Hello! :)
6m-n
6(7)-5
We plug in the values and solve:
42-5
37
Hope it helps!
If you have any query, feel free to ask! :)
~An excited gal
[tex]MagicalNature[/tex] here to help
combine like the like terms
34w - 4g + 4g - 36w
the answer is -2w (i have the write at least 20 words to dont worry about this)
Answer:
-2w
Step-by-step explanation:
Like terms have same variable.
34w - 4g + 4g - 36w = 34w - 36w - 4g + 4g
= - 2w + 0 = -2w
what is the awnser and solve for C
2c=6–3c
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
[tex]\fbox \colorbox{black}{ \colorbox{white}{C} \: \: \: \: \: \: \: \: \colorbox{white}{ = } \: \: \: \: \: + \colorbox{white}{6/5}}[/tex]
[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]
Let's find the value of c ~
[tex]2c = 6 - 3c[/tex][tex]2c + 3c = 6[/tex][tex]5c = 6[/tex][tex]c = \dfrac{6}{5} \: \: or \: \: 1.2[/tex]Answer:
c= -6
Step-by-step explanation:
2c -6 = 3c
we move all to the left
2c -6 (3c)= 0
add everything and the variables
-1c - 6 = 0
move all terms containing c to the left everything else to the right
-1c = 6
c=6/-1
c=-6
Can someone help’ it’s due today pls help pls pls
Answer:
MQP = 138
Step-by-step explanation:
Since the angle bisector always divides the angle in half exactly, we know both of the angle measures we have are the same, and set it up like this: 5x + 19 = 2x + 49 (subtract 2x from both sides) 3x + 19 = 49 (subtract 19 on both sides) 3x = 30 (divide by 3) x = 10
Substitute that x value (10) into the original equations in place of x for each angle to get MQN = 69 and NQP = 69
Add the two values to get 138. MQP = 138
Answer:
138
Step-by-step explanation:
QN bisects ∠MQP. ⇒ ∠MQN = ∠NQP
5x + 19 = 2x + 49
Subtract 19 from both sides
5x = 2x + 49 - 19
5x = 2x + 30
Subtract 2x from both sides
5x -2x = 30
3x = 30
x = 30/3
x = 10
∠MQN = 5x + 19
= 5*10 + 19
= 50 +19
= 69
∠MQP = ∠MQN +∠NQP = 69 + 69 = 138
Help me plz i wanna make an an A
(27/8)^1/3×[243/32)^1/5÷(2/3)^2]
Simplify this question sir pleasehelpme
Step-by-step explanation:
[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]
[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]
[tex]\large\underline{\sf{Solution-}}[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
We can write as :
27 = 3 × 3 × 3 = 3³
8 = 2 × 2 × 2 = 2³
243 = 3 × 3 × 3 × 3 × 3 = 3⁵
32 = 2 × 2 × 2 ×2 × 2 = 2⁵
[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now, we can write as :
(3³/2³) = (3/2)³
(3⁵/2⁵) = (3/2)⁵
[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now using law of exponent :
[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]
[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]
3. A gym charges a fee of $15 per month plus an additional charge for every group class
attended. The total monthly gym cost T can be represented by this equation: T = 15+c*n,
where c is the additional charge for a group class, and n is the number of group classes
attended
Which equation can be used to find the number of group classes a customer attended if we
know c and T?
a. n = I - 15
N
b. n=1 – 150
c. n = (T - 15) - C.
(T-15)
d. n=
1
Answer:
Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]
Step-by-step explanation:
Given the equation, T = 15 + c × n, where:
T = represents the total monthly gym cost
c = represents the additional charge for a group class, and
n = represents the number of group classes attended
Solution:In order to determine which equation can be used to find the number of group classes a customer attended, if there are given values for c and T, we must isolate the variable, n algebraically.
The first step is to subtract 15 from both sides:
T = 15 + c × n
T - 15 = 15 - 15 + c × n
T - 15 = c × n
Next, divide both sides by c to isolate n :
[tex]\huge\mathsf{\frac{({T\:-\:15})}{c}\:=\:\frac{{c\:\times\:n}}{c}}[/tex]
[tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]
Therefore, the correct answer is Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex].
what is the percentage discount when a stereo is reduced from $258 to $199?
Which of the following is true?
|−5| < 4
|−4| < |−5|
|−5| < |4|
|−4| < −5
Answer:
|-4| < |-5|
Step-by-step explanation:
because if modules is given sub sign will be deducate
Which equation, in slope-intercept form, matches the equation shown?
a line that goes through the points (0, -4) and (6, -9)
Question 4 options:
y=47x−4
y=56x+1
y=−56x−4
y=−47x+1
Please help!
Answer: i think it is y=−56x−4
Step-by-step explanation:
The equation in the slope intercept form which passes through the points ( 0, -4 ) and ( 6 , 9 ) is y = (-5 / 6)x - 4.
The correct answer is Option C.
Given data:
To find the equation of a line in slope-intercept form (y = mx + b) that passes through the points (0, -4) and (6, -9), we need to determine the slope (m) and the y-intercept (b).
First, calculate the slope (m):
m = (change in y) / (change in x)
m = (-9 - (-4)) / (6 - 0)
m = (-9 + 4) / 6
m = -5 / 6
Now that we have the slope, we can use one of the given points (let's use (0, -4)) to solve for the y-intercept (b):
-4 = (-5 / 6) * 0 + b
-4 = b
So, the y-intercept (b) is -4.
Now, we can write the equation of the line in slope-intercept form:
y = (-5 / 6)x - 4
Hence, the equation of the line is y = (-5 / 6)x - 4.
To learn more about equation of line, refer:
https://brainly.com/question/14200719
#SPJ3
The complete question is attached below:
Which equation, in slope-intercept form, matches the equation shown?
a line that goes through the points (0, -4) and (6, -9)
A) y = ( 4/7 )x - 4
B) y = ( 5/6 )x + 1
C) y = ( -5/6 )x - 4
D) y = ( -4/7 )x + 1
(2x+y)2-y2 if x=-3 y=4 and z=-5
Please I need help ASAP. Can someone help me?
Answer: The second bubble thing is correct you have picked the wrong one.
The perimeter of a rectangular field is 312m. If the width of the field is 61m,what is the length.
Answer:
95m
Step-by-step explanation:
312 - 61 - 61 = 190
190/2 = 95
Jonnell has finished 20% of an art project that has taken him a total of 3 hours so far. If he continues to work at the same rate, how many hours will it take for him to complete the entire project?
Answer:
15 hours
Step-by-step explanation:
20%=3 hours
times 5 both sides
100%=15 hours
A pizza buffet has prepared 15 pizzas to place on the line at the beginning of lunch at 11:00 a.m. The equation used to describe the total number of pizzas that have been placed out on the buffet line is shown below.
y = 11x + 15
If x represents every 8 minutes after 11:00 a.m, which statement best describes the rate of change in the number of pizzas set out on the buffet?
A.
Every 16 minutes, 11 more pizzas were set out on the buffet.
B.
Every 16 minutes, 22 more pizzas were set out on the buffet.
C.
Every 16 minutes, 32 more pizzas were set out on the buffet.
D.
Every 8 minutes, 21 more pizzas were set out on the buffet.
HELP!!!
Answer:
B. Every 16 minutes, 22 more pizzas were set out on the buffet.
Step-by-step explanation:
At 11:00 am, x would be equal to 0, and there would be 15 pizzas on the buffet line. Then, every 8 minutes, 11 more pizzas are added to the buffet line. So in 16 minutes, 22 pizzas will be added to the buffet.
[tex]\frac{16}{8} =2\\(11)(2) = 22[/tex]
24. A triangle has side lengths of 6, 8, and 9. What type of triangle is it?
acute
equiangular
obtuse
right
•
If the sum of a number and two is tripled, the result is one less than twice the number. Find the number.
Answer:
z
Step-by-step explanation:
hqvqhqvw karrar ras wallah a part
the common multiple of 4 and 20 is? a.3 b.4 c.8 d.20
Answer:
i belive its A
Step-by-step explanation: hope this helps :)
Answer:
B. 4
Step-by-step explanation:
4 times 5 is 20 and 20 divided by 5 is 4
Using the appropriate Algebraic identity evaluate the following:(4a - 5b)²
[tex](4a - 5b)^{2} \\ by \: \: \: using \: \: \: (x - y)^{2} = {x}^{2} - 2xy + {y}^{2} \\ = {(4a)}^{2} - 2(4a)(5b) + {(5b)}^{2} \\ = {16a}^{2} - 40ab + 25 {b}^{2} [/tex]
Answer:[tex] {16a}^{2} - 40ab + {25b}^{2} [/tex]
Hope it helps.
Do comment if you have any query.
(1.7x10^13)+(0.8x10^13)
Answer:
(1.7x10^13)+(0.8x10^13)
=(1.7x1e+13)+(0.8x1e+13)
=1.7e+13+0.8e+13
=2.5e+13
in actual number it would be 25,000,000,000,000
Step-by-step explanation:
PLEASE READ THIS!!! Don't answer my questions with a link. Someone already answered this question, but they gave me a link and it was blocked on my school Chromebook, so it was an entirely useless answer. Thank you. If you answer this question without using a link I will give you an easy to earn 100 points. I just need to know how to turn this shape into as many triangles as possible. Thank you for reading this message.
Answer: 9 triangles
Step-by-step explanation:
Express the tan G as a fraction in simplest terms.
Answer:
[tex]\frac{\sqrt{70} }{5}[/tex]
Before deciding whether to fly or drive, the family decided to estimate a budget of $1,400 for airfare. One airline has
several different airfares and charges $25 round-trip for each bag that is checked. Since there are 4 members of the
family and each person would check 1 bag, Luis wrote the equation 4(t + 25) = 1,400 to find the maximum cost
per ticket, t, that will fit their budget.
What is the maximum cost per ticket that will be in their budget?
325
I hope that helps
What is the common ratio of the sequence 3, 21, 147, … ?
7
Which formula can be used to find the nth term of the sequence 3, 21, 147, … ?
Use the given formula to find the indicated terms of the sequence.
a4 =
1029
a5 =
7203
Answer:
What is the common ratio of the sequence 3, 21, 147, …?
7
Which formula can be used to find the nth term of the sequence 3, 21, 147, …?
c)
Use the given formula to find the indicated terms of the sequence.
a4 = 1029
a5 = 7203
Step-by-step explanation:
Answers for all three questions<3
Can someone help me with this please
Answer:
y=1/2x
Step-by-step explanation:
Answer:
10
9
8
7
6
5
4
3
2
1
0 1 2 3 4 5 6 7 8 9 10
Step-by-step explanation:
So the arrow is pointing at 10 and 5
Answer 10 5
Not 5
its 10 5
So the answer is 10 5
BRAINLIEST, 5 STARS, AND A THANKS FOR WHOEVER HELPS!
Which statement about the answer to this problem is most accurate?
5\6−3\8=19\24
The answer 19\24 is reasonable because both fractions are closer to 1\2 than they are to 1, making the difference close to 0.
The answer 19\24 is reasonable because 5\6 and 3\8 are both closer to 1 than to 1\2, making the difference close to 0.
The answer 19\24 is not reasonable because 5\6 is closer to 1 than to 1\2, and 3\8 is close to 1\2, making the difference close to 1\2.
The answer 19\24 is not reasonable because 5\6 is closer to 1\2 than to 1, and 3\8 is closer to 0 than to 1\2, making the difference close to 1\2.
Answer:
The answer 19\24 is not reasonable because 5\6 is closer to 1 than to 1\2, and 3\8 is close to 1\2, making the difference close to 1\2.
Step-by-step explanation:
Answer:
1/2 1 0
Step-by-step explanation:
Jonah earns $3 an hour working after school and $4 an hour working on Saturdays. Last week he earned $43, working a total of 13 hours. How many hours did he work on Saturday?
Answer:
9 hours worked after school and 4 hours worked on saturday
Step-by-step explanation:
x = amount of hours worked after school
y = amount of hours worked on saturday
x + y = 13 or x = 13 - y
and
3x + 4y = 43
plug:
3 · (13 - y) + 4y = 43
39 - 3y + 4y = 43
y = 4
plug:
x = 13 - y
x = 13 - 4 = 9
9 hours worked after school and 4 hours worked on saturday
While preparing for a morning conference, principal Corsetti is laying out 8 dozen bagels on square plates. Each plate can hold 14 bagels.
A.How many plates of bagels will Mr. Corsetti have.
B. How many more bagels would be needed to fill the final plate with bagels?
Answer:
Step-by-step explanation:
We have 8 dozen bagels, or 8*12=96 bagels. Each plate can hold 14 bagels, so we have enough bagels to fill 96/14=about 6.86 plates. However, we cannot have a fraction of a plate, so we round up to have a total of seven plates. To fill all seven plates fully, 7*14=98 bagels would be needed, which is two more than we have.
To summarize, Mr. Corsetti has seven plates of bagels, and would need two more bagels to fill the last one up.
Write down an example to show that each of the following two siatements is not correct
a) The factors of an even number are always even
Answer:
a) 2 * 3 = 6.
b) 123 is odd but contains an even digit (2).
Step-by-step explanation:
what is the answer to this question: 3.75x =60
Answer:
x = 16
Step-by-step explanation:
If 3.75x would equal to 60, then x would equal to 60/3.75, which would be 16
Hope this helps!
This is a graphing problem and I am trying to find the x-intercepts and the y-intercepts. Please show me the full steps. I really appreciate it thank you.
Answer:
y-intercept: y = 3/4no x-interceptsStep-by-step explanation:
To find the y-intercept, set x=0 and evaluate the function.
f(0) = -3/(0 -4) = 3/4
The y-intercept is (0, 3/4).
__
To find the x-intercept(s), set f(x) = 0 and solve for x.
0 = -3/(x^2 -4)
0 = -3 . . . . . . . . . . multiply by (x^2 -4), x ≠ ±2
There are no values of x that will make this true. There are no x-intercepts.
_____
Additional comments
In general, you find the x-intercepts of a rational function by finding the zeros of the numerator. Here, the numerator is -3, so cannot ever be zero.
I find a graphing calculator to be a useful tool for showing where to look for x-and y-intercepts. The attached graph shows y=0 (the x-axis) is a horizontal asymptote, so there are no x-intercepts.
