explanation:
Given: [∀x(L(x) → A(x))] →
[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]
To prove, we shall follow a proof by contradiction. We shall include the negation of the conclusion for
arguments. Since with just premise, deriving the conclusion is not possible, we have chosen this proof
technique.
Consider ∀x(L(x) → A(x)) ∧ ¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]
We need to show that the above expression is unsatisfiable (False).
¬[∀x(L(x) ∧ ∃y(L(y) ∧ H(x, y)) → ∃y(A(y) ∧ H(x, y)))]
∃x¬((L(x) ∧ ∃y(L(y) ∧ H(x, y))) → ∃y(A(y) ∧ H(x, y)))
∃x((L(x) ∧ ∃y(L(y) ∧ H(x, y))) ∧ ¬(∃y(A(y) ∧ H(x, y))))
E.I with respect to x,
(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ ¬(∃y(A(y) ∧ H(a, y))), for some a
(L(a) ∧ ∃y(L(y) ∧ H(a, y))) ∧ (∀y(¬A(y) ∧ ¬H(a, y)))
E.I with respect to y,
(L(a) ∧ (L(b) ∧ H(a, b))) ∧ (∀y(¬A(y) ∧ ¬H(a, y))), for some b
U.I with respect to y,
(L(a) ∧ (L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b
Since P ∧ Q is P, drop L(a) from the above expression.
(L(b) ∧ H(a, b)) ∧ (¬A(b) ∧ ¬H(a, b))), for any b
Apply distribution
(L(b) ∧ H(a, b) ∧ ¬A(b)) ∨ (L(b) ∧ H(a, b) ∧ ¬H(a, b))
Note: P ∧ ¬P is false. P ∧ f alse is P. Therefore, the above expression is simplified to
(L(b) ∧ H(a, b) ∧ ¬A(b))
U.I of ∀x(L(x) → A(x)) gives L(b) → A(b). The contrapositive of this is ¬A(b) → ¬L(b). Replace
¬A(b) in the above expression with ¬L(b). Thus, we get,
(L(b) ∧ H(a, b) ∧ ¬L(b)), this is again false.
This shows that our assumption that the conclusion is false is wrong. Therefore, the conclusion follows
from the premise.
15
Please help me on this question. Thanks
Answer:
E. p - 7 + 7 = 22 + 7
Step-by-step explanation:
p - 7 + 7 = 22 + 7 ( -7 + 7 = 0)
p = 22 + 7
p - 7 = 22//
Determine whether the triangles are similar. If so, write a similarity
statement.
Answer:
[tex]\triangle FED\sim \triangle JEH[/tex]
Step-by-step explanation:
Both pairs of vertical angles formed at point E are equal. Therefore, the two triangles share two angles. If two triangles share two angles, they must also share the third angle, since the sum of the interior angles of a triangle add up to 180 degrees. Therefore, all three angles of the two triangles are equal, which is a proof of similarity. [tex]\implies \boxed{\triangle FED\sim \triangle JEH}[/tex]
9514 1404 393
Answer:
ΔDEF ~ ΔHEJ
Step-by-step explanation:
The vertical angles at E are congruent, and the marked angles at F and J are congruent. The two triangles are similar by the AA postulate.
The given portion of the similarity statement names the angles in the order "unspecified", "vertical", and "50°". If we name those angles in the same order in the other triangle, the similarity statement becomes ...
ΔDEF ~ ΔHEJ
Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of 1/3
O y + 2 =1/3(x + 3)
O y-2=1/3(x-3)
O y + 3 = 1/3(x+ 2)
O y-3= 1/3(x-2)
Answer:
y - 2 = 1/3(x - 3)
Step-by-step explanation:
Point slope form is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.
Plug in the slope:
y - y1 = m(x - x1)
y - y1 = 1/3(x - x1)
Plug in the given point:
y - y1 = 1/3(x - x1)
y - 2 = 1/3(x - 3)
So, the correct answer is y - 2 = 1/3(x - 3)
which will result in a perfect square trimonial
Answer:
No choices listed.
Step-by-step explanation:
Write the equation and show work please
Answer:
y=-3x-5
Step-by-step explanation:
(-1, -2) (0, -5)
use slope formula
ΔY = (-5 – -2) = -3
ΔX = (0 – -1) = 1
m = -3
y=mx+b
-5 = -3(0)+b
b = -5
y=-3x-5
Determine the radius of a cone that has a volume of 155.521 cubic inches and a height of 9 inches.
Answer:The answer is 4.06
Step-by-step explanation:
Okay I am 98% sure my math could be wrong since I don’t know what the possible answers to the question are but this is what I got.
What is the common ratio for the geometric sequence below, written as a fraction?
768, 480, 300, 187.5, …
/
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Answer:
5/8
Step-by-step explanation:
Since the ratio is common, it can be found from the ratio of any pair of adjacent terms.
r = 480/768 = (5·96)/(8·96) = 5/8
The common ratio is 5/8.
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. y2(y2 − 4) = x2(x2 − 5) (0, −2) (devil's curve)
Answer:
Step-by-step explanation:
Given that:
[tex]y^2 (y^2-4) = x^2(x^2 -5)[/tex]
at point (0, -2)
[tex]\implies y^4 -4y^2 = x^4 -5x^2[/tex]
Taking the differential from the equation above with respect to x;
[tex]4y^3 \dfrac{dy}{dx}-8y \dfrac{dy}{dx}= 4x^3 -10x[/tex]
Collect like terms
[tex](4y^3 -8y)\dfrac{dy}{dx}= 4x^3 -10x[/tex]
[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]
Hence, the slope of the tangent line m can be said to be:
[tex]\dfrac{dy}{dx}= \dfrac{4x^3 -10x}{4y^3-8y}[/tex]
At point (0,-2)
[tex]\dfrac{dy}{dx}= \dfrac{4(0)^3 -10(0)}{4(-2)^3-8-(2)}[/tex]
[tex]\dfrac{dy}{dx}= \dfrac{0 -0}{4(-8)+16}[/tex]
[tex]\dfrac{dy}{dx}= 0[/tex]
m = 0
So, we now have the equation of the tangent line with slope m = 0 moving through the point (x, y) = (0, -2) to be:
(y - y₁ = m(x - x₁))
y + 2 = 0(x - 0)
y + 2 = 0
y = -2
f(x) = 3x + 10
х
f(x)
-3
-2
-1
-4
PLEASE HELP ME I HAVE TO PASS THIS TEST
30 POINTS
Answer:
Hi, there the answer is
These are the equations with exactly one solution
-5x + 12 = –12x – 12
-5x + 12 = 5x + 12
-5x + 12 = 5x – 5
Hope This Helps :)
Step-by-step explanation:
First degree equations
A first degree equation has the form
ax + b = 0
There are some special cases where the equation can have one, infinitely many or no solution
If , the equation has exactly one solution
If a=0 and b=0 the equation has infinitely many solutions, because it doesn't matter the value of x, it will always be true that 0=0
If a=0 and the equation has no solution, because it will be equivalent to b=0 and we are saying it's not true. No matter what x is, it's a false statement.
We have been given some equations, we only need to put them in standard form
-5x + 12 = –12x – 12
Rearranging
7x + 24 = 0
It has exactly one solution because a is not zero
.......................
-5x + 12 = 5x + 12
Rearranging
-10x + 0 = 0
It has exactly one solution because a is not zero
.......................
-5x + 12 = 5x – 5
Rearranging
-10x + 17 = 0
It has exactly one solution because a is not zero
.......................
-5x + 12 = -5x – 12
Rearranging
0x + 24 = 0
It has no solution, no matter what the value of x is, it's impossible that 24=0
Answer: These are the equations with exactly one solution
-5x + 12 = –12x – 12
-5x + 12 = 5x + 12
-5x + 12 = 5x – 5
I need help ASAP anyone
Answer:
90
Step-by-step explanation:
there is 6 sides of box
2 bigger and 4 smaller
area of bigger side is 5×5 = 25 this is the area of one side as we have 2 sides so are of both sides is 25 + 25 = 50
now come to the smaller sides ( we have 4 here)
are of one side is 2× 5 = 10
so are of all 4 sides is 10× 4 = 40
now we get area of 4 smaller sides and 2 bigger sides
total area of box is 40+ 50 = 90
hope you understand
2(x+3)=x-4
please help me <3
Which state ment is true regarding the graphed function
F(4)= g(4)
F(4)= g(-2)
F(2)= g(-2)
F(-2)= g(-2)
Answer:
F(-2)= g(-2)
Step-by-step explanation:
F(-2)= g(-2), both function have the same points of intersect.
What’s the value of X????
What is the value of z in the equation 3z+9=z?
Please help!!! Urgent ….
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Answer:
ΔWZT ~ ΔWXY
Step-by-step explanation:
Angle XWY and angle ZWT are vertical angles, so congruent.
The sides on either side of those angles are proportional:
WZ/WX = WT/WY
11/22 = 10/20 = 1/2
so, we can claim similarity by the SAS Theorem.
ΔWZT ~ ΔWXY
Bill can hit a bucket of 323 golf balls in 17 hours.
How many golf balls can Bill hit in 23 hours?
HELP plsssss I will GIVE YOU BRAINLYEST
Answer: B
Step-by-step explanation:
Answer:
-5ºC < 5ºC is an inequality that compares temperatures.
B is the correct answer for the multiple choice question.
Solve for X in the triangle. Round your answer to the nearest tenth
Answer:
[tex]\displaystyle x \approx 9.9[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityTrigonometry
[Right Triangles Only] SOHCAHTOA[Right Triangles Only] sinθ = opposite over hypotenuseStep-by-step explanation:
Step 1: Define
Identify variables
Angle θ = 64°
Opposite Leg = x
Hypotenuse = 11
Step 2: Solve for x
Substitute in variables [sine]: [tex]\displaystyle sin(64^\circ) = \frac{x}{11}[/tex][Multiplication Property of Equality] Multiply 11 on both sides: [tex]\displaystyle 11sin(64^\circ) = x[/tex]Rewrite: [tex]\displaystyle x = 11sin(64^\circ)[/tex]Evaluate: [tex]\displaystyle x = 9.88673[/tex]Round: [tex]\displaystyle x \approx 9.9[/tex]please help me find the area
Answer:
320 square feet.
Step-by-step explanation:
For the moment, let's put the square back in place. That would make the length 16 + 8 = 24 and the width 16.
L = 24
W = 16
Area = L * W
Area = 24 * 16
Area = 384
Now the next step is to take out the square. It is 8 * 8 = 64
The area of the figure = 384 - 64 = 320 square feet, and that's the answer.
Answer:
320 in^2
Step-by-step explanation:
we need to find the area of this figure
Firstly divide above picture in two parts
1st figure = (16*16)in.
2nd figure = (8*8)in.
Area of 1st figure = 16*16 = 256 in^2
Area of 2nd figure = 8*8 = 64 in^2
Area of whole figure = ( 256 + 64 )in^2
= 320 in^2
4x-1divide by 2=x+7
what is x
3. Two dice are rolled. What’s the conditional probability that both dice are 5’s if it’s known that the sum of points is divisible by 5?
Answer:
[tex]Pr =\frac{1}{3}[/tex]
Step-by-step explanation:
Given
[tex]S = \{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)[/tex]
[tex](3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)[/tex]
[tex](5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)\}[/tex] --- sample space
First, list out all outcomes whose sum is divisible by 5
[tex]A = \{(4,6), (5,5),(6,4)\}[/tex]
So, we have:
[tex]n(A) = 3[/tex]
Next, list out all outcomes that has an outcome of 5 in both rolls
[tex]B = \{(5,5)\}[/tex]
[tex]n(B) =1[/tex]
The required conditional probability is:
[tex]Pr =\frac{n(B)}{n(A)}[/tex]
[tex]Pr =\frac{1}{3}[/tex]
Complete the input-output table for the function y = 3x.
Input-Output table
Answer:
Y: 0, x:0
Y:1, x: 3
Y: 2, x: 6
Y: 3, x:9
Step-by-step explanation:
Plug in the x to get the y
simplify the expression (2r^4y4xy^2) completely
Step-by-step explanation:
we can simplify the stuff inside the parentheses to
[tex] \frac{ {x}^{3} }{2y} [/tex]
now we need to multiply it with itself, giving us
[tex] \frac{ {x}^{6} }{4 {y}^{2} } [/tex]
so yeah, D is the correct answer
