Fill in the blank and dropdown menus to form a true statement below.​

Answer:

1) 44  

a) 7 + 37

b) 3 + 41

c) 13 + 31

2) 36

a) 5 + 31

b) 7 + 29

c) 17 + 19

3) 24

a) 5 + 19

b) 7 + 17

c) 11 + 13

4) 18

a) 5 + 13

b) 7 + 11

Expressing the numbers as sum of two odd primes we have,

Prime numbers are numbers which are only divisible by 1 and itself.

Prime Numbers are: 2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,...

Odd numbers are numbers which are not divisible by 2.

Odd numbers are give by: 1,3,5,7,9,11,.....

2 is the only even number which is prime. So all prime numbers except 2 are odd numbers.

So odd prime numbers are given by: 3,5,7,11,13,17,19,23,29,31,37,41,43,47,....

Expressing the give numbers as the sum of odd prime numbers we get,

A) 44

41+3 = 44

37+7 = 44

31+13 = 44

B) 36

31+5 = 36

29+7 = 36

23+13 = 36

19+17 = 36

C) 24

19+5 = 24

17+7 = 24

13+11 = 24

D) 18

13+5 = 18

11+7 = 18

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Answer:

C. 2x

Step-by-step explanation:

Let

B's age = x years

A's age = 2 times older than B

= 2 * x

= 2x years

A's age = 2x years

For instance, if B's age is 17 years

Then,

A's age = 2x

= 2(17)

= 34 years old

Answer:

A

Step-by-step explanation:

Last year He was 7 years old.

His father is 4 times the age 7 x 4 = 28

Last year his dad was 28, so this year he is 29.

Combined age this year = 29 + 8 = 37

51 - 37 = 14 years

14/ 2 people = 7 years

8 + 7 = 15

29 + 7 = 36

15 + 36 = 51

It will take 7 years.

Given:

The expression is:

[tex]\dfrac{25x^2}{2x+6}\cdot \dfrac{2}{5x}[/tex]

To find:

The simple product.

Solution:

We have,

[tex]\dfrac{25x^2}{2x+6}\cdot \dfrac{2}{5x}[/tex]

It can be written as:

[tex]=\dfrac{5\times 5\times x\times x}{2(x+3)}\cdot \dfrac{2}{5x}[/tex]

Cancel out the common factors.

[tex]=\dfrac{5\times x}{x+3}[/tex]

[tex]=\dfrac{5x}{x+3}[/tex]

Therefore, the correct option is C.

Answer:

Step-by-step explanation:

Hope this Helps ;)

Answer:

15

Step-by-step explanation:

32-19 = 13 that have both

70-57= 13 that have both again from that sample

total number of people that have both : 13 + 13 = 26

11 kids don't have either one, so :

26-11 = 15

Answer:

2 × 10⁻⁶

Step-by-step explanation:

( 1 × 10⁻³ ) ÷ ( 5 × 10² )

→ Rewrite into normal form

0.001 ÷ 500

→ Simplify

2 × 10⁻⁶

Answer:

[tex]\frac{1}{500,000}=2*10^{-6}[/tex]

Step-by-step explanation:

[tex]\frac{1*10^{-3} }{5*10^{2} } =\frac{1}{5} *10^{-3-2}=\frac{1}{5} *10^{-5} = 500,000^{-1}= \frac{1}{500,000} = 2*10^{-6}[/tex]

We have:

[tex]\frac{a^{x} }{a^{y} } = a^{x-y}[/tex]

In this case: [tex]\frac{10^{-3} }{10^{2} } = 10^{(-3)-2} =10^{-5} =\frac{1}{100,000}[/tex]

Answer:

usual number of yellow eggs = 12

Usual maximum = 21

Usual minimum = 3

Step-by-step explanation:

To solve this, we will use the expected value of a binomial probability.

The formula is;

E(X) = np

Where;

n is sample size

p is probability of success.

We are given;

n = 58

p = 21%

Thus;

usual number of yellow eggs in samples = np = 58 × 21% = 12.18 ≈ 12

From USL(Upper specification limit) and LSL(Lower specification limit) formula, we can find the maximum usual number and minimum usual number of eggs respectively.

Thus;

USL = n(p + 3√(p(1 - p)/n)

USL = 58(0.21 + 3√(0.21(1 - 0.21)/58)

USL = 21.48 ≈ 21

LSL = n(p - 3√(p(1 - p)/n)

LSL = 58(0.21 - 3√(0.21(1 - 0.21)/58)

LSL = 2.87 ≈ 3

Answer:

in neighbourhood q the total number of people in the nine families I higher than that in neighbourhood s because of we add up the number of people in the families in neighbourhood q we get a total of 35 yet we have a total of only 27 people in the nine families in neighbourhood s

hope that helps ❤

Answer:

H0 : The mean difference in strikes between pre and post strike is equal to 0

H1 : The mean difference in strikes between pre and post strike is not equal to 0

Step-by-step explanation:

The scenario described abibe meets the condition for a paired (dependent) sample t test as the same subject is involved in both the pre and post strike data. Therefore measurement from the strike(pre) must be paired with measurement from the strike(post) data.

For a paired test involving a single subject ; The mean difference in the two sample is 0 ; that is both are the same while the alternative negates the null by claiming that the mean difference is not equal to zero.

Answer:

LHS = (cosA+cosB)²+(sinA+sinB)²

= (cos²A+2cosAcosB+cos²B)+

(sin²A+2sinAsinB+sin²B)

/* By algebraic identity:

(x+y)² = x²+2xy+y² */

Rearranging the terms, we get

= (cos²A+sin²A)+(cos²B+sin²B)+2(cosAcosB+sinAsinB)

= 1+1+2cos(A-B)

________________________

we know that,

i) cos²x + sin²x = 1

ii) cosxcosy+sinxsiny = sin(x-y)

________________________

= 2+2cos(A-B)

= 2[1+cos(A-B)]

\boxed {1+cos\theta = 2cos^{2}\frac{\theta}{2}}

1+cosθ=2cos

2

2

θ

= 2\times 2cos^{2}\frac{(A-B)}{2}2×2cos

2

2

(A−B)

=4cos^{2}\frac{(A-B)}{2}4cos

2

2

(A−B)

=RHSRHS

Therefore,

(cosA+cosB)²+(sinA+sinB)²

=4cos^{2}\frac{(A-B)}{2}4cos

2

2

(A−B)

Answer:

70 x 47x = 3290

.

. . . . . . . . . . ........

Answer: 6x^3-35x^2+47x-12

Step-by-step explanation:

(2x-3)(x-4)(3x-1)

=(2x^2-11x+12)(3x-1)

=6x^3-35x^2+47x-12

Answer:

4 > [tex]-\frac{n}{4}[/tex]

-16 > n

Step-by-step explanation:

Greater than would mean that the "arrow" is not facing the number. It would mean it is larger than the other number. Also, you have to construct the other part of the inequality which would be [tex]-\frac{n}{4}[/tex].

4×4 > [tex]-\frac{n}{4}[/tex]×4

16 > -n

-16 > n

Answer:

= 16

Step-by-step explanation:

= 8 \div 2 . 4

= 16

Answer:

[tex]8\div \:2\left(2+2\right)[/tex]

[tex]=8\div \:2\cdot \:4[/tex]

[tex]=16[/tex]

OAmalOHopeO

Answer:

Step-by-step explanation:

7) PQ // RS,  RQ is transversal

x = 38 {Alternate interior angles are congruent}

In ΔPQR ,

x + y + ∠P  = 180   {Angle sum property of triangle}

38 + 90 + y = 180

  128 + y =  180

           y = 180 - 128

y = 52

9) Construct XY // AB

XY // AB  & AC is transversal

∠1 = ∠4     ---------(I)      {alternate interior angles are equal}

XY // AB  & BC is transversal

∠3 = ∠5     ---------(II)      {alternate interior angles are equal}

∠1 + ∠2 + ∠3 = 180   {straight line angles}

∠4 + ∠2 + ∠5 = 180    {From (I) & (II) }

Sum of three angles of triangle is 180.Hence proved.

Answer:

b)48 km/hr (12 km in .25 hrs)

c) avg speed: 60/3 = 20 km/hr

Step-by-step explanation:

a)

.5  18

.75 18

1      30

1.5   30

2     40

2.25  40

3        60

Answer:

12

Step-by-step explanation:

because line FB divides triangle f v w into two equal halves therefore line WP is equal to line PV which is equal to 12

The required value of the PV is 12 in triangle DEF where p is the incenter.

Point P is the incenter of ΔDEF. Point P is the point of concurrency of the angle bisector. PV to be determined.

The incenter of a triangle is the intersection point of the internal angle bisectors of the triangle. In additional expressions, it can be clarified as the point where the internal angle bisectors of the triangle and perpendicular distance from this point to any of the sides of triangle is the same.

Since in triangle FGH, P is the incenter and PW, PV,PX is perpendicular distance to the sides HF, GF and GH respectively.
From image,
PW = 12
So by the property of incenter, perpendicular distance from this point to any of the sides of triangle is the same.

PW = PV
PV = 12

Thus, the required value of the PV is 12 in triangle DEF where p is the incenter.

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Answer:

I have no clue sorry bro.

Answer:

100%_$40.80

? × _$38.76

Step-by-step explanation:

100%×$38.76÷$40.80=95%

Answer:

40.80

Step-by-step explanation:

Answer:

3/5

Step-by-step explanation:

cos A = adjacent side / hypotenuse in a right triangle

cos A = 24/40

Cos A = 6/10

cos A = 3/5

Given:

The expression is:

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}[/tex]

To find:

The correct form of the partial fraction decomposition for the given expression.

Solution:

We have,

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}[/tex]

By partial fraction decomposition, it can be written as:

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}=\dfrac{A}{x+1}+\dfrac{B}{(x+1)^2}+\dfrac{Cx+D}{x^2+7}[/tex]           ...(i)

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}=\dfrac{(x+1)^2(Cx+D)+(x+1)(x^2+7)A+(x^2+7)B}{(x+1)^2(x^2+7)}[/tex]

[tex]4x^3+3x^2=(x+1)^2(Cx+D)+(x+1)(x^2+7)A+(x^2+7)B[/tex]

[tex]4x^3+3x^2=x^3A+x^3C+x^2A+x^2B+2x^2C+x^2D+7xA+xC+2xD+7A+7B+D[/tex]

[tex]4x^3+3x^2=x^3(A+C)+x^2(A+B+2C+D)+x(7A+C+2D)+7A+7B+D[/tex]

On comparing both sides, we get

[tex]A+C=4[/tex]

[tex]A+B+2C+D=3[/tex]

[tex]7A+C+2D=0[/tex]

[tex]7A+7B+D=0[/tex]

On solving these equations, we get

[tex]A=\dfrac{23}{32},B=-\dfrac{1}{8},C=\dfrac{105}{32},D=-\dfrac{133}{32}[/tex]

Substituting these values in (i), we get

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}=\dfrac{\dfrac{23}{32}}{x+1}+\dfrac{-\dfrac{1}{8}}{(x+1)^2}+\dfrac{\dfrac{105}{32}x-\dfrac{133}{32}}{x^2+7}[/tex]

Therefore, the required partial fraction decomposition is:

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}=\dfrac{\dfrac{23}{32}}{x+1}+\dfrac{-\dfrac{1}{8}}{(x+1)^2}+\dfrac{\dfrac{105}{32}x-\dfrac{133}{32}}{x^2+7}[/tex]

Answer:

A on Edg

Step-by-step explanation:

got it right

Answer:

d. The APR helps compare loans with the same payback period, but with different monthly rates and different fees.

Step-by-step explanation:

A loan can be defined as an amount of money that is being borrowed from a lender and it is expected to be paid back at an agreed date with interest.

Generally, the financial institution such as a bank lending out the sum of money usually requires that borrower provides a collateral which would be taken over in the event that the borrower defaults (fails) in the repayment of the loan.

An annual percentage rate (APR) is an amount of money paid as interest by borrowers or earned on loans by lenders such as banks, expressed as a percentage of the amount borrowed or invested over a 12-month period i.e on an annual basis.

Generally, the annual percentage rate (APR) helps compare loans with the same payback period, but with different monthly rates and different fees.

Answer:

A- If you have good credit, you will get a higher APR

Step-by-step explanation:

Answer:

Step-by-step explanation:

So, yearly $2100 is paid, plus the 1.73% interest, so 1.73% interest is $2136.33every year interest stacks on itself so youll take 1.73% of the year 1 total with interest.  

Year 1 total: $2136.33

Year 2 total:$2173.29

Year 3 total:$2210.89

Year 4 total:$2249.14

Year 5 total:$2288.05

Total Paid After 5 years:$11057.70

Year 1 total interest:$36.33

Year 2 total interest:$36.96Year 3 total interest:$37.60Year 4 total interest:$38.25Year 5 total interest:$38.91

Total Interest paid after 5 years:$188.05

Answer:

His loss is 90

He sold it 1710

Step-by-step explanation:

1) 1800x5/100= 90

2) 1800-90=1710

Answer:

Step-by-step explanation:

CP = ₹1800

Loss  = 5%

[tex]SP =\frac{100-Loss}{100}*CP\\\\= \frac{100-5}{100}*1800\\\\=\frac{95}{100}*1800\\\\[/tex]

= ₹  1710

Loss = CP - SP

        = 1800 - 1710

        = ₹ 90

Answer:

9/10 or 90 %

Step-by-step explanation:

There are 54+27+5+4 total people = 90

The people with diploma is 54+27 = 81

P (diploma) = number with diploma / total

                  = 81/90

                  =9/10

                   90%