Express 0.02 as a percent.

Answer:

cost for adults=$8.29

cost for children=$6.47

cost for 2 adults and 4 children are =$(2×8.29)+(4×6.47)=$16.58+25.88=$42.46

Answer:

A.

Step-by-step explanation:

a strange question, as 2 answer options are actually possible, as they define valid domains for this function.

and if the range of the function would include imaginary numbers ("i"), all 4 would be correct.

the problem statement has to be much more precise. you can tell your teacher that.

but I assume, we base just on real numbers and want the biggest domain range. and that is A.

A. for x=1 we get sqrt(0) + 2, which is absolutely valid.

B. a square root of a negative number is undefined in the works of real numbers. we would need "i", the imaginary numbers, to make this a valid function.

C. is also valid. no bad values and expressions involved. it is just a snake range than A.

D. the same a for B.

The domain of the function [tex]f(x) = \sqrt{x - 1} + 2[/tex] is [tex][1,\infty)[/tex]

The function is given as:

[tex]f(x) = \sqrt{x - 1} + 2[/tex]

Set the radicand greater than or equal to 0

[tex]\sqrt{x - 1} \ge 0[/tex]

Take the square of both sides

[tex]x - 1 \ge 0[/tex]

Add 1 to both sides

[tex]x \ge 1[/tex]

This means the possible values of x starts from 1 till infinity

Hence, the domain of [tex]f(x) = \sqrt{x - 1} + 2[/tex] is [tex][1,\infty)[/tex]

Read more about domain at:

https://brainly.com/question/1770447

Answer: The instructor randomly selects one student to record for the group and another student to spy on the other groups.

[tex]\color{yellow}{}[/tex]

Answer:

use miss r sir hope I helped you

Answer:

[tex]y = 3x - 2[/tex]

Step-by-step explanation:

Required

The equation of the above linear function

From the table, we have:

[tex](x_1,y_1) = (1,1)[/tex]

[tex](x_2,y_2) = (2,4)[/tex]

Calculate slope (m)

[tex]m = \frac{y_2 -y_1}{x_2 -x_1}[/tex]

[tex]m = \frac{4 -1}{2 -1}[/tex]

[tex]m = \frac{3}{1}[/tex]

[tex]m =3[/tex]

The equation is:

[tex]y = m(x - x_1) + y_1[/tex]

So, we have:

[tex]y = 3(x - 1) + 1[/tex]

[tex]y = 3x - 3 + 1[/tex]

[tex]y = 3x - 2[/tex]

Answer:

A) BEM is an acute angle. B) MBX is an obtuse angle. C) XBE is a straight angle. D) XBE is an angle of vertex B. E) MBY is an angle of side [My). F) Another name for angle BER is REB. G. XBY and MBE are adjacent. EBY and XBM are supplementary angles.

Answer:

The 1st graph is the answer and matches

-x/2 + 2   -2  ≤ x < 2 because it is equal to -2

The 4th graph is incorrect slightly at = 2x - 3   x  ≥ 2

as  the graph is descending and shows x = -1/2 as the gradient 4/-2 = -1/2

m = -1/2 would be the equation.

Therefore 2 (-1/2) = -1 and  -1 - 3 = -4 and 4 is not  greater than 2 so is wrong/.

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Try it.

Answer:Its B or C

Step-by-step explanation:I expain it so A is wrong ebcause 3 times 20 is 60 and since x is 14 that measn 14 times 3 is 42 so 60 minus 42 is not 44 but 18.C is wrong becasue 2 times 14 is 28 and 2 times 3 is 6 so if u subract you get 22 and D is worng because 14 minus 3 isnt 22.

Answer:

The sum converges at: [tex]\frac{10}{3}[/tex]

Step-by-step explanation:

Given

[tex]\sum\limits^{\infty}_{n =2} \frac{8}{n^2 - 1}[/tex]

Express the denominator as difference of two squares

[tex]\sum\limits^{\infty}_{n =2} \frac{8}{(n - 1)(n+1)}[/tex]

Express 8 as 4 * 2

[tex]\sum\limits^{\infty}_{n =2} \frac{4 * 2}{(n - 1)(n+1)}[/tex]

Rewrite as:

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{2}{(n - 1)(n+1)}[/tex]

Express 2 as 1 + 1 + 0

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{1+1+0}{(n - 1)(n+1)}[/tex]

Express 0 as n - n

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{1+1+n - n}{(n - 1)(n+1)}[/tex]

Rewrite as:

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{(n + 1)-(n - 1)}{(n - 1)(n+1)}[/tex]

Split

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{(n + 1)}{(n - 1)(n+1)}-\frac{(n - 1)}{(n - 1)(n+1)}[/tex]

Cancel out like terms

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{1}{(n - 1)}-\frac{1}{(n+1)}[/tex]

In the above statement, we have:

[tex]a_3 + a_5 = 4[(\frac{1}{2} - \frac{1}{4}) + (\frac{1}{4} - \frac{1}{6})][/tex]

[tex]a_3 + a_5 = 4[(\frac{1}{2} - \frac{1}{6})][/tex]

Add [tex]a_7[/tex]

[tex]a_3 + a_5 + a_7= 4[(\frac{1}{2} - \frac{1}{6}) + (\frac{1}{7 - 1} - \frac{1}{7+1})][/tex]

[tex]a_3 + a_5 + a_7= 4[(\frac{1}{2} - \frac{1}{6}) + (\frac{1}{6} - \frac{1}{8})][/tex]

[tex]a_3 + a_5 + a_7= 4[(\frac{1}{2} - \frac{1}{8})][/tex]

Notice that the pattern follows:

[tex]a_3 + a_5 + a_7 + ...... + a_{k}= 4[(\frac{1}{2} - \frac{1}{k+1})][/tex]

The above represent the odd sums (say S1)

For the even sums, we have:

[tex]4 * \sum\limits^{\infty}_{n =2} \frac{1}{(n - 1)}-\frac{1}{(n+1)}[/tex]

In the above statement, we have:

[tex]a_4 + a_6 = 4[(\frac{1}{3} - \frac{1}{5}) + (\frac{1}{5} - \frac{1}{7})][/tex]

[tex]a_4 + a_6 = 4[(\frac{1}{3} - \frac{1}{7})][/tex]

Add [tex]a_8[/tex] to both sides

[tex]a_4 + a_6 +a_8 = 4[(\frac{1}{3} - \frac{1}{7}) + \frac{1}{7} - \frac{1}{9}][/tex]

[tex]a_4 + a_6 +a_8 = 4[\frac{1}{3} - \frac{1}{9}][/tex]

Notice that the pattern follows:

[tex]a_4 + a_6 + a_8 + ...... + a_{k}= 4[(\frac{1}{3} - \frac{1}{k+1})][/tex]

The above represent the even sums (say S2)

The total sum (S) is:

[tex]S = S_1 + S_2[/tex]

[tex]S =4[(\frac{1}{2} - \frac{1}{k+1})] + 4[(\frac{1}{3} - \frac{1}{k+1})][/tex]

Remove all k terms

[tex]S =4[(\frac{1}{2}] + 4[(\frac{1}{3}][/tex]

Open bracket

[tex]S =\frac{4}{2} + \frac{4}{3}[/tex]

[tex]S =\frac{12 + 8}{6}[/tex]

[tex]S =\frac{20}{6}[/tex]

[tex]S =\frac{10}{3}[/tex]

The sum converges at: [tex]\frac{10}{3}[/tex]

Answer:

Solution given:

a.

tn=12-n

1 st term =12-1=11

2nd term =12-2=10

3rd term=12-3=9

4th term=12-4=8

10th term=12-10=2

b.

tn=5-2n

1st term=5-2*1=3

2nd term=5-2*2=1

3rd term=5-2*3=-1

4th term=5-2*4=-3

10th term=5-2*10=-15

(a) Solution

T(n) = 12 - n

T(1) = 12 - 1 = 11

T(2) = 12 - 2 = 10

T(3) = 12 - 3 = 9

T(4) = 12 - 4 = 8

T(10) = 12 - 10 = 2

(b) Solution

T(n) = 5 - 2n

T(1) = 5 - 2 = 3

T(2) = 5 - 4 = 1

T(3) = 5 - 6 = -1

T(4) = 5 - 8 = -3

T(10) = 5 - 20 = -15

Answer:

10000 litres

Step-by-step explanation:

using proportion

if 7000 litres equals 42 minutes

then, x litres equals 60 minutes

x = (60×7000)÷ 42

x = 10000 litres

Answer:

450g coffee or 21.95$ coffee

Step-by-step explanation:

again, divide whichever pair you want to and you still have the same answer whether it is less or more: 450/250 is math would be 9/5 and 21.95/12.35 is 1.77732793522. so if we find the true value of 9/5, which is 1.8, and since it is more that the original price that means the more coffe you get, the cheaper it gets (basically all of life is like this), so the 450 g coffee is worth alot less than and is bigger than the 250 g coffee

I think the 4th one but Im not too sure please forgive me if I'm wrong.

Answer:

E

Step-by-step explanation:

45-165n

15(3-11n)

basically

45/15=3. 165/15=11

35 × 2/7 =

2 × 35 / 7 =

2 × 5 × 7 / 7 =

Simplify 7

2 × 5 =

10

Answer:

8

Step-by-step explanation:

8 is the correct answer

Answer:

12 2/3

Step-by-step explanation:

Answer:

1/2( x+16)

Step-by-step explanation:

1/2x + 8

Factor out 1/2

1/2*x + 1/2 *16

1/2( x+16)

Answer:

80

Step-by-step explanation:

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Answer:

[tex]f(20) =3.25[/tex]

Step-by-step explanation:

Given

[tex]f(m) = 1.25 + 0.10m[/tex]

Required

[tex]f(20)[/tex]

We have: [tex]f(m) = 1.25 + 0.10m[/tex]

Substutute 20 for m

[tex]f(20) =1.25 + 0.10*20[/tex]

[tex]f(20) =1.25 + 2[/tex]

[tex]f(20) =3.25[/tex]

Answer:

A = 0.25*j + 1

Step-by-step explanation:

The question presented here is an application of linear models. The $1 amount is fixed and does not depend on any factor such as the cups of orange juice sold.

Furthermore, we are informed that we earn $0.25 for every cup of orange juice sold. This means that we shall earn 0.25 j by selling  j cups of orange juice.

The variable total amount, A will thus depend on the fixed amount of $1 and the variable income 0.25 j.

The equation in two variables that will represent the total amount A (in dollars) you have after selling j cups of orange juice will thus be;

A = 0.25*j + 1

Hope this helped.....

Answer:

5 points huh thats mean

Step-by-step explanation:

the sum of two numbers that is 45 and their difference is 7 it is 39 and 6 more like 39+6

Answer:

[tex]n(A\ u\ B) = 10[/tex]

[tex]n(A'\ u\ C) = 10[/tex]

[tex]n(A\ n\ B)' = 6[/tex]

Step-by-step explanation:

Given

[tex]n(U) = 12[/tex]

[tex]n(A\ n\ B) =n(A\ n\ C) = n(B\ n\ C) =6[/tex]

[tex]n(A\ n\ B\ n\ C)=4[/tex]

[tex]n(A\ u\ B\ u\ C)=10[/tex]

Required

Solve a, b and c

There are several ways to solve this; the best is by using Venn diagram (see attachment for diagram)

Solving (a):

[tex]n(A\ u\ B)[/tex]

This is calculated as:

[tex]n(A\ u\ B) = n(A) + n(B) - n(A\ n\ B)[/tex]

From the attachment

[tex]n(A) = 0+2+4+2 = 8[/tex]

[tex]n(B) = 0+2+4+2 = 8[/tex]

[tex]n(A\ n\ B) = 4 +2 = 6[/tex]

So:

[tex]n(A\ u\ B) = 8 + 8 - 6[/tex]

[tex]n(A\ u\ B) = 10[/tex]

Solving (b):

[tex]n(A'\ u\ C)[/tex]

This is calculated as:

[tex]n(A'\ u\ C) = n(A') + n(C) -n(A'\ n\ C)[/tex]

From the attachment

[tex]n(A) = n(U) - n(A) = 12 - 8 = 4[/tex]

[tex]n(C) = 0+2+4+2 = 8[/tex]

[tex]n(A'\ n\ C) = 2[/tex]

So:

[tex]n(A'\ u\ C) = 4 + 8 - 2[/tex]

[tex]n(A'\ u\ C) = 10[/tex]

Solving (c):

[tex]n(A\ n\ B)'[/tex]

This is calculated as:

[tex]n(A\ n\ B)' = n(U) - n(A\ n\ B)[/tex]

[tex]n(A\ n\ B)' = 12- 6[/tex]

[tex]n(A\ n\ B)' = 6[/tex]

Answer:

4 serving cups

Step-by-step explanation:

Given

[tex]Serving\ cup = \frac{1}{6}[/tex]

[tex]Rice\ cup = \frac{2}{3}[/tex]

Required

The number of serving cup (n)

This is calculated by dividing the rice cup by the serving cup

[tex]n = \frac{Rice\ cup}{Serving\ cup}[/tex]

[tex]n = \frac{2/3}{1/6}[/tex]

Rewrite as:

[tex]n = \frac{2}{3} \div \frac{1}{6}[/tex]

Change to multiplication

[tex]n = \frac{2}{3} * \frac{6}{1}[/tex]

[tex]n = \frac{12}{3}[/tex]

[tex]n=4[/tex]

Answer:

sin∅ = 12/13

Step-by-step explanation:

use pythagorean theorem to find the missing side

a² + 5² = 13²

a² = 13² - 5²

a² = 169 - 25

a² = 144

a = 12

-----------------------------

Sin∅ = opp/hyp

sin∅ = 12/13

Answer:

Solution given:

19

<JKL=<KLS

20

FD=GD

9514 1404 393

Answer:

  19) ∠JKL ≅ ∠SLK

  20) FD ≅ GD

Step-by-step explanation:

It works well to identify the locations of the letters in the congruence statement, then use the letters in the same order from the other part of the congruence statement.

19) Letters JKL have the order 312 in the first part of the congruence statement ΔKLJ ≅ ....

The last part of the congruence statement is ... ≅ ΔLKS. The letters in order 312 from that part are SLK, so we want our angle congruence to read ...

  ∠JKL ≅ ∠SLK

__

20) The letters we're given (FD) are in positions 31 of the first part of the triangle congruence statement. The letters in those positions in the second part are GD, so our segment congruence is ...

  FD ≅ GD

Answer:

3179cm^3

Step-by-step explanation:

[tex]volum = height × width × length \\ = 17cm \times 17cm \times 11cm \\ = {3179cm}^{3} [/tex]

Answer:

16.8 [tex]m^{3}[/tex]

Step-by-step explanation:

Find your answer by using the formula of a cone (v= [tex]\frac{1}{3}[/tex]π[tex]r^{2}[/tex]h)

r= 2 (half of your diameter, which is 4)

h= 4

By inserting your radius and height, you get v= [tex]\frac{1}{3}[/tex]π([tex]2^{2}[/tex])4.

Put that into a calculator and you get 16.75516, which rounds to 16.8.

Answer:

55

Step-by-step explanation:

u + xy, for u = 20, x = 5, and y = 7

u + xy = 20 + 5 * 7 = 20 + 35 = 55

Step-by-step explanation:

hear is your please check attachment