If we use the Gizmo to find the freezing, melting, and boiling points of water at 5,000 meters (16,404 feet) then,
Freezing point: 32 ºF (0ºC)
Melting point: 32 ºF (0ºC)
Boiling point: 203°F (95°C)
The freezing point is defined as the temperature at which a liquid becomes a solid. Increased pressure usually raises the freezing point with the melting point of the solid. The boiling point of a pure substance is defined as the temperature at which the substance transitions from a liquid to the gaseous phase. At the boiling point the vapor pressure of the liquid is equal to the applied pressure on the liquid. The melting point of a substance is defined as the temperature at which the substance changes from a solid to a liquid.
Melting occurs at a single temperature for the pure substances. The normal and average melting point and boiling point of water at 1 atmospheric pressure are 0°C and 100°C respectively. Decreasing the pressure under 1 atm. will lower the boiling point since the external pressure will be lower so it will become equal with the vapor pressure at a lower temperature.
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Consider the reaction between aqueous solutions of potassium hydroxide and chromium (III) chloride. Based on your balanced equation for this reaction, answer the following questions: 1) What are the spectator ions in this reaction? and 2) What is the formula for the precipitate formed in this reaction? 3) What is the sum of all the coefficients in the net ionic equation for this reaction? Net lonic Equati....pdf Hydrocarbon C....pdf
The net ionic equation for the given reaction is: 1 Cr3+(aq) + 3OH-(aq) → Cr(OH)3(s)
2. The formula for the precipitate formed in this reaction is Cr(OH)3.
3. The sum of all coefficients in the net ionic equation is 4.
Consider the reaction between aqueous solutions of potassium hydroxide and chromium (III) chloride. The balanced chemical equation for the given reaction is:KOH(aq) + CrCl3(aq) → KCl(aq) + Cr(OH)3(s)1) Spectator ionsThe ions that do not take part in the reaction are known as spectator ions.
These ions are present on both sides of the equation without undergoing any chemical changes.The ionic equation for the given reaction is:3K+(aq) + 3OH-(aq) + Cr3+(aq) + 3Cl-(aq) → 3K+(aq) + 3Cl-(aq) + Cr(OH)3(s)The spectator ions are K+ and Cl-.2)
PrecipitateThe precipitate is formed when the two reactants are combined together, and it can be identified from the ionic equation. In this reaction, the precipitate is formed when KOH is added to the aqueous solution of chromium(III) chloride.The formula for the precipitate formed in this reaction is Cr(OH)3.3) Sum of all coefficientsThe net ionic equation represents the actual chemical change occurring in the reaction.
The spectator ions are removed, and only the ions that participate in the reaction are shown. The net ionic equation for the given reaction is:Cr3+(aq) + 3OH-(aq) → Cr(OH)3(s)The sum of all coefficients in the net ionic equation is 4.
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When a mineral breaks along a weekly bonded plane it is called
Answer: Cleavage
Explanation:
When a mineral breaks along a weekly bonded plane it is called cleavage
use the trendline equation in fig6.2 to determine the kelvin temperature at which the pressure equals .72 atm
When the pressure is 0.72 atm, the temperature in Kelvin is 156 K.
To determine the Kelvin temperature when the pressure is 0.72 atm, you will need to use the trendline equation given in Fig 6.2. First, find the equation of the trendline by using the graph's two points, (300 K, 1 atm) and (500 K, 2 atm).
The equation for the trendline is:
y = mx + b
Where y is pressure, x is the temperature in Kelvin, m is the slope, and b is the y-intercept. We can find the slope of the trendline by using the two points provided in the graph:
Slope (m) = (y2 - y1) / (x2 - x1)
Slope = (2 atm - 1 atm) / (500 K - 300 K)
Slope = 0.005 atm/K
The equation for the trendline can now be written: y = 0.005x + b. To find the y-intercept, b, we can use one of the two points: Solving for b:
1 atm = 0.005(300 K) + bb = 1.5 atm
Now we can use the equation for the trendline to find the temperature (x) at which the pressure (y) equals 0.72 atm:
0.72 atm = 0.005x + 1.5 atm
0.72 atm - 1.5 atm = 0.005x
-0.78 atm = 0.005xx
= -0.78 atm / 0.005x
= 156K
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Using C2H4 + 3 O2 -> 2 CO2 + 2 H2O. If 20 moles of fuel are combusted in the above equation, how many moles of CO2 are produced?
Which of the following molecules is drawn in a conformation that has a proton and a leaving group anti-periplanar? H₂C, Br Ph. H CH3 Br H H₂C Br H₂C Ph H₂C CH3 H Ph H₂C, Br H Ph Save for Later CH3 CH3 CH3 CH3 CH3 Sul
The molecule that is drawn in a conformation that has a proton and a leaving group anti-periplanar is H₂C, Br.
The A, B, C, and D bond angles of a molecule are referred to as anti-periplanar, or antiperiplanar, in organic chemistry. The dihedral angles of the A–B and C–D bonds in this conformer are larger than +150° or less than 150°. In textbooks, the term "anti-periplanar" is frequently used to refer to a strictly anti-coplanar structure with a 180° AB CD dihedral angle. The anti-periplanar functional groups will be 180° apart from one another and in a staggered configuration in a Newman projection of the molecule.
Conformation is an essential factor in predicting reactivity in organic molecules. The anti-periplanar conformation of a molecule is one that occurs when two atoms in a molecule are in the same plane and are separated by 180 degrees. In this case, the proton and leaving group are placed in a perpendicular plane to the atoms directly in between them. This is the most stable conformer of the molecule. A significant factor in predicting reactivity in organic molecules is conformation. In this case, the molecule H₂C, Br is drawn in a conformation that has a proton and a leaving group anti-periplanar.
Therefore, the correct option is H₂C, Br.
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What kind of scientist would study the effects of acid rain on marble statues? A. A physicist B. A biologist C. A chemist D. An economist
Scientists would research the impacts of marble monuments and acid rain. A chemist. Hoping this is useful.
The correct answer is :C.
What are the substances that change the earth's surface?Surface sediments are transported and large stones are broken up through wind, water, and ice. Years are often needed for weathering, erosion, and deposition to cause noticeable changes. Nonetheless, certain things change the Planet's surface far more quickly than others. Extreme events, earthquakes, and volcanic eruptions are a few of them.
What adjustments to the Planet's surface may rain makes?Weathering and erosion caused by water movement change the properties of the terrain. Regional wind patterns and climate are defined by several interactions, including the role of the ocean. The unique physical and chemical properties of water have a profound effect on the planet's dynamics.
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Identify each of the following orbitals, and determine the n and quantum numbers. Explain your answers.
(a) one radial node the Number of radial nodes = n - l - 1
And number of angular nodes = l
n = 3 and l = 1
Orbital is 3p.
(b) It has zero angular node hence s-orbital and there is 1 radial node . 1 = n - 0 - 1 ; n = 2 and l = 0
The orbital is 2s.
(c) the shape of the orbital is that of dz². There is two angular nodes and there is no radial node.
n = 3 and l = 2
Hence the orbital is 3dz².
What is radial node?In atomic physics, a radial node is a point in space where the probability density of finding an electron in an atom is zero. It is a type of nodal plane that occurs in atomic orbitals, which are regions of space where electrons are most likely to be found.
Radial nodes occur in the radial distribution function of an atomic orbital, which describes the probability density of finding an electron at a given distance from the nucleus. The number of radial nodes in an atomic orbital is equal to n - l - 1, where n is the principal quantum number and l is the azimuthal quantum number.
Radial nodes represent regions of space where the radial wave function of the electron changes sign.
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match each substance correctly to the principal type(s) of intermolecular force(s) present, other than covalent bonding.
Substance intermolecular force
CH2OH ---> Hydrogen bonding
CH3F --> Dipole-dipole forces
C3H8 --> Dispersion forces
CaCL2 --> Ionic bonding
The intermolecular force present in CH2OH is hydrogen bonding. The intermolecular force present in CH3F is Dipole-dipole forces. Ionic bonding is defined as a type of chemical bonding that involves the electrostatic attraction between oppositely charged ions or between two atoms with sharply different electronegativities. It is the primary interaction occurring in ionic compounds. Hydrogen bonding results from the attractive force between a hydrogen atom covalently bonded to a very electronegative atom such as a N, O, or F atom and another very electronegative atom.
Dipole-dipole forces are defined as a attractive forces between the positive end of one polar molecule and the negative end of another polar molecule. Dispersion force is defined as a temporary attractive force that results when the electrons in two adjacent atoms occupy positions that make the atoms form temporary dipoles.
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The complete question is,
Match each substance correctly to the principal type(s) of intermolecular force(s) present, other than covalent bonding.
CH2OH Ionic bonding
CH3F Hydrogen bonding
C3H8 Dispersion forces
CaCL2 Dipole-dipole forces
