Answer:
Right coronary artery
Explanation:
Right coronary artery (RCA). The right coronary artery supplies blood to the right ventricle, the right atrium, and the SA (sinoatrial) and AV (atrioventricular) nodes, which regulate the heart rhythm.
Answer:
A.) Pulmonary artery
Explanation: Someone told me Aorta and i got it wrong....
what voltage produces a current of 100 amps with a resistance of 50 ohms
[tex] \sf• \: Current \: (I) = 100 \: Amps.[/tex]
[tex] \sf• \: Resistance \: (R) = 50 \: ohms[/tex]
[tex] \\ [/tex]
[tex]\bf{ \underline{To \: Find:- }}[/tex][tex] \sf• \: Voltage \: (V)[/tex]
[tex] \\ [/tex]
[tex] \huge\bf{ \underline{Solution:- }}[/tex]
[tex] \bf \red{ \bigstar{ \: The \: formula \: of \: Voltage \: (V) = IR}}[/tex]
[tex] \rightarrow \sf V = 100 \times 50[/tex]
[tex] \rightarrow \sf V = 5000[/tex]
[tex] \\ [/tex]
[tex] \bf \purple{Therefore, \: Volatage \: is \: 5000 \: v.}[/tex]
A highway speed limit is posted as 90 km/hr. Is this average speed or instantaneous speed? Explain your answer.
An object of mass m is placed on Spring A, which is compressed by distance x. The spring is released and the velocity of the pushed object as it leaves the spring is measured. The experiment is repeated with the same object on Spring B, which is compressed by the same distance x. The object travels faster when pushed by Spring B. What can be concluded?
A .Spring A had a higher elastic potential energy than Spring B.
B. Spring A's spring constant is higher than Spring B's.
C. Spring A's spring constant is lower than Spring B's.
D. Spring A has more mass than Spring B.
Answer:
C
Explanation:
The speed of the wooden bar is changed so that the bar hits the water fewer times each second.
What happens to the frequency of the waves produced?
A. Increases
B. Does not change
C. Decreases
Answer:
c - the frequency of the waves decreases
While driving his sports car at 20.0 m/s through a residential neighborhood, Royston
comes up behind a slow-moving grandma and decides to pass her on the left. If
Royston can accelerate at 6.00 m/s2, how long will it take for him to reach a velocity of
30.0 m/s?
Answer:
1.67s
Explanation:
Given parameters:
Initial velocity = 20m/s
Acceleration = 6m/s²
Final velocity = 30m/s
Unknown:
Time taken = ?
Solution:
Acceleration is the rate of change of velocity with time. It is mathematically expressed as;
Acceleration = [tex]\frac{v - u }{t}[/tex]
v is the final velocity
u is the initial velocity
t is the time taken
6 =[tex]\frac{30 - 20}{t}[/tex]
6 = [tex]\frac{10}{t}[/tex]
10 = 6t
t = 1.67s
