Answer:
48
Step-by-step explanation:
a=2
b=3
3a^2+4b^2
3(2)^2+4(3)^2
3(2)(2)+4(3)(3)
3(4)+4(9)
12+36
48
Hope this helps ;) ❤❤❤
If 120 is divided into 3 parts which are proportional to 1, [tex]\frac{1}{2} [/tex], and [tex]\frac{1}{6}[/tex], what is the middle part?
[tex]k+\frac{k}{2}+\frac{k}{6}=120\\\\6k+3k+k=720\\10k=720\\k=72[/tex]
72,36,12
answer: 36
What is 5 divided by 3,678
Answer:
Simple division..
divide 5 by 3,678
you'll get answer
0.00135943447
●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●
Hi my lil bunny!
❧⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯☙
[tex]5\ \div \ 3678[/tex]
[tex]= \frac{5}{3678}[/tex] (Decimal: 0.001359)
●✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎❀✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎✴︎●
If this helped you, could you maybe give brainliest..?
❀*May*❀
Given f(x) = -4(x-3)^2-2
a) Determine the inverse of f(x)
b) List the domain and range of inverse.
Answer:
[tex]\sqrt{\frac{x+2}{-4} }+3=y[/tex] d=(-infinity,-2) r=(3,+infinity)
Step-by-step explanation:
i did the math
The box plots display the same data set for the number of touchdowns a quarterback threw in 10 seasons of play. Including outlier: A number line goes from 5 to 30. The whiskers range from 5 to 29, and the box ranges from 18 to 26. A line divides the box at 21.5. Excluding outlier: A number line goes from 5 to 30. The whiskers range from 17 to 29, and the box ranges from 19 to 27. A line divides the box at 21. There is an asterisk at 5. Complete the statements describing the effect of the outlier on the measures of variability. The outlier of the data set is . The range of the data set including the outlier is more than the one excluding the outlier. The interquartile range of the data set including the outlier is more than the one excluding the outlier. The outlier had the most effect on the .
Answer:
5
12
0
range
Step-by-step explanation:
i just did it, these are the right answers.
Answer:
5,12,0, and the last answer is range
Step-by-step explanation:
Did it on Edge2021. Hope this helps!
The net of a right rectangular prism is shown below: Find the volume of the prism with the given net (in cubic inches).
Answer:
240 inches cubed
Step-by-step explanation:
Volume equals length times width times height. Imagine the net is folded into its shape. The product of the base, 6 x 10 = 60, and the height, 4, equals 240. Remember that each square accounts for two inches. Hope this helps.
Find the number set which satisfies each of the problems. If 7 is subtracted from the absolute value of the sum of a number and 6, the result is 3.
Answer:
x=4 or x= - 16
Step-by-step explanation:
|x+6|
Now subtract 7 which equals to 3.
|x+6|-7=3
|x+6|=10
Now remove the mode by adding plus minus sign in the front of 10.
x+6=±10
x+6=10 or x+6=-10
x=4 or x=-16
PLEASE HELP! 10 POINTS Which line would be the line of best fit for the scatter plot?
Answer:
The first one
Step-by-step explanation:
This line is the best fit for the scatter plot because it touches a lot more points than the second
Answer:
The first line
Step-by-step explanation:
Hey there!
Well the first lie is a positive slope just like the dots whereas,
the second line is a negative slope.
Therefore, the first line is the line of best fit.
Hope this helps :)
5. Find the measures of the following. Round to the nearest whole number
Answer:
a - HT = 17
b - ∠T = 62
c - ∠H = 28
Two functions, A and B, are described as follows: Function A y = 9x + 4 Function B The rate of change is 3 and the y-intercept is 4 How much more is the rate of change of function A than the slope of function B? 3 6 2 9
Answer:
6
Step-by-step explanation:
Function A
y = 9x + 4
Function B
y = max+b
m = 3 and b = 4
y = 3x+4
The difference in the slopes is 9-3 = 6
Answer:
6
Step-by-step explanation:
The two functions are A and B.
A's equation is khown
● y =9x + 4
B is also khown. We should only gather tge information.
● the rate of change is 3
●the y-intercept is 4
So B's equation is:
● y = 3x + 4
3 is the rate of change wich is khown as the slope.
Divide A's slope by B's slope to khow how much A's slope is bigger than B's.
● 9/3 = 3
Substract 3 from 9 and you get the difference 9-3= 6
What is the total surface area of the square pyramid below? A square pyramid. The square base has side lengths of 10 centimeters. The triangular sides have a height of 14 centimeters. 100 cm2 200 cm2 280 cm2 380 cm2
Answer:
380 cm^2
Step-by-step explanation:
10*10=100(base square)
Each triangle= (14*10) /2=70
4 sides, so therefore: 70*4=280
280+100=380
Since the square base has side 10 cm and triangular side has height 14 cm, the total surface area of square pyramid is 380 cm²
To answer the question, we need to find the total surface area of the square pyramid
Total surface area of a square pyramid.Since a square pyramid has a square base and four triangular sides, its surface area, A = area of square base + 4 × Area of triangular side.
Area of square base
Area of square with side, L is A = L²
Area of triangular base
Area of triangle with height, h and base, L which is the length of the square base is A' = 1/2Lh
So, total surface area of square pyramid is A" = L² + 4 × 1/2Lh
= L² + 2Lh
Given that the length of the square base is 10 cm and the height of the triangular side is 14 cm.
We have that
L = 10 cm and h = 14 cmSo, substituting the values of the variables intot he equation, we have
A" = L² + 2Lh
A" = (10 cm)² + 2 × 10 cm × 14 cm
A" = 100 cm² + 280 cm²
A" = 380 cm²
So, the total surface area of square pyramid is 380 cm²
Learn more about total surface area of square pyramid here:
https://brainly.com/question/22744289
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The coefficient of 6x is
1
6
Х
Answer:
6
Step-by-step explanation:
If a number and a variable were together in a term, the number would the the coefficient. The coefficient would multiply the variable.
In '6x', the number '6' is the coefficient. '6' would be multiplying 'x'.
The correct answer should be 6.
Jill paid $36 for calendars marked down $5 apiece from the original price, she could have gotten 5 fewer calendars. How many cards did she buy
Answer:
she bought 7 cards
Step-by-step explanation
7x5=35 and im sure there is tax
Simplify (−3c3w5)3. −9c6w8 −9c9w15 −27c6w8 −27c9w15
Answer:
-6723cw
Step by Step:
(-3c * 3w * 5) * 3 - 9c * 6w* 8 - 9c * 9w * 15 - 27c * 6w * 8 - 27c * 9w * 15
Tamara walked 3/4 mile in 1/2 hour. Which of the following represents the unit rate that Tamara walked? A. 1/2 mi/h B. 2/3 mi/h C. 3/4 mi/h D. 1 1/2 mi/h Include ALL work please!
Answer:
1 1/2 miles / hour
Step-by-step explanation:
We want distance / time
3/4 miles
---------------
1/2 hour
3/4 ÷ 1/2
Copy dot flip
3/4 * 2/1
3/2
1 1/2 miles / hour
Answer:
D
Step-by-step explanation:
Multiple (3/4) by 2 to find the information for one hour)
6/4 in one hour
3/2 or 1 + 1/2 mi/h
D is the answer
WILL GIVE BRAINLY!!!!!! NEED HELP ASAP!!!!!!!! what is the range of f(x)=3^x+9
Answer:
y > 9
Step-by-step explanation:
The range of a function is the interval of all possible y-values that make the function true.
Here, one way to figure this out is to look at a graph of the function (see attachment).
From the graph, we can see that y-values approach very closely the value 9 and then the line rises beyond 9 forever. Thus, we can conclude that the range for f(x) is y > 9.
~ an aesthetics lover
Solve for x show work plz
Answer:
20
Step-by-step explanation:
We know that ΔBAC and ΔBED are similar becuase of the AA Postulate (they both have a right angle and they both share ∠B). Since AC is 15/3 = 5 times longer than ED, the scale factor is 5 which means AB is 5 times longer than EB. This makes EB = 25 / 5 = 5. Since AB = AE + EB and we know that AB = 25, AE = x and EB = 5, 25 = x + 5 which means x = 20.
Name five fractions whose values are between 3/8 and 7/12
Answer:
convert them to decimasls
Step-by-step explanation:
convert thhem to decimals to make it easier
Answer:
1/2 2/4 4/8 6/12 9/18
Step-by-step explanation:
solve for m. √m-7 = n+3 It is worth like 40 points
Answer:
sqrt of (m-7) = n+3
m = (n+3)^2 + 7 or m= n^2 + 6n + 16
sqrt of (m)-7 = n+3
m = (n+10)^2 or m =n^2 + 20n + 100
Step-by-step explanation:
(2) move the constants to the other side, and square
or (1) square and move constants
then you can solve for m
Answer:
[tex]n^2+6n+16[/tex]
Step-by-step explanation:
I'm going to assume you meant [tex]\sqrt{m-7} = n+3[/tex], not [tex]\sqrt{m} - 7 = n+3[/tex].
[tex](\sqrt{m-7}) ^2 = (n+3)^2\\\\(\sqrt{m-7}^2) = (n+3)^2\\\\(m-7)^{\frac{2}{2} } = (n+3)^2\\\\m - 7 = (n+3)^2\\\\m - 7 = n^2 + 2n\cdot3 + 3^2\\\\m - 7 = n^2 + 6n + 9\\\\m - 7 + 7 = n^2 + 6n + 9 + 7\\\\m = n^2 + 6n + 16[/tex]
Hope this helped!
-5+2(10b-2)=31 need help thanks!
Answer:
[tex]\Large \boxed{b=2}[/tex]
Step-by-step explanation:
-5+2(10b-2)=31
Expand brackets.
-5+20b-4=31
-9+20b=31
Add 9 on both sides.
20b=40
Divide both sides by 20
b=2
Answer:
b = 2Step-by-step explanation:
-5+2(10b-2)=31
Multiply the terms in the bracket
That's
- 5 + 20b - 4 = 31
Group like terms
Send the constants to the right side of the equation
That's
20b = 31 + 4 + 5
Simplify
20b = 40
Divide both sides by 20
We have the final answer as
b = 2Hope this helps you
please help me.... The question no.b and would like to request you all just give me correct answer.
Answer: see proof below
Step-by-step explanation:
You will need the following identities to prove this:
[tex]\tan\ (\alpha-\beta)=\dfrac{\tan \alpha-\tan \beta}{1+\tan \alpha\cdot \tan \beta}[/tex]
[tex]\cos\ 2\alpha=\cos^2 \alpha-\sin^2\alpha[/tex]
LHS → RHS
[tex]\dfrac{2\tan\ (45^o-A)}{1+\tan^2\ (45^o-A)}\\\\\\=\dfrac{2\bigg(\dfrac{\tan\ 45^o-\tan\ A}{1+\tan\ 45^o\cdot \tan\ A}\bigg)}{1+\bigg(\dfrac{\tan\ 45^o-\tan\ A}{1+\tan\ 45^o\cdot \tan\ A}\bigg)^2}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan\ A}{1+\tan\ A}\bigg)}{1+\bigg(\dfrac{1-\tan\ A}{1+\tan\ A}\bigg)^2}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{1+\bigg(\dfrac{1-2\tan\A+\tan^2 A}{1+2\tan A+\tan^2A}\bigg)}\\[/tex]
[tex]=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{\dfrac{(1+2\tan A+\tan^2A)+(1-2\tan A+\tan^2 A)}{1+2\tan A+\tan^2A}}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{\dfrac{2+2\tan^2A}{1+2\tan A+\tan^2A}}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{2\bigg(\dfrac{1+\tan^2A}{(1+\tan A)^2}\bigg)}\\\\\\=\dfrac{\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{\bigg(\dfrac{1+\tan^2A}{(1+\tan A)^2}\bigg)}[/tex]
[tex]=\dfrac{1-\tan A}{1+\tan A}}\times \dfrac{(1+\tan A)^2}{1+\tan^2A}\\\\\\=\dfrac{1-\tan^2 A}{1+\tan^2 A}\\\\\\=\dfrac{1-\dfrac{\sin^2 A}{\cos^2 A}}{1+\dfrac{\sin^2 A}{\cos^2 A}}\\\\\\=\dfrac{\bigg(\dfrac{\cos^2 A-\sin^2 A}{\cos^2 A}\bigg)}{\bigg(\dfrac{\cos^2 A+\sin^2 A}{\cos^2 A}\bigg)}\\\\\\=\dfrac{\cos^2 A-\sin^2 A}{\cos^2 A+\sin^2 A}\\\\\\=\dfrac{\cos^2 A-\sin^2 A}{1}\\\\\\=\cos^2 A-\sin^2 A\\\\\\=\cos 2A[/tex]
cos 2A = cos 2A [tex]\checkmark[/tex]
f(x) = [tex]\sqrt{x+7} -\sqrt{x^2+2x-15}[/tex] find the domain
Answer:
x >= -7 ................(1a)
x >= 3 ...............(2a1)
Step-by-step explanation:
f(x) = [tex]\sqrt{x+7}-\sqrt{x^2+2x-15}[/tex] .............(0)
find the domain.
To find the (real) domain, we need to ensure that each term remains a real number.
which means the following conditions must be met
x+7 >= 0 .....................(1)
AND
x^2+2x-15 >= 0 ..........(2)
To satisfy (1), x >= -7 .....................(1a) by transposition of (1)
To satisfy (2), we need first to find the roots of (2)
factor (2)
(x+5)(x-3) >= 0
This implis
(x+5) >= 0 AND (x-3) >= 0.....................(2a)
OR
(x+5) <= 0 AND (x-3) <= 0 ...................(2b)
(2a) is satisfied with x >= 3 ...............(2a1)
(2b) is satisfied with x <= -5 ................(2b1)
Combine the conditions (1a), (2a1), and (2b1),
x >= -7 ................(1a)
AND
(
x >= 3 ...............(2a1)
OR
x <= -5 ................(2b1)
)
which expands to
(1a) and (2a1) OR (1a) and (2b1)
( x >= -7 and x >= 3 ) OR ( x >= -7 and x <= -5 )
Simplifying, we have
x >= 3 OR ( -7 <= x <= -5 )
Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.
The two points on the coordinate plane represent Jane's house and her friend's house. Find the distance between the houses. Question 3 options: A) units B) units C) units D) units
Answer:
8.3
Step-by-step explanation:
To do this use the distance formula
[tex]d = \sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]
First find the coordinates Jane (-5, -2) Friend (3, -4)
Now solve for d (8.246)
Answer:
10 units or approx. 8.25 units
Step-by-step explanation:
Jane's house is at coordinate (-5,-2) and her friend's house is at coordinate (3,-4).
You can find the answer in 2 ways.
1) Hypotenuse (the diagonal side or side across from the right angle) - approx. 8.25 units
2) Down and Side (go down 2 units and go side 8 units) - 10 units
Hope that helps and maybe earns a brainliest!
Have great day ahead! :)
If we transform the parabola y=(x+1)^2+2 by shifting 7 units to the right and 5 units down, what is the vertex of the resulting parabola? Vertex of resulting parabola: (__ a0,__ a1)
Hey there! I'm happy to help!
The vertex form of a parabola is y=a(x-h)²+k. The h represents the horizontal transformation, while the k represents the vertical. The vertex of a parabola in this form is (h,k). The a represents a vertical stretch or shrink.
Our parabola is y=(x+1)²+2. This is already in vertex form, so we do not need to change the equation. There is no a (basically a=1), which means that the parabola has not been stretched or shrunk from its parent form.
We see that the h is -1. This is because in the original equation it is (x-h)², so it has to be -1 because the two negatives make a positive which is the +1. (x--1)=(x+1).
We see that the k value is 2.
Since the vertex is (h,k), this vertex is (-1,2).
However, we have to shift the parabola 7 units to the right and 5 units down. So, we add 7 to the x-value and subtract 5 from the y-value of the vertex.
(x,y)⇒(x+7,y-5)
(-1,2)⇒(6,-3)
Therefore, the vertex of the resulting parabola is (6,-3).
Have a wonderful day! :D
35= -5(2k+5)?????? need help
Answer:
k=-6
Step-by-step explanation:
Answer:
[tex]\Large \boxed{k=-6}}[/tex]
Step-by-step explanation:
35 = -5(2k+5)
Expand brackets.
35 = -10k - 25
Add 25 on both sides.
60 = -10k
Divide both sides by -10.
-6 = k
help me plz can i have help
Answer:
6×[tex]10^{-4}[/tex]
Step-by-step explanation:
what is (8*8*8) * (8*8*8*8) in exponential form?
The exponent 7 tells us how many copies of "8" are being multiplied together.
The expression 8*8*8 is equal to 8^3, while 8*8*8*8 = 8^4
Multiplying 8^3 and 8^4 will have us add the exponents to get 8^7. The base stays at 8 the entire time.
The rule is a^b*a^c = a^(b+c) where the base is 'a' the entire time.
Answer:
8^ 7
Step-by-step explanation:
(8*8*8) * (8*8*8*8)
There are 3 8's times 4 8's
8^3 * 8^4
We know that a^b * a^c = a^ (b+c)
8 ^ ( 3+4)
8^ 7
URGENT!!!! PLEASE HELP NOW!!! WHO EVER GIVES THE CORRRECT ANSWER WILL GET BRAINLIEST!!!
Items Sold at a Clothing Store
The bar graph shows the number of each item sold at a clothing store. Which
statement about the graph is true?
Answer:
The correct ans is..... ( which i believe )
3rd option
Hope this helps...
Pls mark my ans as brainliest
If u mark my ans as brainliest u will get 3 extra points
Answer:
3rd option
Step-by-step explanation:
because 2/5 of 40 is equal to 16, and thats the equivelent of the pants sold.
*PLEASE ANSWER* Compare the volume of these two shapes,given their radii and heights are the same .
Answer:
The correct option is;
Left object volume = right object volume
Step-by-step explanation:
The shapes given in the question are two circular cones that have equal base radius and equal height
The formula for the volume, V of a circular cone = 1/3 × Base area × Height
The base area of the two shapes are for the left A = π·r², for the right A = π·r²
The heights are the same, therefore, the volume are;
For the left
[tex]V_{left}[/tex] = 1/3×π·r²×h
For the right
[tex]V_{right}[/tex] = 1/3×π·r²×h
Which shows that
1/3×π·r²×h = 1/3×π·r²×h and [tex]V_{left}[/tex] = [tex]V_{right}[/tex], therefore, the volumes are equal and the correct option is left object volume = right object volume.
What’s x ?? Help plzzz
Answer:
x = 69°
Step-by-step explanation:
1). JFGHI is a pentagon, every angle in a Pentagon is equal to 108°.
2). angle JIH + angle HIE = 180°; angle JIH = 108, so angle HIE = 72°.
3). angle JDI is equal to 39° and angle IEH; so angle IEH = 39°
4). Now we know 2 out of the three angles in the triangle IHE, so we can find x!
5). x + angle HIE + angle IEH = 180°
x + 72° + 39° = 180°
x = 69°
Find the sine and cosine of each angle as a fraction and as a decimal. Round to the nearest hundredth.
Answer:
1st triangle:
sin(C): 0.64, [tex]\frac{16}{25}[/tex]
cos(C): 0.8, [tex]\frac{4}{5}[/tex]
Second triangle:
sin(C): 0.75, [tex]\frac{\sqrt{5} }{3}[/tex]
cos(C): 0.67, [tex]\frac{2}{3}[/tex]
Step-by-step explanation:
Using SOH CAH TOA, we know that to find the sin of an angle, it's Opposite/Hypotenuse.
To find the cos of an angle, it's adjacent/hypotenuse.
In the 1st triangle:
The adjacent to C is 16, the hypotenuse is 25.
[tex]\frac{16}{25} = 0.64[/tex] is the sin of C.
The adjacent to C is 20, and the hypotenuse is 25.
[tex]\frac{20}{25} = 0.8[/tex] is the cos of C.
In the second triangle:
The opposite to C is [tex]\sqrt{5}[/tex] and the hypotenuse is 2.
[tex]\frac{\sqrt{5} }{2} \approx0.75[/tex] is the sin of C.
The adjacent to C is 2 and the hypotenuse is 3.
[tex]\frac{2}{3} \approx 0.67[/tex] is the cos of C.
Hope this helped!