Factor 140c + 28 -14a to identify the equivalent expressions.

Answer:

I hope this helps. There is a link

b

So what is that distance well we know that to get to negative 4 pi over 3 we took negative pi and travelled pi over 3.. So this is just pi over 3.. So our reference angle would be pi over 3.

Step-by-step explanation:

Explanation:

Angles 4 and 8 are corresponding angles since they are both in the southwest corner of their respective 4 corner configuration.

Corresponding angles are congruent when we have parallel lines like this.

Set the expressions equal to each other and solve for x

angle 4 = angle 8

x+20 = 2x+5

x-2x = 5-20

-x = -15

x = 15

Use this x value to find the two angles to help confirm we have the correct x value, and to finish up to answer the question.

So that's why the answer is B) 35 degrees

Answer:

-9

Step-by-step explanation:

Answer:

-9

Step-by-step explanation:

-8 +___= - 17

___=-17 +8

___=-9

=-9

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]x=6[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Solving for 'x'...}}\\\\3x + 15 = 33\\--------------\\\rightarrow 3x + 15 - 15 = 33 - 15\\\\\rightarrow 3x = 18\\\\\rightarrow \frac{3x=18}{3}\\\\\rightarrow \boxed{x = 6}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

x=6

Step-by-step explanation:

3x+15=33

or as, 3x=33-15

or as, 3x=18

x=18/3=6

so we got 6 is the answer

Answer:

20.6 m

Step-by-step explanation:

Hi there!

Assuming that the utility pole makes a 90-degree angle with the ground, this scenario creates a right triangle.

The 45 m-long cable is the hypotenuse and the 40 m between the base of the pole and the cable is one of the legs.

We must solve for the height of the utility pole, which is essentially the other leg of the right triangle.

We can use the Pythagorean theorem: [tex]a^2+b^2=c^2[/tex] where a and b are the legs and c is the hypotenuse

Plug in the known information (leg=40, hyp=45)

[tex]40^2+b^2=45^2\\1600+b^2=2025\\b^2=2025-1600\\b^2=425\\b=20.6[/tex]

Therefore, when rounded to the nearest tenth, the height of the utility pole is 20.6 m.

I hope this helps!

Answer:

You can choose between 10 different choices.

Step-by-step explanation:

Given that a lunch menu consists of 2 types of tortillas and 5 different fillings, to determine how many choices are there for ordering a burrito with one filling, the following calculation must be performed:

2 x 5 = X

10 = X

Therefore, you can choose between 10 different choices.

Answer:

4a^2

Step-by-step explanation:

GCF of 12 and 32 is 4.

GCF of a^3 and a^2 is a^2.

Therefore, the answer is 4a^2.

Answer:

A

Step-by-step explanation:

This is because when you do a the answer states, multipliying the top by 2, makes the top equation 6x-6y=12. When you subtract the second from the first you get:

 6x - 6y = 12

- 6x + (-)9y = (-)3

Which results in -15y = 9.

This results in an eliminated variable from the start of the system of equation.

The steps that will eliminate a variable in this system are:

Multiply the first equation by 2.

Then subtract the second equation from the first.

The elimination method is the process of eliminating one of the variables in the system of linear equations using the addition or subtraction methods in conjunction with multiplication or division of coefficients of the variables.

[tex]3x - 3y = 6\\6x +9y = 3\\\\6x - 6y = 12\\6x +9y = 3\\\\15y = -9\\y = -3/5\\x= 2-3/5 = 7/5[/tex]

Learn more about method of elimination here

https://brainly.com/question/14619835

#SPJ2

Answer:

100

Step-by-step explanation:

5x4=20

20x5=100

Answer:

The weight of the package of chili powder is 181.44 g.

Step-by-step explanation:

Amount of chili powder = 4/10 pound

1 pound = 453.6 g

So,

4/10  pound = 4/10 x 453.6 = 181.44 g

The weight of the package of chili powder is 181.44 g.  

Step-by-step explanation:

hope it helps you...........

Answer:

Falso.

Step-by-step explanation:

Sea [tex]d = \frac{a}{b}[/tex] un número racional, donde [tex]a, b \in \mathbb{R}[/tex] y [tex]b \neq 0[/tex], su opuesto es un número real [tex]c = -\left(\frac{a}{b} \right)[/tex]. En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:

(a) El exponente es cero.

(b) El exponente es un negativo impar.

(c) El exponente es un negativo par.

(d) El exponente es un positivo impar.

(e) El exponente es un positivo par.

(a) El exponente es cero:

Toda potencia elevada a la cero es igual a uno. En consecuencia, [tex]c = d = 1[/tex]. La proposición es verdadera.

(b) El exponente es un negativo impar:

Considérese las siguientes expresiones:

[tex]d' = d^{-n}[/tex] y [tex]c' = c^{-n}[/tex]

Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:

[tex]d' = \left(\frac{a}{b} \right)^{-n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}[/tex]

[tex]d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]y [tex]c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{b}{a} \right)\right]^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = - \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' \neq c'[/tex], la proposición es falsa.

(c) El exponente es un negativo par.

Si [tex]n[/tex] es par, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' = c'[/tex], la proposición es verdadera.

(d) El exponente es un positivo impar.

Considérese las siguientes expresiones:

[tex]d' = d^{n}[/tex] y [tex]c' = c^{n}[/tex]

[tex]d' = \left(\frac{a}{b}\right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = - \left(\frac{a}{b} \right)^{n}[/tex]

(e) El exponente es un positivo par.

Considérese las siguientes expresiones:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es par, entonces [tex]d' = c'[/tex] y la proposición es verdadera.

Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.

Answer:

D

Step-by-step explanation:

dfjhygcftujnnbiijjhfsrfhhhuu

Answer:

204g + 48

Step-by-step explanation:

simplifying the expression

Answer:

See explanation

Step-by-step explanation:

Given:

5⁴/25 = 5²

25 = 5²

Then,

5⁴ / 25

= 5⁴/5²

Note:

• multiplication sign means addition in indices

• Division sign means subtraction in indices

Both numerator and denominator have the same base, so you'll pick one of the bases and subtract the powers

So,

5⁴/5²

= 5^(4 - 2)

= 5^(2)

= 5²

Therefore,

5⁴ / 25 = 5²

Answer:

D......................

Answer:

h=31.4 cm

Step-by-step explanation:

A=lateral surface area

c=circumference

h=height

A= c*h

solving for h we get:

h=A/c=120pi/12=10pi

Step-by-step explanation:

100*77+72/4

100*77+18

7700+18

7718

Answer:

Step-by-step explanation:

54 ×100=5400

5400+77=5477

5477÷2 = 2738.5

Answer:

x=13

y= -9

(13, -9)

Step-by-step explanation:

If we are solving using the substitution method, we can take the first equation and set it to y so y=4-x.

Then, we can take that equation and plug it into the bottom one so

3x+4(4-x)=3

Simplify:

3x+16-4x=3

-x=-13

x=13

We can then plug 13 into any of the two given equations (I am just going to plug it into the top one)

So, 13+y=4 which y= -9

Answer:

y = x + 4

Step-by-step explanation:

y = mx + b

y = 1x + b

5 = 1 + b

b = 4

y = x + 4

Answer:

-8

Step-by-step explanation:

Answer:

thomas is 25 years old

Step-by-step explanation:

ratio = 3:1

3+1=4

total age=100

Thomas age = 1/4 × 100 = 25

Answer:No

Step-by-step explanation:

Answer:

9. A. 2

Rectangle R:

Rectangle S:

Rectangle Area:

Rectangle R = L · W

Rectangle S = 2L · 2W = 2(L · W)

10.  A. (1, 3)

x + 2 = -2x + 5

x + 2x = 5 - 2

3x = 3

x = 1

y = x + 2 = 1 + 2 = 3

[tex]\displaystyle\bf \underbrace{19}_910{\underbrace{1}_9} \Longrightarrow This\: is \:an \:\:arithmetic\:\: progression[/tex]

Answer:

3 + 2k

Step-by-step explanation:

Given:

1/5(15 + 10k)

= (1/5 * 15) + (1/5 * 10k)

= (1 * 15)/5 + (1 * 10k)/5

= 15/5 + 10k/5

= 3 + 2k

Therefore,

1/5(15 + 10k) = 3 + 2k

The equivalent expression is 3 + 2k

Answer:

x^5+8x^4+17x^3-14x^2-84x-72

Step-by-step explanation:

( f ∘ g ) ( x ) is equivalent to f ( g ( x ) ) . We solve this problem just as we solve f ( x ) . But since it asks us to find out f ( g ( x ) ) , in f ( x ) , each time we encounter x, we replace it with g ( x ) . In the above problem, f ( x ) = x + 3 . Therefore, f ( g ( x ) ) = g ( x ) + 3 . ⇒ ( f ∘ g ) ( x ) = 2 x − 7 + 3 ⇒ ( f ∘ g ) ( x ) = 2 x − 4 Basically, write the g ( x ) equation where you see the x in the f ( x ) equation. f ∘ g ( x ) = ( g ( x ) ) + 3 Replace g ( x ) with the equation f ∘ g ( x ) = ( 2 x − 7 ) + 3 f ∘ g ( x ) = 2 x − 7 + 3 we just took away the parentheses f ∘ g ( x ) = 2 x − 4 Because the − 7 + 3 = 4 This is it g ∘ f ( x ) would be the other way around g ∘ f ( x ) = 2 ( x + 3 ) − 7 now you have to multiply what is inside parentheses by 2 because thats whats directly in front of them. g ∘ f ( x ) = 2 x + 6 − 7 Next, + 6 − 7 = − 1 g ∘ f ( x ) = 2 x − 1

Hello,

[tex]f(x)=7x-3\\g(x)=x^2\\\\(fog)(x)=g(f(x))=g(7x-3)=(7x-3)^2=49x^2-42x+9\\\\(gof)(x)=f(g(x))=f(x^2)=7x^2-3\\\\(fog)(0)=g(f(0))=49*0^2-42*0+9=9\\\\(gof)(0)=f(g(0))=7*0^2-3=-3\\[/tex]

Since i don't know what is (g°O(1)  and you haven't correct your question ,

i has put the 2 possibles answsers.