Experts believe the rate of obesity (defined as having a BMI greater than 30) of adults in the United States is approximately 24.5%. A Gallup poll examined the rate of obesity in adults in the United States with a survey of 86,664 randomly sampled U.S. adults. Of the adults surveyed, 23,053 said that they were obese. Select the best description of the sample.

Answers

Answer 1

Answer:

86,664 randomly selected U. S Adults

Step-by-step explanation:

The sample is a subset of the population, that is a representative observation which is chosen from a larger population usually used in place of the population due to various reasons which may hamper the use of the entire population on a certain research project. Here, the population of interest is the entire U.S adult.

The subset of the population employed is the 86,664 randomly sampled US adults, this is called the sample as it representative of the population of interest.


Related Questions

Gillian swears her computations for the
following equations prove they do not
intersect. Her brother who just finished
learning about intersecting lines told her they
definitely intersect because the slopes are
different. Gillian remembered that logic from
class and then decided she needed to be able
to prove intersection by using algebra.
Although there are multiple strategies, how
might she prove intersection without graphing
of the following equations?
4x +3y = 6 and 6x + 2y = 10

Answers

Step-by-step explanation:

Given

Two lines are [tex]4x+3y=6[/tex] and [tex]6x+2y=10[/tex]

Two lines [tex]a_1x+b_1y=c_1[/tex] and [tex]a_2x+b_2y=c_2[/tex] will intersect when

[tex]\dfrac{a_1}{a_2}\neq \dfrac{b_1}{b_2}[/tex]

for the given lines

[tex]a_1=4,a_2=6,b_1=3,b_2=2[/tex]

[tex]\therefore \dfrac{4}{6}\neq \dfrac{3}{2}\\\\\dfrac{2}{3}\neq\dfrac{3}{2}[/tex]

Hence, lines are intersecting

116,02 LC)
Which of the triangles shown are obtuse triangles? (2 points)
A. Triangle A and Triangle B
B. Triangle B and Triangle D
C. Triangle C
D. Triangle A, Triangle B, and Triangle C

Answers

B. Triangle B and Triangle D
Triangle A has all equal sides and Triangle C is a right triangle.

Answer:

Trangle B and D

Step-by-step explanation:

They look more than 90 degrees

subtract 8x-8y+9 from 5x-8y-z

Answers

The answer is 3x+z+9 hope this helps

Chuck performed an experiment with a list of shapes. He randomly chose a shape from the list and recorded the results in the frequency table. The list of shapes and the frequency table are given below. Find the experimental probability of a parallelogram being chosen.

Answers

Answer:

1/6 (simplified)

Step-by-step explanation:

It's 3/18, but in most cases you should simplify unless it says to not.

Hello please help asap, thanks!

Answers

Answer:

Last image.

Step-by-step explanation:

So, we know that the orginal graph is of [tex]\sqrt[7]{x}[/tex]

We need to find the graph of [tex]-\sqrt[7]{x}-8[/tex]

First off, we see a negative in front of the root.

This means that all the values will be flipped across the x axis.

This removes the first two answer graphs, for they are of the postive root.

Next, we have a -8 following the root.

So, when another number is inside of the root(example: [tex]\sqrt[7]{x-6}[/tex]) You are going to add 6 to the x axis, basically shifting everything to the right(postive). If it was a postive 6 inside the root, we would move it left(negative)

This is not what is being done in our graph, I just wanted to explain this for future graphing.

Now, when a number is outside the root, such as the one above, then it shifts the y axis. In this case we have a -8 outside the root. This means that the graph will be shifted down(negative) by 8.

This eliminates the 3rd graph image, leaving the last graph answer shown below.

Hope this helps!

Find the 94th term of the arithmetic sequence -26, -37, -48

Answers

Answer:

-1049

Step-by-step explanation:

Let's assume it's a arithmetic sequence

a_1 = -26

d = a_2-a_1 = -11

==> a_94 = a_1+93*d = -1049

Answer:

-1071

Step-by-step explanation:

Let the common difference be 'd'.

d is 11

Find the difference from a (first term) and 11

Then use (n-1)

Which value cannot represent the probability of an event occurring

Answers

Answer:

zero

Step-by-step explanation:

everything is theoretically possible

solve for x please !URGENT!

Answers

Answer:

It is x=908.

Might be wrong tho so dont jump me

Answer: 908

Step-by-step explanation:

x/4 = 89 + 138

x/4 = 227

x = 227 x 4

x = 908

What is the measure of KPN?

Answers

Answer:

angle KPN=95 degree

Step-by-step explanation:

angle KPN = angle JPO (because they are vertically opposite angles)

Now,

angle JPO+angle LOP=180 degree(being co interior angles)

angle JPO + 85 =180

angle JPO =180-85

angle JPO =95

since angle JPO is equal to KPN ,angle KPN is 95 degree

a study is planned to compare the proportion of men who dislike anchovies with the proportion of women who dislike anchovies. the study seeks to determine if the proportions of men and women who dislike anchovies are different. a sample of 41 men was taken and the p^ estimate for the true proportion of men who dislike anchovies was determined to be 0.67. a sample of 56 women was also taken and the p^ estimate for the true proportion of women who dislike anchovies was determined to be 0.84. are the requirements satisfied to perform this hypothesis test

Answers

Answer:

d. No because n·(1 - [tex]\hat p[/tex]) = 8.96 is less than 10

Step-by-step explanation:

Question options;

a. Yes because the sample sizes of both groups are greater than 5

b. Yes, because in both cases n·[tex]\hat p[/tex] > 10

c. Yes, because we know that the population is evenly distributed

d. No, because the n·(1 - [tex]\hat p[/tex]) is less than 10

Explanation;

The given data are;

The number of men in the sample of men, n₁ = 41

The proportion of men who dislike anchovies, [tex]\hat p_1[/tex] = 0.67

The number of women in the sample of women, n₂ = 56

The proportion of men who dislike anchovies, [tex]\hat p_2[/tex] = 0.84

The assumptions for an analysis of the difference between means using a T-test are;

1) The data should be from a random sample of the population

2) The variables should be approximately normal (n·[tex]\hat p[/tex] ≥ 10, and n·(1 - [tex]\hat p[/tex]) ≥ 10)

3) The scale of the data is a continuous ordinance scale

4) The sample size should be large

5) The sample standard deviations should be approximately equal

From the requirement for normality, we have;

For the sample of men, n₁·[tex]\hat p[/tex]₁  = 41 × 0.67 = 24.47 > 10

n₁·(1 - [tex]\hat p[/tex]₁) = 41 × (1 - 0.67) = 13.53 > 10

For the sample of women, n₂·[tex]\hat p[/tex]₂  = 56 × 0.84 = 47.04 > 10

n₂·(1 - [tex]\hat p[/tex]₂) = 56 × (1 - 0.84) = 8.96 < 10

Therefore, the for n₂·(1 - [tex]\hat p[/tex]₂), the sample does not meet the requirement for normality

The correct option is d. No because n₂·(1 - [tex]\hat p[/tex]₂) = 8.96 is less than 10

What are the vertices of the resulting image A'B'C'D'E' after rotating the figure 90° about the origin? ty A 4 B 2. E D 0 0 N 4​

Answers

Answer:

A (5,4)

B (5,3)

C (6, 3)

D (2,0)

E (2,1)

Step-by-step explanation:

If the figure is rotated about the origin by 90 degrees, then the values of the co-ordinates of all the vertices will be as follows -

A (5,4)

B (5,3)

C (6, 3)

D (2,0)

E (2,1)

The total surface area of a cube is 433.5 cm2.
Find its volume.

Answers

Answer:

Step-by-step explanation:

The area of 1 face is s^2

The area of 6 faces is 6s^2

6s^2 = 433.5                 Divide by 6

s^2 = 433.5 / 6

s^2 = 72.25                   Take the square root of both sides

sqrt(s^2) = sqrt(72.25)

s = 8.5

Normally you would find the volume of parallelepiped by using L * W * H

Since L W and H are all equal in a cube, the volume = s^3

S^3 = 8.5^3 = 614.125

Peter gets 1 star for every 3 correct answers he gets on khan academy. What is the minimum number of correct answers Peter must enter if he wants to get 12 stars?

For full points you need to write an equation that uses a variable and division, show what work you did to solve it, and then give me a final answer.

Answers

Answer:

Peter needs to get 36 problems correct to get 12 stars

Step-by-step explanation:

for every 3 correct answers, Peter gets 1 star

1/3

if he wants 12 stars he will have to get 'x' amount of questions correctly

considering this is constant, 1/3 will have to equal 12/x

[tex]\frac{1}{3} = \frac{12}{x} \\\\1x = 36\\[/tex]

1x = x, so you don't need to do anything to 36

therefore the answer is that you need to get 36 problems correct to get 12 stars

The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room at a four-star hotel, beverages, breakfast, taxi fares, and incidental costs. Click on the datafile logo to reference the data. City Daily Living Cost ($) City Daily Living Cost ($) Bangkok 242.87 Mexico City 212.00 Bogota 260.93 Milan 284.08 Cairo 194.19 Mumbai 139.16 Dublin 260.76 Paris 436.72 Frankfurt 355.36 Rio de Janeiro 240.87 Hong Kong 346.32 Seoul 310.41 Johannesburg 165.37 Tel Aviv 223.73 Lima 250.08 Toronto 181.25 London 326.76 Warsaw 238.20 Madrid 283.56 Washington, D.C. 250.61 a. Compute the sample mean (to 2 decimals). b. Compute the sample standard deviation (to 2 decimals). c. Compute a confidence interval for the population standard deviation (to 2 decimals).

Answers

Answer:

[tex]\bar x = 260.1615[/tex]

[tex]\sigma = 70.69[/tex]

The confidence interval of standard deviation is: [tex]53.76[/tex] to [tex]103.25[/tex]

Step-by-step explanation:

Given

[tex]n =20[/tex]

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

[tex]\bar x = \frac{\sum x}{n}[/tex]

So, we have:

[tex]\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}[/tex]

[tex]\bar x = \frac{5203.23}{20}[/tex]

[tex]\bar x = 260.1615[/tex]

[tex]\bar x = 260.16[/tex]

Solving (b): The standard deviation

This is calculated as:

[tex]\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}[/tex]

[tex]\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}[/tex][tex]\sigma = \sqrt{\frac{94938.80}{19}}[/tex]

[tex]\sigma = \sqrt{4996.78}[/tex]

[tex]\sigma = 70.69[/tex] --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

[tex]c =0.95[/tex]

So:

[tex]\alpha = 1 -c[/tex]

[tex]\alpha = 1 -0.95[/tex]

[tex]\alpha = 0.05[/tex]

Calculate the degree of freedom (df)

[tex]df = n -1[/tex]

[tex]df = 20 -1[/tex]

[tex]df = 19[/tex]

Determine the critical value at row [tex]df = 19[/tex] and columns [tex]\frac{\alpha}{2}[/tex] and [tex]1 -\frac{\alpha}{2}[/tex]

So, we have:

[tex]X^2_{0.025} = 32.852[/tex] ---- at [tex]\frac{\alpha}{2}[/tex]

[tex]X^2_{0.975} = 8.907[/tex] --- at [tex]1 -\frac{\alpha}{2}[/tex]

So, the confidence interval of the standard deviation is:

[tex]\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} }[/tex] to [tex]\sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }[/tex]

[tex]70.69 * \sqrt{\frac{20 - 1}{32.852}[/tex] to [tex]70.69 * \sqrt{\frac{20 - 1}{8.907}[/tex]

[tex]70.69 * \sqrt{\frac{19}{32.852}[/tex] to [tex]70.69 * \sqrt{\frac{19}{8.907}[/tex]

[tex]53.76[/tex] to [tex]103.25[/tex]

Pedro y su socia Karina vendieron 520 calendarios en el mes de Diciembre. Pedro vendió 120 calendarios más que su socia. ¿Cuántos calendarios vendió cada uno?

Answers

Answer:

Pedro vendió = 320 calendarios

Katrina vendió = 200 calendarios

Step-by-step explanation:

Dejemos que el número de calendarios

Pedro vendió = x

Katrina vendió = y

Pedro y su compañera Karina vendieron 520 calendarios en diciembre.

x + y = 520 .... Ecuación 1

Pedro vendió 120 calendarios más que su socio.

x = y + 120

Sustituimos y + 120 por x

y + 120 + y = 520

2 años = 520 - 120

2 años = 400

y = 400/2

y = 200 calendarios

Resolviendo para x

x = y + 120

x = 200 + 120

x = 320 calendarios

Por lo tanto,

Pedro vendió = 320 calendarios

Katrina vendió = 200 calendarios

help solving inequalities true or false (middle school) first person to answer i’ll give brainliest please!!!

Answers

Answer:

aef true and bcd false

hope u get well in your exams

Step-by-step explanation:

Simplify the expression. 4^0

be careful i think this is a trick question

Answers

Answer:

1

Step-by-step explanation:

4^0

Any number raised to the 0 power is 1.

Answer:

1

Step-by-step explanation:

Anything raised to  0  is  1.

Ethan is installing a new tile backsplash in his kitchen. The tile he likes costs $3.50 per square foot. The area he is tiling is 36.5 square feet. How much will Ethan pay for the tile for his backsplash?

Answers

Answer:

$127.75

Step-by-step explanation:

Multiply the cost by the area to find the total cost

36.5*3.5= $127.75 .. you just had to multiply the total square feet and each tile cost to get the result! If this helps can I please have brainliest as I’m one point closer to moving to the next level..

y-(-4) =m(x-(-5)) solve for m

Answers

Answer:

m = [tex]\frac{y+4}{x+5}[/tex]

Step-by-step explanation:

y-(-4) = m(x-(-5))

Simplify, distribute the negative sign outside of the parenthesis, remember negative times negative equals positive

y + 4 = m (x + 5)

Inverse operations, divide the equation by the value inside of the parenthesis

[tex]\frac{y+4}{x+5}[/tex] = m

Answer:

m=y+4x/x+5 your welcome !!

help pls.preparing for my term exam
Jackie is making flower arrangements. She has 2 roses and 4 daisies. If Jackie
wants to make all the arrangements identical and have no flowers left over, what
is the greatest number of flower arrangements she can make?
pls help <3

Answers

Answer:

2

Step-by-step explanation:

she will have 2 arangments of one rose and two daisies.

Answer:

2

Step-by-step explanation:

group off the daisies and rose

2 Rose's

4 raises

in order to make it identical

group 1 consist of ( 1 rose and 2 daisies)

group 2 consist of (1 rose and 2 daises)

only 2 bouquets

Use the Distributive Property to expand
the expression:
2 (y + 5x - 3)

Answers

2y+10x-6, just distribute the 2!

From a stick 2y metres long, I cut a piece of length 4y centimetres. What fraction of the original stick remains?

Answers

Answer: [tex]\dfrac{49}{50}[/tex]

Step-by-step explanation:

Given

Length of the stick is [tex]2y\ m[/tex]

A piece of [tex]4y\ cm[/tex] is cut

We know, 1 m=100 cm

So, [tex]2y\ m[/tex] in cm is [tex]200y\ cm[/tex]

Remaining length after cut is

[tex]\Rightarrow 200y-4y=196y[/tex]

Fraction of length that is left after the cut is

[tex]\Rightarrow \dfrac{196y}{200y}\\\\\Rightarrow \dfrac{49}{50}[/tex]

Thus, [tex]\frac{49}{50}[/tex] fraction of original stick remains after cut

There are 5 red, 4 blue, and 3 green marbles in a bag. What are the odds of randomly pulling a blue marble out of the bag and then randomly pulling a green marble out of the bag? The blue marble is NOT replaced.

A - 7/2
B - 12/24
C - 1/12
D - 1/11

Answers

C -1/12 is the answer

The amount of ice cream dispensed from a machine at an ice cream shop is normally
distributed. If the machine is used 800 times in a day, how many times did the
machine dispense an amount that falls within three standard deviations from the
mean amount?
A 798
B 760
C 544
D 267

Answers

The answer is no one can answer me lol lol yeah I’m gonna be there for so the rest is

158.46

Max bought three items for $18.95 each and two items for $26.71 each. How much change would he get from $500 ?

Answers

Answer:

$389.73 in change

Step-by-step explanation

500-( (18.95 x 3)+(26.71 x 2) )=

500-(56.85+53.42)=

500-110.27=

389.73

Given csc(A) = 65/16 and that angle A is in Quadrant I, find the exact value of sec A in simplest radical form using a rational denominator . Someone please help me!

Answers

Answer:

[tex]secA = \frac{65}{63}[/tex]

Step-by-step explanation:

[tex]cosec A = \frac{65}{16}\\\\sin A = \frac{1}{cosecA} = \frac{16}{65}\\\\cos^2 A = 1 - sin^2 A[/tex]

        [tex]= 1 - (\frac{16}{65})^2\\\\=\frac{4225-256}{4225}\\\\=\frac{3969}{4225}\\[/tex]

[tex]cos A = \sqrt{\frac{3696}{4225}} = \frac{63}{65}[/tex]

[tex]secA = \frac{1}{cosA} = \frac{65}{63}[/tex]

Let z be inversely proportional to the cube root of y. When y =.064, z =3
a) Find the constant of proportionality k.
b) Find the value of z when y = 0.125.​

Answers

Given:

z be inversely proportional to the cube root of y.

When y =0.064, then z =3.

To find:

a) The constant of proportionality k.

b) The value of z when y = 0.125.​

Solution:

a) It is given that, z be inversely proportional to the cube root of y.

[tex]z\propto \dfrac{1}{\sqrt[3]{y}}[/tex]

[tex]z=k\dfrac{1}{\sqrt[3]{y}}[/tex]              ...(i)

Where, k is the constant of proportionality.

We have, z=3 when y=0.064. Putting these values in (i), we get

[tex]3=k\dfrac{1}{\sqrt[3]{0.064}}[/tex]

[tex]3=k\dfrac{1}{0.4}[/tex]

[tex]3\times 0.4=k[/tex]

[tex]1.2=k[/tex]

Therefore, the constant of proportionality is [tex]k=1.2[/tex].

b) From part (a), we have [tex]k=1.2[/tex].

Substituting [tex]k=1.2[/tex] in (i), we get

[tex]z=1.2\dfrac{1}{\sqrt[3]{y}}[/tex]

We need to find the value of z when y = 0.125.​ Putting y=0.125, we get

[tex]z=1.2\dfrac{1}{\sqrt[3]{0.125}}[/tex]

[tex]z=\dfrac{1.2}{0.5}[/tex]

[tex]z=2.4[/tex]

Therefore, the value of z when y = 0.125 is 2.4.

Proportional quantities are either inversely or directly proportional. For the given relation between y and z, we have:

The constant of proportionality k = 1.2, andWhen y = 0.125 , z = 2.4

What is directly proportional and inversely proportional relationship?

Let there are two variables p and q

Then, p and q are said to be directly proportional to each other if

[tex]p = kq[/tex]

where k is some constant number called constant of proportionality.

This directly proportional relationship between p and q is written as

[tex]p \propto q[/tex]  where that middle sign is the sign of proportionality.

In a directly proportional relationship, increasing one variable will increase another.

Now let m and n are two variables.

Then m and n are said to be inversely proportional to each other if

[tex]m = \dfrac{c}{n}[/tex]

or

[tex]n = \dfrac{c}{m}[/tex]

(both are equal)

where c is a constant number called constant of proportionality.

This inversely proportional relationship is denoted by

[tex]m \propto \dfrac{1}{n}\\\\or\\\\n \propto \dfrac{1}{m}[/tex]

As visible, increasing one variable will decrease the other variable if both are inversely proportional.

For the given case, it is given that:

[tex]z \propto \dfrac{1}{^3\sqrt{y}}[/tex]

Let the constant of proportionality be k, then we have:

[tex]z = \dfrac{k}{^3\sqrt{y}}[/tex]

It is given that when y = 0.064, z = 3, thus, putting these value in equation obtained above, we get:

[tex]k = \: \: ^3\sqrt{y} \times z = (0.064)^{1/3} \times (3) = 0.4 \times 3 = 1.2[/tex]

Thus,  the constant of proportionality k is 1.2. And the relation between z and y is:

[tex]z = \dfrac{1.2}{^3\sqrt{y}}[/tex]

Putting value y = 0.0125, we get:

[tex]z = \dfrac{1.2}{^3\sqrt{y}}\\\\z = \dfrac{1.2}{(0.125)^{1/3} } = \dfrac{1.2}{0.5} = 2.4[/tex]

Thus, for the given relation between y and z, we have:

The constant of proportionality k = 1.2, andWhen y = 0.125 , z = 2.4

Learn more about proportionality here:

https://brainly.com/question/13082482

3/4x × 12/11 ÷ 3x/22​

Answers

Answer:

242/48

Step-by-step explanation:

Factor the common factor out of each expression: 18u^2v^5-27uv^5+54uv^4

Answers

Answer:

9uv⁴

Step-by-step explanation:

9uv⁴(2v-3v+6)

Answer:

Factor out 9uv^4 from the expression

9uv^4(2uv - 3v + 6)

If you need more steps just ask :)

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.
y=-16x^2+165x+69

Answers

Answer:

The rocket hits the gorund after approximately 10.71 seconds.

Step-by-step explanation:

The height of the rocket y in feet x seconds after launch is given by the equation:

[tex]y=-16x^2+165x+69[/tex]

And we want to find the time in which the rocket will hit the ground.

When it hits the ground, its height above ground will be 0. Hence, we can let y = 0 and solve for x:

[tex]0=-16x^2+165x+69[/tex]

We can use the quadratic formula:

[tex]\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

In this case, a = -16, b = 165, and c = 69.

Substitute:

[tex]\displaystyle x=\frac{-165\pm\sqrt{(165)^2-4(-16)(69)}}{2(-16)}[/tex]

Evaluate:

[tex]\displaystyle x=\frac{-165\pm\sqrt{31641}}{-32}=\frac{165\pm\sqrt{31641}}{32}[/tex]

Hence, our solutions are:

[tex]\displaystyle x_1=\frac{165+\sqrt{31641}}{32}\approx 10.71\text{ or } x_2=\frac{165-\sqrt{31641}}{32}\approx-0.40[/tex]

Since time cannot be negative, we can ignore the first answer.

So, the rocket hits the gorund after approximately 10.71 seconds.

Answer:

10.71

Step-by-step explanation:

the person below was correct!

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