Find a solution to the following system of equations –5x + 2y = 9 3x + 5y = 7

Answer:

[tex](13)\ 1 <x < 15[/tex]

[tex](14)\ 6 <x < 18[/tex]

Step-by-step explanation:

Question 13:

[tex]a,b = 8,7[/tex] -- the two sides

Using triangle inequality theorem, we have:

[tex]a + b > x[/tex]

[tex]a + x > b[/tex]

[tex]x + b > a[/tex]

So, we have:

[tex]a + b > x[/tex]

[tex]8 + 7 > x[/tex]

This gives:

[tex]15 > x[/tex]

[tex]a + x > b[/tex]

[tex]8 + x > 7[/tex]

Collect and evaluate like terms

[tex]x > -1[/tex]

[tex]x + b > a[/tex]

[tex]x + 7 > 8[/tex]

Collect and evaluate like terms

[tex]x > 1[/tex]

Ignore the inequality with a negative value.

So, we have:

[tex]x > 1[/tex] and [tex]15 > x[/tex]

Rewrite as:

[tex]1< x[/tex] and [tex]x < 15[/tex]

Merge

[tex]1 <x < 15[/tex]

Question 14:

[tex]a,b = 12,6[/tex] -- the two sides

Using triangle inequality theorem, we have:

[tex]a + b > x[/tex]

[tex]a + x > b[/tex]

[tex]x + b > a[/tex]

So, we have:

[tex]a + b > x[/tex]

[tex]12 + 6 > x[/tex]

This gives:

[tex]18 > x[/tex]

[tex]a + x > b[/tex]

[tex]12 + x > 6[/tex]

Collect and evaluate like terms

[tex]x > -6[/tex]

[tex]x + b > a[/tex]

[tex]x + 6 > 12[/tex]

Collect and evaluate like terms

[tex]x > 6[/tex]

Ignore the inequality with a negative value.

So, we have:

[tex]x > 6[/tex] and [tex]18 > x[/tex]

Rewrite as:

[tex]6< x[/tex] and [tex]x < 18[/tex]

Merge

[tex]6 <x < 18[/tex]

Answer:

Scale model width = 12.5 yards

Step-by-step explanation:

Given:

Actual length of field = 120 yards

Actual width of field = 50 yards

Scale model length = 30 yards

FInd:

Scale model width

Computation:

Scale model width = [Scale model length / Actual length of field] Actual width of field

Scale model width = [30/120]50

Scale model width = [1/4]50

Scale model width = 0.25 x 50

Scale model width = 12.5 yards

(n! + (n + 1)!) / n! = n!/n! + (n + 1)!/n! = 1 + (n + 1) = n + 2

because (n + 1)! = (n + 1)n!.

Answer:

0.395

Step-by-step explanation:

We need to solve the given expression.

[tex]-\dfrac{3}{4}\times \dfrac{4}{5}-\dfrac{1}{2}\times\dfrac{1}{4}+\dfrac{4}{5}\times \dfrac{7}{5}[/tex]

We can also write it as :

[tex]-\dfrac{3}{4}\times \dfrac{4}{5}+\dfrac{4}{5}\times \dfrac{7}{5}-\dfrac{1}{2}\times\dfrac{1}{4}\\\\=\dfrac{4}{5}(\dfrac{-3}{4}+\dfrac{7}{5})-\dfrac{1}{2}\times\dfrac{1}{4}[/tex](Distributive property is used)

So,

[tex]=\dfrac{4}{5}\times \dfrac{13}{20}-\dfrac{1}{2}\times\dfrac{1}{4}\\\\=\dfrac{4}{5}\times \dfrac{13}{20}-\dfrac{1}{8}\\\\=\dfrac{13}{25}-\dfrac{1}{8}\\\\=0.395[/tex]

So, the value of the given expression is equal to 0.395.

The number of servings you can make is 6

The given parameters are:

Next, we convert oz to pounds

Content per serving = 8 * 0.0625 pound

This gives

Content per serving = 0.5 pound

The number of serving is then calculated as:

Number = Available/Content per serving

This gives

Number = 3/0.5

Evaluate

Number = 6

Hence, the number of servings is 6

Read more about proportions at:

https://brainly.com/question/1781657

#SPJ9

Answer:

that thing is not seeing properly and you can capture it again and resend it

Step-by-step explanation:

???????? what is easy??

Answer:

V = 133 cm³

Step-by-step explanation:

The formula for the volume of a cone is V = (πr²h) / 3, which is just the formula for the volume of a cylinder but divided by 3, by the way.

If the diameter is 6, divide that by 2 to get a radius of 3 cm. The height and pi are already given.

V = ((3.14)(3)²(12)) / 3

V = (339.12) / 3

V = 113.04 cm³, or if rounded, it should just be 133 cm³

Answer:

113.0

Step-by-step explanation:

You have to round. Also its correct on Imagine Math.

Answer:

i dont  know tryna get points

Step-by-step explanation:

Answer: x= 112°, y = 34°

Step-by-step explanation:

"Angles formed by drawing lines from the ends of the diameter of a circle to its circumference form a right angle."

"The angle formed at the centre of the circle by lines originating from two points on the circle's circumference is double the angle formed on the circumference of the circle by lines originating from the same points."

x = 180° - 68° = 112°

y = 68 ÷ 2 = 34°

Circle theorems source: https://revisionmaths.com/gcse-maths-revision/shape-and-space/circle-theorems#:~:text=Angles%20formed%20by%20drawing%20lines%20from%20the%20ends,the%20point%20on%20the%20circumference%20our%20triangle%20touches.

Step-by-step explanation:

log 25 + log 8 = log (25 × 8) = log 200

log 200 - log 2 = log (200 ÷ 2) = log 100

logarithm base 10 of 100 is 2.

Answer:

4/3 =a

Step-by-step explanation:

10 − 3(2a − 1) = 3a + 1

Distribute

10 -6a +3 = 3a+1

Combine like terms

13 -6a = 3a+1

Add 6a to each side

13-6a+6a = 3a+6a +1

13 = 9a+1

Subtract 1 from each side

13-1 = 9a+1-1

12 = 9a

Divide by 9

12/9 = 9a/9

4/3 =a

a = 4/3

10 - 3( 2a - 1 ) = 3a + 1

10 - 3 × 2a -3 × -1 = 3a + 1

10 - 6a + 3 = 3a + 1

10 + 3 - 6a = 3a + 1

13 - 6a = 3a + 1

13 - 6a - 3a = 3a - 3a + 1

13 - 9a = 1

13 - 13 - 9a = 1 - 13

- 9a = - 12

-9a / - 9 = - 12 / - 9

a = 4/3

Answer: the second one

Step-by-step explanation:

Answer:

The asnwer is D

Step-by-step explanation:

D is a proportional relationship because

-3*-4 is 12

-6*-4 is 24

-9*-4 is 36

Hope this helps! :)

Answer:

14/3

Step-by-step explanation:

4 and 2/3 = 4 2/3 = 4 + 2/3 = 4/1 + 2/3 = 12/3 + 2/3 = 14/3

the sum of interior angle is 180:

[tex]x + 160 = 180 \\ x = 180 - 160 \\ x = 20[/tex]

Answer:

x = 3

Step-by-step explanation:

Step-by-step explanation:

3(8x-8)/2=64

3(8x-8)=64×2

24x-24=128

24x=128+24

24x=152

24x/24=152/24

x=6.3

Answer:

Using the net below, find the surface area

of the pyramid.

sto

5 in

5 in.

Surface Area

=

[?] in?Step-by-step explanation:

Given:

In quadrilateral EFGH, [tex]FG\parallel EH,\angleE\cong \angle H,EF=4n-4,FG=3n+3, GH=2n+6[/tex]

To find:

The length of segment GH.

Solution:

Draw a figure according to the given information as shown below.

In quadrilateral EFGH, [tex]FG\parallel EH,\angleE\cong \angle H[/tex], it means the quadrilateral EFGH is an isosceles quadrilateral because base angles are equal.

Now, quadrilateral EFGH is an isosceles quadrilateral, so the sides EF and GH are equal.

[tex]EF=GH[/tex]

[tex]4n-4=2n+6[/tex]

[tex]4n-2n=4+6[/tex]

[tex]2n=10[/tex]

Divide both sides by 2.

[tex]n=\dfrac{10}{2}[/tex]

[tex]n=5[/tex]

Now,

[tex]GH=2n+6[/tex]

[tex]GH=2(5)+6[/tex]

[tex]GH=10+6[/tex]

[tex]GH=16[/tex]

Therefore, the correct option is C.

Answer:

the answer is C

Step-by-step explanation:

:]

The choose (C) 60

The measure of the angles of a triangle is 180, and this triangle is equilateral, so 180/3=60, each angle is 60°

Answer:

x = 2

Step-by-step explanation:

note that 4096 = [tex]8^{4}[/tex] , then

[tex]8^{2x}[/tex] = [tex]8^{4}[/tex]

Since bases on both sides are equal, both 8 , then equate the exponents

2x = 4 ( divide both sides by 2 )

x = 2

Answer:

x = 2

Step-by-step explanation:

[tex]8^{2x} = 4096[/tex]

Step 1 :- Write 4096 in the exponential form with the base of 8.

[tex]8^{2x} = 8^4 [/tex]

Step 2 :- Since the base of both equation is same , set the exponents equal.

2x = 4

Step 3 :- Divide both side by 2

[tex]{2x}{2} = \frac{4 }{2}[/tex]

x = 2

Answer:

Probably 10

Step-by-step explanation:

10/5=2

Answer:

-6 -b

Step-by-step explanation:

I have attached the explanation above. hopefully this will help you

Answer:

ones

Step-by-step explanation:

Given:

30-hour review course average a score of 620 on that exam.

70-hour review course average a score of 749.

To find:

The linear equation which fits this data, and use this equation to predict an average score for persons taking a 57-hour review course.

Solution:

Let x be the number of hours of review course and y be the average score on that exam.

30-hour review course average a score of 620 on that exam. So, the linear function passes through the point (30,620).

70-hour review course average a score of 749. So, the linear function passes through the point (70,749).

The linear function passes through the points (30,620) and (70,749). So, the linear equation is:

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

[tex]y-620=\dfrac{749-620}{70-30}(x-30)[/tex]

[tex]y-620=\dfrac{129}{40}(x-30)[/tex]

[tex]y-620=\dfrac{129}{40}(x)-\dfrac{129}{40}(30)[/tex]

[tex]y-620=\dfrac{129}{40}(x)-\dfrac{387}{4}[/tex]

Adding 620 on both sides, we get

[tex]y=\dfrac{129}{40}x-\dfrac{387}{4}+620[/tex]

[tex]y=\dfrac{129}{40}x+\dfrac{2480-387}{4}[/tex]

[tex]y=\dfrac{129}{40}x+\dfrac{2093}{4}[/tex]

We need to find the y-value for [tex]x=57[/tex].

[tex]y=\dfrac{129}{40}(57)+\dfrac{2093}{4}[/tex]

[tex]y=183.825+523.25[/tex]

[tex]y=707.075[/tex]

[tex]y\approx 707.1[/tex]

Therefore, the required linear equation for the given situation is [tex]y=\dfrac{129}{40}x+\dfrac{2093}{4}[/tex] and the average score for persons taking a 57-hour review course is 707.1.

Answer:

110 marbles

side 14

Step-by-step explanation:

Draw triangles using marbles as the sides.

If the side is 2 marbles long, the triangle uses 3 marbles. 1 + 2 = 3

If the side is 3 marbles long, the triangle uses 6 marbles. 1 + 2 + 3 = 6

If the side is 4 marbles long, the triangle uses 10 marbles. 1 + 2 + 3 + 4 = 10

If the side is n marbles long, the triangle uses n(n + 1)/2 marbles.

These numbers are called triangular numbers.

We are looking for the side, n.

n(n + 1)/2 + 5 = (n + 1)(n + 2)/2 - 10

n^2 + n + 10 = n^2 + 3n + 2 - 20

n + 10 = 3n - 18

-n = -14

n = 14

For n = 14

n(n + 1)/2 =

= 14(15)/2

= 105

For n = 15

n(n + 1)/2 =

= 15(16)/2

= 120

105 + 5 = 120 - 10

You have 110 marbles. If you had 5 fewer, 105, you'd have a triangle with sides 14. If you had 10 more, 120, you'd have a triangle with sides 15. Since you have 110, you have 5 too many for side 14 and 10 too few for side 15.

The sides of the triangle is 14.

Answer:

y=43/2

Step-by-step explanation: