Examine the linear functions that represent Abel and Neal's mountain biking scenario. Abel: d = 14t, Neal: d = 11t + 6 How will you inspect the equations to determine the number of solutions? Compare the slopes. If they are the same, there will be one solution. Compare the slopes. If they are different, there will be one solution. Compare the y-intercepts. If they are the same, there will be one solution. Compare the y-intercepts. If they are different, there will be one solution.

Answer:

n - 324 = 394

STEP BY STEP EXPLANATION

Answer:

10.875 total, 1.5 times each are below.

Step-by-step explanation:

1.5 (1 1/2) x 1.5 = 2.25

0.5 (2/4) x 1.5 = 0.75

0.125 (1/8) x 1.5 = 1.875

4 x 1.5 = 6

2.25 + 0.75 + 1.875 + 6 = 10.875 total

Answer:

Jaylen's conclusion is not valid because association does not imply causation.

Step-by-step explanation:

Answer:

7 is divided by 15 =0•4666666667

Answer:

x = 50

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other two sides , then

x² = 48² + 14² = 2304 + 196 = 2500 ( take the square root of both sides )

x = [tex]\sqrt{2500}[/tex] = 50

Answer:

all diagram can be folded into triangular pyramid.

The Annuity payment will be "65,209.35 Taka". A further solution is provided below.

Given:

Monthly payment,

= 3000 Taka

Interest rate,

= 6% (compounded monthly)

Time,

= 18 years

The Future value will be:

→ [tex]FV = PMT\times \frac{((1+r)^{nt}-1)}{r}[/tex]

By putting the values, we get

         [tex]=3000\times \frac{((1+\frac{6}{12\times 100} )^{12\times 18}-1)}{\frac{6}{12\times 100} }[/tex]

         [tex]=3000\times \frac{((1+\frac{6}{1200} )^{216}-1)}{\frac{6}{1200} }[/tex]

         [tex]=1,162,059.58 \ Taka[/tex]

hence,

The Annuity payment will be:

→ [tex]P=\frac{PV(\frac{r}{n\times 100} )}{1-(1+\frac{4.5}{4\times 100} )^{-4\times 5}}[/tex]

      [tex]=P=\frac{PV(\frac{r}{n\times 100} )}{1-(1+\frac{4.5}{4\times 100} )^{-20}}[/tex]

By substituting all the values, we get

      [tex]=65,209.35 \ Taka[/tex]

Thus the correct answer is "65,209.35 Taka".

Learn more the Annuity payment here:

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Answer:

67°

Step-by-step explanation:

let the base angle=x

x+x+46=180

2x=180-46=134

x=134/2=67

Answer:

Step-by-step explanation:

It's a ray. A ray has 1 fixed point. The other end of the ray goes on forever, just as this diagram shows.

(i) The number of students who registered for political science is 150

(ii) The number of students who registered for political science and geography but not economics is 50

(iii) The number of students who registered for economics and political science but not geography is 20

The Venn diagram for the question is shown in the attachment below.

E represents Economics

G represents Geography

and P represents Political science

From the question,

10 for economics only, that is, n(E∩G'∩P') = 10

150 from economics and geography, that is n(E∩G) = 150

90 from economics but not political science, that is, n(E∩P') = 90

210 from geography, that is, n(G) = 210

120 from political science and geography, n(P∩G) = 120

180 from economics, that is, n(E) = 180

Total of student registered for courses is 250, that is, n(ξ) = 250

Now from the given information,

n(E∩G∩P') = n(E∩P') - n(E∩G'∩P') = 90 - 10 = 80

n(E∩G∩P) =  n(E∩G) - n(E∩G∩P') = 150 - 80 = 70

n(E∩P∩G') = n(E) - [n(E∩G'∩P') + n(E∩G∩P') + n(E∩G∩P)]

= 180 - [10+80+70] = 180 - 160 = 20

n(P∩G∩E') = n(P∩G) - n(E∩G∩P) = 120 - 70 = 50

n(G∩E'∩P') = n(G) - [n(E∩G∩P') + n(E∩G∩P) + n(P∩G∩E')]

= 210 -[80+70+50] = 210 - 200 = 10

All of these are shown in the Venn diagram

(i) To determine the number of students who registered for political science, we will first determine n(P∩G'∩E'), that is, those who registered for political science only.

Let n(P∩G'∩E') = x

Then, using the Venn diagram, we can write that

10 + 80 + 20 + 70 + 10 + 50 + x = n(ξ) = 250

240 + x = 250

x = 250 - 240

x = 10

n(P∩G'∩E') = 10

∴ 10 registered for political science only

Now, number of students who registered for political science n(P) is

n(P) = n(E∩P∩G') + n(E∩G∩P) +  n(P∩G∩E')  + n(P∩G'∩E')

n(P) = 20 + 70 + 50 + 10

n(P) = 150

∴ 150 students registered for political science

(ii) For the number of students who registered for political science and geography but not economics, that is, n(P∩G∩E')

As determined above and as shown in the Venn diagram,

n(P∩G∩E') = 50

∴ 50 students registered for political science and geography but not economics

(iii) For the number of students who registered for economics and political science but not geography​, that is, n(E∩P∩G')

As determine above and as shown in the Venn diagram as well

n(E∩P∩G') = 20

∴ 20 students registered for economics and political science but not geography​

Hence,

(i) The number of students who registered for political science is 150

(ii) The number of students who registered for political science and geography but not economics is 50

(iii) The number of students who registered for economics and political science but not geography is 20

Learn more here: https://brainly.com/question/15311191

Hi there!  

»»————-　★　————-««

I believe your answer is:

[tex]13x^8[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]4x^5 - 16x^2 + 13x^8[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

-0.555

Step-by-step explanation:

-2/3÷12

=-2/3÷12×3/1×3

=-2/3÷36/3

=-2/3×3/36

=-2/36

=-0.0555

I got this answer but don't know how did you got -8?!

Answer:

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (1, 4) and (x₂, y₂ ) = (2, 5 ) ← 2 ordered pairs from the table

m = [tex]\frac{5-4}{2-1}[/tex] = [tex]\frac{1}{1}[/tex] = 1

The line crosses the y- axis at (0, 3 ) → c = 3

y = x + 3 ← equation of line → A

Answer:

x = 8/3

Step-by-step explanation:

Copy the right side of the given to the right side of the equation.

sqrt(x - 5) = sqrt(3 - 2x)            Square both sides.

x - 5 = 3 - 2x                             Add 2x to both sides

2x + x - 5 = 3                            Combine

3x - 5 = 3                                  Add 5 to both sides.

3x = 3 + 5                                 Combine

3x = 8                                       Divide by 3

x = 8/3

Answer:

6/n = n/18

n^2 = 108

n = sqrt 108

a^2 + b^2 = c^2

36 + 108 = m^2

144 = m^2

m=12

Let me know if this helps!

Answer:

Step-by-step explanation:

Draco is a daddy’s boy

Answer:

4sqrt(3)

Step-by-step explanation:

If the triangle is equilateral, the hypotenuse is 2x

We can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

x^2 + 12^2 = (2x)^2

x^2 + 144 = 4x^2

144 = 4x^2 -x^2

144 = 3x^2

48 = x^2

Taking the square root of each side

sqrt(48) = sqrt(x^2)

sqrt(16*3) = x

4 sqrt(3) =x

Answer:

[tex] \sin(45) = \frac{o}{h} \\ 0.7 = \frac{x}{18 \sqrt{2} } \\ 0.7 \times 18 \sqrt{2} = x \\ 0.7 \times 25.45 = x \\ 17.8 = x[/tex]

[tex] {x}^{2} + {y}^{2} =( 18 \sqrt{2} ) ^{2} \\ {17.8}^{2} + {y}^{2} = 648 \\ 316.84 + {y}^{2} = 648 \\ {y}^{2} = 648 - 316.84 \\ {y}^{2} = 331.16 \\ y = 18.19[/tex]

Answer:

C

Step-by-step explanation:

E's coordinates are (-2,-4). When you will reflect the point about y axis, the new coordinates will be (2,-4)

Answer: C (2,-4)

Step-by-step explanation:

1:-

[tex]\\ \sf \longmapsto 4+8r-6r=6+2r[/tex]

[tex]\\ \sf \longmapsto 4+2r=6+2r[/tex]

[tex]\\ \sf \longmapsto 2r-2r=6-4[/tex]

[tex]\\ \sf \longmapsto 0=2[/tex]

[tex]\\ \sf \longmapsto r=\infty[/tex]

2:-

[tex]\\ \sf \longmapsto 1-3x=-6+7-2x-x[/tex]

[tex]\\ \sf \longmapsto 1-3x=1-3x[/tex]

[tex]\\ \sf \longmapsto 0=0[/tex]

[tex]\\ \sf \longmapsto x=\infty[/tex]

false                                               dsddsfsdfsfdfdsfdsdfsdfsdsfdfsfdsdfsdfsdfsfdsfd

Answer:

irrational

[tex]\sqrt{-15}[/tex] would be imaginary

Step-by-step explanation:

Hey there! I'm happy to help!

An irrational number is a real number that can't be written as a ratio of two other integers (non-fraction numbers) so a number like π or √2.

An imaginary number is one that breaks a mathematical rule so it can't necessarily exist as a real number. The main imaginary number is i, and here is the thing it does that breaks the rules and makes it imaginary:

i²=-1

so

√-1=i

We know that you cannot square a real number and have it be negative because a negative number can only be obtained by multiplying a positive and a negative number. This also shows us that there cannot be a square root of a negative number.

We have the number -√15. The placement of that negative sign is CRUCIAL! The square root of any positive integer is going to be a real number, but the square root of a negative number is nonexistent aka imaginary. √-15 would be an imaginary number, but we have -√15, which is the same thing as -1·√15. The negative sign is not inside the square root, which makes it not imaginary, so this is an irrational number. You can plug it into a calculator and it would be -3.872983346....

Have a wonderful day and keep on learning :)

Answer:

[tex]3g + 9g = - 48 \\ 12g = - 48 \\ g = - \frac{48}{12} \\ g = - 4 \\ \\ - 4m - 6m - 30 = - 80 \\ - 4m - 6m = - 80 + 30 \\ - 10m = - 110 \\ m = \frac{ - 110}{ - 10} \\ m = 11 \\ \\ 12 = - 8n - 24 - 4n \\ 12 + 24 = - 8n - 4n \\ 36 = - 12n \\ n = \frac{36}{ - 12} \\ n = - 3 \\ \\ 5y + 2y + \frac{1}{2} = - \frac{1}{2 } \\ 5y + 2y = - \frac{1}{2} - \frac{1}{2} \\ 7y = - 1 \\ y = - \frac{1}{7} \\ \\ 22x + 0.25 - 16x = 0.85 \\ 22x - 16x = 0.85 - 0.25 \\ 6x = 0.6 \\ x = \frac{0.6}{6} \\ x = 0.1 \\ \\ 17k + 6k + 11 = 80 \\ 17k + 6k = 80 - 11 \\ 23k = 69 \\ k = 3[/tex]

Now in pot experiments the most important point is to have the same number of plants per pot. To achieve this you plant more seeds and then you thin them after emergence to keep the same number of uniform plant per pot.

Now for calculating fertilizer rate of application in pots, you calculate according to soil weigh as you correctly indicated 2.2 M Kg/ha. You don't have to weigh the soil, just use the bulk density to calculate weigh from volume. Forget about space in pot experiment. you will have a lot of problems since pots have different shapes and forms!

Another recommandation mix soil and fertilizers for each treatment for the number of replicate pots. If you are using 5 replicates pot of 2 Kg soil/ pot, mix the fertilizers you want to apply to the 5 pots with 10 Kg of soil and after mixing well (preferably mechanically) distribute the same volume of soil in each one of the 5 pots.

If the amount of fertilizer to apply is small mix with some soil first and mix well before mixing to the whole soil. The idea is to have as much as possible, a uniform distribution.

You might also consider fractionating you nitrogen source if it will be leached.

Now according to the exact aim of your work other method sof fertilizationare possible.

Finally remember that maize is a mycorrhizal plant and this beneficial symbiosis can be influenced by the amount of soluble P you are adding.

Wishing you a lot of success in your work

hope it will helps you

ashley here

Answer:

a: x=90 b: x=45 y=45 c: y=68 x=68

Answer:

x = 60

Step-by-step explanation:

The sum of the interior angles of a quadrilateral is 360 degrees.

So if we sum up all the given angles, we would get this equation:

2x + x + 90 + 90 = 360

which simplifies to

3x + 180 = 360

subtract 180 from both sides

3x = 180

divide both sides by 3

x = 60

Answer:

Below!

Step-by-step explanation:

Since all angles in this shape add up to 360, I used this formula to find x

  360 = 90 + 90 + x + 2x

  360 = 180 + 3x

  180 = 3x

Divide both sides by 3

   60 = x

You can check to see if this works

90 + 90 + 60 + 120 = 360

Hope this helps!

Answer:

7.2

Step-by-step explanation:

Since the angle is equal, 24/(x+8.7)=13.1/8.7. x=7.2

Answer:

x ≈ 7.2

Step-by-step explanation:

Δ MNO and Δ MKL are similar, so the corresponding sides are in proportion, that is

[tex]\frac{MN}{MK}[/tex] = [tex]\frac{MO}{ML}[/tex] , substitute values

[tex]\frac{13.1}{13.1+10.9}[/tex] = [tex]\frac{8.7}{8.7 +x}[/tex]

[tex]\frac{13.1}{24}[/tex] = [tex]\frac{8.7}{8.7+x}[/tex] ( cross- multiply )

13.1(8.7 + x) = 208.8 ← distribute left side

113.97 + 13.1x = 208.8 ( subtract 113.97 from both sides )

13.1x = 94.83 ( divide both sides by 13.1 )

x = [tex]\frac{94.83}{13.1}[/tex] ≈ 7.2 ( to the nearest tenth )