Fill in geometry proofs. ANGLES. ( I WILL GIVE BRAINLIEST! PLS HELP!)

refer to attachment

Answer:

d

Step-by-step explanation:

2x = x - 4

2x - x = - 4

x = - 4

________

Hope it helps ⚜

Answer:

x=-4

Step-by-step explanation:

2x=x-4

2x-x=-4

x=-4

Proof

2*(-4)=-4-4

-8=-8

Answer:

A. vertex, (3, 0); y-intercept 4.5

Step-by-step explanation:

Rewrite in vertex form and use this form to find the vertex  

( h , k ) . ( 3 , 0 )

To find the x-intercept, substitute in  0  for  y  and solve for  x . To find the y-intercept, substitute in  0  for  x  and solve for  y .

x-intercept(s):  

( 3 , 0 )

y-intercept(s):  

( 0 , 4.5 )

A student must answer at least 35 of the 40 homework assignments correctly to get an A.

Inequality is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are not equal.

To determine the fewest number of problems a student could answer correctly and still get an A, we need to set up an inequality that represents the condition for getting an A.

If Mr. Discrete determines the score by doubling the number of correct problems out of 50 and then adding the bonus, then the score for each student can be represented by the equation:

2x + 4% × 50 = 100, where x is the number of correct problems.

If the student needs to get an A, then the score must be at least 90. Therefore, we can set up the inequality:

2x + 4% × 50 ≥ 90

Substituting 4% for 0.04, we get:

2x + 0.0450 ≥ 90

Solving for x, we find:

x ≥ 35

Therefore, to receive an A, a student must complete at least 35 out of the 40 homework assignments.

Learn more about the inequalities here:

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Answer:

N = -44

Step-by-step explanation:

have a great day! :)

Answer:

n=44

Step-by-step explanation:

n/4=11/1

crossmultiply

n=4×11=44

Answer:

a.

Step-by-step explanation:

Answer:

A, B, E

Step-by-step explanation:

I just put the number of fiction books over the number of nonfiction books. Then I plugged it into a calculator and if the answer was the same as 15/22, then it was right!

2385/3498=15/22

3945/5786=15/22

2340/3588≠15/22

2480/3410≠15/22

4650/6820≠15/22

2310/3696=15/22

Answer:

decrease

Step-by-step explanation:

the percent change measures FROM the first value. A change from 50 to 75 is a change of 50% (25 is the difference between the two numbers, and 25 is 50% of 50). A change from 75 to 50 is a change of -33.3% (25 is still the difference between the two. 25 is 33.3% of 75

Answer: What do you mean? if you till me i can help you

Step-by-step explanation:

Answer:

try y = 3x + -6 it might be wrong tho

Step-by-step explanation:

slope intercept form is y = mx + b where m = the slope and b = the y intercept. the y intercept is -6 and the slope is 3/1 or 3 so just plug the numbers in

Answer:

$56.10

Step-by-step explanation:

The first step is to multiply the values.

28.50 for large.

27.60 for small.

Add them together.

You get 56.10.

Answer/Step-by-step explanation:

Given:

$5.70= Large necklace

$4.60 = Small necklace

To Find:

How much will Kevin earn from selling 5 large necklaces and 6 small necklace?

Solution:

To Find how much Kevin will earn from selling 5 large necklaces/6 Small necklace...

Multiply 5.70 by 5 and 4.60 by 6.

5.70 x 5 = 28.5

4.60 x 6 = 27.6

Hence, Kevin will earn $28.5 from selling 5 large necklaces and 27.6 from selling 6 small necklaces.

To Find all Kevin earn add both together = 56.10

Therefore Kevin earn $56.10 altogether.

Answer:

Quadratic

Step-by-step explanation:

Formula: ax^2+bx+c

If the two of you can wash 1 car in 6 minutes:

It will take you 10 minutes to wash the car alone

take your friend 15 minutes to wash the car alone

Let the duration you can work be represented by y

Let the duration your friend can work be represented by x

You can wash a car 1.5 times as fast as your friend

That is, y = 1.5x

Working together, the two of you can wash 1 car in 6 minutes

This can be represented by the equation

[tex]\frac{1}{x}+\frac{1}{y} = \frac{1}{6}[/tex]

Substitute x = 1.5y into the equation above

[tex]\frac{1}{1.5y}+\frac{1}{y} = \frac{1}{6}\\\\\frac{1+1.5}{1.5y} = \frac{1}{6}\\\\\frac{2.5}{1.5y} = \frac{1}{6}\\\\1.5y=2.5(6)\\\\1.5y=15\\\\y=\frac{15}{1.5} \\\\y=10[/tex]

It will take you 10 minutes to wash the car alone

Substitute y = 10 into x = 1.5y

x  =  1.5(10)

x  =  15 minutes

It will take your friend 15 minutes to wash the car alone

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Answer: First do 145 - 25, which is 120. Then do 120 ÷ 15 = 8. Therefore the slope intercept is y ÷ 15 = x. Their voyage will last 8 days.

Explanation: Brainliest please

Answer:

You would need the intial fee in dollars/cents

Expression:

c=initial fee

x=amount of miles

[tex]1.80x+c=12[/tex]

Step-by-step explanation:

You would need the intial fee in dollars/cents

Expression:

c=initial fee

x=amount of miles

[tex]1.80x+c=12[/tex]

Answer:

A. 23, 37.....

B. 26, 42......

Step-by-step explanation:

have a great day!

Answer:

if there are 2 negatives by each other it would become a postive so -5+8

Step-by-step explanation:

Answer:

-5+8

Step-by-step explanation:

minus a negative is equivalent to plus a positive

Answer:

40

Step-by-step explanation:

Answer:

40.20 luv:)

Step-by-step explanation:

Answer:

y=1/2x

Step-by-step explanation:

I first did point-slope form which is

y+1=1/2(x-2)

Then, I converted it into slope-intercept form which is

y=1/2x

Answer:

12 cups

Step-by-step explanation:

There are 48 hours in two days.

48 · 2 = 96 ( 2 being fluid ounces per hour )

96 ÷ 8 = 12 ( 8 being fl oz in each cup )

I hope that this helped!!!

Answer:

x  =  − 2

Step-by-step explanation:

Answer:

I have attached the answer below.

Step-by-step explanation:

The diagram which has red ink cannot take a perfect feeding path.

Hopefully this helps.

Answer:

21417500

Step-by-step explanation:

Calculate 50% of the given amount then 13% of result

50% of 329500000

= [tex]\frac{50}{100}[/tex] × 329500000

= 0.5 × 329500000

= 164750000

Then

13% of 164750000

= [tex]\frac{13}{100}[/tex] × 164750000

= 0.13 × 164750000

= 21417500

https://www.algebra.com/algebra/homework/Circles/Circles.faq.question.407869.html

Answer:

16.3x

17. 8y

18.x+y

I thing these are the answers of these equations

The expected gain or loss is an illustration of mean and expected values.

The expected total gain is 83 points

The given parameters are:

The probability of rolling a 6 in a fair die is 1/6.

The probability of not rolling a 6 in a fair die is 5/6.

So, the expected gain in each game is:

[tex]\mathbf{E(x) = 20 \times \frac 16 - 3 \times \frac 56}[/tex]

[tex]\mathbf{E(x) = \frac{20}6 - \frac{15}6}[/tex]

Take LCM

[tex]\mathbf{E(x) = \frac{5}6}[/tex]

[tex]\mathbf{E(x) = 0.83}[/tex]

The number of games is 100.

So, the expected gain is:

[tex]\mathbf{Gain = 100 \times 0.83}[/tex]

[tex]\mathbf{Gain = 83}[/tex]

Hence, the expected total gain is 83 points

Read more about expected value at:

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Transformation involves changing the form of the function

The transformation that is not performed is (a) vertical shift

The function is given as:

[tex]\mathbf{y = cot(x)}[/tex]

From the complete question, the transformed function is:

[tex]\mathbf{y=3cot[\frac 15(x+2)]}[/tex]

On y = cot(x); start by translating the function 2 units left.

The rule of this transformation is:

[tex]\mathbf{(x,y) \to (x +2,y)}[/tex]

So, we have:

[tex]\mathbf{y = cot(x + 2)}[/tex]

Next, stretch the function horizontally by a factor of 1/5

The rule of this transformation is:

[tex]\mathbf{(x,y) \to (\frac 15x,y)}[/tex]

So, we have:

[tex]\mathbf{y=cot[\frac 15(x+2)]}[/tex]

Lastly, stretch the function vertically by a factor of 3

The rule of this transformation is:

[tex]\mathbf{(x,y) \to (x,3y)}[/tex]

So, we have:

[tex]\mathbf{y=3cot[\frac 15(x+2)]}[/tex]

From the above transformations, we have:

Hence, the transformation that is not performed is (a) vertical shift

Read more about transformations at:

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Answer:

vertical shift

Step-by-step explanation:

edge

Answer: should be 86°, not sure.

Step-by-step explanation:

It looks like given matrices are supposed to be

[tex]\begin{array}{ccccccc}\begin{bmatrix}3&2\\2&3\end{bmatrix} & & \begin{bmatrix}1&-1\\2&-1\end{bmatrix} & & \begin{bmatrix}1&2&3\\0&2&3\\0&0&3\end{bmatrix} & & \begin{bmatrix}3&1&1\\1&3&1\\1&1&3\end{bmatrix}\end{array}[/tex]

You can find the eigenvalues of matrix A by solving for λ in the equation det(A - λI) = 0, where I is the identity matrix. We also have the following facts about eigenvalues:

• tr(A) = trace of A = sum of diagonal entries = sum of eigenvalues

• det(A) = determinant of A = product of eigenvalues

(a) The eigenvalues are λ₁ = 1 and λ₂ = 5, since

[tex]\mathrm{tr}\begin{bmatrix}3&2\\2&3\end{bmatrix} = 3 + 3 = 6[/tex]

[tex]\det\begin{bmatrix}3&2\\2&3\end{bmatrix} = 3^2-2^2 = 5[/tex]

and

λ₁ + λ₂ = 6   ⇒   λ₁ λ₂ = λ₁ (6 - λ₁) = 5

⇒   6 λ₁ - λ₁² = 5

⇒   λ₁² - 6 λ₁ + 5 = 0

⇒   (λ₁ - 5) (λ₁ - 1) = 0

⇒   λ₁ = 5 or λ₁ = 1

To find the corresponding eigenvectors, we solve for the vector v in Av = λv, or equivalently (A - λI) v = 0.

• For λ = 1, we have

[tex]\begin{bmatrix}3-1&2\\2&3-1\end{bmatrix}v = \begin{bmatrix}2&2\\2&2\end{bmatrix}v = 0[/tex]

With v = (v₁, v₂)ᵀ, this equation tells us that

2 v₁ + 2 v₂ = 0

so that if we choose v₁ = -1, then v₂ = 1. So Av = v for the eigenvector v = (-1, 1)ᵀ.

• For λ = 5, we would end up with

[tex]\begin{bmatrix}-2&2\\2&-2\end{bmatrix}v = 0[/tex]

and this tells us

-2 v₁ + 2 v₂ = 0

and it follows that v = (1, 1)ᵀ.

Then the decomposition of A into PDP⁻¹ is obtained with

[tex]P = \begin{bmatrix}-1 & 1 \\ 1 & 1\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}1 & 0 \\ 0 & 5\end{bmatrix}[/tex]

where the n-th column of P is the eigenvector associated with the eigenvalue in the n-th row/column of D.

(b) Consult part (a) for specific details. You would find that the eigenvalues are i and -i, as in i = √(-1). The corresponding eigenvectors are (1 + i, 2)ᵀ and (1 - i, 2)ᵀ, so that A = PDP⁻¹ if

[tex]P = \begin{bmatrix}1+i & 1-i\\2&2\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}i&0\\0&i\end{bmatrix}[/tex]

(c) For a 3×3 matrix, I'm not aware of any shortcuts like above, so we proceed as usual:

[tex]\det(A-\lambda I) = \det\begin{bmatrix}1-\lambda & 2 & 3 \\ 0 & 2-\lambda & 3 \\ 0 & 0 & 3-\lambda\end{bmatrix} = 0[/tex]

Since A - λI is upper-triangular, the determinant is exactly the product the entries on the diagonal:

det(A - λI) = (1 - λ) (2 - λ) (3 - λ) = 0

and it follows that the eigenvalues are λ₁ = 1, λ₂ = 2, and λ₃ = 3. Now solve for v = (v₁, v₂, v₃)ᵀ such that (A - λI) v = 0.

• For λ = 1,

[tex]\begin{bmatrix}0&2&3\\0&1&3\\0&0&2\end{bmatrix}v = 0[/tex]

tells us we can freely choose v₁ = 1, while the other components must be v₂ = v₃ = 0. Then v = (1, 0, 0)ᵀ.

• For λ = 2,

[tex]\begin{bmatrix}-1&2&3\\0&0&3\\0&0&1\end{bmatrix}v = 0[/tex]

tells us we need to fix v₃ = 0. Then -v₁ + 2 v₂ = 0, so we can choose, say, v₂ = 1 and v₁ = 2. Then v = (2, 1, 0)ᵀ.

• For λ = 3,

[tex]\begin{bmatrix}-2&2&3\\0&-1&3\\0&0&0\end{bmatrix}v = 0[/tex]

tells us if we choose v₃ = 1, then it follows that v₂ = 3 and v₁ = 9/2. To make things neater, let's scale these components by a factor of 2, so that v = (9, 6, 2)ᵀ.

Then we have A = PDP⁻¹ for

[tex]P = \begin{bmatrix}1&2&9\\0&1&6\\0&0&2\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}1&0&0\\0&2&0\\0&0&3\end{bmatrix}[/tex]

(d) Consult part (c) for all the details. Or, we can observe that λ₁ = 2 is an eigenvalue, since subtracting 2I from A gives a matrix of only 1s and det(A - 2I) = 0. Then using the eigen-facts,

• tr(A) = 3 + 3 + 3 = 9 = 2 + λ₂ + λ₃   ⇒   λ₂ + λ₃ = 7

• det(A) = 20 = 2 λ₂ λ₃   ⇒   λ₂ λ₃ = 10

and we find λ₂ = 2 and λ₃ = 5.

I'll omit the details for finding the eigenvector associated with λ = 5; I ended up with v = (1, 1, 1)ᵀ.

• For λ = 2,

[tex]\begin{bmatrix}1&1&1\\1&1&1\\1&1&1\end{bmatrix}v = 0[/tex]

tells us that if we fix v₃ = 0, then v₁ + v₂ = 0, so that we can pick v₁ = 1 and v₂ = -1. So v = (1, -1, 0)ᵀ.

• For the repeated eigenvalue λ = 2, we find the generalized eigenvector such that (A - 2I)² v = 0.

[tex]\begin{bmatrix}1&1&1\\1&1&1\\1&1&1\end{bmatrix}^2 v = \begin{bmatrix}3&3&3\\3&3&3\\3&3&3\end{bmatrix}v = 0[/tex]

This time we fix v₂ = 0, so that 3 v₁ + 3 v₃ = 0, and we can pick v₁ = 1 and v₃ = -1. So v = (1, 0, -1)ᵀ.

Then A = PDP⁻¹ if

[tex]P = \begin{bmatrix}1 & 1 & 1 \\ 1 & -1 & 0 \\ 1 & 0 & -1\end{bmatrix}[/tex]

[tex]D = \begin{bmatrix}5&0&0\\0&2&0\\0&2&2\end{bmatrix}[/tex]