The distance the bus will go, if it is travelling at a rate of 50 km/hr for 3.8 hours is 190 kilometers (Option A)
How do I determine the distance the bus will go?We know that speed is defined as distance travelled per unit time i.e
Speed = Distance travelled / time
Cross multiply
Distance travelled = Speed × time
With the above formula, we can calculate the distance the bus will go. Details below:
Speed = 50 km/hr Time = 3.8 hoursDistance travelled =?Distance travelled = Speed × time
Distance travelled = 50 × 3.8
Distance travelled = 190 kilometers
Thus, we can conclude that the distance the bus will go is 190 kilometers (Option A)
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which of the following observations indicates that conditions on mars may have been suitable for life in the past?
Answer:
Liquid water one flowed on mars,the existence of nutrients,and the previous discovery of a past magnetic field that protected the planet from cosmic and solar radiation.
The elevator descends with an acceleration of 0.9 m/s². Find how much a 95 kg person weighs in it at the moment of descent.
If a cable originates inside one building and leaves the building, the landlord loses control of that cable. T or F?
It is true to say that If a cable originates inside one building and leaves the building, the landlord loses control of that cable.
Cable originating from one building to another building will have total control by the landlord from which the cable have passed. Since cable passes from one building to another building in that case some part of cable is not inside the building due to that control over the cable is distributed between more than one type of landlords .Worms can be spread through means other than direct network .Now, when it passed between the two building, in that case if one landlord did some changes in some part of cable then that change will not be controlled by the landlord who live in other building.
Hence, given statement is true.
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The linear density of a string is 1.6 10-4 kg/m. A transverse wave on the string is described by the equation y = (0.021 m) sin[(2.7 m-1)x + (20 s-1)t].what is the wave speed?what is the tension in the string?
The required wave speed and tension in the string are 15 m/s , 0.036 N respectively.
What is speed?Speed is characterized as. The pace of progress of position of an item toward any path. Speed is estimated as the proportion of distance to the time in which the distance was covered. Speed is a scalar amount as it has just course and no extent.
According to question:(a) The wave speed is given by v=λ/T=ω/k,
where λ is the frequency, T is the period ω is the precise recurrence (2π/T), and k is the rakish wave number(2π/λ).
The displacement has the structure y=y sin(kx+ωt), so 4k=2.0m
furthermore, ω=30 rad/s.
Hence v=(30 rad/s)/(2.0m)=15 m/s.
b) Since the wave speed is given by v= τ/μ
, where τ is the pressure in the string and μ is the straight mass thickness of the string, the strain is
τ=μv =(1.6×10 kg/m)(15 m/s) =0.036 N.
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one of the strongest emission lines observed from distant galaxies comes from hydrogen and has a wavelength of 122 nm (in the ultraviolet region).
(a) The galaxy moves with a velocity of 0.8 c away from us.
(b) When the galaxy moves towards us we observed that the wavelength of the line is 40.67 nm.
We know that,
The relativistic Doppler effect when the galaxy is moving away from us
In this case, when the source moves away from the observer its frequency ([tex]f[/tex]) is lower than the emitted frequency ([tex]f_{0}[/tex]) and the preceding wavelength ([tex]\lambda[/tex]) is higher than the emitted wavelength ([tex]\lambda_{0}[/tex]).
[tex]f=f_{0} \sqrt{\frac{1-\frac{u}{c} }{1+\frac{u}{c} } }[/tex]
[tex](\frac{\lambda_{0} }{\lambda})^{2} = \sqrt{\frac{c-u}{c+u} }[/tex]
Given that
[tex]\lambda_{0} =122 nm\lambda=366nm[/tex]
So
[tex](\frac{122}{366} )^{2} =\frac{c-u}{c+u} \frac{1}{9} = 8cu=0.8c[/tex]
Where c is the velocity of light it is equal to [tex]3*10^{8} m/s[/tex].
So when the galaxy moves towards us we observed that the wavelength of the line is 40.67nm.
(b) When the galaxy moves towards us its wavelength is shorter than the emitted wavelength.
The expression of the wavelength in this case is given by
[tex]\frac{\lambda _{0} }{\lambda } =\sqrt{\frac{c-u}{c+u} }[/tex]
= 40.67 nm
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after extinguishing a fire on the first floor of a two-story balloon-framed house, the best action for crews is to immediately open the walls and check for fire in the:
After extinguishing a fire on the first floor of a two-story balloon-framed house, the best action for crews is to immediately open the walls and check for fire in the basement, second floor, and attic.
The vertical struts of the outer wall are continuous from the foundation to the roof with a balloon frame structure. When the roof collapses into a structure, it can provide a watertight cover over a buried fire. Heavy wood is more stable than lightweight structures in fire conditions.
Marion of the building is surrounded by balloons, from the foundation to the eaves line he extends upwards more than two stories. A mansard or mansard roof is his four-sided gambrel-style hipped roof characterized by his two slopes on either side, the lower slope pierced with dormer windows and angled more steeply than the upper.
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An alien spaceship traveling at 0.550c toward the Earth launches a landing craft. The landing craft travels in the same direction with a speed of 0.790c relative to the mother ship (as measured by aliens on the mother ship). As measured on the Earth, the spaceship is 0.160 ly from the Earth when the landing craft is launched.
(a) What speed do the Earth-based observers measure for the approaching landing craft?
c
(b) What is the distance to the Earth at the moment of the landing craft's launch as measured by the aliens (mother ship)?
ly
(c) What travel time is required for the landing craft to reach the Earth as measured by the aliens on the mother ship?
yr
(d*) What travel time is required for the landing craft to reach the Earth as measured by Earth-based observers?
yr
(e*) What travel time is required for the landing craft to reach the Earth as measured by those on the landing craft?
yr
(a)The velocity (Xv) of the craft as measured from the earth is given as follows:
Vx = v¹x+v/1+( v¹x+v/c²) = 0.79∝ + 0.550c/1+(0.79c)(0.550c)
= Vx = 0.434c
Hence Vx is the velocity of the craft with respect to the mother ship and the velocity of the mother ship with respect to earth.
(b) distance between craft and earth, as measured by the mother ship as follows.
[tex]L0 = \sqrt[L]{\frac{1-V^{2} }{C^{2} } } = (0.160ly)\sqrt{1-(\frac{0.550}{c})^{2} }[/tex]
L0 = 0.1336ly.
(c)The velocity of craft with respect to earth as measured from the mother ship is as follows:
VCO = Vcmt + Vme
= 0.790 + 0.550 = 1.34c
Time taken by craft to land on earth as measured by the mother ship is as follows:
t = 0.1336ly/1.34 = 0.0997yr
(d) Time taken by craft to reach earth as measured from the earth is as follows:
t = 0.60ly/0.934c
t = 0.171yr
(e) Time taken by the craft to reach earth with respect to its rest frame is as follows:
to =[tex]\sqrt[t]{1-\frac{v^{2} }{c^{2} } }[/tex]
= 0.171 yr [tex]\sqrt{1-\frac{(0.934c)^{2} }{c^{2} } }[/tex]
to = 0.0610yr
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A 4kg blob of putty moving at 8 m/s slams into a 12 kg blob of putty at rest. What is the velocity of the two stuck- together blobs immediately after colliding?
The speed of the to stick together blobs immediately after colliding will be 2m/s.
How to solve?Given that:
Mass of first blob = 4kg = m1
Velocity of blob = 8m/s = v1
Mass of second blob = 12kg = m2
Velocity of blob = 0m/s = v2
To find:
Final velocity = Vf
Formula to be use:
(m1*v1) + (m2*V2) = Vf(m1 + m2)
(4*8) + (12*0) = Vf(4+12)
32 + 0 = Vf(16)
32 = Vf(16)
Vf = 2m/s
So the speed of two blobs immediately after colliding = 2m/s
How do we arrive at the V1 and V2 equations for elastic collisions?V1: (m1-m2/m1+m2)
u1 + (2m2/m1+m2)
u2 V2: ( 2m1/m1+m2) u1 + (m2-m1/m1+m2) u2 Assume that mass 1 has an initial velocity of u1, a final velocity of v1, a mass 2 beginning velocity of u2, and a mass 2 final velocity of v2.
What in physics does m1v1 m2v2 mean?V1 stands for the volume of stock solution required to create the new solution. M1 = Stock solution concentration. The total volume of the solution is V2.
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dr. bronfman has administered her new 100-item test of abstract reasoning to a large sample of students. she is presently comparing their scores on the odd-numbered questions with those on the even-numbered questions in an effort to
Determine the test's reliability. Test-retest reliability is a metric of dependability that is acquired by giving the same test to a set of people twice over time.
How long should reliability tests be repeated?Although the ideal testing interval will vary depending on the construct being assessed, its stability over time, and the target population, several research have demonstrated that the target time of 2 weeks is the most frequently advised interval [15].
Interrater reliability between tests is it?The degree to which various raters and observers provide consistent estimates of the same occurrence is measured by inter-rater or inter-observer reliability. Test-Retest Reliability: Used to evaluate a measure's consistency across time.
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the gravitational force exerted on a solid object is 5.00 n. when the object is suspended from a spring scale and submerged in water, the scale reads 3.50 n (fig. p14.11). find the density of the object
Density of the object is 3333.33 kg/m³.
Density can be defined as the ratio of the mass of a body to its volume.
The SI unit of density is kg/m³.From Archimedes principle,
Rd = W/U = D/D'
Where Rd = relative density,
W = weight of the object in air,
U = upthrust in water,
D = Density of the object,
D' = Density of water.
W/U = D/D'
Density (D) of the solid can be calculated by the equation,
D = D'(W/U)
As we have,
W = 5.0 N,
U = 5.0 -3.5 = 1.5 N,
D' = 1000 kg/m³
Since U = lost in weight = weight in air - weight in water
D = 1000(5/1.5)
D = 3333.33 kg/m³
Thus the density of the solid object is 3333.33 kg/m³
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Two blocks with masses 3m and 4m are on a collision course with the same initial speeds v The block with mass 3m is traveling to the left, and the 4 block is traveling to the right. They undergo a head-on elastic collision and each bounces back, along the same line as it approached. Find the final speeds of the particles (Enter your answers in terms of the initial speed of each mass.) Vam X Apply the final velocity equations for elastic collisions: mi 2m2 11+ 22 m, m2 + 2m m + mm Note that il- lvl = v. Be careful of your signs! Vam
The final velocity equations for elastic collisions is
[tex]$\begin{aligned}& u_1=\frac{3}{2} v_i \\& u_2=\frac{1}{2} v_i\end{aligned}$$[/tex]
A collision between two bodies in physics is referred to as an elastic collision if their combined kinetic energy stays constant. There is no net conversion of kinetic energy into other forms, such as heat, noise, or potential energy, in an ideal, fully elastic collision.
Lat their final speeds of bouncing back are u_1 and u_2 As the collision is clastic, e=1So,u_1+u_2=v_i+v_i=2 v_i
From momentum conservation, 3 m v_i-4 m v_i=4 m u_2-3 m u_1
[tex]$$\begin{aligned}& \Rightarrow \quad-2 v_i=4 u_2-3 u_1 \\& \Rightarrow 3 u_1-5 u_2=2 v_i-\text { (2) }\end{aligned}$$[/tex]
From (1) and (2),
[tex]$$\begin{aligned}u_1+u_2 & =3 u_1-5 u_2 \\\Rightarrow 2 u_1 & =6 u_2 \Rightarrow u_1=3 u_2\end{aligned}$$[/tex]
From (1),
[tex]$3 u_2+u_2=2 v_i$[/tex]
[tex]$$\text { and } \begin{aligned}\Rightarrow u_2 & =\frac{1}{2} v_i \\u_1 & =3 u_2=\frac{3}{2} v_i .\end{aligned}$$[/tex]
So,
[tex]$$\begin{aligned}& u_1=\frac{3}{2} v_i \\& u_2=\frac{1}{2} v_i\end{aligned}[/tex]
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landings at the top and bottom of stairs should be at least equal in length to the of the stairway.
In cases when the stairway is straight, the width of the landing in the direction of travel must at least match the stair's width and cannot be greater than 1219mm.
The four main axes are north, south, east, and west. A map is a representation or drawing of the entire or a portion of the surface of the earth done to scale and on a flat surface. A spherical shape, however, cannot be totally flattened. Distance, direction, and symbol are the three elements that make up a map.
Most maps have an arrow with the letter "N" on them in the upper right-hand corner. North is indicated by this arrow's orientation. It is referred to as the north line. You can determine which direction is east, west, or south once you know which way is north. The four main axes are North, South, East, and West.
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An electromagnetic wave travelling in the x-direction has frequency of 2×10 14 Hz and electric field amplitude of 27 Vm −1. From the options given below, which one describes the magnetic field for this wave?
The magnetic field for this wave is
[tex]B(x, t)=(9*10^{-8}T )i sin[2\pi (1.5*10^{-8}x-2*10^{14}t )][/tex].
Electromagnetic Wave:
The oscillations between an electric field and a magnetic field produce waves known as electromagnetic waves or EM waves. In other words, magnetic and electric fields oscillate to form electromagnetic (EM) waves.
Given,
Frequency of the wave; [tex]f=[/tex] [tex]2*10^{14} Hz[/tex]
The amplitude of the Electric Field; [tex]E_{0} = 27 N/C[/tex]
We know that Maxwell's equation is given by,
[tex]\frac{E_{0} }{B_0} =c[/tex] .....................(1)
Where,
[tex]E_{0} =[/tex] The amplitude of the electric field
[tex]B_{0}=[/tex] The amplitude of the magnetic field
[tex]c=[/tex] The velocity of light = [tex]3*10^{8} N/m^{2}[/tex]
By solving equation (1), we get
[tex]B_{0} =\frac{27}{3*10^{8} }[/tex]
[tex]B_{0}=9*10^{-8}[/tex]
We know that,
Angular frequency; ω [tex]= 2\pi f[/tex]
The equation of the magnetic field can be given by
[tex]B_{0}sin(kx-\omega t) =B_{0}sin(2\pi (\frac{x}{\lambda}-ft ))[/tex]
[tex]B_{0}sin(kx-\omega t)=9*10^{-8} sin(2\pi (\frac{x}{\lambda}-2*10^{14} t))[/tex].
Hence,
The magnetic field for this wave is
[tex]B(x, t)=(9*10^{-8}T )i sin[2\pi (1.5*10^{-8}x-2*10^{14}t )][/tex].
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a concentration of 400 ppm is the safe soil lead concentration threshold. the scientist used method a and found the soil sample had a lead concentration of 1358 ppm. write a conclusion about the lead concentrations in this sample of soil. in your conclusion include one recommendation from the table.
The lead pollution can be remediated by the appllication of the approppiate reagents.
What is the recommendation?We know that we need to always consider the threshold concentration of pollution as we are looking at the safety of the environment
Now we are told that the safe concentration of the lead must not be more than 400 ppm. Above that concentration, the effects may be quiet fatal.
There should be spirited attempts to remediate the soil by the use different methods so that the soil can become good again for the growing of crops.
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the bitewing tab is a heavy paperboard tab or loop fitted around a periapical film or sensor and used to stabilize the receptor during exposure. (2) the periapical receptor is oriented in the bite loop so that the tab portion extends from the white side (tube side) of the film or sensor.
the bitewing tab is a heavy paperboard tab or loop fitted around a periapical film or sensor and used to stabilize the receptor during exposure. true
What is stabilize?
to stop changing and fix something, especially to prevent it from getting worse, or to induce something to stop changing and fix it: These drugs reduce blood pressure and calm your heart rate.
the periapical receptor is oriented in the bite loop so that the tab portion extends from the white side (tube side) of the film or sensor.True
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g draw shear force and bending moment diagrams of the below beam. make sure to include/show all necessary values on the diagrams and the way that you calculate them
The maximum absolute values of the shear and bending moment is 2P and 3Pₐ respectively.
(a) Diagram is shown in image.
From A to B:
+∑Fy = 0: V = -P
+∑M₁ = 0: M = -P
From B to C:
+∑Fy = 0:
-P-P-V = 0
⇒ V = -2P
+∑M₂ = 0:
Pₓ+P(x - a)+M =0
⇒ M = -2Pₓ + Pₐ
(b) The maximum bending moment occurs in a beam, when the shear force at the section is zero or changes the sign because at point of contra fixture the bending moment is zero.
Therefore
= |V|max = 2P
= |M|max = 3Pₐ
Thus, the maximum absolute values of the shear and beading moment is 2P and 3Pₐ.
-- The given question is incomplete, I answer the question in general according to my knowledge and the complete question is
"For the beam and loading shown, (a) draw the shear and bending-moment diagrams, (b) determine the maximum absolute values of the shear and bending moment." --
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In a series resonant LCR circuit, the voltage across R is 100 volts and R= 1Ω with C = 2μF. The resonant frequency ω is 200 rad/s. At resonance, the voltage across L is :A4×10 −3voltB2.5×10 −2voltC40 voltD2.5×10 5volt
In a series resonant LCR circuit, the voltage across R is 100 volts and R= 1Ω with C = 2μF. The resonant frequency ω is 200 rad/s. At resonance, the voltage across L is D) 2.5 × 10⁵ volt.
given that :
V = 100 v
R = 1Ω
ω = 200 rad/s
C = 2μF
ω² = 1 / LC
(200)² = 1/ L × 2 × 10⁶
L = 12.5 H
current = 100 A
now, at resonance ,
voltage across the L is equals to voltage across C
voltage across L = 100 × ( 1 / 200 × 2 × 10⁶)
voltage across L = 2.5 × 10⁵ volt.
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Consider a circuit where the input voltage source is connected in series with a capacitor, inductor and resistor. Which of the following statements are true: a. Voltage across the inductor must be continuous c. Voltage across the resistor in this circuit must be continuous c. Current through the capacitor must be continuous d. None of the above
Consider a circuit where the input voltage source is connected in series with a capacitor, inductor and resistor. Which of the following statements are true (A) Voltage across the inductor must be continuous.
Due to the physical property of electric charge, charged material experiences a force when it is exposed to an electromagnetic field. You could be electrically positive or negative. While like charges repel one another, opposite charges attract.
Because the charge (Q) is constant and equal, the capacitor's value alone
V = Q /C
determines the voltage drop across the capacitor. Lower capacitance values will produce higher voltages, but bigger capacitance values will provide smaller voltage drops.
The voltage drop across a capacitor is correlated with its charge and is uncharged, as opposed to a resistor where the voltage drop is proportional to the initial current and there is an initial current.
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If a conductor is in electrostatic equilibrium near an electrical charge:A) The total charge on the conductor must be zero.B) The electric field inside the conductor must be zero.C) The charges on the conductor must be uniformly distributed.D) The sum of all forces between conductor and the electrical charge must be zero.
If a conductor is in electrostatic equilibrium near an electrical charge i.e. the correct option is, B) The electric field inside the conductor must be zero.
Because charge carriers can freely move within a conductor, when a charged or uncharged conductor is exposed to an external electric field, charge will flow until a steady state is reached, at which point the net flow of charge will cease. This state is known as electrostatic equilibrium. If the conductor is charged, the charges within it are rearranged, resulting in a zero net electric field inside the conductor. The net field inside the conductor again becomes zero if the conductor is polarized after being neutral.A neutral or charged conductor will typically achieve electrostatic equilibrium with a net zero electric field inside of it when it is kept close to an electric charge.The conductor in electrostatic equilibrium has characteristics such as a zero electric field inside and excess charges that are located on the surface. Therefore, the conductor's internal electric field must be zero.
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The __________ field of the earth is produced in part by the flow of hot liquid iron near the earth's core.
The magnetic field of the earth is produced in part by the flow of hot liquid iron near the earth's core.
What is a magnetic field?A magnetic field is defined as the field that is being created or produced by a magnetic material which permits the action of magnetic force.
The innermost part of the earth is made up of the earth core which is surrounded by an outer part.
The outer core of the earth is mostly made up of liquid iron and nickel.
Therefore, the magnetic field of the earth is produced in part by the flow of hot liquid iron near the earth's core.
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a person holds a book at rest a few feet above a table. the person then lowers the book at a slow constant speed and places it on the table. which of the following accurately describes the change in the total mechanical energy of the earth-book system?
The person exerts negative work on the book by applying a force in the direction opposite to its displacement, causing the total mechanical energy to decrease. Hence, option (D) is correct.
The given problem is based on the concept of mechanical energy. The mechanical energy is the energy of any object by virtue of its position or motion. And mathematically, it is expressed as the sum of kinetic energy and potential energy.
And the work completed is described as,
W = F * d
here,
W is the work done
F is the applied force
d is the displacement
The individual lowers the book in the provided situation at a slow manner. This means some work has been done by applying force in downward direction. This work will be negative, because it is opposite to the displacement. So, work done is negative.
And according to work energy concept,
Work done = Change in kinetic energy
Negative work accounts for negative value of kinetic energy. Which means kinetic energy is decreasing continuously. Additionally, if kinetic energy declines, mechanical energy will eventually follow.
The question is incomplete. The complete question is ' A. the total mechanical energy is unchanged, because there is no change in the book's kinetic energy as it is lowered to the table.
B. the total mechanical energy is unchanged, because no work is done on the earth-book system while the book is lowered.
C. the total mechanical energy decreases, because the person does positive work on the book by exerting a force that opposes the gravitational force.
D. The total mechanical energy decreases, because the person does negative work on the book by exerting a force on the book in the direction opposite to its displacement.'
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Question From what activity can you be sure that athletes find great utility?
Composing music
Raising children
Playing sports
Reading books
Playing sport is the activity in which you can be sure that athletes find great utility and is therefore denoted as option C.
Who is an Athlete?This is referred to a person who competes in one or more sports such as soccer, basketball etc that involve physical strength, speed, or endurance etc.
Therefore playing sports by an athlete will lead to an increase in utility as a result of them developing various skills and composure from it in the form of endurance, strength etc and various positions on the field which isn't applicable in reading books or composing music and is therefore the reason why it was chosen as the correct choice in this scenario.
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Explain how magnetic stripes on the ocean floor are evidence for sea-floor spreading
Answer:
When the Earth's magnetic field reverses, a new stripe, with the new polarity, begins. Such magnetic patterns led to recognition of the occurrence of sea-floor spreading, and they remain some of the strongest evidence for the theory of plate tectonics.
Explanation:
a converging lens with a focal length of 20 cm and a diverging lens with a focal length of -38 cm are 78.0 cm apart. a 2.7-cm-tall object is 40 cm in front of the converging lens.
The image height for a converging lens with a 20 cm focal length and a diverging lens with a 38 cm focal length that are 78.0 cm apart is 1.35 cm. 40 cm are in front of the converging lens
And a 2.7 cm tall object is there. An optical lens that converges all light rays travelling through it is known as a converging lens. A converging lens main function is to concentrate and converge the incoming light rays from an object to create an image. Depending on how close an object is to the lens, the image may be enlarged or unchanged.
h = (-di/do)(-di2/do2)*height
h = (-38/38)(-(-15))/30 (2.7)
h = -1.35 cm
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The complete question is-
a converging lens with a focal length of 20 cm and a diverging lens with a focal length of -38 cm are 78.0 cm apart. a 2.7-cm-tall object is 40 cm in front of the converging lens. Calculate the image height. Express your answer to two significant figures and include the appropriate units.
find the linear acceleration of the spool below (mass m, moment of inertia i) if it is rolling without slipping:
The linear acceleration of the spool below (mass m, moment of inertia i) if it is rolling without slipping: A spool of mass m and moment of inertia I (around its center) is free to roll without slipping on a table. It has an inner radius of r and an outer radius of R.
In mechanics, acceleration is the charge of the alternate velocity of an item with recognition of time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the internet pressure acting on that item.
Acceleration, is the price at which speed modifications with time, in terms of each pace and path. A point or an object transferring in an instant line is accelerated if it quickens or slows down. movement on a circle is multiplied although the rate is constant due to the fact the path is always converting.
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an automobile of mass m is proceeding around a highway curve of 40 meter radius. The surface of the roadway is horizontal, and the coefficient of friction between the tires and roadway is 0.50. The max speed with which the car can round the curve without slipping isa. 6.3 m/sb. 4.9 m/sc. 9.8 m/sd. 14.0 m/se. 19.6 m/s
The max speed with which the car can round the curve without slipping is 14 m/s
What is friction?
Friction is a force that develops when objects rub against one another. The ability of the tyre to "push" off the road and propel the vehicle is due to the frictional force between the road and tyre.
The radius of the curve,r = 40m
The coefficient of friction μ = 0.5
From the Newton's law, we have, μmg = mv^2/r
in terms of speed we get, v = √μrg
v = √(0.5)(40m)(9.8m/s^2)
= 14 m/s
Therefore the max speed with which the car can round the curve without slipping is 14 m/s
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Which em spectrum pass through our atmosphere most easily?
Visible light, gamma ray, infrared radiation, or radio waves??
Answer:
Gamma Ray but read below
Explanation:
All of the types of electromagnetic radiation listed can pass through Earth's atmosphere, although some types are absorbed or blocked more easily than others.
Visible light, infrared radiation, and radio waves are able to pass through the atmosphere relatively easily, while gamma rays are more likely to be absorbed.
This is because gamma rays have a higher energy than the other types of radiation, so they are more easily absorbed by the atoms and molecules in the atmosphere.
Answer:
Gamma Rays
Explanation:
It has the highest possible frequency lowest wavelength and the most energetic charge. Its travels at the speed of light and is highly penerative
this is a record of climate from 1880 and on with measures of land and ocean temperatures around the world increasing over time.
From the 1880s to the 1910s, the yearly average worldwide temperature was roughly 13.7 °C (56.7 °F). The temperature increased by around 0.1 °C (0.18 °F) per decade from the 1920s through the 1940s.
The average worldwide temperature then remained stable until the 1980s at about 14.0°C (57.2°F). The total land and ocean temperature has risen at an average pace of 0.14 degrees Fahrenheit (0.08 degrees Celsius) every decade since 1880, according to NOAA's 2021 Annual Climate Report; however, the average growth rate since 1981 (0.18°C / 0.32°F) has been more than double that rate. NASA utilizes the years 1951–1980 as a baseline to track changes in the earth's temperature. Since the start of modern recordkeeping in 1880, the last eight years have collectively been the warmest on record. The worldwide temperature record is comprised of these annual temperature measurements.
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Match the astronomical distance measuring techniques with their approximate ranges: Triangulation. distances up to about 1000 light years.
Spectroscopy. distances up to about 10,000 light years.
What is astronomical distance?Astronomical distance is the measurement of space between objects in the universe. It is usually measured in light years, which is the distance light travels in a year. Astronomical distance is incredibly vast and hard to comprehend, as it is measured in trillions of miles. Astronomical distance is used to measure distances between objects in the universe such as stars, galaxies, and planets. Astronomical distances are also used to measure the size of the universe, as well as the age of galaxies and stars. Astronomical distances can be measured using advanced instruments such as telescopes and spectroscopes. Astronomical distances are essential for understanding the structure of the universe and the evolution of galaxies and stars.
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One end of an object has a definite positive charge, which is an instance of _____ or a positive or negative state that reacts to an electric field.
One end of an object has a definite positive charge, which is an instance of inverse-square or a positive or negative state that reacts to an electric field.
A positive or negative energy is what?
A fundamental characteristic of some of the constituent particles, of which all matter is made, is electric charge.
Electric charges come in two different flavours.
(+) positive charges
adverse charge (-)
A negative charge is present when there are more electrons than protons in an item.
When an atom has more protons than electrons, it has a positive charge.
Protons have a positive charge, whereas electrons have a negative charge.
The coulomb is the unit of charge (C).
Similar charges repel one another.
Similar charges are drawn to one another.
The positive charge produces an electric flux.
The negative charge is the point where electric flux ends.
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